C OMPOSITIO M ATHEMATICA
A. V ARCHENKO
Critical points of the product of powers of linear functions and families of bases of singular vectors
Compositio Mathematica, tome 97, n
o3 (1995), p. 385-401
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Critical points of the product of powers of linear functions and families of
bases of singular vectors
A. VARCHENKO*
Department of Mathematics, University of North Carolina, Chapel Hill, NC 27599, USA
E-mail address: varchenko @math. unc. edu
Received 28 December 1993; accepted in final form 5 May 1994
© 1995 Kluwer Academic Publishers. Printed in the Netherlands.
Abstract. The quasiclassical asymptotics of the Knizhnik-Zamolodchikov equation with values in the tensor product of sl2 representations are considered. The first term of asymptotics is an eigenvector of
a system of commuting operators. We show that the norm of this vector with respect to the Shapovalov
form is equal to the determinant of the matrix of second derivatives of a suitable function. This formula is an analog of the Gaudin and Korepin formulae for the norm of the Bethe vectors. We show that the
eigenvectors form a basis under certain conditions.
Introduction
Consider the Lie
algebra sl2
with standardgenerators
e,f, h
such that[e, f]
=h, [h, e]
=2e, [h, f]
=-2 f .
Let Ln be the(n
+1 )-dimensional
irreduciblesl2
module. The module is
generated by
itssingular
element vn such that evn = 0 andhvn =
nvn. The elements vn,f vn,..., fnvn
form a basis of Ln. TheShapovalov
form on Ln is the bilinear form Bn such that
The tensor
product
of irreduciblerepresentations
is direct sum of irreducible repre- sentations : Ln 0 L’n = Lm -n eL’n-n+2
~ ··· eLm+n
for m n, and asingular
vector of
Lm+n-2k
has the formLet B
== Bn 0
Bm be theShapovalov
form on the tensorproduct.
* The author was supported by NSF Grant DMS-9203929.
Consider the rational function
Let t0 = (t1,
... ,tk)
be a criticalpoint
of (b such thatti ~ tj
for if= j.
THEOREM.
The formula is an
analog
of the Gaudin andKorepin
formulae for the norm of the Bethe vectors in thetheory
ofquantum integrable
models[Ga, K].
We prove the formula and itsgeneralizations.
The main results of this work are Theorem
(1.2.1), Corollary (2.4.6),
and The-orem
(2.5.1 ).
This work is
inspired by [RV]
in which connections between thequasiclassical asymptotics
of solutions of the Knizhnik-Zamolodchikovequation
and the Betheansatz vectors for the Gaudin model are
explained.
The author thanks R.
Askey,
I.Cherednik,
N.Reshetikhin,
and V. Tarasov forstimulating
and very useful discussions.1. Critical
points (1.1) Conjecture
Let
fj: Ck ~ C, j
=1,..., N,
bepairwise
differentpolynomials of degree
1. Forevery i denote
by Hi
thehyperplane
inCk
definedby fj
= 0. Let C= {Hj}Nj=1
be the
configuration
of thehyperplanes,
the
complément
to the union ofhyperplanes.
Let A ={03BBj}Nj=1
be a collection ofcomplex
numbers. Consider a function03A6039B
is a multivaluedholomorphic
function on T. Apoint t
e T is criticalfor 03A6039B
ifits first derivatives vanish at t. First derivatives vanish at t for all branches
of 4l A simultaneously,
since the ratio of every two branches is constant.Assume that the
configuration
has a vertex.CONJECTURE. For
generic
039B all criticalpoints of 03A6039B are nondegenerate and the
number
of critical points
isequal
to the absolute valueof the
Euler characteristicof T.
The
conjecture
isproved
below for the case in which allpolynomials {fj}
havereal coefficients.
REMARKS.
(a)
Anedge
of aconfiguration
is anonempty
intersection of some of itshyperplanes.
A vertex is a zero dimensionaledge.
(b)
Generic A means that there exists analgebraic
subset CeN
such that theconjecture
is trueif 039B ~ CN -
E.(c)
Thedefining equations
for criticalpoints
of03A6039B
have the form:(d) According
to[OS],
the Euler characteristic~(T)
is definedcombinatorially
in terms of the lattice of
edges
of theconfiguration:
where the sum is over all
edges of C, M(E)
is the value of the Mobius function of C at E.(e)
There are theorems on Newtonpolygons
in which one considers apolyno-
mial
system
ofequations depending
onparameters.
Under certain conditions on thesystem,
the number of solutions of thesystem
forgeneric
values ofparameters
isdefined
combinatorially
in terms of Newtonpolygons
ofequations,
see[BKK].
Itwould be
interesting
to find a connection between those theorems and the statement of theconjecture.
(f)
A multidimensionalhypergeometric integral
is anintegral
of the formwhere R: T ~ C is a rational function
and 1
C T is a suitablecycle.
If thepolyno-
mials {fj} depend
on additionalparameters,
such anintegral
becomes a functionof additional
parameters
called a multidimensionalhypergeometric function,
see[A, G, V].
Multidimensionalhypergeometric
functionssatisfy
remarkable differen- tialequations.
Forexample,
the Knizhnik-Zamolodchikovequation
in conformal fieldtheory
is solved inhypergeometric
functions[SV].
In theapplication
to the KZequation
theexponents {03BBj}
have the formt Ai
=03B1j/03BA}
where is aparameter
of the
equation. Studying asymptotics
of solutions of the KZequation
as 03BA tendsto 0 leads to
studying
criticalpoints
of the function03A6039B.
Thisproblem
motivatedthe
conjecture.
(g)
If theconfiguration
has novertices,
then there exist linear coordinates u1,..., uk inCk
such that allpolynomials {fj}
do notdepend
on ul, ... , uT forsome r and the
configuration,
cutby
C in ul = ... = ur =0,
has a vertex.(1.2)
RealConfiguration
Assume that all
polynomials {fj}
have real coefficients:and all
numbers {amj}
are real.Let
TR =
T nRk.
LetTR
=U a Da
be thedecomposition
into the union of connectedcomponents.
Eachcomponent
is a convexpolytope.
By [BBR],
the number of boundedcomponents
isgiven by
the formula(1.2.1)
THEOREM. Let allnumbers {03BBj}
bepositive.
Then the unionof all
criticalpoints of 03A6039B
is contained in the unionof
all bounded componentsof TE.
Eachbounded component contains
exactly
one criticalpoint.
All criticalpoints
arenon-degenerate.
The theorem
implies
theconjecture
for the case in which allpolynomials {fj}
are real.
Proof.
First we formulate a trivial but useful lemma.Let t be the
complex
coordinate onC,
andr, 0
thepolar
coordinates onC,
t = rexp(io).
Let v =aO/,Or
+b~/~~
be atangent
vector at apoint
t =tO
in C - 0. Denote
by Lv
In t the derivative of In talong
v.(1.2.2) LEMMA. If a
>0,
thenRe(Lv ln t)
> 0.The theorem is
implied by
thefollowing
three lemmas.(1.2.3)
LEMMA. Let D be an unboundedcomponent of TR.
Then there are nocritical
points
in D.Proof.
Let p E D.By [BBR]
there exists a vector v ER k
such that the rayp(s)
= p + sv, s ER0,
has no intersection with the union ofhyperplanes
of C.By
Lemma(1.2.2)
wehave
Hence p is not critical.
(1.2.5)
LEMMA.Let p ~ T - Rk.
Thenp is
not critical.Proof. Let p
= w + iv where w, v Ee.
The rayp(s)
= p +isv,
s ER0,
has no intersection with the union
of hyperplanes
of C.By
Lemma(1.2.2)
we haveinequality (1.2.4).
Hence p is not critical.(1.2.6)
LEMMA. Let D be a boundedcomponent of TR.
Then D containsexactly
one critical
point,
and this criticalpoint
isnon-degenerate.
Proof.
We have anequality
in D:where S =
E Aj In 1 fj 1.
Hence03A6039B
and S have the same criticalpoints
in D. Wehave
S(p)
~ -~ as p ~ c9D. So S has a criticalpoint
in D. The criticalpoint
isunique
since S is convex. The criticalpoint
isnon-degenerate
because the matrixof second derivatives of S is
positive
definite.(1.3) Example
Let
where a,
(3,
q arecomplex parameters.
We describe criticalpoints
of 03A6.The critical set of 4$ is invariant with
respect
to the group ofpermutations
ofcoordinates.
By
Theorem(1.2.1)
the number of criticalpoints
is notgreater
than!.
Let
03BB1
=tl
+ ··· +tk, A2 = 03A3titj,...,03BBk = t1 · ··· · tk
be the standardsymmetric
functions. Let pi 1 =(1 - tl)
+ ... +(1 - tk),
p2 =(1.3.1)
THEOREM.If (tl, ... , tk)
is a criticalpoint of 03A6,
thenfor
all l.Proof.
Thedefining equations
for criticalpoints
areMultiplying the
ithequation by ti/t1 · ··· · tk
andtaking
the sum of theequations we get
Similarly,
for every p =0,..., k - 1,
weget
This
system
ofequations implies
for p = 0, ... ,
k - 1. HereAo
= 1.(1.3.4)
LEMMA.System (1.3.3)
isequivalent
to thesystem:
for p = 0,..., k -
1.Lemma
(1.3.4)
isproved by
induction on p. Lemma(1.3.4)
proves Theo-rem
(1.3.1).
REMARK.
After
this work was written Prof. R.Askey
informed me that Theo-rem
(1.3.1)
could be deduced from T.J.Stieltjes’
Theorem[Sz,
Th.6.7.1] proved
more than hundred years ago: if
(t 1, ... , tk)
is a criticalpoint
of03A6,
thent 1 , ... , t k
are zeros of the Jacobi
polynomial p(a,b) (2t-1),
where a =al ,-1,
b =03B2/03B3-1.
This
Stieltjes’
Theorem was rediscovered manytimes,
inparticular, by
I.Schur,
C.L.
Siegel,
F.Calogero, ...
Set
for p
=0,...,k.
(1.3.5)
LEMMA.If (t?,..., t2)
is a criticalpoint of
thefunction 03A6(t;
a,03B2, 1’),
then
The vector
Ak = (Ak,0,..., A0,k)
has thefollowing interpretation.
Consider the Lie
algebra s12
with the standardgenerators
e,f,
h. For a e C letVa
be anS12
module withhighest weight
a, thatis,
the moduleV03B1
isgenerated by
a vector Va such that evcy = 0 and
hVa
= ava . For03B1, 03B2
~ C consider the vectorof the tensor
product Va 0 V03B2.
We havehFk
=(a
+03B2 - 2k)Fk.
COROLLARY OF LEMMA
(1.3.5).
The vectorFk(a, fi)
is asingular
vector:eFk
= 0.Explanations
of this fact see in[RV]
and in Section 2.The
Shapovalov
form onVa
is theunique symmetric
bilinear formBa
definedby
the conditions:for all x, y
~ V03B1.
Consider the bilinear form B= Ba 0 B03B2
onVa
0V03B2.
(1.3.6)
LEMMA. We haveThe
proof easily
follows from the formulaand the formula can be
proved by
induction.Denote the number
B(F(a, 03B2), F(a, (3)) by b(a, (3; k).
(1.4) Asymptotics
ofSelberg Integral
The
Selberg
formulawhere A - tt
eRk | 0 t
1 ...tk 1} (see [A, As, M, S]),
has beautifulapplications,
inparticular,
in conformal fieldtheory [DF].
Assume that a =
alr,, 03B2 = b/03BA, 03B3
=c/03BA
where a,b,
c, 03BA arepositive
numbersand 03BA tends to zero. We
compute asymptotics
of both sides of formula(1.4.1).
The method of
steepest
descentgives
thefollowing asymptotics
for the left hand side of(1.4.1):
where
t0
is the criticalpoint
of S in AThe
symmetric
functions of coordinatest01,
...,t0k
aregiven by
formula(1.3.2)
inwhich a,
03B2, 03B3
must bereplaced by
a,b,
c,respectively.
Asymptotics
of theright
hand side of(1.4.1)
can becomputed by
theStirling
formula.
Comparing
bothasymptotics
weget
thefollowing
formulae:Formula
(1.4.3)
is anexample
of the series of rathersurprising
formulae in which the determinant of a bilinear form is theproduct
of verysimple
factors[V1-3, L, LS, SV, BV].
The list of suchexamples
includes formula(1.4.1),
theLegandre equation,
the Vandermondedeterminant,
and many others.1 was informed
by
Prof. R.Askey
that Formula(1.4.2)
is due toStieltjes, Hilbert, Schur,
see[Sz,
Th.6.71 ],
the formulagives
the discriminant of the Jacobipolynomial.
Comparing
formula(1.4.3)
and Lemma(1.3.6)
weget
(1.4.4)
THEOREM. LetF( ae, 0)
EV03B1
0V03B2 be
the vectordefined
in Section(1.3),
B the
Shapovalov form
onYa
0Vp.
ThenThis theorem
implies
the theorem formulated in the introduction.2. Families of bases of
singular
vectors(2.1)
KZEquation
Consider the Lie
algebra
g =sl2
with thegenerators
e,f,
h.Let h
be the Cartansubalgebra
of ggenerated by h,
let a~ h*
be thesimple
root,( , ) the
bilinear formon h*
such that(03B1, a)
= 2.Denote
by
S2 the element h (Dh / 2 + e ~ f + f ~ e ~ g ~ g corresponding
tothe
Killing
form.Let
V1,..., Vn
be gmodules,
V =V1 ~ ··· ~ Vn.
For ij
let03A9i,j
be thelinear
operator
on Vacting
as Qon Vi 0 Vi
and as theidentity operator
on otherfactors.
The
Kni.zhnik-Zamolodchikov equation (KZ)
on anV-valued function 03A8(z1,..., zn )
is thesystem
ofequations
where 03BA is a
parameter
of theequation
andFor
039B1,
... ,039Bn ~ h*
letVI, ... , Vn
behighest weight
g modules withhighest weights AI, ... , An
andhighest weight
vectors v1,..., vn,respectively.
For a
nonnegative integer
letbe the
weight
space andthe
subspace
ofsingular
vectors ofweight
k.The KZ
equation
preserves thesubspace
ofsingular
vectors.Let
Bi
be theShapovalov
form onVi.
Denoteby B
the bilinear formB1 ~ ···
~Bn
on V. IfV1,
... ,Vn
areirreducible,
then B isnondegenerate.
It is easy to see that theoperators Hl , ... , Hn
aresymmetric:
for all i and all x, y e V.
(2.2) Intégral Representations
There is an
integral representation
for solutions of the KZequation
with values inSing(V)k [SV].
Set
A monomial of
weight
k is an element of(V)k
of the formhere
For a monomial
fI,
define a differential k-form in t and z:The sum is over the set
S(k, i1,..., in ) of maps u from {1,...,k} to {1,..., n},
such that for all m the
cardinality of cr -1 (m)
isim.
Let C = C(z1,..., zn )
be theconfiguration
ofhyperplanes
in
Ck.
LetT(z1,..., zn)
be thecomplement
to the union ofhyperplanes
of C inCk.
Assume that z1, ..., zn are
pairwise
different real numbers. LetD(z1,..., zn)
be a bounded
component
ofT(z1,
...,zn) ~ Rk continuously depending
on z.(2.2.1)
THEOREM[SV].
Thefunction
takes values in
Sing(V)k
andsatisfies
the KZequation.
REMARK. If the
integrals diverge,
then their value must be taken in the sense ofanalytic
continuation withrespect
toparameters A i , ... , An’
03BA. If ZI, - - - , Zn are notreal,
thenD(z)
must bereplaced by
ak-cycle
inT(z)
with coefficients in asuitable local
system,
see[SV, V5].
(2.3)
Basis of SolutionsFor i =
1,...,
n, letY
be the Verma module withhighest weight Ai.
This meansthat
Vi
is an infinite dimensional modulegenerated by
a vector vi such thathvi =
(Ai, a) vi
and evi = 0.Consider the set of
solutions {03A8D}
where D ranges over all bounded com-ponents
of T -Rk. According
to[SV], ITDI generate
all solutions of the KZequation
with values inSing(V)k
forgeneric 039B1,
...,An’
03BA. Below we willgive
a formula for a suitable determinant which will make the above statement more
explicit.
Assume that z, Z2 ... zn . We say that a bounded
component D(z)
ET(z) - R kis
admissible if it lies in the cone Zltl t2
...tk.
Admissiblecomponents
have the formwhere
A
monomial
called admissible.
The number of admissible
components
isequal
to the number of admissible monomials. Denote this numberby
N.Set
Consider the determinant det(D(z) 03A6·~(fI)) where D(z) ranges overall
admissiblecomponents
andfI
ranges over all admissible monomials. We willgive
a formulafor this determinant.
For any admissible domain D and for any
function g
of the formfix a branch
of g
over D. This choice determines a branchof 4l and, hence,
a branchof the determinant.
For any
such g
and for any admissibleD,
let t be apoint
of the closure ofD which is the most remote
point
from thehyperplane
ofsingularities
of g. The numberg(t)
will be called the extreme value of g on D and will be denotedby c(D, g).
For every g and
D,
the numberc(D, g)
isequal
to(zl - zm)-(039Bl,03B1)/03BA,
or(Zl _ zm)-(039Bm,03B1)/03BA,
or(Zl - zm)2/03BA,
for suitable 1 and m.For any admissible monomial
fI,
set(2.3.2)
THEOREM[V3].
We havewhere pi =
(n+k-i-3 k-i-1),
thefirst product
is over all admissible domains andover all
functions
described in(2.3.1),
the secondproduct
is over all admissiblemonomials.
The
sign ::1:
in the formuladepends
on the choice of the orientation ofdomains,
see
[V1, V2].
It is easy to see that dim
Sing(V)k
= N(2.3.4)
COROLLARY. Assume that039B1,...,039Bn, 03BA
are such that(039B1, a) ~ 0, 1,..., k - 1,
and theright-hand
sideof (2.3.3)
iswell-defined
and notequal
tozero. Then
{03A8D} form a
basisof
solutionsof
the KZequation
with values inSing(V)k,
where D ranges over admissible components.(2.4) Quasiclassical Asymptotics
Assume that
039B1,
... ,An
are suchthat -(039B1, a), 1(An, a)
arepositive.
Assumethat K is
positive
and tends to zero. We willcompute asymptotics
of the basis{03A8D},
see
Corollary (2.3.4).
For an admissible domain
D(z),
lettD(z)
be theunique
criticalpoint
of (b inD(z),
see Theorem(1.2.1 ).
Thepoint tD(z) depends
on z,039B1,..., 039Bn
and doesnot
depend
on 03BA.By
the method ofsteepest
descent we have anasymptotic expansion
where S = 03BA In &
the sum is over all monomials in
(V)k.
(2.4.2)
THEOREM[RV].
The vectorF(tD(z), z)
lies inSing(V)k. For any l
=1, ... , n,
the vectorF(tD(z), z) is
aneigenvector of
the operatorHl(z)
witheigenvalue ~S ~zl(tD(z), z).
Moreoverwhere B is the
Shapovalov form defined
in Section(2.1 ),
and const. does notdepend
on z.
REMARK. Theorem
(1.4.4)
states that const. = 1 if n = 2.(2.4.3)
THEOREM. We havethe following two formulae.
Here the
first product
is over admissibledomains,
the secondproduct
and piare
explained
in Theorem(2.3.2).
Here the rows
(columns) of
the determinant are numeratedby
admissible domains(admissible monomials).
Thefirst (second) product
is over admissible domains(admissible monomials),
andTo prove the theorem it is
enough
to write anasymptotic expansion
for therhs of
(2.3.3) by
theStirling formula,
for the lhsby
formula(2.4.1),
and then tocompare the
corresponding
terms.(2.4.6)
COROLLARY. Vectors{F(tD(z), z)} form
a basis inSing(V)k if
-(111, a), ... , -(An, a)
arepositive
and zl, ... , zn are realpairwise different
numbers.
REMARKS.
1. There are
integral
formulae for solutions of the KZequation
associated withan
arbitrary Kac-Moody algebra [SV].
Theorem(2.4.2)
holds in this moregeneral
context
[RV].
Aconjectural analog
of Theorem(2.3.3)
is formulated in[VI].
Itis
plausible
that theconjectural
determinant formula in[V1]
wouldimply
that theeigenvectors given by
the first terms ofasymptotic expansions
of solutions of the KZequation
for aKac-Moody algebra generate
a basis of thecorresponding
space ofsingular
vectors.2. It is
plausible
that there areanalogs
of formulae of Theorem(2.4.3)
for anarbitrary configuration
ofhyperplanes,
and theseanalogs
are corollaries of theconjectural
determinant formula in[Vl].
(2.5)
Norms ofEigenvectors
(2.5.1 )
THEOREM. Underassumptions of
Theorem(2.4.3)
we haveCOROLLARY. For
arbitrary 039B1,
...,An and for arbitrary nondegenerate
criticalpoint t
=t (z) of the function 03A6(t, z),
we haveProof of
the Theorem. LetWi,
i =1, 2,
beS12
modules. Let wi EWi
bea
singular
vector ofweight
mi EC,
thatis,
ewi = 0 andhw2
= mi wi . For anonnegative integer 1,
the vectoris a
singular
vector inWl
0W2 of weight
ml + m2 - 21.Let
V1,..., Yn
besl2
modules withhighest
vectors v1, ... , vn andhighest weights 039B1,..., An, respectively.
Set mi =(039Bi, a).
For any sequence of non-negative integers
I =(i2,..., in), i2
+ ···+ in
=k,
setThe vector vI is
a singular vector in
V =V10...0 Vn of weight
m1+...+mn -2k.
(2.5.3)
LEMMA. Let B =B1 ~ ···
(DBn
be theShapovalov form
on V. Thenwhere
b(cx, 03B2; i)
isdefined
in Section(1.3).
The lemma
easily
follows from Lemma(1.3.6).
For any l =
2,...,
n, set(2.5.4)
LEMMA[RV].
For every l and I -(Í2’...’ in),
the iterated vector VI isan
eigenvector of Gl
witheigenvalue
Under
assumptions
of Theorem(2.4.3)
assume that zj =sj, j
=1,...,
n, ands tends to +00.
be the admissible domain
corresponding
to this sequence. Lettl(z)
be the criticalpoint
of 03A6 inDI(z).
For any 1 =2,...,
n, introduce a functionwhere al = mi + ... + ml-1 -
2(z2
+ ... +il-1 ). Let tl
be a criticalpoint
of,Sl.
(2.5.6)
LEMMA. We havewhere
d(I)
is someinteger,
see[RV].
where
c(I)
is someinteger.
3. For any l =
2,...,
n, the operatorHl(z) = 03A3j~l03A9j,l/(zj - zi)
has thefollowing asymptotics:
Proof. Make a change
of variables : Then we havefor some number A. This formula and the
explicit
formula forF(t, z) imply
thelemma.
By
Theorem(1.4.4)
and Lemma(2.5.3)
we haveNow Theorem
(2.4.3) implies equality 2d(I)
=c(I)
and Theorem(2.5.1).
REMARK.
Using part
3 of Lemma(2.5.6)
and Lemma(2.5.4)
we can com-pute asymptotics
ofeigenvalues
of theoperators Hl(Z),..., Hn(z)
on vectors{F(tD(z), z)}
for Zl Z2 ··· zn. Thiscomputation
shows that theeigen-
values
separate
the vectors. This means that the vectors arepairwise orthogonal
with
respect
to theShapovalov
form[RV].
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