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HAL Id: hal-00004638

https://hal.archives-ouvertes.fr/hal-00004638v2

Preprint submitted on 22 Mar 2006

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Continuity of the trace operator with respect to the

domain and application to shape optimization

A. Boulkhemair, A. Chakib, A. Nachaoui

To cite this version:

A. Boulkhemair, A. Chakib, A. Nachaoui. Continuity of the trace operator with respect to the domain and application to shape optimization. 2006. �hal-00004638v2�

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Continuity of the trace operator with respect to the domain and

application to shape optimization

A. Boulkhemair1, A. Chakib2 and A. Nachaoui1

1 Laboratoire de Math´ematiques Jean Leray,

CNRS UMR6629/ Universit´e de Nantes,

2, rue de la Houssini`ere, BP 92208, 44322 Nantes, France.

E-mail: boulkhem@math.univ-nantes.fr & nachaoui@math.univ-nantes.fr

2 D´epartement de Math´ematiques Appliqu´ees et Informatique

FST de Beni-Mellal, Universit´e Cadi-Ayyad B.P. 523, Beni-Mellal, Morocco.

E-mail: chakib@fstbm.ac.ma

Abstract

Shape optimization amounts to find the optimal shape of a domain which minimizes a given criterion, often called a cost functional. Here, we are interested in the case where the criterion is computed through the solution of a partial differential equation, the so-called state equation, which makes the optimization problem non-trivial. We use a general parameterization of the unknown boundary in order to preserve the physical general information and we prove the continuity of the cost functional.

1

Introduction

Varying domains constitute an important type of inverse problems which appear in connection with a variety of phenomenon in different fields. Shape Identification, free or moving boundary problems, phase change or elastic contact problems fall into the class of such inverse problems with a priory unknown domains. Some problems that lead to boundary inverse problems are: the dam seepage problem [14]; Riabouchinsky flow past circular disks [21]; Falling droplets [35, 32, 38]; the Alt-Caffarelli or Bernoulli problem [4]. The common structure of these problems is that there are elliptic equations for m unknowns and m + 1 mixed Dirichlet-Neumann conditions on the unknown surface. Many more problems also fall into this general category, with applications to aluminium production by electrolytic reduction [13]; groundwater flow [25, 29]; free surface waves [9]]; semiconductors [2, 16]; electromagnetic casting [33, 31]; the Dam and Bernoulli problems [10, 37, 28, 22, 17].

There is no previous analytic theory covering this general class of boundary inverse problems, although there has been progress on individual problems.

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A variety of techniques exist for numerically solving boundary inverse problems, see [14, 26, 16, 1, 11] and the references therein. Among this, shape optimization technique is a useful method for solving the type of problems mentioned above. This is a variational approach, minimizing an integral functional over the variable domain having an unknown boundary. For an introduction to shape optimization, cf [23, 36] and some examples of its use are given in [5, 8, 15, 18, 34].

A general formulation of such optimal shape approaches can be expressed as follows

(

Minimize J(Ω, u)

subject to Ω ∈ Θad and u ∈ U(Ω),

(1) where U(Ω) denotes the set of solutions of a given partial differential equation on the domain Ω (state equation on Ω) and Θad is a set of admissible domains.

In order to show the existence of a solution for this type of problems, a widely used method is to show that the space F = {(Ω, u) , Ω ∈ Θad, u ∈ U(Ω)} is compact with a suitable topology on

F which is induced from topologies on Θad and U(Ω), and that the cost functional J is lower semi

continuous on F [23].

In this paper, we are interested in the continuity of cost functionals that can be associated to the determination of the location, size and shape of an unknown portion Γ, of the boundary ∂Ω of a domain Ω ⊂R2, from given, Dirichlet and Neumann, boundary conditions on this unknown part of the boundary. More precisely, we consider the boundary cost functional J defined by

J(Ω, u) =

Z

Γ(u − g)

2dσ, which is associated with problems where a condition of the type u = g has

to be imposed on Γ. The function g is given and u is the solution of a partial differential equation on Ω. In the case where the unknown boundary Γ is the graph of a function, continuity results for this type of functionals with a suitable topology on F have been obtained in [6, 10, 24]. However, in many physical problems this assumption on the unknown boundary is too restrictive. The situation where the unknown boundary can not be the graph of a function occurs in many engineering problems such as, for example, the dam problem in non-homogeneous porous media [10, 19, 22], the Stefan problem [20], optimal insulating and electro-chemistry [3, 17] and the semiconductor problem [27, 16]. Here, we use a general parameterization of the unknown boundary in order to preserve the physical general information on this boundary. The topology we use on Θad is just

that associated to the C1 convergence of the parameterizations.

The main result of this paper is the continuity of the trace operator from Hr(Ω) (1 ≥ r > 1 2)

to L2(Γ) with a constant independent of Γ. This is proved in section 3. At this stage, it should be

noted that, in the case of a family of domains with parallel boundaries, a similar result has been obtained by Lions and Magenes in [30]. The continuity of the cost functional J on the space F is established in section 4. Actually, we prove the continuity of a more general functional.

2

Notations and definitions

Let D be a fixed C1 open connected bounded subset of R2. An admissible domain Ω will be an

open subset of D. The boundary ∂Ω of Ω is assumed to consist in two parts ∂Ω = Γ0∪ Γ such that

Γ0∩ Γ = ∅, meas(Γ0) > 0 and meas(Γ) > 0, where Γ is the free boundary part defined by Γ = Γ(ϕ) = {ϕ(t) = (ϕ1(t), ϕ2(t)) ; t ∈ [0, 1]},

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ϕ : [0, 1] →R2 is a parameterisation and Γ is assumed to have its endpoints on the boundary of D (see figure 1). In fact, in this general setting, the curve Γ(ϕ) can divide D into two open subsets. This is the case for example when D is simply connected. We have then to choose Ω. We can make for example the following choice : We follow the natural orientation given by the parameterisation and take the open set whose exterior unit normal boundary vector is on the left.

We shall also write Ω = Ω(ϕ) to indicate the dependence on the parameterization ϕ.

Ω = Ω(ϕ)

Γ0

Γ(ϕ)

D

Figure 1: An example of the considered domain Ω = Ω(ϕ). We shall denote by ν(x) the exterior unit normal vector to ∂D at x ∈ ∂D. Define Vadto be the set of vector functions ϕ ∈ C1

¡

[0, 1],R2¢satisfying the following conditions :

|ϕ(t)| ≤ C0, ∀t ∈ [0, 1],

C1|t − t0| ≤ |ϕ(t) − ϕ(t0)| ≤ C2|t − t0|, ∀t, t0∈ [0, 1],

ϕ([0, 1]) ⊂ D and, for t = 0 or 1, ϕ(t) ∈ ∂D,

for t = 0 or 1, |ν(ϕ(t)).ϕ0(t)| ≥ ²0, (2) and, for all t ∈ [0, 1], d(ϕ(t), ∂D) ≥ ²1t(1 − t), (3)

where C0, C1, C2, ²0and ²1are positive fixed constants, d(ϕ(t), ∂D) is the distance of the point ϕ(t)

from the boundary ∂D, and we are using the standard notations |(a, b)| =√a2+ b2, (a, b).(a0, b0) =

aa0+ bb0. Note that the assumptions (2) and (3) are made to insure that the curve Γ(ϕ) touches the

boundary ∂D only two times (with the endpoints) and in a transverse manner. The consequence of this is that the domain Ω(ϕ) is Lipschitz regular.

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Now, the set Uad of admissible functions will be any compact subset of Vad. In other words,

Uad is a subset of Vad whose elements and their derivatives are equicontinuous as it follows from

Ascoli-Arzel`a theorem. An example of such a set Uad is that of a closed subset of Vad which is bounded in C1,δ¡[0, 1] ,Rfor some δ such that 0 < δ ≤ 1.

The space of admissible domains is then defined by :

Θad= {Ω = Ω(ϕ) ⊂ D ; ϕ ∈ Uad} .

Note that the elements of Θad are uniformly Lipschitz open sets of R2 and so they satisfy the

uniform cone property [34].

Assume that u = u(Ω) ∈ H1(Ω) is the solution of a well posed problem such as

(

Lu = f in Ω

L∂Ωu = h on ∂Ω,

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where Ω ∈ Θad and Land L∂Ω are partial differential operators on Ω and ∂Ω respectively.

The cost functional J we are interested in is then defined on the set

F = {(Ω(ϕ), u(Ω)) ; Ω(ϕ) ∈ Θad and u(Ω) solves (4) on Ω(ϕ)}

by

J(Ω(ϕ), u(Ω)) =

Z

Γ(ϕ)(u(Ω) − g) 2dσ,

where g is a given function on D having essentially the same regularity as u(Ω). For simplicity and without any restriction on our study, we shall assume that g = 0.

Now, the customary problem of shape optimization or optimal shape design is

to minimize J(Ω, u) on F. (5)

As we have already said, this minimization problem is usually solved by endowing the set F with a topology for which F is compact and J is lower semi-continuous. Let us therefore define the topology we shall work with. First, we define the convergence of a sequence (ϕn)n⊂ Uad by

ϕn −→ ϕ ⇐⇒

(

ϕn−→ ϕ uniformly on [0, 1]

ϕ0n−→ ϕ0 uniformly on [0, 1] (6) that is, iff ϕn → ϕ in the C1 topology. Then, the convergence of a sequence (Ω

n)n ⊂ Θad, such

that Ωn= Ω(ϕn), to Ω = Ω(ϕ) ∈ Θad is simply defined by

n −→ Ω ⇐⇒ ϕn −→ ϕ. (7)

Denote byu the uniform extension of u from Ω to an open smooth bounded domain B (a disc, fore

example), such that D ⊂ B (see [12]). We define the convergence of a sequence (un)n of solutions

of (4) on Ω(ϕn) to u the solution of (4) on Ω(ϕ) by

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Finally, the topology we put on F is the one induced by the convergence defined by (Ωn, un) −→ (Ω, u) ⇐⇒ ( Ωn−→ Ω un−→ u. (9) Thus, the compactness of F with respect to this topology depends on the type of the state problem (4) and on the compactness of Θad with respect to the convergence (7). At this stage, we have to

say that it is not our objective here to prove the compactness of F, the setting being too general. But since Uad is compact, one can obtain the compactness of F from the continuity of the state problem (4), which is based on the following (reasonable) condition : There exists a constant C > 0 such that ku(Ω)k1,Ω ≤ C, ∀Ω ∈ Θad. Anyhow, the chosen topology is rather natural, is used in

many applied problems and, as we shall see, it allows to prove the continuity of the cost functional

J and even the continuity of more general boundary functionals (see section 4).

3

Continuity of the trace operator

In this section, we give a proof of the trace theorem which allows us to estimate the norm of the trace operator by a constant independent of the free boundary Γ.

Theorem 1 Let u be in Hr(B), 1 ≥ r > 1

2, and Ω(ϕ) ∈ Θad. Then, there exists a constant K

independent of ϕ such that

kuk0,Γ(ϕ) ≤ K kukr,B

where k · k0,Γ(ϕ) is the L2(Γ(ϕ))-norm and k · k

r,B is the Hr(B)-norm.

The proof of this result is based on the following constructions and techniques.

Let ϕ ∈ Uad. By using standard techniques, we can construct a continuous extension operator

from C[0, 1] ,Rto ˜C[−1, 2] ,R= {ϕ ∈ CR,R; supp(ϕ) ⊂ [−1, 2]}, such that the

extensionϕ of ϕ toe Rsatisfies

e0kL(R)= kϕ0kL([0,1]), (10)

where k · kL is the L∞-norm.

Now, let χ ∈ D(R) such that χ ≥ 0,

Z

R

χ dx = 1 and supp(χ) ⊂ [−1, 1]. We define the function ψk = (ψ1,k, ψ2,k), k ∈N, on Ras a regularized function ofϕ, that is,e

ψk(t) = Z R e ϕ(t − τ ) χ(kτ ) k dτ. Note that ψk0(t) = Z R e ϕ0(t − τ ) χ(kτ ) k dτ. Since ϕe0 is continuous, it is well known that ψ0

k converges uniformly to ϕe0 on any compact subset

ofR as k −→ ∞. In particular,

lim

k−→∞kψ 0

k− ϕ0kL∞([0,1])= 0.

In fact, we can show that for any ε > 0, there exists kε∈N∗independent of ϕ such that, for k ≥ kε,

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Indeed, we have k0(t) −ϕe0(t)| = | Z R ¡ e ϕ0(t − τ ) −ϕe0(t)¢ χ(kτ ) k dτ | Z R e0(t −τ k) −ϕe 0(t)| χ(τ ) dτ.

Since the extension operator is continuous from C[0, 1] ,Rto Ce1¡[−1, 2] ,R, the functions e

ϕ0, are equicontinuous and uniformly continuous when ϕ describes U

ad. So, for ε > 0, there exists

γε> 0 independent of ϕ such that

∀t, t0∈R, |t − t0| ≤ γε implies that e0(t) −ϕe0(t0)| ≤ ε, ∀ϕ ∈ Uad. (11)

Hence, for k such that |τ |

k 1 k ≤ γε and all t ∈R, k0(t) −ϕe0(t)| ≤ Z R ε χ(τ ) dτ = ε.

So, we can take kε= [γ1

ε] + 1, where [ · ] denotes the integral part.

Now, to the given ϕ ∈ Uad, we associate the function Φ ∈ C[0, 1] ×R,Rdefined by

Φ(t, s) = ϕ(t) + s ψk0ε(t)⊥, s ∈R, (12) where we are using the notation (a, b)⊥= (−b, a). In what follows, we shall omit the index k

ε and

write ψ instead of ψkε.

The following lemma is basic for the proof of Theorem 1.

Lemma 1 There exists a small enough s0 > 0 such that s0 is independent of ϕ ∈ Uad and the

following three assertions hold.

(i) The Jacobian, JΦ, of Φ is such that

|JΦ| ≥ 1

2C

2

1 on [0, 1] × [−s0, s0] . (13)

(ii) There exists C3 > 0 independent of ϕ such that

|Φ(t, s) − Φ(t0, s0)| ≤ C3|(t − t0, s − s0)|, ∀(t, s), (t0, s0) ∈ [0, 1] × [−s0, s0]. (14)

(iii) Φ is injective in [0, 1] × [−s0, s0], and, more precisely,

|Φ(t, s) − Φ(t0, s0)| ≥ 2 4 C1|(t − t 0, s − s0)|, ∀(t, s), (t0, s0) ∈ [0, 1] × [−s 0, s0]. (15)

where C1 is the same constant as that in the definition of Uad.

Proof :

(i) We have that

Φ0 = Ã ϕ0 1− s ψ200 −ψ20 ϕ02+ s ψ100 ψ01 ! .

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So,

JΦ = det(Φ0) = ϕ01ψ10 + ϕ02ψ20 + s (ψ100ψ02− ψ01ψ200) = |ϕ0|2+ ϕ0· (ψ − ϕ)0− s ψ00· ψ0⊥.

It follows from the definition of ψ = ψkε that

kψ0⊥kL([0,1])≤ kψ0kL(R)≤ kϕe0kL(R) Z R χ(kετ ) kεdτ kϕe0kL∞([0,1])≤ C2 (16) and kψ00kL([0,1])≤ kψ00kL(R) ≤ kϕe0kL(R)k2ε Z R |χ0(kετ )| dτ ≤ C2 Z R |χ0(τ )| dτ ≡ C20kε. (17)

Using equations (16), (17) and the inequality C1 ≤ kϕ0kL∞([0,1]) ≤ C2, which follows from the

definition of Uad, we obtain

|JΦ| ≥ C12− C2ε − |s| C2C20kε≥ C12− C2(ε + s0C20kε), ∀s, |s| ≤ s0.

Finally, choosing ε and s0 so small that

C2(ε + s0C20kε) ≤ 12C12, we obtain |JΦ| ≥ 1 2C 2 1 on [0, 1] × [−s0, s0] .

(ii) We have, for all (t, s) ∈ [0, 1] × [−s0, s0],

|ϕ0(t) + s ψ00(t)⊥| ≤ kϕ0kL([0,1])+ s kψ00kL([0,1])

≤ C2+ s0C20kε,

and

|ψ0(t)⊥| ≤ kψ0kL([0,1])≤ C2.

Hence, if C3C2(1 + s0kεkχ0kL1), we obtain, by Taylor formula,

|Φ(t, s) − Φ(t0, s0)| ≤ C3|(t − t0, s − s0)|,

for all (t, s), (t0, s0) ∈ [0, 1] × [−s

0, s0].

(iii) Let us now show that Φ is injective in [0, 1] × [−s0, s0], for s0 small enough and independent

of ϕ. To this end, we shall show that there exists a constant M such that

|Φ(t, s) − Φ(t0, s0)| ≥ M |(t − t0, s − s0)|, ∀(t, s), (t0, s0) ∈ [0, 1] × [−s0, s0]. Let (t, s), (t0, s0) ∈ [0, 1] × [−s

0, s0]. We have

Φ(t, s) − Φ(t0, s0) = ϕ(t) − ϕ(t0) + s ψ0(t)⊥− s0ψ0(t0)

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Now, we discuss two cases :

First case, if |s − s0| ≤ η |t − t0|, η small enough, we have

|Φ(t, s) − Φ(t0, s0)| ≥ C1|t − t0| − η |t − t0| kψ0kL∞([0,1])− s0kψ00kL([0,1])|t − t0| ≥ (C1− η kψ0kL∞([0,1])− s0kψ00kL([0,1])) |t − t0| ≥ (C1− η C2− s0C20kε) |t − t0| ≥ (C1− η C2− s0C20kε) µ 1 2|t − t 0|2+1 2 1 η2 |s − s 0|2 ¶1 2 .

Assuming that η ≤ 1, we obtain

kΦ(t, s) − Φ(t0, s0)k ≥ 1

2(C1− η C2− s0C

0

2kε) |(t − t0, s − s0)|.

Second case, if |s − s0| ≥ η |t − t0|, we can rewrite the terms ϕ(t) − ϕ(t0) and (s − s0) ψ0(t)⊥ in (18) as ϕ(t0) − ϕ(t) = (t0− t) ϕ0(t) + (t − t0) Z 1 0 ¡ ϕ0(t + τ (t − t0)) − ϕ0(t)¢ and (s − s0) ψ0⊥(t) = (s − s0) (ϕ0(t))⊥+ (s − s0) ¡ψ0(t) − ϕ0(t)¢⊥. We know that kψ0− ϕ0kL([0,1]) ≤ ε

and, from (11), that there exists γε> 0 independent of ϕ such that

|t − t0| ≤ γε implies that |ϕ0(t + τ (t − t0) − ϕ0(t)| ≤ ε, ∀τ ∈ [0, 1]. (19) Hence, |s − s0| ≤ η γε implies that | Z 1 0 ¡ ϕ0(t + τ (t − t0) − ϕ0(t)¢dτ | ≤ ε. (20) Thus, for s0 12η γε , we have

|Φ(t, s) − Φ(t0, s0)| ≥ | − (t − t0) ϕ0(t) + (s − s0) ϕ0(t)⊥| − ε |t − t0| − ε |s − s0| − s0kψ00kL∞([0,1])|t − t0| ³|t − t0|2|ϕ0(t)|2+ |s − s0|2|ϕ0(t)|2´ 1 2 − (2ε + s 0C20kε) |(t − t0, s − s0)| ≥ (C1− 2 ε − s0C20kε)|(t − t0, s − s0)|.

The constants ε, η and s0 can be chosen such that, for example,

η C2+ s0C20kε≤ C1 2 , 2 ε + s0C 0 2kε≤ C1 2 and s0 1 2η γε. Hence, it suffices to take

η = C1 4 C2, ε = C1 8 and s0 = min ½ C1γε 8C2 , C2 8C2kεkχkL1 ¾ .

This shows that there exists s0 independent of ϕ, such that Φ is injective in [0, 1] × [−s0, s0] and

|Φ(t, s) − Φ(t0, s0)| ≥ 2 4 C1|(t − t 0, s − s0)|, ∀(t, s), (t0, s0) ∈ [0, 1] × [−s 0, s0].

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Proof of theorem 1 :

Let us denote by I =]0, 1[ and J =] − s0, s0[ and let us consider u ∈ Hr(B) (1

2 < r ≤ 1). We have

that

u(ϕ(t)) = u◦ ϕ(t), ∀t ∈ [0, 1],

and, on the other hand,

u(ϕ(t)) = u(Φ(t, s))|s=0≡ v(t, s)|s=0, ∀t ∈ [0, 1],

where Φ is the function defined in (12) and v = u ◦ Φ. From the above lemma, we have that Φ is a

C1 diffeomorphism from I × J onto an open set ofR2 which is some tubular neighborhood of Γ,

and thus v ∈ Hr(I × J ). Now,

kuk0,Γ(ϕ)≤ C2ku ◦ ϕk0,I = C2kv(t, s)|s=0k0,I,

and, according to the standard result on the continuity of the trace operator from Hr(I × J ) to L2(I × {0}) (for r > 1

2), there exists a constant β, independent of v, such that kv|s=0k0,I

βkvkr,I×J for all v ∈ Hr(I × J ). Hence,

kuk0,Γ(ϕ)≤ C2β kvkr,I×J.

Next, there exists a constant C4 independent of ϕ, such that

kvkr,I×J ≤ C4kukr,B. Indeed, we have Z Z I×J |u(Φ(t, s))| 2dt ds =Z Z e Ω|u(x, y)| 2|det((Φ−1)0(x, y)| dx dy

whereΩ = Φ(I × J ) and (x, y) = Φ(t, s), and it follows from Lemma 1 thate

Z Z I×J |u(Φ(t, s))| 2dt ds = Z Z e Ω|u(x, y)| 2 dx dy |detΦ0−1(x, y))| 2 C2 1 Z Z e Ω|u(x, y)| 2dx dy 2 C2 1 kuk2 0,eΩ. Thus, ku ◦ Φk20,I×J 2 C2 1 kuk20,e. (21)

On the other hand, setting U = I × J , we have from Lemma 1

Z Z U×U |u ◦ Φ(t, s) − u ◦ Φ(t0, s0)|2 |(t, s) − (t0, s0)|2r+2 dt dt0ds ds0 = Z Z e Ω×e|u(x, y) − u(x0, y0)|2 |Φ−1(x, y) − Φ−1(x0, y0)|2r+2 × |det((Φ−1) 0 (x, y)| |det((Φ−1)0(x0, y0)| dx dx0dy dy0 4 C4 1 Z Z e Ω×e|u(x, y) − u(x0, y0)|2 |Φ−1(x, y) − Φ−1(x0, y0)|2r+2dx dx0dy dy0,

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Since Φ is Lipschitz of constant C3, we have that |Φ−1(x, y) − Φ−1(x0, y0)| ≥ 1 C3|(x − x 0, y − y0)| ∀(x, y), (x0, y0) ∈Ω ×e Ω.e (22) Therefore, Z Z U×U |u ◦ Φ(t, s) − u ◦ Φ(t0, s0)|2 |(t, s) − (t0, s0)|2r+2 dt dt0ds ds0 4 C4 1 C32+2r Z Z e Ω×eΩ |u(x, y) − u(x0, y0)|2 |(x, y) − (x0, y0)|2r+2dx dx0dy dy0. 4 C 2+2r 3 C4 1 kuk2r,B (23)

(21) and (23)imply the theorem when r < 1.

When r = 1, we estimate the partial derivatives of in the same manner (one can also estimate

kukr,B by kuk1,B). This achieves the proof of the theorem.

Now, as a consequence of Theorem 1, we state and prove the following convergence result which essentially says that u|Γn −→ u|Γ. It will also be needed in next section.

Corollary 1 Let (ϕn)n ⊂ Uad be a sequence such that ϕn→ ϕ in the sense of (6), that is for the

C1 convergence, and let u ∈ H1(B). Then

lim

n−→∞u ◦ ϕnu ◦ ϕ in L

2([0, 1]).

Proof :

First, it follows from the density of D(B) in H1(B) (see [?]) that, for a given ε > 0, there exists

υε∈ D(B) such that

kυε− uk1,B ε

3√C1K

,

where K is the constant of Theorem 1. Next, we can write

ku ◦ ϕn− u ◦ ϕk0,[0,1] = ku ◦ ϕn− υε◦ ϕn+ υε◦ ϕn− υε◦ ϕ + υε◦ ϕ − u ◦ ϕk0,[0,1] ≤ ku ◦ ϕn− υε◦ ϕnk0,[0,1]+ kυε◦ ϕn− υε◦ ϕk0,[0,1] +kυε◦ ϕ − u ◦ ϕk0,[0,1]. (24) Now, by Theorem 1, kυε◦ ϕn− u ◦ ϕnk0,[0,1]= µZ 1 0 |υε◦ ϕn(t) − u ◦ ϕn(t)| 2dt ¶1 2 pC1K kυε− uk1,B,

and according to the Lebesgue convergence theorem, we have

lim n−→∞kυε◦ ϕn− υε◦ ϕk0,[0,1] = limn−→∞ µZ 1 0 |υε◦ ϕn(t) − υε◦ ϕ(t)| 2dt ¶1 2 = 0 Thus, kυε◦ ϕn− u ◦ ϕnk0,[0,1]= µZ 1 0 |υε◦ ϕn(t) − u ◦ ϕn(t)| 2dt ¶1 2 pC1K kυε− uk1,B 3ε, (25)

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kυε◦ ϕ − u ◦ ϕk0,[0,1]= µZ 1 0 |υε◦ ϕ(t) − u ◦ ϕ(t)| 2dt ¶1 2 pC1K kυε− uk1,B 3ε, (26)

and there exists N ∈N such that n ≥ N implies

kυε◦ ϕn− υε◦ ϕk0,[0,1] = µZ 1 0 |υε◦ ϕn(t) − υε◦ ϕ(t)| 2dt ¶1 2 ε 3. (27) Hence, for n ≥ N , ku ◦ ϕn− u ◦ ϕk0,[0,1] = µZ 1 0 |u ◦ ϕn(t) − u ◦ ϕ(t)| 2dt ¶1 2 ≤ ε, (28)

which ends the proof of the corollary.

4

Applications

We now apply Theorem 1 to study the continuity of the boundary cost functional

J(Ω, u) =

Z Γ|u|

2

which appears in many problems of optimal shape design, often as a shape optimization formulation of the Dirichlet type condition of a free boundary problem. Of course, Theorem 2 below can also be considered as a continuity result for the trace operator with respect to the couple (u, Γ). Theorem 2 The functional J is continuous on F with the topology induced by the convergence

defined in (9).

Proof :

Let {(Ωn, un)}nbe a sequence of F, such that Ωn= Ω(ϕn), Ω = Ω(ϕ) and (Ωn, un) −→ (Ω, u) as n −→ ∞ .

In what follows, the functions under consideration are of course the extensions u,e uen ∈ H1(B),

but for simplicity we shall drop the “e”. To show that J(Ωn, un) −→ J(Ω, u), let us prove that

p J(Ωn, un) −→ p J(Ω, u). We have: ¯ ¯ ¯ ¯ q J(Ωn, un) − q J(Ω, u) ¯ ¯ ¯ ¯ = ¯¯¯kun◦ ϕn· |ϕ0n| 1 2 k0,[0,1]− ku ◦ ϕ · |ϕ0|12 k0,[0,1] ¯ ¯ ¯ ° ° °un◦ ϕn· |ϕ0n| 1 2 − u ◦ ϕ · |ϕ0| 1 2 ° ° ° 0,[0,1] °°°(un◦ ϕn− u ◦ ϕn) |ϕ0n|12 ° ° ° 0,[0,1]+ ° ° °(u ◦ ϕn− u ◦ ϕ) |ϕ0n|12 ° ° ° 0,[0,1] +°°°u ◦ ϕ³n0 |12 − |ϕ0|12 ´ ° ° ° 0,[0,1] ≤ kun− uk0,Γn+ p C2k(u ◦ ϕn− u ◦ ϕ)k0,[0,1]+ 1 C1 kuk0,Γsup [0,1] ¯ ¯ ¯|ϕ0n|12 − |ϕ0| 1 2 ¯ ¯ ¯ ≤ kun− ukr,B+pC2k(u ◦ ϕn− u ◦ ϕ)k0,[0,1]+ 1 2C1 kuk0,Γsup [0,1] ¯ ¯ϕ0 n− ϕ0 ¯ ¯, (29)

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1

2 < r < 1, by Theorem 1. The theorem follows from Corollary 1 and the compactness of the

injection of H1(B) into Hr(B).

Last, we establish the following more general continuity result. It concerns a general boundary cost functional of the form

J(Ω, u) =

Z

Γf (x, u(x))dσ (30)

where f is a real continuous function defined inR2×R(or R2×Cif u is allowed to take complex values) such that

|f (x, u)| ≤ C³1 + |u|2´ (31) for all x and u, C being a positive constant. Note that it follows from (31) that J is well defined on F.

Theorem 3 Under the above assumptions, J is continuous on F with the topology induced by the

convergence defined in (9).

Proof :

Taking the same sequence (Ωn, un) as in the beginning of the proof of Theorem 2, we can write

J(Ωn, un)I1(n) + I2(n) + J(Ω, u) where I1(n) = Z 1 0 [f (ϕn(t), un(ϕn(t))) − f (ϕ(t), u(ϕ(t)))] |ϕ 0 n(t)| dt, I2(n) = Z 1 0 f (ϕ(t), u(ϕ(t))) ¡ |ϕ0n(t)| − |ϕ0(t)|¢dt. I2(n) is easy to estimate. Indeed, obviously,

|I2(n)| ≤ C Z 1 0 (1 + |u(ϕ(t))| 2)dt sup [0,1] ¯ ¯ϕ0 n− ϕ0 ¯ ¯, so, lim n−→∞I2(n) = 0.

To treat I1(n) , we need the following lemma which improves Corollary 1.

Lemma 2 Let (ϕn) ⊂ Uad be a sequence such that ϕn −→ ϕ ∈ Uad in the sense of (6), and let

u, un∈ H1(B) such that un converges weakly to u in H1(B). Then, un◦ ϕn−→ u ◦ ϕ in L2([0, 1]).

Proof : We have kun◦ ϕn− u ◦ ϕk0,[0,1] ≤ kun◦ ϕn− u ◦ ϕnk0,[0,1]+ ku ◦ ϕn− u ◦ ϕk0,[0,1] 1 C1 kun− uk0,Γn+ k(u ◦ ϕn− u ◦ ϕ)k0,[0,1] √K C1 kun− ukr,B+ k(u ◦ ϕn− u ◦ ϕ)k0,[0,1],

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Γn = Γ(ϕn), 12 < r < 1, by Theorem 1. Thus, the lemma follows from Corollary 1 and the

compactness of the canonical injection of H1(B) into Hr(B).

End of proof of Theorem 3: Since un◦ ϕn −→ u ◦ ϕ in L2([0, 1]), there exists a subsequence

unk◦ ϕnk and v ∈ L2([0, 1]) such that (see[7])

unk◦ ϕnk −→ u ◦ ϕ, a.e. and |unk◦ ϕnk| ≤ v, a.e. (32)

Consider now I1(nk). We have :

• [f (ϕnk(t), unk(ϕnk(t))) − f (ϕ(t), u(ϕ(t))) ] |ϕ0nk(t)| −→ 0, a.e.

• |f (ϕnk(t), unknk(t))) − f (ϕ(t), u(ϕ(t)))| |ϕ0

nk(t)| ≤ C2C(2 + v(t)

2+ |u(ϕ(t))|2), a.e.

So, it follows from the Lebesgue convergence theorem that I1(nk) −→ 0. However, this does not

al-low us to conclude. Therefore, consider limJ(Ωn, un). Since (J(Ωn, un)) is a bounded real sequence,

this limit exists and is equal to lim J(Ωnk, unk) for some subsequence. Now, limJ(Ωn, un) = lim J(Ωnk, unk) = lim J(Ωnkl, unkl)

where (nkl) is such that the subsequence unkl ◦ ϕnkl satisfies (32). Hence, by the argument given

above,

limJ(Ωn, un) = lim J(Ωnkl, unkl) = J(Ω, u).

Of course, the same argument works for limJ(Ωn, un), and this proves the theorem.

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Figure

Figure 1: An example of the considered domain Ω = Ω(ϕ).

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