A NNALES DE L ’I. H. P., SECTION B
M ICHEL T ALAGRAND
Small tails for the supremum of a gaussian process
Annales de l’I. H. P., section B, tome 24, n
o2 (1988), p. 307-315
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Small tails for the supremum of
aGaussian process
Michel TALAGRAND
Equipe d’Analyse, Tour n° 46, Université Paris-VI, 4, place Jussieu, 75230 Paris Cedex 05;
The Ohio State University,
231 W. 18th, Columbus, OH 43210
Vol. 24, n° 2, 1988, p. 307-315. Probabilités et Statistiques
ABSTRACT. - Let T be a compact metric space. Let be a
Gaussian process with continuous covariance. Assume that the variance has a
unique
maximum at somepoint
t and thatXt
has a. s. boundedsample paths.
We prove thatif and
only
ifwhere
T,={teT; E(X~)-h2~.
Key words : Gaussian process on abstract sets, Borell’s inequality.
Soit T un espace compact
metrique,
et(X)teT
un processusgaussien
a convariance continue.Supposons
que(Xt)
soit p. s. borne et que 1’ecart type deXt
ait un maximumunique
en un certainpoint
t. Nousmontrons que
Classification A. M. S. : Primary 60G 15, 60G 17.
Annales de l’lnstitut Henri Poincaré - Probabilités et Statistiques - 0294-1449
Vol. 24/88/02/307/09/~ 2,90/@ Gauthier-Villars
308 M. TALAGRAND
si et seulement si
1. INTRODUCTION
Let T be a compact metric space. Let be a
(real separable)
Gaussian process with mean zero and continuous covariance. Asume that
(Xt)
has a. s. boundedsample paths,
soSup Xt
oo a. s. We want toteT
determine when the tail of the distribution of
Sup Xt
is minimal in somesense. Let 03C32
(t)
=EXt ,
and 03C3 =Sup
a(t).
If Y is standardnormal,
weteT
have for all u
We want to characterize the Gaussian processes for which the
following
occurs:
Our work is motivated
by
several recent papers([1], [2], [7])
thatgive
sufficient conditions for
(*)
inspecific
situations. These resultsrely
onconditions on the covariance
function,
andappropriate computations.
Onthe other
hand,
we willapproach
theproblem
from the abstractpoint
ofview,
and our result will be anelementary
consequence of(a
weak formof)
Borell’sinequality. (See [8]
for aprevious
use of Borell’sinequality
inthe
study
ofSup
THEOREM. - Condition
(*)
isequivalent
to thefollowing
two conditions(I)
There exists aunique
i in T such that ~(i)
= a.(II) If, for h
>0,
we setwe have
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques
Both of these conditions seem rather easy to check in
practice. (In particular
condition(II)
iscompletely
elucidatedby
thetheory
of[9].)
Asan
illustration,
we prove the result of[1]:
let o be a Gaussian process with mean zero andstationary increments,
and such thatXo=0.
Assumethat the incremental variance function
~2 (t)
is convex and thatlim
0’2 (t)/t = o.
Then condition(*)
holds on each interval[0, i]
for i > 0.t -~ 0
First
(I)
isobviously
satisfied. We now check(II).
Sincefor
t E Th,
we havea2 (t) >_ a2 (i) - 2 h2.
Sincea2
is convex, it has a left derivative at eachpoint,
so for t inTh
we have for someconstant K. Since the process has
stationary incremants,
to check(II)
it isenough
to show thatThis is done in a few lines of
computations using,
e. g., the bound of ESup I Xt by Dudley’s entropy integral (see
e. g.[6],
p.25).
2. PREPARATION
In this section we list some facts that our
proof
will use. Letcp (x) _ (2 ~) -1~2 exp ( - x2/2)
be the standard normaldensity
function. LetWe denote
by Ki, K2,
...positive
universal constants. The first two lemmas areelementary.
Proof - (1)
is wellknown,
andimplies
the crudeinequality (2). (3)
Vol. 24, nO 2-1988.
310 M. TALAGRAND
follows from the
explicit
form of cp. To prove(4),
we note that since(p (x)
decreases for x ~
0,
we havebY ( 1).
LEMMA 2. - Let
(w")" >
o be a sequence with w" > 0 and 2 wnfor
each n. ThenProof. -
This is an obvious consequence of the fact that for x >0;
The
following
is well known and goes back to[4]
and[5].
LEMMA 3. -
If P(Sup Xt ~ A) ~ 1/2,
thenKSA.
We
finally
state the version of Borell’sinequality [3]
that we need.LEMMA 4. - Let
(Y t)
be aseparable
Gaussian process. Assume thalw) ~ 1/2,
and let Thenfor
u >_ wIn
particular, for
all u3. PROOF OF THE THEOREM
Changing Xt in 0’ - 1 Xt
we can assume a =1. Thenecessity
of condition(I)
follows from thefollowing elementary observation,
whoseproof
weleave to the reader. If the
couple (Y, Z)
of random variables isjointly Gaussian,
and ifthen lim
P(Max(Y, Z)
>u)/t~r (u) = 2.
Annales de t’Institut Henri Poincaré - Probabilites et Statistiques
We now on assume
(I).
Forsimplicity
ofnotation,
we set a(t)
= E(Xt X~),
The process
(Zt)
is henceindependent
ofX,.
We haveso we have
This shows that condition
(II)
isequivalent
to thefollowing
condition( III)
limSup
h -+ 0
Proof
that(*) ~ (III).
- Let s > 0 be smallenough
that 2E2 1,
and letw ~
1 be such thatFix
u >_
w. If we conditionequation (6)
with respect toXt,
we haveWe set
T’={teT; a (t) >_ 0~,
andThis is
obviously
anincreasing
function of y.For y
> u,taking
t = i, wesee
that ~ (y) =1.
It follows from(7)
thatUsing (4),
we haveThis shows
that 11 (v) 1/2.
So we haveVol. 24, n° 2-1988.
312 M. TALAGRAND
We observe that for h >
0, a (t) >- 1- h2,
we haveIt follows that
Suppose
now that h ~s/w,
and take w. We haveand
h2u=Eh,
so(8)
becomesIt follows from lemma 3 that
E ( Sup
3E h Ks
and this concludes theproof.
Proof
that(~
andimply (*). -
Wetake ~
> 0 with r~2 - 4.
Leta > 0 be such that a -
2 - 3,
and thatFor n >_ 0,
we define thefollowing
subsets of T :We note that
Since the covariance is continuous and T is compact, condition
(I) implies
thatTake now w
large enough
thatw) ~ 1 /2.
For u >_ w, it follows from Lemma 4 thatThis
implies
thatAnnales de l’Institut Henri Poincaré - Probabilités et Statistiques
To prove
(*),
it isenough
to show that for some universal constantK,
we have
We first note that from
(9)
we haveso in
particular
Since for t in
A"
we have soIt follows from
( 10) that, for y >_ 0,
we haveSince
B~
cAn,
it follows from(12)
and(5)
thatWe set
Vol. 24, n° 2-1988.
314 M. TALAGRAND
We have
For y _ 0,
we haveso we have J
(u) _ P(Sup u).
SinceSup EZ~ l,
we seeby
lemma 4Ao t e Ao
that lim J
(u)
= o.u -. o0
From
( 13),
wehave,
sinceA o =
UBn,
Making
thechange
of variable y = u - z, andsetting
we get
Using ( 1)
and(3),
we haveso
We note now the
important
factthat,
sincea2 2 - 3, ~ 2 - 4,
Annales de I’Institut Henri Poincaré - Probabilités et Statistiques
Using (2),
we get after a shortcomputation,
that for some constantsK6, K7,
And from
( 15)
we haveSince it follows from lemma 2 that for some universal constant
K,
we haveI (u) K ~ 2 ~ (u). Together
with(14),
this proves( 11),
and concludes theproof.
REFERENCES
[1] S. M. BERMAN, An Asymptotic Formula for the Distribution of the Maximum of a
Gaussian Process with Stationary Increments, J. Applied Probability, 22, 1985, pp. 454- 460.
[2] S. M. BERMAN, The Maximum of a Gaussian Process with Nonconstant Variance, Ann.
Inst. Henri Poincaré, 21, 1985, pp. 383-391.
[3] C. BORELL, The Brunn-Minkowski Inequality in Gauss Space, Invent. Math., 30, 1975,
pp. 207-216.
[4] X. FERNIQUE, Intégrabilité des vecteurs gaussiens, C.R. Acad. Sci. Paris, 270, 1970, pp. 1698-1699.
[5] H. LANDAU and L. A. SHEPP, On the Supremum of a Gaussian Process, Sanka, 32, 1970, pp. 369-378.
[6] M. B. MARCUS and G. PISIER, Random Fourier Series with Applications to Harmonic Analysis, Ann. Math. Studies, Vol. 101, 1981, Princeton University Press, Princeton, N.J.
[7] V. I. PITERBARG and V. P. PRISJAZNJUK, Asymptotics of the Probability of Large
Encursions for a Nonstationary Gaussian Process, Theor. Probability Math. Statist., Vol. 19, 1978, pp. 131-144.
[8] M. TALAGRAND, Sur l’intégrabilité des vecteurs Gaussiens, Z. Wahrsch. verw. Gebiete, 68, 1984, pp. 1-8.
[9] M. TALAGRAND, Regularity of Gaussian Process, Acta. Math., 159, 1987, pp. 99-149.
(Manuscrit reçu le 18 mars 1987.)
Vol. 24, n° 2-1988.