C OMPOSITIO M ATHEMATICA
H ELMA G LADDINES
J AN V AN M ILL
Hyperspaces of infinite-dimensional compacta
Compositio Mathematica, tome 88, n
o2 (1993), p. 143-153
<http://www.numdam.org/item?id=CM_1993__88_2_143_0>
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
Hyperspaces of infinite-dimensional compacta
HELMA GLADDINES and JAN van MILL
Faculteit Wiskunde en Informatica, Vrije Universiteit, De Boelelaan 1081a, 1081 HV Amsterdam, The Netherlands
Received 18 July 1991; accepted 20 July 1992
Abstract. If X is an infinite product of non-degenerate Peano continua then the set dim~(X) =
{A~2x:dim A
=~)
is an F,,,-absorber in 2’. As a consequence, there is ahomeomorphism f: 2x --. 6°° such that f[dim~(X)] = B’, where B denotes the pseudo-boundary of
the Hilbert cube Q. There is a locally infinite-dimensional Peano continuum X such that for every n,
dim~(Xn) is not homeomorphic to BOO.
Keywords: Hilbert cube, absorbing system, F,,, hyperspace, Peano continuum, cohomological
dimension.
AMS Subject Classification: 57N20.
1. Introduction
If X is a
compact
metric space then2x
denotes thehyperspace
of allnonempty
closed subsets of Xtopologized by
the Hausdorff metric. Fork~{0, 1,..., ~}
letdimk(X)
denote thesubspace consisting
of all k-dimensional elements of2X.
We define
dimk(X)
anddimk(X)
in the same way.Let
Q
denote the Hilbert cube. InDijkstra
et al.[9]
it isproved
that thereexists a
homeomorphism f:2Q ~ Q~
such that forevery k 0,
where B is the
pseudo-boundary
ofQ.
As a consequence,The
proof
of(1)
is based in an essential way on the "convex" structure ofQ
aswell as on the
technique
ofabsorbing systems.
Since for every
non-degenerate
Peano continuum X we have2x z Q (Curtis
and Schori
[7];
see also[13, Chapter 8]),
it is natural to ask for which Peano continua X there is ahomeomorphism
ofpairs (2X,dim~(X)) ~ (Qoo, B°°).
Sincedim~(X)~~
iff dim X = oo, thisquestion
is of interestonly
when X isinfinite-dimensional.
In this paper we will prove that if X is an infinite
product
ofnon-degenerate
Peano continua then there is a
homeomorphism
ofpairs
This
generalizes (2)
above. We do not know whether(1)
can also begeneralized.
We come back to this in
§4,
where we willexplain why
ourproof
does not workfor
obtaining
ageneralization
of(1).
The
proof
of our result is different from theproof
of(1)
inDijkstra
et al.[9]
because a "convex" structure is not available on an
aribtrary
infiniteproduct
ofPeano continua.
We also
present
anexample
of aneverywhere
infinite-dimensional Peano continuum X such that for every n EN, dim~(Xn)
Boo. So our result is in a sense "bestpossible".
2.
Terminology
All spaces under discussion are
separable
and metrizable. For any space X we let d denote an admissible metric onX, i.e.,
a metric thatgenerates
thetopology.
Allour metrics are bounded
by
1.As usual 7 denotes the interval
[0, 1 ]
andQ
the Hilbert cube03A0~i=1[-1, 1]i
with metricd(x, y)
=03A3~i= 12-(i+1)|xi
-yi 1.
In addition s is thepseudo-interior
ofQ, i.e., {x
EQ: (Vi
EN)(|xi| 1)}.
Thecomplement
B of s inQ
is called thepseudo- boundary
ofQ. Any
space that ishomeomorphic
toQ
is called a Hilbert cube. If X is a set then theidentity
function on X will be denotedby 1X.
Let A be a closed subset of a space X. We say that A is a Z-set
provided
thatevery map
f:Q -
X can beapproximated arbitrarily closely by
a mapg: Q -+ XBA.
The collection of all Z-sets in X will be denotedby (X).
Acountable union of Z-sets is called a 03C3Z-set. A
Z-embedding
is anembedding
therange of which is a Z-set.
Let .A be a class of spaces that is
topological
and closedhereditary.
2.1. DEFINITION. Let X be a Hilbert cube. A subset A z X is called
strongly
M-universal in X if for every M E with M ~
Q
and everycompact
set K ~Q,
every
Z-embedding f:Q -
X can beapproximated arbitrarily closely by
a
Z-embedding g: Q -+ X
such thatg 1 K = fi K
while moreoverg-1[A]BK = M B K.
2.2. DEFINITION. Let X be a Hilbert cube. A subset A - X is called an .A- absorber in X if
(1) A ~ ;
(2)
there is a 6Z-set S ~ X with A -S;
(3) A is strongly
M-universal in X.2.3. THEOREM
([9]).
Let X be a Hilbert cube and let A and B be -/Y-absorbersfor
X. Then there is ahomeomorphism
h: X ~ X withh[A]
= B.Moreover,
h canbe chosen
arbitrarily
close to theidentity.
There are three absorbers that are
important
for us in thepresent
paper. The first one is an absorber for the classconsisting
of all finite-dimensionalcompacta.
Such absorbers were first constructedby
Anderson andBessaga
andPetczynski [2]
and werecalled fd-capsets by
Anderson. A basicexample
of anfd-capset
inQ
isFor
details,
see[2].
The second one is an absorber for the class of allcompacta.
Again,
such absorbers were first constructedby
Anderson andBessaga
andPelczynski: they
were called capsetsby
Anderson. A basicexample
of acapset
inQ
is B. Fordetails,
see[2]
and[ 13, Chapter 6].
The third one is an absorber for the Borel classF03C303B4.
Such absorbers were first constructed in Bestvina andMogilski [3];
see alsoDijkstra
et al.[9].
A basicexample
of anF03C303B4-absorber
isB~ in the Hilbert cube
Q~.
The space B~ has been studiedintensitively
ininfinite-dimensional
topology during
the last years. For moreinformation,
seee.g.
[3, 4, 10, 9, 8, 1].
2.4. DEFINITION. A subset A of a space X is
locally homotopy negligible
in Xif for every map
f:
M -X,
where M is anyANR,
and for every open cover U of X there exists ahomotopy
H: M x I ~ X such that{H({x} I)}x~M
refinesu, Ho = f
andH[M
x(0, 1]] ~ XBA.
By
a result ofTorunczyk [14],
if X is anANR,
for a set A g X to belocally homotopy negligible
it suffices to considermaps f :
M ~X,
whereM~{{pt}, I, 12, ... , ln, ... }.
If A is an M-absorber in X and if AI contains the class of all finite- dimensional
compacta
then both A andXBA
arelocally homotopy negligible
inX
(Baars
et al.[1, Corollary 4.4]).
So it follows inparticular
that if E is one of theabsorbers for
Q
mentionedabove,
then there is ahomotopy
H :Q
x I- Q
suchthat
Ho
=1Q
andH[Q
x(0, 1]] ~
E. This can be seen alsoby noting
that on theone hand for the three basic
examples
of absorbers suchhomotopies
exist andthat on the other hand every absorber is
"equivalent"
to its own model(Theorem 2.3).
Let X be a
non-degenerate
Peano continuum. Thesubspace
of2x consisting
of all subsets of X
of cardinality
at most n is denotedby Fn(X) and F(X)
denotesUn
1Fn(X).
We will make use of the
following
basic result.2.5. THEOREM
(Curtis [5]).
Let X be anon-degenerate
Peano continuum.Then F(X)
containsan fd-capset for 2x.
The
following corollary
to this result isprobably
well-known.2.6. COROLLARY. Let X be a
non-degenerate
Peano continuum.If F(X) ~
Y 92x
then Y is an AR.Proof
This followsimmediately
from Theorem 2.5 andTorunczyk [14].
DLet X be a
compact
space. It is easy to see that forevery k
the setdimk(X)
isan
F6-subset of 2X (Dijkstra
et al.[9,
theproof of Theorem 4.6]). Consequently, dim~(X)
is anF aô-subset
of2X.
We will also need the
following
result.2.7. THEOREM
(Curtis
and Michael[6]).
Let X be anon-degenerate
Peanocontinuum. Then
dim 1(X)
is a capsetfor 2x.
If A is a
non-empty
closed subset of X then the inclusion A 4 X induces a naturalembedding 2A ~ 2X.
We willalways identify 2A
and the range{B~2X:B ~ AI
of thisembedding.
Let X be a
compact
space with admissible metric d. Then the formuladH(A, B)
=min(03B5
0:(VxEA)(d(x, B) E)
and(dx E B)(d(x, A) E)j
defines an admissible metric on
2X.
It is called theHausdorff
metric on2X.
3. The space of infinite-dimensional
subcompacta
In this section we will
present
aproof
of our main result that for an infiniteproduct
ofnon-degenerate
Peano continuaX,
the spacedim~(X)
is anF aÔ-
absorber for
2x.
3.1. LEMMA. Let X be a
non-degenerate
Peano continuum.Then for
every c ~ X there are a continuousinjective
map p : 1 -+[0, 2],
and amap 0:
X x21
~2x
suchthat:
(1) p(0) = 0, (2) 03C1(t)
tfor
all t,(3) ~| {c}
xF1(I)
-F1(X)
is anembedding
the rangeof which
is a proper subsetOf F1(X),
(4) If A~2I
then0(c, A)
=U{~(c, {a}):
a EA}, i.e., ~| {c}
x21
is thehyper-
space
embedding
inducedby
theembedding 0 |{c}
xF1(I)
~F1(X),
(5) o(x, {0}) = {x}, for
all xE X,
(6)
dim0(x, A)
1for
all A E2’
and xE X,
(7) dH({x}, 0(x, A)) p(max(A)) for all A~2I
and xeX.Proof.
Pick anarbitrary
c~X. There is anembedding ~:I ~ X
such that~(0)
= c([13,
Theorem5.3.13]).
We may assume without loss ofgenerality
that~[I] ~
X. Let A be thesubspace
of X x
21
and definet/1:
A ~F(X) 2~[I]
as follows:Note that A is closed in X x
21.
SinceF(X) 2lI’l
is an AR(Corollary 2.6)
wecan
extend t/1
over X x2’
to amap 0:
X x2’ ~ F(X)
u2~[I].
It is clearthat 0
satisfies
(3) through (6)
above.Define u: I - 7
by
Note that a is
increasing
and thata(t)
= 0 iff t = 0. Define pby o(t) = a(t)
+ t(t e l).
Then 0
and p are as desired. D3.2. LEMMA. Let X be a
non-degenerate
Peano continuum.Then for
every c ~ X there is ahomotopy
r: X x I ~5(X)
such thatfor
every xE X,
(1) r(x, 0)
={x}, (2) r(x, 1)
={c}.
Proof.
Pick anarbitrary
c ~ X.By Corollary
2.6 it follows that5(X)
is an AR.So F(X)
can be contracted to thepoint {c},
sayby
thehomotopy
H. It is clear that the functionr(x, t)
=H({x}, t) (t
EI)
is as desired. 1:1On a
product
space X =Il ’
1X n
we willalways
use the admissible metric d on Xgiven by
where dn
is anarbitrary
admissible metric onXn.
Note that if twopoints
agreeon their first n
coordinates,
then their distance is2-n.
We also let for every m, 03C0m be theprojection
from X ontoXm.
The
following
result is one of the main tools in ourproof.
3.3. LEMMA. Let X =
1-I’, Xn,
where eachXn
is anon-degenerate
Peanocontinuum.
Then for
every c =(Cl,
c2,... )
E X there ishomotopy
r’: X x I ~F(X)
such
that for
all x E X and tEl:(1) r(x, 0) = {x},
(2) If
t E[2-n, 2-(n-l)J then for
all m a n +1, nm[r(x, t)]
={cm}, (3) If
t E[2-n, 2-(n-1)]
thenfor
all m n -1,
03C0m[r(x, t)]
={xm}, (4) dH({x}, 0393(x, t))
2t.Proof.
Pick anarbitrary
element c =(c1,
C2,... )
E X. Define for n E N a map03B3n:[2-n,2-(n-1)]
~ I such thatYn(2-n)
= 0 and03B3n(2-(n-1))
= 1.For every n let rn:
X n
x 1~ F(Xn)
be as in Lemma 3.2 for thepoint
Cn~ Xn.
Now define a
homotopy
r: XI ~ F(X)
as follows:Claim 1. r is well-defined and continuous on X x
(0,1].
Note that thepoints
inwhich r is not
trivially
well-defined are of the form(x, 2-"), (x E X,
n EN).
Sopick arbitrary
x E X and n E N. Then on the onehand,
Note that
rn(xn, 03B3n(2-n))
=rn(xn, 0) = {xn},
thusOn the other
hand,
Note that
rn+1{xn+1, y,+i(2 "))
=rn+1(xn+1, 1)
-{cn+1},
thusWe conclude that 0393 is well-defined and continuous on X x
(0,1].
Claim 2. For every x ~ X and
tel, dH({x}, 0393(x, t))
2t.-n, 2 -(n-1)].
If t = 0 this is clear. If t >
0,
find n~N such thatt ~ [2-n, 2-(n-1)].
ThendH({x}, 0393(x, t)) 03A3~i=n2-i
=2-(n-1)
2t.Thus r is also continuous on X x
{0}.
Since wealready
know from Claim 1 that r is continuous on X x(0, 1],
we conclude that r is continuous. DWe now corne to the main result in this section.
3.4. THEOREM. For
every n let Xn be a non-degenerate
Peano continuum and let X =n:= 1 Xn.
Thendim~(X) is strongly F03C303B4-universal in 2X .
Proof.
Let A ~Q
be anF03C303B4,
let K ~Q
becompact,
let 0 03B5 1 and letf : Q ~ 2x
be aZ-embedding.
For every n, letAn ~ Q
be6-compact
such that~n= 1 An
= A. We may assume without loss ofgenerality
thatif n
m thenAn 2 Am .
For every n~N there are a
cn~Xn,
ahomotopy ~n:Xn 2I~2xn
and aninjective
continuous map 03C1n: 1 ~[0,2] satisfying
the conditions(1) through (7)
of Lemma 3.1.
Define 03B4 : Q ~
1 and for every n EN, bn: Q ~
1by
Observe
that b"
is well-defined because of theproperties
of the map pn .By (2)
inLemma 3.1 we have for every n and
x E Q,
By
Theorem 2.5 there is ahomotopy
H:2’
x I -2’
such that:(1) Ho
is theidentity, (2) d(Ht, 1) 2t,
(3) H[2x
x(0, 1]] ~ F(2X).
Define g :
Q ~ 2x by
Observe that
(4)
for every x ~Q, dH(f(x), g(x)) 203B4(x) (so
inparticular, g | K
=fi K), (5) g[QBK] ~ F(X).
By
Theorem 2.7 there is for every n anembedding jn:Q~2I
such thatjn 1 [dim1(I)]
=An .
For every n E N and x E X letObserve that
Sn(x) ~
I iscompact
andnon-empty
anddepends continuously
onx. Let r : X x I
~ F(X)
be as in Lemma 3.3 for thepoint (c1, c2, ... ) E X .
Nowdefine a function h :
Q - 2’ by
the formula:Note that this map is well-defined because for every x ~
Q
and n ~ N we haveSn(x) ~
I.Also,
h isclearly
continuous. We claim that h is theapproximation of f
that we are
looking
for.Claim 1. For every x ~
Q, dH( f (x), h(x)) 5ô(x)
e. Take anarbitrary
x ~Q
andput
G =~{0393(y, 03B4(x)):y~g(x)}. By (4), dH(f(x), g(x)) 2ô(x).
Inaddition, by
Lemma
3.3(4)
it follows thatdH(g(x), G) 2ô(x).
We conclude thatdH(f(x), G) 4b(x).
Now take anarbitrary
element(yl,
y2,... ) E
G. Observe thatby (7)
and
by
the fact that Pn isincreasing,
dH({yn}, ~n(yn, Sn(x)) 03C1n(max(Sn(x)) 03C1n(03B4n(x)) = Ô(X)-
This
clearly implies
thatdH(G, h(x)) b(x).
We conclude thatdH( f (x), h(x)) 5ô(x)
e, which is asrequired.
Claim 2.
h K
=f | K
Note that for all k~K and
n~N, 03B4(k)
= 0 =03B4n(k).
Thisimplies
thatClaim 3. h is an
embedding.
First observe that
h[K]
nh[QBK]
= 0. This followseasily
from the factthat f
is an
embedding
and from Claims 1 and 2 because for everyx~Q
we havedH(f(x), h(x)) 503B4(x) 5 6dH(f(x), f[K])
=5 6dH(f(x), h[K]).
Sinceby
Claim2, h | K
=fi | K andf
K is anembedding,
it followsthat h )
K is anembedding.
Theonly thing
left to prove is therefore thatif x, y E QBK
andh(x)
=h(y),
then x = y.To this
end, pick
such x and y andput
r =03B4(x)
and t =03B4(y).
Observe thatby
theabove,
r, s > 0. Thereconsequently
exists m such that2-(m-1) min{r, t}.
Then
03C0m[~{0393(z, r): z~g(x)}] =
Cm =03C0m[~{0393(z, t) : z~g(y)}]. Also, 03C0m[h(x)] =
~m(cm, Sm(x))
and03C0m[h(y)]
=~m(cm, Sm(Y)).
Since~m | {cm}
x2I
is anembedding,
it follows that
Sm(x)
=Sm(y).
Sincemin(Sm(x))
=03B4m(x)/4
andmin(Sm(y)) = c5m( y)/4
we obtain thatc5m(x) = c5m( y).
Observe thatc5m(x) = c5m(y)
> 0 so thatand
Therefore, jm(x)=jm(y)
becauseSm(x)=Sm(y)
and03B4m(x)=03B4m(y).
So x = ybecause jm
is anembedding.
Claim 4.
h[Q]~L(2X).
For every n~N let
Jn = ~{~n(cn, {t}):t~I}.
Observe that for every n,Jn ~ Xn.
For N~N defineÍ4N
={B~2X:(n N)(nn[B] £ Jn)}.
ThenÍ4N
isclearly
closed and we claim that it is a Z-set in2X. Indeed,
for a verylarge
indexi > N
let f :
X ~ X be the function that is theproduct
of theidentity
functions onall factors of
X, except
for the i-thfactor,
and a constant functionXi ~ X i the
range of which misses
Ji .
Then the inducedhyperspace
function2/: 2x -+ 2x ([13,
§5.3])
is close to theidentity
and its range missesPiN.
Now note that for x ~
QBK
there is an N ~N such that forall n N, 03C0n[h(x)] ~ Jn.
So sinceh[K]
is a Z-set in2X,
we conclude thath[Q]
is contained in aaZ-set,
and is therefore a Z-set itself.Claim 5.
h-1[dim~(X)]BK
=~~k=1AkBK.
Note that for
x~QBK
there is anNx~N
such that for everyn Nx, 03C0n[h(x)] = ~n(cn, Sn(x)). If x ft ~~k=
1Ak u K,
there is a KNx
such that for allk K, dim jk(x)
= 0. Soby (4)
and(6)
it follows thath(x)
is a finite union ofproducts
of K at most one-dimensional spaces andinfinitely
many zero- dimensional spaces. This means thath(x)
is at mostK-dimensional,
and hencenot infinite-dimensional. If x ~
nk
1AkBK
then for all i we havethatji(x)
is one-dimensional,
thus there are y1,...,yNx-1 such thath(x)
contains the infinite dimensional set(y1,
...,yNx-1)
x03A0~i=Nx ~i(ci, Si (x)).
This
completes
theproof
of the Theorem. D3.5. COROLLARY. For every n let
Xn
be anon-degenerate
Peano continuum and let X =03A0~n=1 X n .
Thendim~(X) is an F03C303B4-absorber in 2X.
Proof.
In thelight
of Theorem3.4,
it suffices to prove thatdim~(X)
is anF03C303B4
and is contained in a 6Z-set. But this follows
immediately
from the remarkfollowing Corollary
2.6 and Theorem 2.7. D3.6. COROLLARY. For every n let
Xn
be anon-degenerate
Peano continuum and letX = 03A0~n=1Xn.
Then there is ahomeomorphism f:2X ~ Qoo
such thatf[dim~(X)]
= B"0.Proof.
Since as was observed in§2
that B~ is anF03C303B4-absorber
inQoo,
thisfollows from
Corollary
3.5 and Theorem 2.3. D4. The
Example
In this section we will
present
anexample
of aneverywhere
infinite-dimensional Peano continuum X such that for every n,dim~(Xn)
BOO.By
Dranisnikov[11],
there exists an infinite-dimensionalcompactum
withcohomological
dimensionequal
to 3. There even exists an infinite-dimensionalcompactum
withcohomological
dimensionequal
to 2(Dydak
and Walsh[12]).
Let D be any infinite-dimensional
compactum
with finitecohomological dimension,
say n. We will use D as abuilding
block for the construction of ourexample.
By
Edwards and Walsh[ 15],
there is a cell-likemap f: Y~D,
for somecompact
space Y with dim Y n. There also is a nullséquence
=(Yi)~i=1
ofcopies
of Y inI2n + 1 such
that(1) if 1 ~ j then Yi ~ Yi = ~;
(2) ~~i=1 Yi is
dense inI2n+1.
([13,
Theorem4.4.4]).
We nowreplace every Y
inI2n+ 1 by
a copyDi
of Dby using
maps of theform f ° 03BEi,
where03BEi: x -
Y is anyhomeomorphism.
Theresulting quotient space X
iscompact
and metrizable because y is null.Observe that X is an
everywhere
infinite-dimensional Peano continuum: X isa continuous
image
of12n
+ 1 and everynon-empty
open subset of X contains ahomeomorph
of the infinite-dimensional space D.Also,
thecohomological
dimension of X is finite because X is a cell-like
image
ofIln + 1.
If m~N then thecohomological
dimension of X m is alsofinite,
forexample
because X m is a cell-like
image
ofIm(2n 11).
So in order to prove that X is asrequired,
it suffices toverify
thefollowing:
4.1. PROPOSITION. Let X be a compactum with
finite cohomological
dimen-sion. Then
dim~(X) is
a-compact, and hence nothomeomorphic
to BOO.Proof.
This is easy. Let n be thecohomological
dimension of X. Sincecohomological
dimension andcovering
dimension agree on finite dimensionalcompact
spaces, it follows that if A ~ X is closed then eitherdim A n
or dim A = 00.Consequently, dim~(X)
=dimn+1(X),
which is known to be a-compact ;
see the remarksfollowing Corollary
2.6. That B~ is not03C3-compact
isleft as an exercise to the reader. D
It is also
possible
to construct anexample
of aneverywhere
infinite-dimensional Peano continuum Y such that for no n,
dim,,,( yn)
ishomeomorphic
to
B~,
whileyet
for every n,dim~(Yn)
is a "true"F,,. Simply
take the space Xconstructed here and let Y be the space obtained from X and
Q by glueing
them
together
in onepoint.
4.2. REMARK. In the introduction we
promised
toexplain
herewhy
ourmethod does not work for
obtaining
ageneralization
of(1) in §1.
For ageneralization
of(1),
theapproximation
h in theproof
of Theorem 3.4 shouldsatisfy
thefollowing:
(k~N)(h-1[dimk(X)]BK = AkBK).
It is
impossible
however for anarbitrary
x ~QBK
to calculate the dimension ofh(x).
All we know abouth(x)
is that it is a finite unionof products
of at most one-dimensional spaces. It seems that a much more delicate
argument
than ours is needed to control the dimension ofh(x).
Added in
proof:
It wasrecently
shownby
Gladdines that for aspace X
such asin Theorem 3.4 the sequence
(dimK(X))K
isabsorbing.
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