R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
D. T. F INKBEINER O. M. N IKODÝM
On convex sets in abstract linear spaces where no topology is assumed (Hamel bodies and linear boundedness)
Rendiconti del Seminario Matematico della Università di Padova, tome 23 (1954), p. 357-365
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SPACES WHERE NO TOPOLOGY IS ASSUMED (HAMEL
BODIES AND LINEARBOUNDEDNESS)
Nota (*)
di D. T. FINKBEINER e di O. M.NIKODÝM (Kenyon College Ohio)
1. Introduction.
This note continues the
study,
initiatedby
W. D. BERG and 0. M. NIgODYbI, of basic notionsconcerning
convex setsin
general
linear spaces. In[1.]
these authors exhibited manyparadoxical properties
of such sets in infinite dimensional spaces. Thepresent investigation
is concernedprimarily
withthe
concept
of linear boundedness in infinite dimensional spaces, and attention isgiven
to aparticularly simple
and usefultype
of
linearly
bounded convexsets,
called Hamel bodies. It is shown that two Hamel bodies can be chosen in such a way that their vector sum is the entire space. Also for any convexbody
B there exists asymmetric image
B’ of B such that the vector sum of B and B’ includes the entire line ofsymmetry
and therefore is not
linearly
bounded.°
2. Hamel Bodies.
Throughout
this paper L will denote a real linear vector space. We first recall several basic definitions most of whichwere stated
by Berg
andNikod’m,
in[1].
(1)
A set S C: L is said to be convex if andonly
if theconditions ~,
y E S
and 0 ~ ~ 1imply
X1c +( 1 ~)y
E S.(*) Pervenuta in Redazione il 19 Giugno 1954.
358
(2)
A set S is said to belinearly
bounded if andonly
if foreach line I in L set is contained in a finite
segment
of 1.(3)
A set S is said to belinearly
closed if andonly
if foreach’line I in L the is closed in the natural
topo- logy
of 1.(4)
Apoint x
is said to be alinearly
innerpoint
of a set Sif and
only
if on each linethrough x
there exists an open intervalcontaining
x andbelonging
to S.(5)
A convex set which possesses at least onelinearly
innerpoint
is called a convexbody.
(6)
A Hamel basis for L is a set H oflinearly independent
vectors with the
property
that if x E L there exist a finite sequence of vectorshi, h2,
..., hn E H(where n depends
onx)
and a sequence of real numbers
~1, À2,
...,À..
such that~ =
Xihi -y Xzh2 -i-
...+
Let H be a Hamel basis for L and let - H =
t z
The Hamel
body B (H)
determinedb y
H is defined to be theintersection of all convex sets
containing
bothH and H ;
that
is,
We shall ses that
B (H)
is alinearly closed, linearly
boundedconvex
body, symmetric
about the zero vector 0 which is alinearly
innerpoint
ofB (H).
The usefulness of Hamel bodies is indicatedby
their relation togeneral
convex bodies asgiven by
thefollowing
result.THEOREM 1. If B is a convex
body
and if S E B. thereexist a Hamel
body B (H)
and a vector y such that x E B(H) + y C B.
Proof. Let B be a convex
body,
T, EB,
and z alinearly
inner
point
of B.Then y
=( x + z)/2
is also alinearly
innerpoint
of B. Let B’ -B - y = b
y, for all b E the trans- lation of Bby
the vector - y. Then x y E B’ and z y === - B’. Since B’ is a convex
body with Q
as alinearly
innerpoint,
a Hamel basis .g for L may be formedby
and then
extending
the set( hi ) I
to a Hamelbasis
by choosing
eachha
in such a way thatha
are in 13’. Then B.
An immediate consequence of Theorem 1 is that any convex
body
B is the union of all translated Hamel bodies contained in B. Since every convexbody
contains many translated Hamelbodies,
it is natural to w onder whether eachlinearly
boundedconvex
body
is contained in asuitably
chosen translated Hamelbody.
That this is not the case follows from a result of Klee[3]
who showed that in any infinite dimensional space L there exists a
linearly bounded,
convex,ubiquitous
subset U. Thisimplies
that U C cl U L. On the other hand Theorem 3 below establishes that any Hamelbody
islinearly closed;
hence U is contained in no translated Hamel
body.
Our next theorem and its corollaries
provide simple
geo- metricdescriptions
of Hamel bodies.THEOREM 2. If H is a Hamel
basis,
then thefollowing
areequivalent:
( 1) ~ E B ( H).
(2)
there exist a finite sequence of real numbers"1’ À?,
...,Xn
and a sequence of a distinct
vectors hi E H
such thatProof.
(- H)).
From[ 1 ] ,
thereexist two
positive integers,
mand k,
vectors11’
...,fm
E H and...,
H,
andnon-negative
real numbers a1, ..., I IB1, Pk
such that E a; =1-[- Epigi.
1 1 I 1
It is
quite possible
that for some i andsome j.
Wemay suppose that
fu
...,f,
are distinct from each other and from all gi, and that gl, ..., are distinct from each other and fromall f
¡(where ~==~2013(m2013r)~:0)y
and thatand let
360
Then we have
Furthermore the vectors h. are all distinct vectors of
H,
andThis
completes
the first half of theproof.
To prove the con-n
verse, let x = E where
hi
EH,
thehi
aredistinct,
andn 1
£ À¡ c~ 1.
We may assumeX ; > 0
for i m and for1
be distinct from
hi,
..., and let Then we haveSince this is a linear combination of vectors in
H U ( H)
inwhich the coefficients are
non-negative
with sumequal
to one, x E hullTHEOREM 3.
(2) B ( H)
is alinearly
bounded andlinearly
closed con-vex
body.
Proof. From Theorem 2 it follows
immediately
that ifx E
B (H),
then x EB (H).
Theconvexity
ofB (H)
isexplicit
in the definition of a Hamel
body.
To prove thatB (H)
is abody,
we show that 0 is alinearly
innerpoint.
Let I be anarbitrary
linethrough
0. 0 and xE 1,
we havex = Eaihi ; -,
let y = ( I )
ai Theny %
0 andy E 13(9)
n Z.1
°
1
Thus the closed
segmenti ry, - y]
of I is inB (H),
and 0 is alinearly
innerpoint
ofB (H).
m
To
verify
that islinearly
bounded,and y
= E be-
two
arbitrary
but distinctpoints.
For eachpoint
z on the line determinedby s
and y there exists a real number X such that+ (1 À)y.
Define n real numbers~,~
by letting
for 1 2 m and Ii, =(I - ),)Pi
forConsider the real function p defined
by
-i- ~ ~ ~3; ~ > 0, p(X)
increases without bound as X - oo. Then forsufficiently large X, p (X)
>1,
and z ThusB (H)
islinearly
bounded.Furthermore,
p is anon-negative,
continuousfunction which assumes a minimum value M =
min (£ I cxi
Eat either = 0 or = 1. If M >
1,
then the linejoining
x andy does not intersect
B ( H).
IfM ~ 1,
theequation
determines tw o and
only
two valuesÀ1
andÀ2 (possibly e4ual)
such that p
(k,)
= p(À2)
=1,
p(X)
1 for~1 ~ À2,
andp ( ~)
> 1 otherwise. Hence in all cases the intersection ofB ( H)
with the line
joining x and y
is a closed set in the naturaltopo- logy
of the line. Since sand y are arbitrary, B (.H)
islinearly
closed.
3. The Vector Sum of Hamel Bodies.
We first recall the definition of the vector sum of two
sets, S,
and82:
It has been shown
by Berg
andNikody.m [2]
that the convexhull of two
linearly
bounded convex bodies is notnecessarily linearly
bounded. Here we obtain acorresponding
result for the vector sum of twolinearly
bounded convex bodiesby showing (in
Theorem4)
the even moresurprising
result that the vectorsum of two Hamel bodies may include the entire space.
LEMMA. If L is a linear space with a finite or denumerable Hamel basis
H,
then there exists a denumerable sequence of00
vectors such that
-~- ~~).
1
362
Proof. We first recall the well known result of
L6wig [4]
that any two Hamel bases for a
given
space have the same cardinal number. This number is often called the dimension of the space. If a Hamel basis for L consists of asingle vector h,
then
B (H)
is thesegment [h, - h], Clearly
the entire real line is contained in the denumerable union of +he translations ofby
allintegral multiples
of h. Weproceed by induction, assuming
the lemma valid for any space with a finite Hamel basis of fewer than k vectors. Let H =I h,,
...,hk I
be a Hamelbasis for
L,
and let L’ be the spacespanned by
H’‘ { ~Cl,
...,For iz E L we
+
where ~’ E L’.By
the in-duction
hypothesis
L’ is contained in a denumerable union of translations ofB(H’),
and hence L’ is contained in a denume- rable union translationsTs, i = 1, 2,
..., ofB (H). Likewise,
theline
generated by
hk is contained in a denumerable union of translations=1, 2,
..., ofB (H).
LetRij
be the translation obtainedby following Ti by Renumbering
theRij by
a dia-gonal
process, we see that theRsJ
are denumerable. Further-more L is contained in the union of all the translations
R;~
of
B (H).
Hence the lemma is valid in any space with a finite Hamel basis. But any space with adenumerably
infinite Hamel basis is the union ofdenumerably
many spaces with finite Hamelbasis,
and a denumerable union of denumerable sets of translations is denumera.ble. Hence the lemma is valid in any space with a denumerable Hamel basis.With the aid of this lemma we now show the existence of two Hamel bodies whose vector sum includes the entire space.
THEOREM 4. If L has a
denumerably
infinite Hamel basisH,
there exists a Hamel basis l~ such that
Proof. From the lemma we obtain the
representation
00
L =
(J Bi,
where each Bi is a translation of the Hamelbody
1
B (H),
and therefore eachBi
is a convexbody
in L. For eachn =
1, 2,
...,choose gi E Bi, for i n
such that the set{~ ~
"-19*1
islinearly independent.
This isclearly possible
for n =
1,
For fixed m supposethat gi
EBi
for i ~ m such thatI 91’
g2, ..., 19- 1
islinearly independent.
If for eachBlithe
setgl,
..., .g,", ,gtn+1 I
islinearly dependent,
then
Bm+i
is contained in the spacespanned by
the vectors91’ ..., g., which contradicts the fact that
Bm+1
is a convexbody
in L.By induction,
a Hamel basis G =gi t
may be chosen for L with We nextverify
thatL = B ( H)
++ B ( G).
Let x EL,
and consider the vector 2s. For some in-teger k, +
yk for some vector But gk E Bk soThus, 2~ = gk -~ (02 - b1).
But
B ( G),
the Hamelbody
determinedby
G, sogk/2 E B(G).
Likewise
b2 E B (H),
so(b2 - bi) /2
E B(H).
There-+ B (H),
whichcompletes
theproof.
COROLLARY. For every convex
body
B in a space L with adenumerable Hamel
basis,
there exists a Hamelbody B ( G)
such that
Proof.
By
theorem1,
B contains a translated Hamelbody,
so for some
y E L and
some Hamelbody B (H), B (H) C B y.
From theorem 4 a Hamel
body
exists such thatL =
B (H) +
CB y + B ( G).
Since L-~- y - ~,
we have.T3 -~- B ( (~) L.
4.
Symmetric Images
ofLinearlg
Bounded Convex Bodies.In this final section we
study
the linear boundedness of the vector sum of two verysimply
related convexbodies, namely
any convex
body
B and asymmetric image
of B. To define theterm
symmetric image,
we let M and N becdmplementary
sub-spaces of
L ;
thatis,
L - M+ (0).
It followsthat every vector of L is the sum of two
uniquely
determinedvectors, x
m+
n, where m E ill and n E N. Thesymmetric
image
~’ = m+
n relative to the orderedpair (M, N)
isdefined = m - n.
The
symmetric image
S’ of a set S relative to the orderedpair (M, N)
is definedby
S’= I x’ I x
From these defi- nitions it is clear that(S’)’
- S and(S + T)’
= S’+
T’. Alsoif S is a convex
body,
so are S’ and S-~- S’,
and if S islinearly bounded,
so is S’.We shall be
concerned
here with theparticular
case inwhich is a one dimensional space I
(a
linethrough 0)
andN is a
hyperplane
P. A set will be said to besymmetric
rela-tive to
(1-, P)
if andonly
if S - S’. The line I is called the tineof s ymnletry.
"7e shall show that for any convex
body B
in an infinite di-mensional vector space there exists a
hyperplane
P such that if then the vector sum of B and itsymmetric image B’
rela-tive to
(1, P)
contains the entire line ofsymmetry
1.In this connection w e shall make use of the
following
theo-rem
[1].
THEOREM
( Berg.Nikodym).
If B is a convexbody
in an in-finite dimensional vector space
L,
there exists ahyperplane
P such that every translation of P intersects B.
This result may be restated in the
following equivalent
form.
THEOREM 5. If B is a convex
body
in an infinite dimensional vector spaceL,
there exists ahyperplane
P such thatProof. Let
B,
L and P be as described in theBerg-Nikodym
theorem. For each x E L there exists b E B such that b E P + x.
Then there exists
p E P
such that b p-f -
~ ; since P is ahyperplane, p E P
and hence ~ p+
b E P+
B. A re-versal of this
argument
shouTs that theBerg-Nikodym
state-ment follows
directly
from theorem 5.THEOREM 6. If B is a convex
body
in an infinite dimensional vector spaceL,
if P is ahyperplane
such that L - P+ B,
if I is a line such that
t n P
=(0),
and if B’ is thesymmetric image
of B relative to(l, P),
then t C B+
B’.Proof. Theorem 5
guarantees
the existence of ahyperplane
P such that L == P
+
B. Let I be any line for which1 fl
P==(0).
For we havefor some b E B and some
p E P,
~’~b’-~p’=b’
p.Thus x
+
~’ b+
b’ E B + B’. For any yE 1, y/2 E 1,
andt/ = ~ so y = y/2 + y’/2 E B + B’.
Hence containsthe entire line of
symmetry.
In an n-dimensional space the n-dimensional
sphere
withcenter at 0 has the
following property :
for everyhyperplane
P there exists a line I such that the
sphere
issymmetric
relat-ive to the
pair (l, P).
Hence thesymmetry,
of thesphere
canbe considered as
being
«perfect >>,
and of course many bodies other thanspheres
have the sameproperty. However,
in an in-finite dimensional space, no convex,
linearly
boundedbody
with «
perfect >> symmetry
exists. Thisparadoxical
absence ofperfectly symmetric,
convex,linearly
bounded bodies is esta- blished as our final result.THEOREM 7. If B is a
linearly
bounded convexbody
in aninfinite dimensional space
L,
if P is ahyperplane
such thatL P
+ B,
and if I is any line for which P =(0),
thenB is not
symmetric
relative to thepair (1, P).
Proof. Let
B, L,
P and I be as described in thehypothesis.
If B is
symmetric
relative to(1, P),
thenby
theorem 6since B is convex. Hence 2B is not
linearly bounded,
andneither is
B, contradicting
thehypothesis.
REFERENCES
1. BERG, W. D. and
NIKODÝM,
O. M., Sur les espaces linéaires réels abstraits ou aucune topologie n’est admise. Comptes Rendus de l’Académie de Science, Paris, T. 235 (1952), pp. 1005-1007.2. BEBG, W. D. and NIKODYM, O. M., Sur les ensembles convexes dans l’espace linéaire ou aucune topologie n’est admise. Comptes Rendus, Paris, T. 235 (1952), pp. 1096-1097.
3. KLEE, V. L., Convex sets in linear spaces, III. Duke Math J., vol. 20 (1953), pp. 105-111.
4. LÖWIG, H., Über die Dimension linearer Räume. Studia Math. 5
(1934), pp. 18-23.