A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
F RANCESCO A MOROSO
U MBERTO Z ANNIER
A relative Dobrowolski lower bound over abelian extensions
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 29, n
o3 (2000), p. 711-727
<http://www.numdam.org/item?id=ASNSP_2000_4_29_3_711_0>
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http://www.numdam.org/
A Relative Dobrowolski Lower Bound
overAbelian Extensions
FRANCESCO AMOROSO - UMBERTO ZANNIER
Abstract. Let a be a non-zero algebraic number, not a root of unity. A well-
known theorem by E. Dobrowolski provides a lower bound for the Weil height h(a) which, in simplified form, reads h(a) »
D-l-’,
where D = [Q(a) : Q].On the other hand, F. Amoroso and R. Dvomicich have recently found that if a
lies in an abelian extension of the rationals, then h (a) is bounded below by a positive number independent of D. In the present paper we combine these results
by showing that, in the above inequality, D may be taken to be the degree of a over
any abelian extension of a fixed number field. As an application, we also derive
a new lower bound for the Mahler measure of a polynomial in several variables, with integral coefficients.
Mathematics Subject Classification (2000):11 G50 (primary), I I Jxx (secondary).
1. - Introduction
Let a be a non zero
algebraic
number which is not a root ofunity. Then, by
a theorem ofKronecker,
the absolutelogarithmic
Weilheight h(a)
is > 0.More
precisely,
let K be any number fieldcontaining
a.By using
Northcott’s theorem(see [No]),
it is easy to see thath (a) ~: C(K),
whereC(K)
> 0 is aconstant
depending only
on K. In otherwords,
0 is not an accumulationpoint
for the
height
in K.In a remarkable paper, Lehmer
[Le]
asked whether there exists apositive
absolute constant
Co
such thatThis
problem
is still open, the best unconditional lower bound in this directionbeing
a theorem of Dobrowolski[Do],
whoproved:
Pervenuto alla Redazione il 11 novembre 1999 e in forma definitiva il 2 maggio 2000.
for some absolute constant
Cl
1 > 0.However,
in somespecial
cases notonly
theinequality conjectured by
Lehmer is true, but it can also besharpened.
Assumefor instance that is an abelian extension of the rational field. Then the first author and R. Dvomicich
proved
in[Am-Dv]
theinequality:
(notice
that such a result was obtainedlong
time ago as aspecial
case of amore
general result, by
Schinzel(apply [Sch], Corollary 1’,
p.386,
to the linearpolynomial P (z )
= z -a),
but with the extraassumption 1).
The aim of this paper is to
generalise
both a result of this type and Dobrowolski’sresult,
to obtain:THEOREM l.1. Let K be any number
field
and let L be any abelian extensionof K. Then for
any nonzeroalgebraic
number a which is not a rootof unity,
we havewhere D =
[L (a) : IL]
andC2 (K)
is apositive
constantdepending only
on K.This result
implies
thatheights
in abelian extensions behave somewhatspecially.
In thisrespect,
it may not be out ofplace
to recall thefollowing
result
recently
obtainedjointly by
E. Bombieri and the second author.Let K be a
number field
and consider thecompositum
Lof all
abelian extensionsof K
D. Then Northcott’s theorem(see [No])
holds in L, that is,for given
T, the numberof
elementsof L
withheight
boundedby
T isfinite.
The main
ingredients
for theproof
of Theorem 1.1(given
in Section5)
area
generalisation
of Dobrowolski’skey inequality (Section 3, Proposition 3.4),
which follows as an extension of some ideas from
[Am-Dv],
and a conse-quence of the absolute
Siegel
Lemma ofRoy-Thunder-Zhang-Philippon-David (Section 4, Proposition 4.2).
Let F E
xn ]
be an irreduciblepolynomial.
Define its Mahlermeasure as
Then it is known
(see [Bo], [Law]
and[Sm])
thatM(F)
= 1 if andonly
if Fis an extended
cyclotomic polynomial,
i.e. if andonly
iffor some and for some
cyclotomic polynomial
If n = 1 and a is a root of F, then
log M ( F )
=deg ( F ) ~ h (a ) ; hence,
if Fis not a
cyclotomic polynomial,
by
thequoted
result of Dobrowolski.Recently
the first author and S. Da- vid([Am-Da2])
extended this result in several variables. Assume that F is not an extendedcyclotomic polynomial. Then,
as aspecial
case of Corollaire 1.8 of[Am-Da2],
where
C3
is apositive
absolute constant and D =deg(F).
Using
Theorem 1.1 and adensity
result from[Am-Da2],
we can now prove(see
Section6):
COROLLARY 1.2. Let F E
Z [X 1, - - - , xn]
be an irreduciblepolynomial.
Assumethat F is not an extended
cyclotomic polynomial
and that d =degxj ( F)
> 1. Then
This estimate is stronger than the
quoted
result of[Am-Da2]
if at leastone of the
partial degrees
of F is small. We also notice that the constant inCorollary
1.2 does notdepend
on the dimension n.2. - Notation and Reductions
Throughout
this paper, we denoteby ~m (m > 3)
aprimitive
m-th root ofunity
andby
ti the set of all roots ofunity.
We also fix a number field K andwe denote
by
P the set of rationalprimes
p > 3 whichsplit completely
in K.For
p E P
we choose once and for all aprime
ideal np ofOK lying
abovep and we
identify
Jrp with thecorresponding place
of K. We normalize thecorresponding
valuation v sothat Iplv
=p
Let L be any abelian extension of K. For a
given p E P,
we define ep(L)
as the ramification index of 7rp in L. Let v be any valuation of L
extending
np . SinceL/K
isnormal,
thecompletion Lv
of L at vdepends only
on p. Since psplits completely
in K we also haveKx
=Qp.
ThenLv
is an abelian extension ofQp
and soLv
is contained in acyclotomic
extension ofQp (see
e.g.[Wa],
p.
320,
Theorem14.2),
which we denoteby
We take m =to be minimal with this
property
and we define as the maximal powerof p
dividing
m. We remark that = 1 for all butfinitely
manyp E P (if
7rp does notramify
in L, thenIL"
for someinteger m
withp f
m:see
[Wa],
p.321,
Lemma 14.4(a)).
We also defineWe note that if L’ C L are abelian extensions of K, then
e’ (IL’ ) e’(L).
From now on we let
C2(K)
be apositive
real numbersufficiently
small tojustify
thesubsequent
arguments.Let L be an abelian extension of K and let be a nonzero
algebraic
number which contradicts Theorem 1.1:
where D =
[L(a) : L].
We may assume that D is minimal with thisproperty,
i.e. that for any JL ofdegree
D’ D over an abelian extension ofK,
wehave:
Notice that t ~-+ t -
(log (2t) / log log (5t))
13 is anincreasing
function on[1, +(0)
and that the Weil
height
is invariantby multiplication by
roots ofunity.
Hen-ce
(2.1)
and(2.2) imply
that:Let A be the set of abelian extensions
L/K
such that forsome ~
E JL. We defineReplacing
if necessary aby Ça
forsome ~
and Lby
L nK(a),
we mayassume that there exists an abelian extension
L/K
contained inK(a) satisfying
the
following properties:
From now on we
fix
once andfor
all analgebraic
number a and an abelianextension
L/K
contained inK(a)
whichsatisfy (2.1), (2.2), (2.3), (2.5), (2.6), (2.7),
and
(2.8).
We also put ep =ep (L) for p E P.
The
following
lemma will be used several times in the next section.LEMMA 2. 1.
i)
For anyinteger
n we haveL (an)
=L (a).
ii) For any integern
suchthatgcd(n, [K(a):
=1 we also have =K (a).
PROOF. We shall use an
argument
from Rausch(see [Ra],
Lemma3).
As-sume first
for some n E N. The minimal
polynomial
of a over is a divisor ofan. Hence its constant term, say
f3
EIL(an),
can be written asÇar, where ~
is a n-th root ofunity.
Moreover,and P V
1L.Hence, by (2.2),
Since
rD’
D and t Hlog(2t)/ log log(5t) increases,
we deduce thatwhich contradicts
(2.1 ) .
Assume now r :=
[K(a) :
> 1 andgcd(n, r) =
1.Arguing
a:before,
we find a n-throot ~
such that EBy
B6zout’sidentity
there exist h, it E Z such that hn + J-tr = 1. Hence
This contradicts
(2.7).
03. -
Congruences
The
following
two lemmasgeneralise
Lemma 2 of[Am-Dv].
We first provea result which shall be
applied
totamely
ramifiedprimes.
LEMMA 3.1. Let
p E P.
Then thereexists 4$p
EGal(L/K)
such thatfor
anyinteger
y E Land for any
valuation vextending
7rp.PROOF.
Lest 9
be aprime
of L above 7rp and let G’ cGal(L/K) (resp.
I cGal(L/K))
be thedecomposition (resp. inertia)
groupnp.
SinceG’/I
isisomorphic
to the Galois group of the residue field extensionthere exists
4Sp
E G’ such thatfor all
integers
y E L. Let or EGal(L/K). Putting
inplace
of y in this congruence andapplying
cr we getOn the other hand
Gal(L/K)
isabelian,
and therefore the firstdisplayed
con-gruence holds modulo each
prime
of Llying
over np. Lemma 3.1 follows. D We now considerprimes having
alarge
ramification index.LEMMA 3.2. Let
p E P.
Then there exists asubgroup Hp of order
such that
for
anyinteger
y E L,for
any a EHp and for
any valuation vof L extending
n p.Moreover, forany extension t
EGal(Q/K) of a
EHpB{Id},
aP.PROOF. Let v be any valuation of IL
extending
7rp, letL v
be thecompletion
of IL at v
(we
recall thatL v depends only
onp)
and let m = be thesmallest
positive integer
such thatLv
Wedecompose m
as m = q ~ nwhere q
= is the maximal power of pdividing
m.If 7rp does not
ramify
in IL the lemma is trivial(we have ep =
1 andwe take
Hp
={Id}).
Therefore we assume that 7rp ramifies in L, whencea fortiori This
implies
that LetEp
be the Galois group of· Then
Ep
iscyclic
of order p orp -1 depending
on whetherp Iq
or not.By
theminimality
property of m we have thatE p
does not fixLv,
and hence induces
by
restriction a nontrivialsubgroup Hv
of Notethat if
p2 t q,
the order ofHU
is at least ep(since
isunramified),
while if
q, necessarily Hv
has order p.We define
Hv
to be the(isomorphic) image
ofHv
in If v’ isanother valuation of IL
extending
.7rp, we have v’ = t v for some r EGal (L/K)
and the
embedding
of IL inLv,
is obtainedby composing
r with theembedding
of IL in
Lv.
We thus see thatLv,
=Lv,
and so the groupHv
does notdepend
on v. The same argument shows that
Hvi
=Therefore,
sinceL/K
is
abelian,
we haveHv
=Hv,.
Hence this groupdepends only
on p, and wedenote it
by Hp. By
theprevious arguments
we have:Let 0 be the
ring
ofintegers
To prove that for anyinteger y E IL,
it suffices toverify
the congruencefor every y E 0 and cr E
E p .
Infact,
if this is true we have inparticular that,
for allintegers
y E IL and for all cr EHp,
theinteger cr y p
E L has order> ep
at v, whence the assertion.To prove the last
displayed
congruence, recall the well-knownequality
0 = Put then y =
f(§m),
wheref
Let a- EHp ;
since afixes we have =
Çae. Combining
these facts with Fermat’s little theorem we findas
required.
We
now prove
the last statement of the lemma. Let o- EHp,
or~
Id andlet r E
Gal(Q/K)
be any extension of a. Assume tap = UP and denoteby
Ethe subfield of L fixed
by
a. We notice that the minimalpolynomial
of aPover L has coefficients in E. Moreover
IL(aP)
=by
Lemma 2.1i).
HenceWe quote the
following
sublemma:SUBLEMMA.
PROOF. Since we have
Therefore, by (3.2),
Remark that I and I Hence
[L(a) :
divides
I
, , . ,
If we had I , then r would fix
L(a),
hencea fortiori
L. Therefore=,A and, by
Lemma 2.1ii),
We infer that
and, by (3.3), [L(a) :
= p. Since the field extension E c L isGalois, [L(a) :
divides[L : E]
which is p. Thereforeand, by
as claimed.Let now fix the
(primitive) q-th
root ofunity ~q - ~.
SinceQp(§m),
the Galois groupEp
inducesby
restriction a nontrivialsubgroup
ofwhich is
necessarily cyclic
oforder p by
the sublemma. Let F C be its fixed field and let p be a generator of Thenand
for some
primitive p-th
root ofunity ~p (recall
thatn).
We claim that there exists an
integer
u such that E We mayassume
a 0 F(aP),
otherwise our claim istrivial;
hence a fortioriMoreover, by
Galoistheory,
divides[L(~q) : F]
=p and
a) by
Lemma 2.1i).
Hencea) : F(aP)] =
pand, again by
Galoistheory,
the restrictionis a group
isomorphism. Let p
be a generator of IThen, by (3.5),
for some u E N. is left fixed
by p
and sobelongs
to asclaimed.
By (3.2)
and(3.4)
we haveSince ) and F c we also have
Therefore
which contradicts the definition
(2.4)
of e’. 0We shall deduce from the two
previous
lemmas twopropositions
whichgeneralise
thekey argument of [Do]. They
will be used toextrapolate
in theproof
of Theorem l.l. To dothis,
we need thefollowing
furtherlemma,
whichis an easy consequence of the
Strong Approximation
Theorem.LEMMA 3.3. Let IE be any
number field
and let v be a non-archimedeanplace ofE. Then, for
any Y1, ... , yn E E there existsf3
EOE
such thatf3
yj is analgebraic integer for j
=1,
... , n andPROOF. See
[Am-Da 1 ],
Lemma 3.2.PROPOSITION 3.4. Let
L and T,
be twopositive integers.
Assume that thereexists a
polynomial
Fof degree L 1 with algebraic integer coefficients, vanishing
at all the
conjugates
aI, ... ,aD of a
over L withmultiplicity > T1.
Let alsop E P
and let v be any valuation
of Q extending
7rp. Thenfor
any T EGal(O/K) extending (Dp.
PROOF. Let r E
Gal(Q/K) extend 4$p.
We extend v to the fieldQ(x)
inthe canonical way
(i.e., by setting Ixlv
=1).
Leta (x) =
ao + alx + ~ ~ ~ +aD-IxD-1
be the minimalpolynomial
of a over L.By
Lemma3.3,
thereexists
f3
EOL
such thatand . Therefore
and
= 1.Using
Fermat’s little theorem and Lemma 3.1 we find thatAgain by
Lemma3.3,
there exists analgebraic integer fJ’
EK(a)
such thatis also
integer
and =max{1,
We haveHence
Since F has
algebraic integer
coefficients andsince
=1, by
Gauss’ lemmawe have the factorisation Hence
as claimed.
PROPOSITION 3.5. Let p, v and a 1, ... , aD be as in
Proposition
3.4. LetL2
andT2
be twopositive integers.
Assume that there exists apolynomial
Fof degree L2
withalgebraic integer coefficients vanishing
ata ,
... ,aD
withmultiplicity
>
T2.
Thenfor
any . such thatPROOF. Let r E
Gal(Q/K)
be suchthat
-CIL EHp.
As in theproof
ofProposition 3.4,
we extend v to the field in the canonical way and weselect a
multiple
of the minimal
polynomial
of a over L, such thatf
EOL and
= 1. Letg (x)
= go + 91X + ... + be thepolynomial
obtainedby multiplying
theminimal
polynomial
of uP over Lby fE.
Thenagain
g EOL[x] and
= 1.Moreover,
g is irreducibleby
Lemma 2.1i). Using
Fermat’s little theorem wefind that
for j
=0, ... ,
D.Moreover, by
Lemma3.2,
Therefore
As in the
proof
ofProposition 3.4,
we deduce thatand
as claimed.
4. - The Absolute
Siegel
LemmaLet
S c On
be a vectorsubspace
of dimension d.Following
Schmidt[Schm], Chapter 1,
Section8,
we define theheight h2(S)
asIn this formula xl , ... , xn denotes any basis of V over the
ground field,
F isa number field
containing
the coordinates of the vectors xj,and ii - 11,
is thesup norm
if v is finite and the euclidean norm if v is archimedean(we
endow with the standard coordinates and the induced euclideanmetric).
Leta E
On
and let S be the one-dimensionalsubspace generated by
it.By
abuseof
notation,
weput h2(a)
=h2 (S).
The
following
resultimproves
the main result of D.Roy
and J. Thunder(see [Ro-Th],
Theorem2.2).
It is a consequence of Theorem 5.2 of[Zh]
and isproved
in[Da-Ph] (see
Lemma 4.7 and the remark which followsit).
LEMMA 4.1. For any 8 > 0 there exists a nonzero vector x E S such that
As an immediate consequence, we find:
PROPOSITION 4.2. Let
PI, ... , ~8k
be distinctalgebraic
numbers and L, Ttwo
positive integers
with L > kT. Then there exists a nonzeropolynomial
Fwith
algebraic integer coefficients, of degree
L,vanishing
atPI, ... , Pk
withmultiplicity >
T, such that:PROOF. Let us consider the vectors:
( j
=1,..., k;
A =0,...,
T -1). Using
theinequality
we
easily
obtainHence The vector
subspace
has dimension d = L - kT and the vectors yj,, are a basis of its
orthogonal complement
From[Schm], Chapter 1,
Section 8 we haveWe now
apply Proposition 4.2, taking
5. - Proof of the Main Result
In the
sequel
we denoteby
ci, c2, ... , c16positive
constantsdepending only
on theground
field K. We also denoteby
C apositive, sufficiently large
constant, chosen so that the
inequalities
below will be satisfied. We fix twoparameters:
Let A be the set of rational
primes p E P
such that (is
sufficiently
small wehave, by
the ChebotarevTheorem,
Let
A
I be the subset ofprimes p E A
such that and letA2
be itscomplement
inA,
i.e. the subset ofprimes p E A
such that ep > E. Wedistinguish
two cases.9 First Case:
We introduce two other parameters:
Using
the absoluteSiegel
lemma(Proposition 4.2)
we find a nonzeropoly-
nomial F with
algebraic integer coefficients,
ofdegree Li, vanishing
ata 1, ... , a D with
multiplicity > Ti,
such that:Using
the upper bound(2.1 )
forh(a)
we obtainif ~ 1
Suppose
that there exist aprime p E A
1 and T EGal(Q/K) extending
4$p
such that 0. Let F be a fieldcontaining.
the coefficients of F’and a.
Using
theproduct formula, Proposition
3.4 and theinequality
we obtain:
Therefore, inserting
the upper bounds(5.1)
forh2(F)
and(2.1)
forh(a),
Hence,
ifC2(K)
we have = 0 for allprimes p E A
1and for all r E
Gal(Q/K) extending (Dp
*Let
p e Ai. By
Lemma 2.1L]
= D. Hence there areexactly
Dhomomorphisms r: L(aP) - Q extending (Dp 1. Moreover,
ifand if il , i2 E
Gal(Q/K),
then-r2otq by
a lemma of Dobrowolski(see [Do]
Lemma 2i).
From these remarks we obtain:which contradicts our choice of parameters. Theorem 1.1 is
proved
in the first9 Second Case:
We introduce two new
parameters:
Let al , ... , aD be the
conjugates
of a over L. Weapply Proposition
4.2(the
absolute
Siegel lemma)
to the set ofalgebraic
numbersWe find a nonzero
polynomial
F withalgebraic integer coefficients,
ofdegree
L2, vanishing
atap, ... , otp
withmultiplicity > T2
for all p EA2,
such that:From the upper bound
(2.1 )
forh (a)
we obtain:if
Suppose
that there exist aprime
p EA2
and T EGal(Q/K)
such thatTIL E
Hp
and 0. Asbefore,
let F be a fieldcontaining
the coefficients of Ft and a.Using
theproduct formula, Proposition
3.5 and the upper bounds forh(a)
andh2(F),
we obtain:Hence, if we have
F(raP)
= 0 for allprimes ,
and for all -r E
Gal(Q/K)
such that ip EHp.
Let p E
A2
and let cr EHp. By
Lemma 2.1i), [L(aP) : L]
= D.Hence there are
exactly
Dhomomorphisms r:L(aP) - Q extending
a. Letor E and let
-r, i
EGal(Q/K)
extend cr and 8respectively. Then, by
the last
statement
of Lemma3.2,
iaP.Moreover,
ifp # q
and if ri ,t2 E
Gal(Q/K),
then-rap 4 t2aq by
thequoted
lemma of Dobrowolski([Do]
Lemma 2
i).
From these remarks and from theinequalities ep >
E and p >E
( p
EP)
we obtain:which contradicts
again
our choice ofparameters.
Theproof
of Theorem 1.1 is nowcomplete.
6. - Proof of
Corollary
1.1We may assume d = 1. Let 8 > 0.
Then, by Proposi-
tion 2.7 of
[Am-Da2], the
set ofalgebraic points (cvl , ... ,
Wn-1,a)
such thatand
F(úJ1,... , 0,
is Zariski-dense in thehypersurface V c G~
defined
by
F = 0. Since F is not an extendedcyclotomic polynomial,
V isnot a union of translates of
subgroups by
torsionpoints. Hence, by
a result ofM. Laurent
(see [Lau]), pn
n V isnot
Zariski-dense in V. Thisimplies
thatthere exist we, ... , wn-i and a E
Q B~
such thatand
Applying
Theorem 1.1 with K= Q
and we obtain:Corollary
1.1easily
follows. ElADDED IN PROOF. The main result of the
present
paper can beslightly improved
if the number of rationalprimes
ramified in the abelian extension is small. We have:THEOREM I . I . BIS . Let K be any
number field
and let L be any abelian extensionof
K. Let also a be a nonzeroalgebraic
number which is not a rootof unity
and put D =[L(a) : L].
Assume that the numberof
rationalprimes ramified
in lL isbounded
by co ( for
somepositive
constant co. Thenwhere
C2 (K, co)
is apositive
constantdepending only
on K and co.PROOF. Assume that the conclusion of Theorem 1.1 bis is false.
Then,
in Section
2,
we can choose an abelian extension L and analgebraic
numbera
satisfying (2.1), (2.2) (with
theexponent -13 replaced by -3
andC2(K) replaced by co)), (2.3), (2.5), (2.6), (2.7),
and(2.8).
We choose inSection 5,
the parameters N =C3 (log(2D))2
(log log(5D)) and E = I and we remark that the set111
I of rationalprimes p E P
such that pN and ep -
1has
cardinality a by
the Chebotarev Theorem andby
the extraassumption
of Theorem 1.1 bis. As in Section5,
we introduce two otherparameters:
The same
arguments
show that there exists a nonzeropolynomial
F with al-gebraic integer coefficients, of degree L1, vanishing
at for allprimes
p E A,
and for all T Eextending 1>;1.
As in theoriginal proof,
wededuce that
- -.T
_ "l- ... T
which contradicts our choice of
parameters.
Theorem 1.1 bis isproved.
Theorem I. I bis allows us to
improve Corollary
1.2:COROLLARY 1.2 BIS. Let F E
Z [X 1,
...,xn]
be an irreduciblepolynomial.
Assumethat F is not an extended
cyclotomic polynomial
and that d = mindegxj (F)
> 1.j=1,... ,n J
-
Then _
PROOF.
Let A
be the union of the sets ofprimitive
p-roots ofunity,
pbeing
anarbitrary prime
number. We remarkthat, by Proposition
2.7 of[Am- Da2],
the set ofalgebraic points (cv 1, ... , Wn-1, a)
such that cv 1, ... ,di, a # 0,
-~- ~ andF (cvl , ... ,
win-1,a)
=0,
is Zariski-dense in thehypersurface
V ={ F
=O} 5; G~.
Thesequel
of theproof
is the same as inSection
6,
but weapply
Theorem 1.1 bis instead of Theorem 1.1.REFERENCES
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D6partement de Mathematiques
Universite de Caen
Campus II, BP 5186 4032 Caen C6dex, France amoroso@ math.unicaen.fr
Istituto Universitario di Architettura Santa Croce, 191
30135 Venezia, Italy
zannier@brezza.iuav.unive.it