C OMPOSITIO M ATHEMATICA
I AN S TEWART
Central simplicity and Chevalley algebras
Compositio Mathematica, tome 26, n
o2 (1973), p. 111-118
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111
CENTRAL SIMPLICITY AND CHEVALLEY ALGEBRAS by
Ian Stewart
Noordhoff International Publishing Printed in the Netherlands
1. Introduction
Our
object
is to presentsimplified
and moreconceptual proofs
of sometheorems of
Hurley [3, 4]
on’Chevalley algebras’
over commutativerings,
andsimultaneously
togeneralise
his results. Our methods arederived from Jacobson
[5 ] p. 109, Kaplansky [6]
p. 150 and were usedby
us in
[9].
It turns out that[9]
can be modified to cover the present situa-tion ;
and for reasonsof compatibility
we shall follow the notation of that paper.Hurley
starts from the theoremof Chevalley [2]
that every finite-dimen- sionalsplit semisimple
Liealgebra
L over a field of characteristic zerohas a basis with respect to which the structure constants are
integers -
the so-called
Chevalley
basis. Thus the Z-modulegenerated by
this basishas a natural
ring
structure; we denote thering by Lz. Interpreting
thestructure constants as elements of a commutative
ring-with-1
R weobtain the
Chevalley algebra LR
which is a Liealgebra
over R.Clearly LR g:;
R QLz,
where the tensorproduct
is over Z.Suppose
now that L issimple.
What conditions on R will ensure that every Lie ideal ofLR
arises as J QLz
for an ideal J of R? The main theorem ofHurley [3 ]
states that if 2 and 3 are not zero-divisors in R thena necessary and sufficient condition is that two
integers
should be in-vertible in
R, namely:
the determinant of the Cartan matrixof L,
and the square of the ratio of thelengths
oflong
and short roots in L. Theproof given
in[3]
involves detailed calculationsusing
aChevalley
basis.In another paper
[4] Hurley
shows that a necessary and sufhcient condition forLR
to have acomposition
series of ideals is that R should have acomposition
series of ideals. In these bare terms the result is rather easy to prove, as we shall show. Of course,[4] provides
much detailed information aboutChevalley algebras
which is not obtainable from themore
general viewpoint
of the present paper.2. Notation and
terminology
We shall show that
Hurley’s
results aretypical
of thegeneral
situationof a tensor
product
R(8)B where B is a certainspecial
kind of(non-asso-
112
ciative) ring, having properties closely
allied to centralsimplicity.
Inorder to state our theorems
concisely
we must introduce some terminol-ogy.
From now on the terms
’ring’, ’algebra’,
and ’ideal’ will beinterpreted
in the non-associative sense unless
suitably qualified.
Let B be a
ring,
with additive groupB+.
LetC(B)
denote the(associa- tive) ring of endomorphisms
of B+. Themultiplication ring M(B)
is theassociative
subring
ofC(B) generated by
theright
and leftmultiplications
for all b e B.
We shall
usually
assume that B satisfies thefollowing hypothèses : (H1 )
B+ isa finitely generated free
Z-module.(H2) Q0B is a
centralsimple Q-algebra.
In H2
(and elsewhere)
the tensorproduct
is over Z. TheChevalley algebra Lz certainly
satisfiesHl ;
and it is well-known that it also satisfies H2.(By
directcomputation (exactly
as in section4)
it follows that the multi-plication algebra
ofQ~LZ
is the fullalgebra
ofendomorphisms,
whichobviously implies
centralsimplicity
ofQ~LZ.)
Notice that if Hl
holds,
thenQ~B
is finite-dimensional.We shall also work with a second
ring
R, which willsatisfy (H3) R
is a commutative associativering-with-1.
Given a set 03C0 of
primes
we shall say that R is03C0-regular
if every p ~ 03C0 is invertible considered as an elementof R ;
and R isn-singular
otherwise.If 03C0 =
{p}
we use the termsp-singular, p-regular.
For any
ring
T we letI(T)
denote the set of ideals of T. There is anatural map
defined
by r(J)
= JOB for JEI(R).
We seek conditions under which i is abijection.
3. Relevant Primes In one
direction,
our results will follow from:THEOREM 3.1. Let R and B
satisfy hypotheses Hl, H2,
H3. Then there exists aninteger
À > 0 such thatFor such an
integer À,
every ideal Iof
RQBsatisfies
for a suitable ideal
J of
R.PROOF: We
modify
theproof
of the ’Sandwich Lemma’ of[9].
Let M =
M(B), C = C(B), WèQ
=M(Q~B).
Let{p03B1}
be a set of freegenerators for
B+,
where oc runsthrough
a finite index set A. Such generators existby
Hl.By H2, Q~B
is centralsimple;
soby
Jacobson’sDensity
Theorem we can find elementst03B103B2
eMQ (a, f3
eA)
such thatBy multiplying together
the denominators of the coefficients involved in theexpression
oft03B103B2
in terms of(p03B4)L
and(p03B4)R (03B4
eA)
we can findintegers Àap
> 0 such thatIf we set
then the elements lie in
fl,
andNow let I be any ideal of R~B, and let J be the ideal of R
generated by
the coefficients m of elements
of I. The ma are
uniquely
determined since RQB is a free R-module(by Hl).
The elements of J take the form¿mar
for allpossible a E A,
mEI, rER.
As in the first part of the
proof
of lemma 2.1 of[9]
we candevelop
from the v03B103B2 elements w,,,.8 E
M(R~B)
such that ifa, b E R
thenfor all a,
03B2
E A. It follows that I contains 03BBJ~B.Clearly
I is containedin J(8)B.
We now define the set 03C0 of relevant
primes
for B to be the set ofprime
divisors of the smallest
integer
> 0 for whichfl(B)
contains03BBC(B).
We may then draw the
following:
114
COROLLARY 3.2. Let R, B
satisfy hypotheses HI, H2, H3;
and let n be the setof
relevantprimes for
B. Then n is afinite
set.If
R isn-regular,
thenthe natural map is a
bijection.
PROOF: Since R is
03C0-regular, 03BB
is invertible. But then 03BBJ = J.This
corollary
may be seen as aqualitative
version of half of theorem 3.3 ofHurley [3].
In the next section we discuss how it may be madequantitative;
and in section 5 we consider the other half of his theorem.4. Some
computations
To find the relevant
primes
forChevalley algebras
we must computea suitable
integer À,
but in the most economical fashionpossible. Hurley’s
calculations in
[3],
can beinterpreted
as choices of the elementst03B103B2
re-quired
for theorem3.1,
andyield:
PROPOSITION 4.1
If B = Lz is a Chevalley algebra,
then the relevantprinles
are(a)
Theprime
divisorsof det(C),
where C is the Cartan matrix,(b)
The ratioof
the squaresof
thelengths of long
and short roots,if
thisis not 1.
It is easy to see that the set of relevant
primes
consists at most of2, 3,
and the divisors of det
(C),
and we sketch theproof.
We take
{p03B1}
to be aChevalley
basis for thesimple
Liealgebra
L.In the notation of
Hurley [3] ]
it consists of{hi} U {er}
where i runsthrough
a system of fundamental roots, r runsthrough
a system of roots, and themultiplication
isgiven by
The structure constants
Nrs
andc(r, s)
areintegers
of absolute value~
3,
andNrs =
0 if r + s is not a root. The Cartan matrix of L is thematrix C =
(c(i,j))
where i,j
runthrough
a system of fundamental roots.If r and s are roots there is a sequence of roots r1, ···, rk such that and such that each
(i
~k)
is a root,by [3]
4.1. Sofor a non-zero
integer
K, which is aproduct
of certainHtu.
Let p be the
highest
root, and let r be any root. As above we can find r1, ···, rk such thatSince
adding
a root ri preserves theordering
of the roots, we know that for all roots s > r we haveTherefore the element
sends er
toK’h p ,
where K’ is aproduct
of structure constants, and kills all the other basis vectors.Now the elements ese-s map
each et
to a scalarmultiple,
and mapht
to
c(t, s)hs .
Hence someinteger
linear combination of these mapsh.
todet(C)hi
for any chosen i.Finally, hi
may bemapped by es
toc(s, i)es . By composing
the above maps we can find an element offl(Lz) mapping
e,. to an
integer multiple
of anygiven
basis vector andannihilating
allother basis vectors. The
integer
concerned will be aproduct
ofdet(C)
and certain structure constants.
In a similar manner we can find an element
of fl(Lz)
with theanalogous
effect on
hi.
So we can find aninteger
of the form2’3 bdet(C),
and somay take x to be a subset of
{2, 3} ~ {divisors
ofdet(C)}.
To get
exactly Hurley’s
results involvestraversing
the root system ina more careful manner; and this is
essentially
what is done in[3]:
forexample
see section 4.2 of that paper.5. Bad Primes
Assume that B satisfies
hypotheses Hl,
H2. Aprime p
is a badprime
for B ifZpQB
is not asimple Zp-algebra.
It followsimmediately
that if p is a badprime
and t is any field of characteristic p, thenis not
simple;
so the natural map i :I(f)
~I(~B)
cannot be asurjec-
tion.
The next
result, though quite simple,
is decisive for our purposes.THEOREM 5.1. Let
B,R satisfy hypotheses Hl, H2,
H3.Suppose
that p is a badprime for B,
and R isp-singular.
Then the natural mapis not
surjective.
116
PROOF: Since R is
p-singular, pR
is a proper ideal of R. N’ow R has anidentity,
so wemay find
a maximal ideal K of R such that K containspR.
Then
R/K
is a field f of characteristic p. Thequotient
(R~B)/(K~B)
is
isomorphic
to~B.
Since p isbad,
thisquotient ring
is notsimple;
therefore there is an ideal I of RQB such that
KOB $ I $
ROB. SinceK is
maximal,
i cannot besurjective.
This result shows that every bad
prime
is relevant. If the converse alsoholds,
we have a characterisation theorem:THEOREM 5.2. Let B,R
satisfy hypotheses H1, H2,
H3.Suppose
thatevery
relevant prime for
B is bad. Then the natural map ’1:I(R) ~ I(RQB)
is a
bijection if
andonly if
R is03C0-regular,
where n is the setof
relevantprimes.
Steinberg [8] ] (p.1120)
discusses thesimplicity,
orotherwise,
of thealgebras ~LZ
where f is a field ofcharacteristic p
> 0. From his re-marks on page
1121, together
with the knownnon-simplicity
of the Liealgebra of type Ar
over a field of characteristic pdividing
l +1,
it follows that when B =Lz
the badprimes
areprecisely
the relevantprimes
described in
proposition
4. l. Thus 5.2applies
and we recover theorem 3.3of
Hurley [3 ] in
itsentirety.
If B is an n x n matrix
ring
over Z then there are no relevant or badprimes,
and we recover the well-known result that underhypothesis
H3the ideals of the matrix
ring
over R are inbijective correspondence
withthe ideals of R under the natural map.
(See
e.g.McCoy [7],
p.37).
The
question
of whether ingeneral
the relevantprimes
are bad is stillopen.
6.
Composition
SeriesIn
[4] ] Hurley
considerscomposition
series of ideals inChevalley algebras,
and proves thatLR
has such acomposition
series if andonly
ifR has a
composition
series of ideals. It should be remarked that ’ideal’here must be
interpreted
as’R-algebra ideal’,
thatis, ’ring
ideal andR-submodule’. For if we take L to be
of type An
and R a field of character- isticp|n+1,
then theChevalley algebra R~LZ
is thealgebra
of(n+1)(n+1)
matrices of trace 0 over R; and any additivesubgroup
ofthe centre, which consists of the scalar
matrices,
is aring
ideal. Now R,being
afield,
has acomposition
series ofideals;
but we caneasily
chooseR so that R+ has neither maximal nor minimal condition on
subgroups,
and hence
RQLZ
has nocomposition
series ofring
ideals.It is therefore necessary to consider
only R-algebra
ideals. Now if Rdoes not have a
composition
series then ROBcertainly
does not have acomposition
series(see Hurley [4]
p.430).
But it is well-known that if R is a commutative associative Artinian(Noetherian) ring
then anyfinitely-generated
R-module is Artinian(Noetherian);
see forexample Atiyah
and MacDonald[1],
or Zariski and Samuel[10] p.
158. From thiswe
immediately
have :PROPOSITION 6.1 Let B, R
satisfy hypotheses H1, H2,
H3. Then ROB has acomposition
seriesof R-algebra
idealsif and only if
R has aconiposi-
tion series
of
ideals.Note that theorems 3.1 and 5.2 refer to
ring
ideals.7.
Extending
the ResultsThe bad
primes
for asimple
Liealgebra
of typeAn
are theprime
divisors of n + 1. If B is the
corresponding Chevalley algebra
overZ,
and f is a field ofcharacteristic p dividing
n + 1, then~B
has non- trivial centre, so is notsimple. However,
the centralquotient,
say K,is
simple,
indeed centralsimple.
In contrast tothis,
the badprimes
forthe other classical Lie
algebras
have a much more drastic effect on thestructure of the tensor
product.
For any commutative associative
ring-with-1
R, wehave pR~K
= 0.It is therefore reasonable to confine our attention to
rings R
such thatpR
=0,
which are thereforealgebras
overZp. By Kaplansky [6] p.
150it follows that the natural map r :
I(R) ~ I(R~K)
is abijection, although p
iscertainly
not invertible in R! Thusby passing
to the centralquotient
we may recovergood
behaviour of the ideals in the case ofAn .
We may also consider what
happens
if R does not have anidentity.
We can still define R(DB; and
by
the methods of[9]
it follows that with 03BB as before every ideal of ROB lies between JOB and03BBJn~B
for an ideal J of R and aninteger
> 0.Using
this and the induction argument of[9] theorem
4.1 we may show that every subideal(with
the obviousdefinition)
of ROB lies between JO B and03BBrJn~B
for suitable r, n > 0 and an ideal J of R.Returning
to the case where R has anidentity,
andassuming
03BB invertible in R, then every subideal of ROB lies between JOB andJn~B.
It is nowpossible
to carry over most of the results of[9]
sections 4 and5;
inparticular
togive examples
of Lierings
in whichthe join
of anypair
of subideals is asubideal,
or whichsatisfy
the maxi-mal condition on subideals.
118
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J. F. HURLEY
[3] Ideals in Chevalley algebras, Trans. Amer. Math. Soc. 137 (1969) 245-258.
J. F. HURLEY
[4] Composition series in Chevalley algebras, Pac. J. Math. 32 (1970) 429-434.
N. JACOBSON
[5] Structure of rings, Amer. Math. Soc. Colloquium Publications XXXVII.
Providence R. I. 1964.
I. KAPLANSKY
[6] Fields and Rings, Chicago 1969.
N. H. MCCOY
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[8 ] Automorphisms of classical Lie algebras, Pac. J. Math. 11 (1961) 1119-1129.
I. N. STEWART
[9] Tensorial extensions of central simple algebras, J. Algebra (to appear).
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(Oblatum 22-111-1972) Mathematics Institute
University of Warwick Coventry, England