c 2008 by Institut Mittag-Leffler. All rights reserved
Power weighted L p -inequalities for Laguerre–Riesz transforms
Eleonor Harboure, Carlos Segovia†, Jos´e L. Torrea and Beatriz Viviani
Abstract.In this paper we give a complete description of the power weighted inequalities, of strong, weak and restricted weak type for the pair of Riesz transforms associated with the Laguerre function system{Lαk}, for any givenα>−1. We achieve these results by a careful estimate of the kernels: near the diagonal we show that they are local Calder´on–Zygmund operators while in the complement they are majorized by Hardy type operators and the maximal heat-diffusion operator.
We also show that in all the cases our results are sharp.
1. Introduction
The purpose of this article is to study boundedness properties in Lp((0,∞), xδdx) for the Riesz transforms associated with the orthogonal systems of Laguerre functionsLαk,α>−1, started in [4], see also [17]. There, following the ideas developed in [12], the appropriate Riesz transforms are introduced and, using a transference method from Hermite systems along with Kanjin’s transplantation theorem for Laguerre expansions, continuity results in Lp((0,∞), xδdx) were ob- tained for δranging in a certain interval depending on pandα. Recently (see [6]
and [3]), sharper results of this kind have been given for the maximal heat operator related to such expansions. There, the authors not only obtain strong type inequal- ities but they analyse the behaviour at the extreme points, proving weak type or restricted weak type inequalities that, as they show, are sharp.
†During the revision process of this article, Carlos Segovia unexpectedly died. The other authors are deeply touched by the loss of such an outstanding colleague and friend. We are also indebted for all we have learnt and enjoyed working in his company. Undoubtedly, his clearness of thinking and his ability for computations are vividly present throughout this manuscript.
Partially supported by Ministerio de Educaci´on y Ciencia (Spain), MTM2005–08350-C03- 01, Proyecto IALE (UAM-Banco Santander Central-Hispano), and grants from CONICET and Universidad Nacional del Litoral (Argentina).
The fourth author was also supported by grant SAB2003-0024 from MEC (Spain).
Our aim in this paper is to perform an analogous analysis for the case of the Riesz operators. Our approach this time is through a careful study of their kernels. We make use of a technique, that nowadays might be called classical, of splitting the kernel into its “global” and “local” parts (see (3.1) and (3.2) for their precise definitions). The local parts of the Riesz transforms are shown to be local Calder´on–Zygmund operators in the sense defined in [10] (see Theorem 3), which gives no restriction on the exponent δ. On the other hand, the global parts are estimated by a sum of positive operators, namely a variation of the maximal heat operator and some Hardy type operators. We combine both estimates to give our main result stated as Theorem 1.
We remark at this point that our boundedness results for the Riesz transforms are a little worse than those for the maximal heat operator. Not only do we not get boundedness onL∞, as expected, but we also get a weaker result at one of the end points, when the range ofpis a finite interval. Nevertheless it turns to be sharp.
As we just mentioned, the main key to achieve our results is a careful analysis of the kernels. Since they involve modified Bessel functions and their derivatives, part of the proof becomes highly technical. However, such precise knowledge of the behaviour of the kernels allows us to get really sharp inequalities. In fact, in Section 6, we show that our boundedness results on Lp
(0,∞), xδdx
cannot be improved any further (see Theorem 2).
Let us remark that this technique of splitting the kernel according to the local and global regions, goes back to Muckenhoupt and Stein (see [7] and [9]) in con- nection with problems concerning Poisson summation and conjugacy for different systems of orthogonal polynomials, like those of Jacobi, Hermite or Laguerre.
Later, even though it is not pointed out explicitly, K. Stempak in [13] did also make use of such technique in order to bound the heat and Poisson maximal oper- ators for various systems of Laguerre expansions. Finally, very recently, A. Nowak and K. Stempak in [11], have obtained boundedness results for Riesz transforms associated to other Laguerre orthonormal functions, using again this type of par- tition of the kernel. We include, as a final section, a brief discussion on how their results are related to ours.
Given a real numberα>−1, we consider the Laguerre second order differential operatorLαdefined by
Lα=−y d2 dy2− d
dy+y 4+α2
4y, y >0.
It is well known thatLαis non-negative and selfadjoint with respect to the Lebesgue measure on (0,∞), furthermore its eigenfunctions are the Laguerre functions Lαk
defined by
Lαk(y) =
Γ(k+1)
Γ(k+α+1) 1/2
e−y/2yα/2Lαk(y),
whereLαk are the Laguerre polynomials of typeαsee [15, p. 100] and [16, p. 7]. The orthogonality of Laguerre polynomials with respect to the measuree−yyαleads to the orthonormality of the family{Lαk}∞k=0in L2((0,∞), dy).
Given the second order non negative and selfadjoint differential operatorLα and its heat semigroupTt=e−tLα, following [12], we shall consider the Riesz poten- tials
L−σf(x) = 1 Γ(σ)
∞
0
tσ−1Ttf(x)dt, σ >0, which can be derived from the identitys−σ=Γ(σ)−1∞
0 tσ−1e−tsdt.
In order to define the corresponding Riesz transforms, the following first order derivatives can be introduced, see [4],
δyα=√ y d
dy+1 2
√ y− α
√y
and ∂yβ=−√ y d
dy+1 2
√ y− β
√y
= (δβ−y 1)∗. The action forα>−1 and β >0 on the Laguerre functions is given by
δyα(Lαk) =−√
kLαk−+11 and ∂yβ(Lβk) =−√
k+1Lβ−k+11. Moreover
Lα− α+1
2
= (δyα)∗δαy=∂yα+1δαy.
Hence the Riesz transforms for the Laguerre function expansions are defined by Rα+=δαy(Lα)−1/2, α >−1, and Rβ−=∂yβ(Lβ)−1/2, β >0,
that is
Rα+(Lαk) =−
√k
k+(α+1)/2Lαk−+11 and Rβ−(Lβk) =−
√k+1
k+(β+1)/2Lβ−k+11. One of the main interests in studying Riesz transforms lies in their intimate con- nection with potential and Sobolev spaces. In our case it is easy to check that Rα+1− Rα+=Tm,the multiplier operator associated with the sequence
mk= k
(k+(α+1)/2)(k+α/2).
The boundedness of Tm andTm−1 in L2((0,∞), dx) is obvious, but moreover [16, Theorem 6.3.4] gives the continuity in Lp((0,∞), dx). From this observation and the boundedness of the above Riesz transforms inLp((0,∞), dx) given in Theorem 1 below, we may write
fp=Tm−1Rα−+1Rα+fp≤CRα+fp=Cδαy(Lα)−1/2fp≤Cfp, forf satisfying∞
0 f(y)Lα0(y)dy=0. Therefore for good enough functions, we get δyαfp∼ (Lα)1/2fp.
This equivalence is the key to define the Sobolev space associated to this Laplacian in terms of theδαy derivative.
The above observation leads us to give the following definition.
Definition1. In what follows we denote by Rα the Riesz transform vector associated to Lα, that is
Rα= (Rα+, R−α+1).
Since we are interested inLp-boundedness of both Riesz transforms simultaneously we shall state our results in terms of the operator
Rα(f) = (|Rα+f|2+|Rα+1− f|2)1/2. Our main result is the following.
Theorem 1. Let α>−1 and δ be a real number. Then the operator Rα satisfies.
(a)Rαis of strong type(p, p)with respect toxδdxas long as−αp/2<δ+1<
(α+2)p/2 and1<p<∞.
(b) Rα is of weak type (1,1)with respect to xδdx as long as −α/2≤δ+1≤ (α+2)/2 ifα=0and0<δ+1≤1whenα=0.
(c) If α=0 and −αp/2=δ+1 for some 1<p<∞, then Rα is of restricted weak type (p, p)with respect to the measure xδdx.
(d)If(α+2)p/2=δ+1for some1<p<∞, thenRαis of restricted weak type (p, p)with respect toxδdx.
We notice that our results include negative values ofδ+1 when α>0. In fact if we fixαandδthe range ofpmay be described as follows.
Forα>0:
Ifδ≤−1−α/2 it is of strong type for−2(δ+1)/α<p<∞, and ifp=−2(δ+1)/α it is of restricted weak type if p>1 and weak type whenp=1.
If−1−α/2<δ≤α/2 it is of strong type for 1<p<∞and weak type (1,1).
Ifδ >α/2 it is of strong type if 2(δ+1)/(2+α)<p<∞and restricted weak type whenp=2(δ+1)/(2+α).
Forα<0:
Ifδ≤−α/2−1 there are no boundedness results except forδ=−α/2−1 when we have weak type (1,1).
If−α/2−1<δ≤α/2 it is of strong type if 1<p<−2(δ+1)/α, weak type (1,1) and restricted weak type forp=−2(δ+1)/α.
If δ >α/2 it is of strong type for 2(δ+1)/(2+α)<p<−2(δ+1)/α and of re- stricted weak type at both end pointsp=2(δ+1)/(2+α) andp=−2(δ+1)/α.
Forα=0:
Ifδ≤−1 there are no results.
If−1<δ≤0 it is of strong type 1<p<∞and of weak type forp=1.
If δ >0 it is of strong type for δ+1<p<∞ and of restricted weak type for p=δ+1.
At this point we would like to remark that if we compare our results for the Riesz transforms with those obtained for the maximal operator of the heat semi- group ([6], [3]) we notice that besides the expected difference at p=∞ we also obtain a weaker result at the end pointp=−2(δ+1)/α. However we will show that it cannot be improved.
In fact the next theorem states that our results are sharp.
Theorem 2. Let α>−1andδ∈R. Then
(a)Rα is not strong type(1,1) with respect toxδdx for any δ.
(b) If α=0 and −αp/2=δ+1 for some p>1, then Rα is not of weak type (p, p)with respect toxδdx.
(c)If(α+2)p/2=δ+1for some1<p<∞, thenRαis not of weak type (p, p) with respect toxδdx.
2. Preliminaries
The heat diffusion semigroupe−tLα is given by Wα(f, t, x) =
∞
0
Uα(s, x, z)f(z)dz, wheres=(1−e−t/2)/(1+e−t/2),andUα(s, x, z) is
1 2
1−s2
2s e−1/4(s+1/s)(x1/2−z1/2)2e−1/2(s+1/s)(xz)1/2Iα 1−s2
2s (xz)1/2
. (2.1)
Iα is the modified Bessel function of order α(see [13] and [6]). We introduce the following notation which we will use frequently
M(s, x, z) =1 2
1−s2
2s e−1/4(s+1/s)(x1/2−z1/2)2e−1/2(s+1/s)(xz)1/2,
and, if we also set w=((1−s2)/2s)(xz)1/2, the kernel for the semigroup can be written as
Uα(s, x, z) =M(s, x, z)Iα(w).
To get the kernel of the Riesz–Laguerre transformR+α we write R+α(x, z) =δαx(Lα)−1/2(x, z) =δαx 1
Γ1
2
∞
0
e−tLα(x, z)t1/2dt t
=Cδαx 1
0
e−2 log((1+s)/(1−s))Lα(x, z)
log 1+s
1−s −1/2
ds 1−s2. Now, using the equalityIα(r)=αIα(r)/r+Iα+1(r), the kernel of the Riesz transform can be written as
R+α(x, z) =C √
x d dx+1
2 √
x− α
√x
(Lα)−1/2(x, z)
=C 1
0
1 2
1−s2
2s z1/2Uα+1(s, x, z)−1 2
(1−s)2
2s x1/2Uα(s, x, z)
×
log 1+s
1−s −1/2
ds 1−s2
=C 1
0
K+α(s, x, z)
log1+s 1−s
−1/2
ds 1−s2.
From Theorems 3 and 4, in the next section, and following the ideas of the proof of Proposition 3.2 in [14], it can be shown that for f, g∈Cc∞((0,∞)) with disjoint compact supports, we have
Rα±f, g = ∞
0
∞
0
Rα±(x, z)f(x)g(z)dx dz.
(2.2)
We leave it to the reader to check the details yielding that the kernel for the other Riesz transform is given by
Rβ−(x, z) =C 1
0
K−β(s, x, z)
log 1+s
1−s −1/2
ds 1−s2,
where
K−β=−1 2
1−s2 2s
z1/2Uβ+1−1+s 1−sx1/2Uβ
− β x1/2Uβ. (2.3)
3. Proof of the main result
We split the kernels of the Riesz transforms into their “local” and “global”
parts. By the local part we mean the restriction of the kernel to the set {(x, z) :x/4< z <4x}
and by the global part its restriction to the complementary set. In what follows we state some results for each of these parts and we show our main result, assuming they are true. The proofs of these theorems will be given in Sections 4 and 5, respectively.
Theorem 3. Let α>−1. We denote byK(x, z)either the kernelRα+(x, z)or Rα−+1(x, z). Then forxandz satisfyingx/4<z <4xwe have
(a)|K(x, z)|≤C/|x−z|; (b)
∂
∂xK(x, z) +
∂
∂zK(x, z) ≤ C
|x−z|2.
Theorem 4. Let α>−1. We denote byK(x, z)either the kernelRα+(x, z)or Rα−+1(x, z).If we denote byTglob the operator given by
Tglobf(x) =
(0,∞)
K(x, z)χ{z≤x/4}∪{z≥4x}f(z)dz, (3.1)
then, we have
(i)Tglob is of strong type(p, p)with respect toxδdxas long as −αp/2<δ+1<
(α+2)p/2 and1<p<∞;
(ii) Tglob is of weak type (1,1) with respect to xδdx as long as −α/2≤δ+1≤ (α+2)/2 if α=0 and0<δ+1≤1when α=0;
(iii) if α=0 and −αp/2=δ+1 for some 1<p<∞, then Tglob is of restricted weak type(p, p)with respect to the measure xδdx;
(iv)if(α+2)p/2=δ+1for some1<p<∞, thenTglob is of restricted weak type (p, p)with respect toxδdx.
Proof of Theorem 1. It is enough to prove the statements for each of the components of Rα. We consider the operator
Rα+,locf=Rα+f−Rα+,globf, (3.2)
where
R+α,globf= ∞
0
Rα+(x, z)χ{z≤x/4}∪{z≥4x}f(z)dz.
By Plancherel’s theorem, Rα+ is bounded on L2((0,∞), dx). From Theorem 4 the operatorRα+,globis also bounded onL2((0,∞), dy). ThereforeRα+,locis bounded on L2((0,∞), dx), for anyα>−1. Moreover by (2.2) we have that forf, g∈Cc∞((0,∞)) with disjoint compact supports
Rα+,locf, g = ∞
0
4x x/4
Rα+(x, z)f(x)g(z)dx dz.
Therefore by using Theorem 3 we have that Rα+,loc is a “local Calder´on–Zygmund operator” as defined in [10]. Hence we can apply Theorem 4.3 (a) in [10] to conclude that Rα+,loc is bounded onLp((0,∞), xδdx) for anyδ∈R and 1<p<∞. Applying again Theorem 4 we get the boundedness ofRα+as stated in (a), (c) and (d).
Moreover asR+α,locis a “local Calder´on–Zygmund operator” we can apply The- orem 4.3 (b) in [10] getting that Rα+,loc is bounded from L1((0,∞), xδdx) into L1,∞((0,∞), xδdx) for any δ∈R. Therefore by using Theorem 4 (ii) we get (b).
All the arguments are also valid forRα+1− .
4. Local region. Proof of Theorem 3
As we have seen in (2.1) the kernelUα(s, x, z) can be expressed by Uα(s, x, z) =M(s, x, z)Iα
1−s2 2s (xz)1/2
, (4.1)
where M(s, x, z)=12((1−s2)/2s)e−1/4(s+1/s)|x1/2−z1/2|2e−1/4(s+1/s)(xz)1/2.
As in the local regionx∼z, the last exponential is equivalent to e−c(s+1/s)x. Now we state some basic inequalities about the behaviour of Iα that we shall use often, (see for example [5]).
(a) If 0≤w≤1, then Iα(w)wα. (b) Ifw≥1 then Iα(w)eww−1/2.
(c) Ifα≥−12 thenIα(w)≤Cαeww−1/2 for anyw≥0.
(d) If−1<β≤α, thenIα(w)≤CIβ(w).
From (b) it is easy to see that forw=((1−s2)/2s)(xz)1/2≥1 andx∼z, Uα(s, x, z)≤C
1−s2 2s
1/2
e−1/4(s+1/s)|x1/2−z1/2|2e−csxx−1/2. (4.2)
Before proceeding to prove Theorem 3 we state two lemmas which give some esti- mates useful to obtain the conditions on the size of the kernels and their derivatives.
Lemma 1. Let γ >12 andε≥0. Assume that L(s, x, z) =|z1/2−x1/2|2((γ−1)+ε)
x1/2+εsγ e−(1/4s)|x1/2−z1/2|2. Then there exists a constant C such that forxandz in the local region
1/2
0 L(s, x, z)
log1+s 1−s
−1/2
ds≤ C
|x−z|.
Proof. Using that log(1+s)/(1−s)∼sfor 0≤s≤1/2 and thatx∼zwe have 1/2
0
L(s, x, z)
log 1+s
1−s −1/2
ds
≤|z1/2−x1/2|2[(γ−1)+ε]
x1/2+ε
1/2 0
e−(1/4s)|x1/2−z1/2|2 sγ−1/2
ds s
≤C |z1/2−x1/2|2[(γ−1)+ε]
|x1/2−z1/2|2γ−1x1/2+ε ∞
0
e−uuγ−1/2−1du
≤C |z1/2−x1/2|2ε
|x1/2−z1/2|x1/2+ε
=C|z1/2−x1/2|2ε|z1/2+x1/2|
|x−z|x1/2+ε ≤ C
|x−z|, as we wanted. This completes the proof of the lemma.
Lemma 2. Let σ≥0andγ such that γ−σ >12. Assume that L(s, x, z) =|z1/2−x1/2|2(γ−3/2)
sγ−σx1+σ e−(1/4s)|x1/2−z1/2|2. Then, in the local region x∼z we have
1/2 0
L(s, x, z)
log 1+s
1−s −1/2
ds≤ C
|x−z|2.
Proof. By the estimate log((1+s)/(1−s))∼s and the fact that in the local regionx∼z, we get
1/2 0
L(s, x, z)
log 1+s
1−s −1/2
ds
≤C|z1/2−x1/2|2(γ−3/2) x1+σ
1/2 0
e−(1/4s)|x1/2−z1/2|2 sγ−σ−1/2
ds s
≤C |z1/2−x1/2|2(γ−3/2) x1+σ|z1/2−x1/2|2(γ−σ−1/2)
∞
0
e−uuγ−σ−1/2du u
≤C |z1/2−x1/2|2σ x1+σ|x1/2−z1/2|2
≤C C
|x−z|2,
which completes the proof of the lemma.
Proof of Theorem 3. As we have seen in (2.3), given α>−1, the kernels of both Riesz transforms before integration in sare:
K+α=1 2
1−s2 2s
z1/2Uα+1−1−s 1+sx1/2Uα
. and
K−α+1=−1 2
1−s2 2s
z1/2Uα+2−1+s
1−sx1/2Uα+1
−α+1 x1/2Uα+1.
Therefore, if we call bs=12(1−s2)/2s and as either (1−s)/(1+s) or (1+s)/(1−s), we get that we should analyse
H1=bs(z1/2Uβ+1−asx1/2Uβ) and H2=−α+1 x1/2Uα+1,
since choosing in H1, as=(1−s)/(1+s) and β=α, we get K+α, while K−α+1 is ob- tained taking as=(1+s)/(1−s), β=α+1 in H1 and then performing −H1+H2. Therefore it would be enough to get the desired estimates for those kernels. Setting ψ(s)=(log((1−s)/(1+s)))−1/2/(1−s2) we must show that in the local regionx∼z,
(a)1
0 |Hi(s, x, z)|ψ(s)ds≤C/|x−z|,i=1,2, (b)1
0 |(∂/∂x+∂/∂z)Hi(s, x, z)|ψ(s)ds≤C/|x−z|2,i=1,2.
We split the first integral in 0≤s≤12 and 12≤s≤1. In the latter case we observe that all the terms in H1 and H2 are bounded in absolute value by Cx1/2Uα with αthat may be assumed to be negative. In fact for H1 we just use thatUγ≤CUγ
whenγ≤γ and thatx∼z, while forH2 we use thatIα+1(w)≤CwIα(w), and so 1
x1/2Uα+1(s, x, z) = 1
x1/2M(s, x, z)Iα+1
1−s2 2s (xz)1/2
≤ C
x1/2Uα(s, x, z)1−s2
2s (xz)1/2≤Cx1/2Uα(s, x, z).
Now, forw=((1−s2)/2s)(xz)1/2≤1 and 12≤s≤1 we have x1/2Uα≤C(1−s2)x1/2
1−s2 2s (xz)1/2
α
e−c|x1/2−z1/2|2e−cx
≤C(1−s2)x1/2+αe−c|x1/2−z1/2|2e−cx≤C(1−s2)1+α
x1/2 e−c|x1/2−z1/2|2, (4.3)
where we used thatx∼zande−cx≤Cx−(1+α).
Similarly forw≥1, using (4.2), we get for someC >0, x1/2Uα≤C(1−s2)1/2e−c|x1/2−z1/2|2e−cx≤(1−s2)1/2
x1/2 e−c|x1/2−z1/2|2. (4.4)
Therefore, lettingγ=min α+1,12
, we have 1
1/2
x1/2Uα(s, x, z)ψ(s)ds≤ C
x1/2e−c|x1/2−z1/2|2 1
1/2
(1−s2)γ
log1+s 1−s
−1/2
ds 1−s2
≤ C
x1/2|x1/2−z1/2|≤C|x1/2+z1/2| x1/2|x−z| ≤ C
|x−z|.
Now we consider 0≤s≤12. This time we observe that all terms in H1 andH2 are bounded by (C/s)x1/2Uα. For this kernel, in the regionw=((1−s2)/2s)(xz)1/2≤1, using thatIα(w)∼wα, we have
C
sx1/2Uα(s, x, z)≤ C sx1/2
x s
1+α
e−cx/se−(1/4s)|x1/2−z1/2|2. Therefore, applying Lemma 1 withε=0 andγ=1 we are done.
The most delicate part concernsH1 in the regionw≥1. Here we will use the cancellation by means of the asymptotic formula ([5], p. 123)
Iα(w) = ew (2πw)1/2
1+Oα
1 w
. First we writeH1 as
H1(s, x, z) =bs(z1/2−x1/2)Uβ+1+bsx1/2(Uβ+1−asUβ) =H11+H12.
The first term follows easily since using the behavior ofIβat infinity,H11is bounded by
C|z1/2−x1/2| s2
s1/2
(xz)1/4e−(1/4s)|x1/2−z1/2|2≤C|z1/2−x1/2|
x1/2s3/2 e−(1/4s)|x1/2−z1/2|2, and we may apply Lemma 1 with γ=32 and ε=0. For the second we use the asymptotic formula to get
|Iβ+1(w)−asIβ(w)| ≤ ew (2πw)1/2
(1−as)+C w
.
But, for both possible values ofas it holds that 1−as≤Csfor 0≤s≤12. Therefore since in our situationwx/s, we get
|H12| ≤Cx1/2
s |Uβ+1−asUβ| ≤C
se−(1/4s)|x1/2−z1/2|2e−csxx1/2 s
s x
s+s
x
≤Ce−(1/4s)|x1/2−z1/2|2 e−csx
s1/2 + 1 s1/2x
≤Ce−(1/4s)|x1/2−z1/2|2 sx1/2 , (4.5)
where we used that e−csx≤C(sx)−1/2 and that in the region w≥1,since w∼x/s, we have 1/x1/2≤C/s1/2. An application of Lemma 1 with ε=0 andγ=1 leads to the desired bound forH12.
Finally we take care of H2 in 0≤s≤12 and w≥1. But, using that for w≥1, Iα+1(w)≤Cew, we get just as above
H2(s, x, z)≤ C
sx1/2e−(1/4s)|x1/2−z1/2|2, and we are done.
Now we turn to the boundedness of the derivatives ofH1andH2.
First we analyze the derivatives with respect toz. Straightforward calculations show that we have to deal with the following type of terms:
Case 1.
β+3 4
1−s2 2s
1 z1/2Uβ+1. Case 2.
1−s2 4s
−1−s2
4s x1/2Uβ−1 4
s+1
s
z1/2Uβ+1
. Case 3.
1−s2 4s
1 4as
s+1
s
x1/2Uβ−1−s2
4s asxz−1/2Uβ+1
.
Case4.
−1−s2 4s
β 2asx1/2
z Uβ. Case5.
−(α+1) 4
s2+1 s
1
x1/2Uα+1+(α+1)1−s2 2s
1
z1/2Uα+2+(α+1)2 1
zx1/2Uα+1. With such notation, (∂/∂z)K+α is the sum of the first four terms with as=(1−s)/(1+s) and β=α, while (∂/∂z)K−α+1 is the sum of Case 5 with all the others with as=(1+s)/(1−s) and β=α+1. As before, for 12≤s≤1, all the terms above are bounded by one of the type
C
x1/2Uα(s, x, z)eεx,
forε>0 small enough and we may assume thatα<0. This is clear for terms having x−1/2,z−1/2 orx1/2z−1. For those withx1/2,z1/2orxz−1/2 we use thatx∼zand that x1/2≤Ceεx/x1/2. Finally, the last term of Case 5 follows from the inequality Iα+1(w)≤CwIα(w) valid for anyw≥0.
Now, for the above kernel we have that for w=((1−s2)/2s)(xz)1/2≤1, x∼z and 12≤s≤1,
1
x1/2Uαeεx≤C1−s2
x1/2 eεxe−cxe−c|x1/2−z1/2|2(1−s2)αxα
≤C(1−s2)1+αx1/2e−cx x1−α
1
|x1/2−z1/2|2(1+α)
≤C(1−s2)1+α x1−α
|x1/2−z1/2|−2α
|x−z|2 |x1/2+z1/2|2
≤C(1−s2)1+α
|x−z|2 , as long as 0<ε<cand−1<α≤0.
On the other hand ifw≥1 we get 1
x1/2Uαeεx≤C(1−s2)1/2
x e−c|x1/2−z1/2|2eεxe−cx
≤C(1−s2)1/2 x
1
|x1/2−z1/2|2≤C(1−s2)1/2
|x−z|2 .
In both cases we arrive at the desired estimate since the integrals againstψ(s) are finite. Now we proceed with the case 0≤s≤12. Here again we notice that all the