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Technical Translation (National Research Council of Canada), 1960
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On the General Solution of the Fundamental Equation of Thermal Conduction in Bodies Whose Thermal Coefficients are Affected by Temperature
Sawada, M.
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One of the projects of the Fire Section of the Division of Building Research concerns the development of a method
for calculating the fire endurance of building elements. The main theoretical problem in this work is that the
classical solutions of the Fourier equation, based on con-stancy of properties, cannot be used because of the Wide variations in temperature involved in this experimental work.
Three papers by Masao Sawada that deal セセQエィ problems
of the heat conduction encountered when the heat capacity and thermal conductivity of the solid are variable, have been translated and issued as NBC Technical Translations
Nos. 895, 896 and 897. From the work of Sawada it is seen
that the more perfectly the mechanism of heat conduction within the solid is approached, the more limited the ap-plicability of the method becomes, as far as the shape of the solid or the boundary conditions are concerned.
Although the introduction of various numerical methods and
computer エ・」pセQアオ・ウ largely reduce the practical value of
such analytical methods, there are certain fields where they are indispensable.
Ottawa,
September 1960
B.F. Legget, Director
Title:
Author: Referenoe: Translator:
Technical Translation 897
On the general solution of the fundamental equation of thermal conduction in bodies whose thermal
coefficients are affected by temperature Masao Sawada
J. Soc. Mech. Engrs., Japan, 37 (201): 15-21, 1934 K. Shimizu
ARE AFFECTED BY TEMPERATURE
Abstract
This is a continuation of my article "On the general solution of the basic equation of thermal conduction", J. Soc. Mech. Engrs., Japan, 05 (183), 1932 (NRC TT-895). Here a solution to the fundamental equation is sought which will be applicable to finite as well as semi-infinite bodies, where thermal conductivity and thermal capacity can be regarded as a function of temperature. A few problems of thermal conduction under simple
bound-ary conditions are considered. Since the law of
super-position is not directly applicable with respect to temperature in this case, the author proposes that a "thermal function" be sought by solving a transformed fundamental equation.
1. Introduction
Thermal conductivity and thermal capacity vary somewhat as an
effect of thermal conduction. It is not easy to treat thermal
con-duction analytically in this case. Even if the solution to the
fundamental equation is possible, it is not easy to apply this to
problems concerning a finite body. The author has sought a
solu-tion· to the fundamental equation by assuming that thermal
conduc-tion Has a funcconduc-tion of temperature. The method follows that of
Van Dusen··. In the case of an ordinary homogeneous body, the
superposition of temperature is valid. It is not valid in the
present case •
•
••
See abstract.
Van Dusen puts V = AO
f
f(v)dv ="0
J
f(v)arvdr where AOf(v)=
conduct1v1ty and 1n dea11ng w1th the fundamental equat10n andre-lated problems he treats th1s as a "thermal funct10n". The author
be11eves th1s to be one of the more conven1ent methods. Only w1th
the estab11shment of th1s thermal funct10n 1s 1t poss1ble to apply
the pr1nc1ple of セオー・イーッウQエQPョL and the problems relat1ng to f1n1te
as well as sem1-1nfin1te bod1es w1th var10us surface cond1t10ns, but not surface rad1at10n, are then access1ble to solut1on.
2. Outline of the Fundamental EQuat10ns Qf Thermal Conduct10n
[1°] The case where the body 1s not a heat source
For conven1ence, let the thermal capac1ty be ーセ
=
g1(X,y,Z) •g2(V) • g3(t) and the thermal conduct1v1ty A
=
f 1 (x,y,z) • f 2(v) •f 3(t). Then, generally, the following cond1t10n holds:
pru,v=div(,logradv) (1)
Further, 1f we put
!fJ,V)dV=v, !fs(t)/Ks(t)odt= T,gz(v)l/J,v)=F{V)
the follow1ng equat10ns can be estab11shed.
KI(x,y, z)·F{V)UTV=div[};(x,y, z) grad VJ. .... (1o)
KI(x,y, Z)!fI(X,y, z)0fitV)uTV
=div(grad V)+grad Vodiv[,l.d,(x,y.z)
.. F{V)uTV=[U.,(fI(X.Y.コIuNLvIKオセHィクNケL z)u" V)
+u.(fl(x,y, z)u. V)]/KI(x,y. z), [ru,UI(r, 0, z)'rUrV)+uo(fl(r, 0, z)UoV)
+ru.[JI(r,0, z ]u.V)]I,-...-·g-,I(.-r.---,;O..-,z--.--).
{sin2
0.ur[tl(r ,O,IP )·y2ur V]+sinOUe[sinOf,(r,O,IP)Ue V]
+オセ{jゥHイLoLアjIXセ V]}/rsin20KIlr ,O.IP ) (11)
If g2(V)
=
f 2(v), then F(V)=
1, and the fundamental equat10nof the same type as 1n the case where ーセ and A are merely funct10ns
of d1mens10ns, 1s obta1ned. Thus, 1f g, (x,y,z)
=
g(l)(x) • g(2)(y)• g(3)(z),
セ
(x,y,z)=
f(l)(x) • f(2)(y) • f(3)(z), there arecases wh1ch are capable of solut10n.· It w1ll be recalled that
Van Dusen'" discussed a solution of the problem of constant flow in
the case where A!P'Y
=
constant, and A= f2 ( v ) . In short, if p'Y andA are a function of the temperature v, the problem should be treated
by putting v equal to
J
r,
(v)dvV.In the case of a long and slender cone or a cylinder, let F be the cross-sectional area, zf the perimeter of the cross-section, E the rate of heat diffusion and va the outside temperature, then
the following equation is obtained:
fJrFf),v=8.(FA8.v)-t· zf· (v"': Va) (12) ••
Further, for an annular or a radial fin, let z be the thickness
of the fin and 2nra the length of circular arc. Then
fJrzr8,v=8r(zrA8,.v)- 2£r(v-va) ••...(13) • •
fJrz(2n:r(J)8,v = 8r(2n:r(JzA8,.v)-2[£lZ+ £2(2n:r(J)](v-va )
... (14),,/<
In (12), (13) and (14 ) F, Zf, z and 0 are either constants or
functions of the セQウエ。ョ」・L and A, p'Y, e, B1 , B 2 and v are
const-a
ants or functions of dimension, temperature or time. Of these
variables, the case in which A, P'Y, F, Zf, z, and a are functions of dimension has already been d1scussed.
[2°] The case where the body is a source of heat
If Q be the amount of heat emitted per unit time and volume,
then since Q
=
q1 (x,y,z) • q2(1)(v) • q3(1)(t), the requ1redfunda-mental equation will be obtained by merely adding Q to the right
side of (1). Similarly Q
=
q1 (x,y,z) • q2(V) • q3(T) should beadded to (10 ) , FQ.
=
Fq 1(x ) • q} 1) (v) • q 3(1) (t) to (12 ) , rzQ =
rzq1(r) • q2(1)(v) • q3(1)(t) to (1 3), and (2nro)zQ = (2"ra)zQ1(r) •
q (l)(v) • q (l)(t) to (1 )
2 3 4 •
•
••
J. Soc. Mech. Engrs., Japan, 33 (161), 329. Abstract 124 •
Dr. Saihara. J. Soc. Mech. Engrs., Japan, 35 (180),318;
Primarily, A, ーセ and Q are complex functions of dimension and
time. However, integration is possible only when the fundamental
equation CRn be expressed as a product of separate functions of di-mension, time and temperature.
The author will not consider the case in which
A
and ーセ arefunctions of time. In this paper he will deal mainly with the case
in which the body.is not a source of heat, but will discuss the
case in which
A
and ーセ are functions of dimension and temperature.3. The Solution of the Fundamental Equation for Finite
Body Problems
[1°]
The case in whiChA
= aセjvIL ーセ=
aセPR•
g21xl ,
limited to rectangular coordinates
l/ao!·g.f..V)8IV=f),/,fj,v)f)",v)+ヲIセuRHvIヲILーI +f).(J2(V)f).V)...(2)
(i) セ =±ik"alx±ik.'a2y±ik.'z-ik'a02{r-t.
W,'al)2+(i k.' a.,j2+(ik.'a3)2=kk{r-.
Transform (2) by putting k1 I , k2 ' , k3 ' , and k ' as 3 or 4. Here the
first constant of ゥョエ・イLイセエゥッョ will be neglected.
ァRHvIヲIセv =ヲIセuRHvIヲIセQG (20) .'. ex p,{fV2(V)/ f g2(v)dvj、カス]a・セ (21) integers, Developing Now let ... II fi v)=1+1,;;·...v..., g2(V)=1+ Lk"v". Am and kn セ 0,
and assume m and n to be positive integers (nesative positive or negative fractions are not impossible). further, we have
JViV)/ J g2(V)dVJdV
=Ag[v·.(v+ OI)"(V+ ( 2)••... (v+ 0,,)'.J
,., V"(V+01)"(V+02)" (v+O,,)·. =Aet HRセI
Note that the left side, when expanded, becomes a multiple degree function of v and the right side becomes identical With the
three dimensional solution in the case of a homogeneous body. If
When
e
can be expressed as follows:fM'=ao2[fJ,/ 8 + fJ,N' + fJ.28 ] (2
5)
but cannot be applied directly to problems.
(11) v
=
w ) + u where Uo
is a constant.(x,y,z,t 0
...
..
fiv)=1+
l)...
v..., g2(V)= 1+Lk..
v",and m and n are pos1t1ve 1ntegers, we have, from (2):
where
...
セQKtk..
HwKQiッIセ fJlw '=ao2diV{[I+ 1'A",(U'+uo)"'}radow} (26) 1+ t k..(W+Uo)"=klOl[I+i k l..I;"} 1+ iA",(W+110)'"= A(Ol[1 +ェ[aHBGwBGセ
•In the above express10n
..
klOI=r
k ..tto". o..
r
11' kIll= -- '-k"u ..-I (n-l)1 0 , I..
k(2) - '"" II! k .._2 - L.J 2!(1I-2)1 ..Uo , 2..
k(3) _ ' " " 11! k ft-3 - .LJ 3'(n-3)! ..uo • , kC..+l)=k.._1KQiォBMャエセP[ k(") =k.., •.o. (1 +
r
kl..IW")fJIW=a2diV[ (1 +r
Al"'IW'")gradW...(27 )
exp
.{! [
(1+ ) ;A("'Iw'")/w(
1+t
kl..1w" j1+1I)Jdw}
=a・セ (28)
Of the
セ
in (21) , the coeff1c1ent
QォG。ッRセR
of t 1n th1s case 1sk' 2 (O)/k(O)
1 aO A • Thus, 1f w(x,y,z,t) and the constant u
o
are super-posed, (2) reduces to (2e ) , a s1m1lar type. If v=
w( t) +x,y,z, u(x,y,z)' th1s no longer holds.
We obtain from (2)
(iii) Let
!f2(V)dV= v, g2(V)!f2(V)=A.V).
F(V)01V"; a02[0.,z V+ 0,,2 V+0.2V] .' HRセI
Thus,
In this case, セ is identical with セ in [10
J,
(i). (25) holdsfor 8.
(iv) If F(V)
=
1, we obtain immediately from (29 ) :。iv]。ッR{PセRカKPLLRカKPNRvj .'. v]a・セ ...(2u )
AI
pry=
).'0/aO:2.
This reduces to the case in which X = XOf:2(v),
if the flow is constant, セRv
=
0 :. V=
b・セN,=
I1IX+112Y+ 11a,Z. 1112+I1l+I1l=o.v=W<..", •.I)+U<e.".•), !ll.l(",...)=w(...)+G(...).
v=!ll.l(",...)+u(..)
However, Putting
and sUbstituting in the fundamental equation, セャ・ obtain:
Ol!ll.l=ao2(O.,z!ll.l +01l25ffi +0.2!ll.l). 。セRオKPLLRオKPNRオ]ッ ...
... .(212) , (213)
Example i. The case in which
A=Ao(l+AIV), or=Ao/ao2•(1+klv)
.', v(1+!klvIRセGォLMQ =Ae:
kl=2AI...カ]a・セL kl=AI ..ᄋᄋᄋᄋvHvKAaャカI]a・セ
Further if A=Aeo"l", or=AoItZo2
•t"'"
Example ii· where
"
. '. exp.[kl/(AI-kl)e<).'-",)tI]=Ael
A=Ao(l+'IV+A2V2), pr=Aoao2.(1 +klfl + k2v2)
. " v(v+XIセ[HカK XRIセG =A expoW16)
81•2=3(kl+r/JII2)/4k2, r/J=k12_ (16/3)k2• t'l=(16/3)k2[A281 - ·Al+(3/2)kl/k 2]r/J1I2
t'l=(16/3)k2[AI-A282-(3/2)kl/k2]/r/J1I2 •
[2°] The case in wh1ch X
=
f,(x,y.z) • f 2 (v)•
f3 ( t ) . pry
=
8.t (x.y.z) •
r,
(v) •s,
(t) reduces to the case in which weput F(V)
=
1 1n the fundamental equation (1,1If V
=
W(X,y,z,t) + uセLケLコIG then substituting this in (2 14 ) we have:K"b'-,y, r)8 rW=div[Jlr,y, z) gradW],
div [Jl(X,y, z) gradU]=0.
Thus, by giving sUitable forms to f 1(x,y,z) and g1(X,y,Z) we can obtain a three-dimensional solution with respect to all
co-ッイ、ゥョセエ・ systems, and one which will be of practical use under
simple boundary conditions.
(i) The case where the flow is constant:
div[Jl(X,y, z) gradU]=0 (21&)
For instance, with respect to the rectangular coordinate by putting
we obtain:
J
l!ll(X,y, z)'dx=x,f
l!ll(X,y, z).dy=Y,J
l!ll(X,y, z)odz=Z8Zl u + 8 l u + 8i1zu=o .'.U=ff2(v)dV=Be l ... (216 )
For two-dimensional ーイッ「ャセュウ analysis by means of complex
numbers is possible. It would be interesting to investigate other
coordinate systems.
where m' expresses curvature. In case
v=Jf2(V)dV T=j'fa(t)/K"3(t)'d/
.. V=exp.(-ao:!,62a2T){It...",,(2ayyP)/y,-,] ...(217)
=exp.(-ao2q2a2T){J±",(2aY;;;;)/y,-,].
[ C? SSin(1I8)J, 111=(mI2+411)1/2tp (211)
セ = cos
a,
m = integer.The above solutions are limited to problems of a
non-vibration-al type. Further, 1f mt = 0, r can be made equal to c
±
x. IfA = A
o
em,x f 2 ( v ) • f3 ( t ) , A/P'Y = a02e-PXg3(t), then substitute eXfor x. If mt = 1 or 2, we can solve the fundamental equation by
and A= Ar/..c±y)1+"',!y"" ·f2(V) ·f3(/),
Atpr]。ッRケBBH」ᄆケIセBAyBB •ga(l) , res pec t 1ve ly ,
i.e., one should seek suitable functions which eliminate the curva-ture. Example 111: Solution: where constant flow. A=Ao(l+A1v). PQrv]r.=t.(a-v.). [AQrV]r,= '.(Vi- h). 2 '=-l/AI +[1/A1 2+2(Af(y)+bIOaセIセ}iヲR ..:... .(2 20) A =[Q+(Q2_1'R)1/Z]/p. B= AoA[Q/P- t.1'.""(1+A1a+aiMiエNyNBBェャゥI}OHエセケNBLGIR + Ao[a(l- Ala/2)/(tiy;",')2-b(1--A1h/ 2)/(t . l'. ""f] /P , P= 1/(6.1'0"'r-1/(ti";"")Z - - - Q=Ao[<1+Ala)/t.y."" m' 0 1 2 セ⦅⦅⦅⦅⦅⦅⦅⦅⦅⦅⦅⦅ +(1+A1h)/ti y;",']+N
f(y) r Agy -1/1' R=(a-b)(a+h+2/A I).
M r; Agy. -1/1'.
N Y.-Yi Agyo/Y, 1/Yi-1/y•
.-
- _
.._ '-For the valueR of f(r), M, and N see the table.
Example 1v: Constant flow.
-A=A o
(1+
l'A",V"'). m = positive integerAO[V+
i
A",V1+"'/(1+tn)]=Ax+B.To determine A and R under sUitable conditions, and to solve
for v.
Lemma: Boundary conditions: セ。 v
=
+ g(v-c) wherer
a
ur
A
=
セッヲ 2 (v>.Consider v
=
w(x,t) + u(r). Since セF
0, if g セ=
0, if セoOァ = 0, w=
0, u=
0, g=
finiteAo/2(w+ u)Qr(w+ u)=±t(w+u-c)
Next, by expandLng f 2(w + u), Ao/2(u)QrU=±t(u-c)
A., [J2(W+u)Qrw+wf'(u)'QrU+!llrf"(u)QrU+ ...]=±tw.
Thus, unless E is finite, solutions are not possible in
applied problems.
Ins1de the body
put
Cond1t1ons:
prutV=u"OU"V) where A=A of2(V), A!pr=ao2
v= !f2(V)d7'. V=W(".t)+U(..), v=[w(w)+G(IO,n)]+U(u)=!m(".l)+U(,,),
ul'1J3=ao2U,,2!m , ['1J31".={|iャNセ}BL]ッL
[llB]I=O=[V]t=o-U, U11=O=ID. U,,2U=O.
[U]".=[
v];::.
[U]",={u}ZセZNu=
[V]l='".1.".{[
v]t=o-U}sin IITrr;-x. dr; (222 )"" X'i-X'a
Example: The case 1n wh1ch f2 (v)
=
1 + A1v ,Subst1tute the following in (22 2 ) :
V=v(1 +!A1V), [V]t=o= !,6(x)[1+!A l!,6(X)], U= [V]t=", = Ax+B= u(1+!Alll),
u= -lIAl+[1/A12-2(Ax+B)/A
oAl]l/2. A =(6-a)[1 +!Al(a+ 6)]/(Xi- x,,), B= [0(1 +!A la)xi-b(1+!A16)x.]/(Xi-X.)
V=(w+ u)[1 +!Al(W+ u)],
Problem 11: 'Nhere [V]".=a, [u"v] .... =O. [v]t=o=!,6(x).
A and A/P'Y as before.
Cond1 t10ns
u
t'1J3=4ul'1J3 , [!m]".=o. [u,,'1J3].... =o.[!ID]I:O= [V]I:O- U. [V]I:O= lD(x).
Further [U"U] .... =o. u= [V]t=",
.', v=l,) +_2_ セ・クーL{⦅H。jャiKA|tイIGエj」ッウサHRQQKQItイ X-Xi} x.-x,L.J
..
X.-Xi 2 X.-Xi1.".[
]
{(211+1)Tr r;-Xi } • 1D(r;)-U cos - 2 - - - dy (2l J ) "I . x.-xiExample: The case 1n wh1ch f2 (v) = 1 + A1 V vセカHQ +!A1V), [V]t:o= lD(x)=!,6(x)[1 +!A l!,6(X)] U= u(I+!A1U) ;' Ax+B. A=O, B=a(I+!A la). tスセ・ above expr-e sstons are substituted 1n (22 3 ) .
Problem 111: AO[U"V]".=t,,(a- [v]".), Ao[U..V] .... = t,{[V]"i- 6), {v}エセッ] lD(x).
Inslde the body atv
=
a02ax2V where €1=
€!/AO' €a=
€a/AO·Condltlons are classlfled ln Table I. The present problem ls
not exact. Table I Boundary condltlons t U<セ COfts'ta ...t • floW' {ッBu}LL[]セサ{v}BiMャiI [o ..ア}セN =セH。M [v]:r.) u]{v}iセGB [o"W]"I=!i[wlr l [o ..W] ...=Mセ{キ}セN [W]I=O= dI(x)- U Example: ee .. V=U+2};r,I5011
..
H。セGK !..i'Xx.-x;)+(a,,'+セANNANxANNゥK !.!!)/a,,'+!/).f...
[dI(71)-uJ[。セ」ッY。セHWQMク[IKAゥウゥョ。セHWQMク[I}、jャ ...(224)ttl:v)=1+A1v, V=W(",I)+U<.). V= W<e.I)+U<.)
V=v(1+!A1v)=W+U ... W=w(1+!A1w)+A1lCilt . ,
U=n(l+!Atu), OIW=ao'O.IW. fJ..'u=o. U=Ax+B.
Dependlng on condltlon A and Bare determlned from Further,
Then AO(l + A1W)axW =
±
€Werror. Consequently, thls
However,
approx1-and lf セQ ls small, let A1ax(WU) セ 0.
clearly holds. However, there ls some
case, strlct1y speaklng, ls not valld.
In problems 1 and 11, lf the external temperature ls lnfluenced by a functlon of tlme, they must be handled by Duhamel arlthmetlc,
although thls may be cumbersome. Further, a solutlon ls ーッウウャ「セ・
ln the case
The solutlon ls also posslb1e ln two or three dlmenslons. ln a general case, the calculation 1s 1mposs1b1e except by mat10n through expanslon.
If A
=
AOf2 (vIdv , p'Y=
Ao/ao
2 • g2(V), problems 1 and 11 canHowever, this is theoretically somewhat unsound, and will not be
discussed here. This is due to the fact that the constant flow
value must be a V function, although there is nothing wrong in using
the
e
function. An exact treatment is possible in such problems as{カ}セN]。L {カ}セ[]「L [V]t=o=q,(,-)
r"'"PTatv=。セHINセBLG。セカI
A=Aorl+"'-"''l2(V), A/PT=Ao/ao2,r--", ,,=m/f>,
one involving a semi-infinite body. Problem iv:
Inside the body where ...(225) Where m'
=
curvature number. In accordance \'1i th [20 ] , putting v= ff2(V)dV, v=wHセNエIKuHセI then, {w}セN]ッL {w}セ[]oL lu}セN]。GL {u}セ[]「GLセMᆳ[W]t=o= [V]t=o- U. [V]t=o= (1)(r), u= [V]t=oo,
Inside the body LNLNKBGMャ。エw]。ッR。セHイQKGB。セキIL 。セLMエKBG。セuI]ッ
co
.', v= [V]t=co+PL'il3,a/exp.(-ao2p2a/ t ) ,
-
MMセuLLHセゥセᄋ r1l+...: I[ (1)(r)-{v}エ]ッッ}セLLHセ、イ. セ[
uョHセ] {jLLHAZIZAMLLHセIM jMLLHNFjLLHセ}OカイMN !:.=2a,vr",
root of U,,(ra)=0 'il3,=(11"/sin"11")2(8,2-1).
8,=jLLHセIOjBHAZゥI] jMBHセIAjMォゥIG
Example: fJV)=l+A1V, V=v(l+tAlv),
(1)(r)=q,(r)[l +!A1q,(X)], {v}セN =[u(l +!A1U)]..=a =a',
{v}セ[] [u(l +tAIU)]..=b=b'.
[V]t=oo=U= [u(l +tAlu)]t=oo='1'1+'I'Jr"',
{v}セセセ]。G]GiGQ +'I'Jra.... [VJr:;;,=b'='I'I+t'2Ir ....
,', U=[V]t=oo=[a'/rr-b'/ra'"
-(a' -b')/r"']/(l/rr -l/ra"') ,
The above values are to be substituted in HRRセIN
{v}セN] 'Fa(t). {v}セ] 'Nt) using Duhamel arithmetic.
ao{。セv}セN]A。H。M [v] ...).
セッ{。セ v}セ[] !.{[vl.;-b), [V]t"o=(1)(1')
17"+--1at v=。セイQKBG。セ V).
Problem v: Inside the body
As in problem iii, consider V
=
W(r,t) + U(r). Then, thefollowing results easily follow, althoug1l they are inexact.
co
r:[V]t=oo+P.L'il3"a/exp,(-ao2p2a,2t)U,,(r)
,
Where
[No.1]= M{ーHAェIORイゥィゥ}jMHヲエK、セLIK J-.(!j),
[No.2]=[P(!::i)/2r,h i] "iョKエHセIK In(rJ) ,
vg-{v)8Iv=kRoflA [v)-S(v-vaVs(v) GHセYI
t=
J
vァHセIO{ kRoN/i(v)-S(v-va)/s(v)}dv+AI (2eo)as 1 s a pos1 t1 ve root of [U/(r)]r.+h..Un(r,,)= 00):iE1R. h"=E"I).r,, h,=Eil).o,
!H,={[(pa.fr"p+h"2r,,2- mh,,ra]ra'"[uイHセI}R
- [(pa.fr!'-2 -mh;/ri+hl](sinnTT:/TT:f}-1 •
Example: /2(v)=1+).lV, V=v(l+t).t v),
(1)(r)=¢(r)[1+t).l¢(X)], u,,=a', ui=h'
u= [V]I=", =u(l+!).IU)=%"l+ rJrm
%"1=[hJ(m/h"r"l+m_r,,-m)a'(m/h,r/+m+r,-;")]/q,
r2=(a J-h')/q, q=m[(l/h"r"I+,"+l/h,r/+m+(r,-m_ r,,-m)].
The above expressions are subst1tuted 1n (22 6 ) .
In the present problem, as 1n problem 111, 1t was assumed that
Newton's Law holds approx1mately. Thus, the solut1on 1s not exact.
[3°]
Thermal condupt1on of heat source 1n wh1ch pos1t1onalchanges 1n temperature are 19nored
In the case of objects such as an electr1c conductor, 1f we add
to the r1ght s1de of the fundamental equat10n (12) the quant1ty of
heat em1tted per un1t t1me and per un1t length Q
=
koI2 / F (where 0:spec1f1c res1stance, I: strength of electr1c current, and k: constant), we cbta1n:
a can be cons1dered a funct1on'of x and v; and I, a funct10n
of t. If we let axv
=
0,.PTFa1v =k aI2/F - t. "l:j" (v-va) ··· (228)
Next, cons1der that PT=g(v), a::fl(v), I2=I02, E=/sEv) , 1ntegrate (22 8 ) w1 th
respect to d1stance, and let V:
J
Fdx: volume, R: aJ
l/F • dx =ROf1 { v ) : total res1stance, S
=
J
セヲ、クZ
surface area.Then we have
Example v: The case 1n wh1ch
PT=PoTo(l+hv), R=Ro(1+R1v),
Let
Then
4.
VPorol(tut1S)=a,
VPuroh=lJ, (kRoN HoVaS)/(totlS) =C,
[kRoRII02-Eo-S{l-ElVa) ]/(totlS)= Zd,
81= d + (c + d 2)IIZ, 8z= d - (c + d2)1f2,
'r1= (a+lJ01)1(81- 8z), 'rZ=(a+ lJOz)1(81-8z).
[V], ...=V...=81
HvMXQIセiOHカBGZGXコIセQ =A"r' A"]Hv。MXQIセiOHv。MXコIエャ
•'. {HカMカBNIOHカ。MカBNI}セi{HカKカュMR、IOHカ。KカュMR、エセQ =rl
...(231)
The Solution of Fundamental Equation Applicable to Semi-infinite Body
[1°] One dimensional body: The case in which A
=
aセゥャャLP'Y
=
Arft!
02 • g2illLet v= !1J..v)dv, G(V)=gJ..v)lJz(V),Tile obtain from (1
1 ) :
G( V)8,V=ag2/y_'.8T'(r""8T'V) (3)
Now, letting!;
=
r 2 / 4 t and transforming (3), we have:fNV+[gHvIO。ァzKHQKエョGIORセ}。エv]o (31)
., V=A!セMHャKュGIORN・クーN{ -ao-2
·f
gHvI、セ スセKb (3z)If G(V)
=
I,If G(V)
=
G(!;), (32 ) can be solved. However, in general,special methods are reqUired, and (32 ) will be of little value.
Example i: The case in lilhich
{v}セ]ッ] Vo. {v}セ]cxャ]oL G(V)=l
Vo= [!JJ..V)dV
leo'
Thus, the case reduces to that of ordinary homogeneous infinite
body. However, mt must be equal to zero.
!Jz(V)dV= VoI(arrl /2)セcxャ イセO。NᄋセiOR、セL セ =r/4t...(34)
If [V]T'=O= tP(t) , used.
[2°] Two-dimensional. homogeneous 「ッ、セイZ The case in which r..
and ーセ are the same as before, and
V
。ョセ⦅gHvI are alsothe same as 「セヲッイ・
By letting or
セ] [(x-x,)2+(y-y'n/4t
セ =[,-2+,..'2-2rr'cos(O-O')]l4t
we obtain the transformed equation and solution of (3 1) and (3
2)
easily from (1 1 ) . However, m'
=
1.[3°] Three-dimensional homogeneous body_ r.. and ーセ same
as before Transform (1 1) by letting or セ =[(X-X')2+ (y-y,)2+(z+z'n/4t セ] [r+,..'2-2rr' cos(O-O')+(z-z'nl4t. or セ] {r+,..'2-2,.,..'[cosO'cosO'+sinO.sinッGN」ッウHセMセGI}スOTエN
It キゥセャ reduce to the same form as (3 1 ) and (32 ) with m'
=
2.Problem ii:
Intide the bOdy ーセ。エv = 0t(r..0xv) where r..
=
r..of
2 ( v ) , イNNOpセ=
ao
2 •
Apply (22 2 ) , the solution to the problem of finite body,
assuming initially [v]x=O
=
b, [v]xa=
O.. 2
I'"
v=[V]c=",+-Xa
..
exp.[ -(aonlr/xaft]sin[ nrr(x- xa)/xa].As xa セ
00,
let nn/x = a, or nix = da.a a
Letting {vjセZZGGGG]「GL He have the required solut ion:
where V=<b'[l-セ fooosinax-e-4 ...cdaLOOSina7}d7}]
2L'"
L'"
+ - 0(7})sina7}d7} e-lJ . · " · 'sin axda Ir 0 0 =2b'/lr1f2.f. . ⦅イセG、ケ ",{2lJ.'/c 1 roo +2rrvtJo PHWスI{・MHセMBGIGiBBGエM・MHセBBBGO」BBG}、Wス ...(36) V=J
fz(v)dv, {v}LセBL] !fz(U)du=Ax+B, Q)(x)=[VJ;;t
C ",\If f 2( v ) = 1 + A,V, the constant flow value {カ}エ]セG when
[v] -0 = b and [v] = 0, can be expressed by the following
expres-x- xa
slon. Thus, when xa セ セL
{vIャ]セ =-1/A1-+[(1/A1+W-(2/A1+b)bx/xa]I/Z
" [v):::'''''=b. !Jen,e,U=[V)l=,.,= b(l+!A1b)=b'.
When ーセ
=
Ao/a
02 • g2(V), exact solution is possible by the use ofthe
e
function.[4°] oョ・M、ゥュ・ョウゥッョ。セャ bOdy キャエNNィセ、オ。ャ change in property:
The case in which A = Aof2{v)rl+m-m'
ッセ
=
aセセ
f (v)r2- p -:2 Problem ill: where where Problem lv: Ins1de the body where
[V)r=O=V" [V)r=",,=O, Hv}ャ]セ]AーHイIN 1"'"pralv=al(Ar'" arv)
A=Ao!Z(V)rl -m- ..., pr=Ao/ao2ᄋARHカIイセMャGL m'=0,
1 and 2, m/p
=
n, further,1: A solution to the problem of finite body to be obtained by
assum1ng [V]r=r = O.
a
v=U+PilB.UkJexp.(
M。ッコーセ。ャI
J:r0yP-m-l [W(r).
Here as 1s a pos1 t1ve root of uLLHセI]オ lB.=[ra".f"-I(Za.Vra,,)]-1 == [ra"JJ"+I(Za.Vra,,)]-I •. CD(r)=
[f
J2(V) dvjZZZセイI ,'. v=v,[ l-(r/ra)"'- I(d.V?)"J,,(za.ViP) •exp.(-ao7J2a,2;"
J/[nll)(a.
v
r
,il: f"+I(Za.v'ra")]+[X] (310)
Where
01
[X]=)IIB.U,,(dexp.(-iZo7J2a/t)
f:'
イBNNNN⦅i{QーGHセ}uLLHイI、イN•
11: In the case 1n wh1ch
[V]x
=00=
0, when r a セ 00,a n iョHクセI • xa
=
O. Therefore Next ".1here 111: jBKiHセI][HzOイイセIQOR sinHセMHziiK 1)rr/4) ={zOイイセM jLLRHセIjQGR]HzOイイクセIQORNa.=a, da=rr/Z,/xa" .'. Za.+1v'ra"-Za.Vr?=;rr
., v]vLサャMセキ| f"'a"-IU,,(d·exp.(-ao7J2a2t)da}+[X] I ".f)0 ...(311) [.xl=2p
L'"
exp.HM。OIセ。セエIᄋ uLLセIuNHNMAZI。、。LOll
クーMュMMャセHクI、ク =pL'"
セHクIクBBBセMMャ・クーNH ⦅イZセセョᄋ QVセクIBB I. (zv'(rx)")d .. iZo7J2t " ao7J2t x .However, n >- MセN and it is needless to add that [X] is not influenced by changes in surrounding temperature with respect to time.
Thus, when one extends the problem from that of a finite body
to that of a semi-infinite body, n
=
m!p >- セ[ however, when theproblem is treated directly as that of a semi-infinite body,
n' > 0 in ( 3e ) •
[5°]
Relation between time and distance in temperature ina body with a gradual change in properties
m' express curvature.
Consider temperature, taking r as a parameter: 1 +n>O [V]I=O= [V]l=oo=0,
l+n<O [V]I=O=O. [V]I=oo=OO.
l+n=O [V]I=O=O' [V]l='" = finite and a function of r.
That is to say, if 1 + n > 0, the temperature is always equal
to zero at the two extremeties of time. Further, if we let
r P/a02p2 セ 0, further consideration gives:
a1v= v«(J/tr-(l+n)/t
••• [81V] 1=0 = [81VJl=oo=[a1v] 1=0'/(1+..) = 0 atv= v[ (J4/t2- 2(2+n)(J2/t+(1 +n)(2+ n)]/t2
.", [aI2V]1:0=[atV]I=OO = [812V]I: O'/[2+n!<2l-n)li'] =0
where
[a
I2V] t =O.(o ...) =-(l+nr a negati ve Quantity.Thus, when t = 0
2/(1
+ n)=
rp/ &o2
p2(1 + n), the temperatureis maximum, and since 1 + n > 0 and p セ 0, vmax• is inversely
proportional to イセーKュN
The above results show that, if p > 0, [v]t=o セ 0 except at
r
=
0; and if p > 0, [V]t=O=
0 except at r=
00. Further the10C4S of vrna x• is the curve t
=
イセpO{。PRーHQ
+ n)]; and it isNext consiner the セオ。ョエゥエケ of heat flow. The amount of heat
flowing through a unit volume per unit time is q]ーイᄋカ]QO。イャᄋセイpMRカ
i.e. ,
Examination by letting r P/a02p2
=
e
shows that, セィ・ョ I + n > 0,{qjャセo] [Q]l="" =0,
Qm..=[PPV]l=9'/Cl+,,)=セッO{ a02(An2/1l1Inc)t+"r 1+"" J
i.e., so long as
e
remains finite, Q is inversely proportional"max,
to rl+m.
If at a certain distance (point, line or surface) a fixed
quantity QO 1s added to a body, the thermal conduction becomes:
v=Qo(Aa2t)-(I+") exp.( -rPlao2p2t).
Further, the quantity of heat flowing through an infinitesimal
volume dQ
=
ーセ • v dx dy dz. Let セ=
r P/(a02 p t )and I +n > 0, and
consider the total quantity of heat: K
=
Ao[a
02(Aa 2 ) I + n ] ,Q".,=o-= QoKf_""';lr. (rPlt)I+" exp.( -rPjao2p2t)dr = 2QoKf..ao2p2)l+"JPPjZ」ッ・MGセBKiMャ、セ
= 2QoKf..ab2)1+"/p°l\l+n) ' ' . ' ' ' ' ' .(316)
That is to say, in an infinite body, p is specially defined as a positive even number or a fractional even number; however, in
a semi-infinite body, p is simply assigned a positive real value
and is one half of the value shown above. In short, since the
quantity of heat which is added to an infinite or a semi-infinite body is constant, A can be determined from the equation
QO=2QoKf..ao2p2)1+"/p. F(l+n),
Again, the values of A can be determined for a circular cylinder or a sphere from the following equations:
Q""=1=2rc'QoKfo""1'-1. (rPlt)I+" exp.( -rPjao2p2t)dr
=2rcQo(ao2p2)i+,,/pol\l+n). K , , ,(317)
In general, if n > 0, by letting R
=
JrP in (2'7) we have:v= Bfo""(za)l+n e x p.( - 。ッセセ。セエIZAョHz。rIH R··d(Za) (319)
]bHzO。ッGjーセエIiKョ exp.( - rRO。ッGjーセエI (320)
Further, it is possible to assume that
R2= (v'Y"P )2+ (v'r'P)2_Zv'(yyl)P cos(O-O').
5. Conclus,ions
1. The solution of the fundamental equation, in which thermal
conductivity and thermal capacity are assumed to be functions of
temperature, is possible only in the case of rectangular coordinates. It is possible to derive an equation analogous to the equation of
ordinary homogeneous heat flow by using
e
or V, certain functionsof temperature. V becomes a heat function only when thermal
con-ductivity is constant, and can be applied to problems of finite or
semi-infinite bodies. Exact oolution is not possible where there
is a natural surface cooling.
2. The solution of the fundamental equation in which thermal
conductivity is a function of temperature and dimension, and
thermometric cmlductivity is a function of dimension, is possible
with respect to all coordinate systems. By introducing V, a heat
function, it is possible to apply it to the solution of problems
concerning finite and semi-infinite bodies. The problems of eddy
current conduction can also be solved as an extension of the problems of finite bodies.