R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
L UISE -C HARLOTTE K APPE
J OHN H. Y ING
On exact power margin groups
Rendiconti del Seminario Matematico della Università di Padova, tome 87 (1992), p. 245-265
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LUISE-CHARLOTTE KAPPE - JOHN H.
YING (*)
1. Introduction.
The
investigation
of groups withspecial
conditions on their power structure is thetopic
ofthis .paper.
Research in this area started withregular
p-groups, introducedby
P. Hall in[3].
Theguiding principle
inHall’s
investigations
has been to look at groups which haveproperties
similar to abelian ones in as far as their power structure is concerned.
We will follows the same
principle by investigating
groups which havean abelian-like structure of their power
margins.
In
1940,
P. Hall in[4]
introduced themargin
ormarginal subgroup
of a word. In the
special
case of asingle
variable wordf(x)
=x n, n
aninteger,
the n-powermargin
of a group G is defined asThe n-power
margin,
as allmargins,
forms a characteristicsubgroup
ofG. The
embedding
of the n-powermargin
in a group for various values of n was thetopic
of a recent paperby
the first author[7].
We start with some observations on power
margins
of abelian groups. Let a be a torsion element of ordera ~ I
in an abelian group G.Then I = g for
all g
EG,
hence a E(G).
This leads to the fol-lowing
definition ingeneral:
DEFINITION 1.1. A torsion element a of a group G is called an ex-
act power
margin
element if a EM 1 a (G).
The set of exact power
margin
elements in a group G is denotedby
(*) Indirizzo
degli
AA.: L.-C. KAPPE: SUNY atBinghamton, Binghamton,
N.Y. 13902-6000; J. H. YING: Montrose, PA 18801.
We will show that this set can be a nontrivial proper
subgroup
ofG,
butit does not have to be a
subgroup
atall,
even in the case of finite p- groups(Example
4.2 andExample 6.3).
Observing Mn (G)
=M -n (G)
andMo (G)
=G,
we will assume fromnow on that n E
N,
where N denotes the set of natural numbers. Set-ting g
=1,
we obtain a n = 1 for a EMn (G).
Thus all elements inMn (G)
have an orderdividing
n.Denoting
withthe set of elements in G of order
dividing
n, we can reformulate this asMn (G) ç G[n]
for any group G. In an abelian group the other inclusion holds too. This leads to thefollowing
definition:DEFINITION 1.2. Let G be a group and n E N. We say G has an ex-
act n-power
margin
ifMn (G)
=G[n].
The class of exact n-powermargin
groups is denoted
by 3lln .
It can be
easily
seen that every n-abelian group, i.e. a group in which(ab)n
= a n b n for all a, b in the group, is in3lln .
An abelian group has an exact n-powermargin
for all n E N. Thus we define:DEFINITION 1.3. A group G is an exact power
margin
group if G EE
3lln
for all n E N. The class of exact powermargin
groups is denotedby 3ll.
We note
that, by
Theorem4.4,
a finite group G is an exact powermargin
group if andonly
ifEPM(G)
= G.Moreover,
a finite exactpower
margin
group isnilpotent.
Thus we can focus our attention on fi-nite p-groups when
studying
finite exact powermargin
groups.The class
3K properly
contains allregular
p-groups. Other suchproperties
have beeninvestigated by
A. Mann in[8]
and M. Y. Xu in[9].
Twospecial
classes defined in[9], namely
the class of groups with aregular
power structure and the class ofstrongly semi-p-abe-
lian groups, are of
particular interest,
becausethey
are both subclassesof
3ll.
To make our notions more
precise,
we introduce thefollowing
nota-tions. For a group G and n E N we define
Gn
=(G[n]),
thesubgroup generated by
the elements of order di-viding
n,=
G ~,
the set of n-th powers of elements inG,
G n = thesubgroup generated by
the n-th powers of ele- ments in G.For the convenience of the reader we list here the notational
equiv-
alents for a p-group G and n =
p i,
a p-power. We haveVi (G)
= andUï (G)
= as well as = andDi (G)
=Gp i .
In
[9],
Xu lists thefollowing
conditions as the mainproperties
of thepower structure of a
regular
p-group:(iii)
7ri:2
is a well-defined
bij ection
fromGIGP,
ontoG EP’3
for all z.We note that
(iii) slightly
differs from what appears in[9], namely:
(ill’)
7ri: is a well-definedbij ection
fromG jGpt
ontoGut
for all i.
Condition
(iii’)
has(i)
as an immediate consequence. Our conditions(i)
and(iii)
turn out to beindependent.
We include two more conditions into ourdiscussion,
also satisfiedby
aregular
p-group:In
[9],
Xu calls a finite p-group astrongly semi-p-abelian
group if it satisfies(iv).
On the otherhand,
a finite p-group satisfies(v)
if andonly
if it is an exact power
margin
group(Proposition 5.1).
Xu calls a finite p-group
satisfying (i), (ii)
and(iii)
a group with aregular
power structure. In[9,
Theorem1],
he states that a finite p- group G satisfies(i), (ii)
and(iii)
if andonly
if G satisfies(i)
and(iv).
Astronger
and moregeneral
version of this theorem isprovided
in Theo-rem 5.3. It turns out that
(ii)
is redundant(Theorem 5.2).
Moreprecise- ly,
we show that thefollowing equivalencies
andimplications
hold:Xu’s
definitions,
as well as theequivalencies
andimplications
of( 1.0.1 ), bring
up a naturalquestion:
what is thecomplete
classification of all the combinations of the above five basic conditions? A main result of our paper is thefollowing graph
that answers thisquestion
in thecase of finite p-groups:
Each of the
zi - 1 non-empty
subsets of the four basic conditions(i), (ii), (iv)
and(v) belongs
to a node in(1.0.2).
Thatis,
each subset isequivalent
to therepresentative
conditions of a certain node in thatgraph.
On the otherhand,
Theorem 5.5 shows that the reverse of eachimplication
in(1.0.2)
is not true. Hence thegraph
of(1.0.2)
cannot be furtherreduced,
and so itrepresents
acomplete
classification.Like
(v),
each of the other conditions has ananalogue
power condi- tion for any n E N in the class of all groups. In thefollowing
section wewill introduce some of these
general
power conditions andinvestigate
their
intrdependencies
and closureproperties. Though
of interest in their ownright,
these results will become essential tools for the above- mentionedcomplete
classification of the five conditions for finite p- groups, as discussed above.2.
Groups
with aspecial
power structure.As an
analogue
to(i)
and(ii)
for p-groups we define thefollowing general
conditions for a group G.DEFINITION 2.1. For a group G and n E N we say G is n-power closed if
(b)
G isn-exponent
closed ifGn
=G[n].
The classes of n-power closed and
n-exponent
closed groups are denot- edby
andAs an
analogue
of(iv)
we define:DEFINITION 2.2. For a group G and n E
N,
we say(a)
G issemi-n-abelian, provided
for a, b E G we have(ab -1)n
=1if and
only
if a’=b’~;
(b)
G has aregular
n-power structure if G is n-power closed and semi-n-abelian.The classes of semi-n-abelian groups and those with a
regular
n-power structure are denotedby 6n
and91n, respectively.
We observe that n-abelian groups
satisfy
all of the above conditionsand abelian groups
satisfy
them for all n. Thisprompts
thefollowing
definitions.
DEFINITION 2.3. A group G is said to be power closed if G E
~n
forall n E
N,
andexponent
closed if G e for all n E N. Therespective
classes are denoted
by B
and F.DEFINITION 2.4.
(a)
A group G is said to bestrongly
semi-abelian if G E6n
for all n e N. The class ofstrongly
semi-abelian groups is de- notedby
6.(b)
A group G is said to haveregular
power structure if G efin
for all n e N. The class of groups with
regular
power structure is denot-ed by ffl.
We now
investigate
theinterdependence
of the above conditions and theirrelationship
to exact n-powermargin
groups. We start with acharacterization of groups with an exact n-powermargin.
THEOREM 2.5. Let G be a group and n e N. Then G has an exact n-power
margin if
andonly if (ab -1 )n =1 implies for
a, bEG.
PROOF. Assume that
implies
a n = b n. Consideru e
G [n]
and b E Garbitrary. Setting
a =ub,
it follows that(ub)n
= b n for allb E G,
henceu E Mn (G),
and therefore Our claimfollows,
sinceMn (G)
CG[n]
holdsalways.
Conversely,
assumeG[n]
=Mn (G).
Thusimplies (ux)n
= x nfor all x e G.
Setting
ux = a andx = b,
we have a n = b n whenever(ab -1 )’~ =1.
The
following corollary,
stated withoutproof,
connects semi-n-abelian and exact n-power
margin
groups.COROLLARY 2.6.
Any
semi-n-abelian group has an exact n-powermargin.
The next result shows that for groups in
general
andarbitrary n E N,
theanalogue
of(iii) always implies
thecorresponding
condi-tion
(ii).
PROPOSITION 2.7. Let G be a group and n E
~T,
such thata
well-defined bijection of G/Gn
onto ThenGn
=G[n].
PROOF.
Suppose a, b E G[n].
We have to show Nowa, b E
G[n] implies
b ’~ eG[n]
cGn .
Therefore b ’~Gn
=Gn ,
and henceab-IGn
=aGn
= Thusby
ourassumption
we have = In.We conclude ab ’~ e
G[n],
and henceGn
=G[n].
The
following
theorem characterizes theproperty
semi-n-abelian.
THEOREM 2.8. For a group G and n e the
following
conditionsare
equivalent:
(a)
G issemi-n-abelian;
(b)
G has an exact n-powermargin
and awell-defined bijection of G/Mn (G)
onto(c)
7rn: awell-defined bijection of G/Gn
ontoPROOF. Assume
(a). By Corollary
2.6 it followsimmediately
thatMn (G)
=G[n].
Thistogether
with ourassumption implies
that a =- b
mod Mn (G)
if andonly
if = 1 if andonly
if a n = b n. We con-clude that is well-defined and one-one. Since maps
trivially
ontoit follows that
(a) implies (b).
Next assume
(b).
Wealways
haveMn (G)
cGn . Thus,
Ghaving
anexact n-power
margin implies Gn
cMn (G),
henceGn
=Mn (G).
There-fore trn = i.e. trn is a well-defined
bijection
ofG/Gn
onto Thus(b) implies (c).
Finally
assume(c);
trn well-defined and one-one means a = -b mod Gn (G)
if andonly
if a n = b n. Butby Proposition
2.7 we haveGn
=G[n].
Thisimplies
a = b modGn
if andonly
if = 1. We con-clude
(ab -1 )n
= 1 if andonly
if a n = Thus G issemi-n-abelian,
and(c) implies (a).
The
following corollary
is an immediate consequence of the above theorems and the definitions.COROLLARY 2.9. For the classes
ffin,
andthe following
inclusions hold:
In Section 5 we will show that the inclusions are strict. The
concluding
result of this section is a discussion of the closureproperties
of the various classes under consideration.
THEOREM 2.10. The classes
Tln
and aresubgroup
and di-rect
product closed,
but notquotient
closed. The class~3n
isquotient
and direct
product closed,
but notsubgroup
closed. The class9in
isonly
directproduct
closed.PROOF. The
proofs
of thesubgroup
and directproduct
closure of3lln
and as well as thequotient
and directproduct
closure of~n
are
straight
forward and omitted here. The p-groupG, p odd,
ofExample
6.1 issemi-p-abelian,
thus in as well as~~ .
But the groupK of
Example 6.4,
ahomomorphic image
ofG,
is not in~p ,
thus not invp
and6p
as well. Thus6n
and3lln
are notquotient-closed.
Thegroup H
ofExample
6.2 is p-power closed. Now H contains an isomor-phic
copy of the group G ofExample
6.1 as asubgroup.
But G is not p-power closed. It follows that
$n
is notsubgroup
closed.Finally,
ob-serving
thatfin
leads to the conclusion that91,,,
is directproduct
closed. To show thatfin
is neithersubgroup
closed nor quo- tientclosed,
we note that H ofExample
6.2 has aregular
power struc-ture,
but it has asubgroup
and aquotient
group not in91P.
3.
Elementary properties
of exact powermargin
elements.The first three lemmas of this section state some
general
facts about powermargins.
LEMMA 3.1. Let G be a groups and
(a) If mln,
thenM~ (G) çMn(G);
(b)
Let a EMn (G) and g
E G. Then[a,
=[a n, g] = [a, g]n
==1;
(c) Suppose (m, n)
= t. Thenfor
any and b E EMn (G)
In
particular, if (m, n)
=1,
then[Mm (G), Mn (G)]
= 1.PROOF. The
proof
of(a)
is omitted here. To prove(b),
we note thatfrom the definition of
Mn (G)
and the fact that it is a characteristic sub-group, it follows hence
[a, g n ] = 1.
The facts that
[a, g] E Mn (G)
and u n = 1 for all uE Mn (G) yield
theother two identities.
To prove
(c), let i, j
beintegers
such that t = im+ jn.
Thenb
=Because a E Mim (G),
we obtain[a,
=[a,
= 1by (b),
andsimilarly b]
= 1. Now[a, b]
EMm (G) together
with(b)
im-plies [a, b]t
=[a, [a, b}’n
= 1.Without
proof
we state thefollowing
result for finite groups.LEMMA 3.2. Let G be a
finite
group and(n, G ~ )
= t. ThenMn (G)
=Mt (G)
andG[n]
=G[t].
This lemma
suggests that,
for finite p-groups,only
those n-powermargins,
where n is a p-power, need to be considered. This will be es-tablished in
Proposition
5.1. Thefollowing
lemmaspecifies
aboundary
for such power
margins
in finite p-groups.LEMMA 3.3. Let G be a
finite
p-group, and n =p’,
anarbitrary positive
powerof
p. ThenMoreover, if
G is aregular
p-group, thenMpt (G) = Di (G).
PROOF.
Obviously, Mpi (G)
ci2i (G).
For H =~Zp _ 1 (G), g), g E G,
weobserve that
H’C- Zp - 2 (G).
Therefore H hasnilpotency dass 5 p - 1,
and hence is aregular
p-group. Consider Then(ag)P’
= for some c E(a, g)’.
But both a and cbelong
toPi (H),
which has
exponent pi
due to theregularity
of H. So Thisshows
a E Mpi (G).
HenceS~i (Zp - 1 (G))
gMp, (G).
If G itself is
regular
and a then for any g EG,
we concludeagain (ag)pt
=gp2.
This showsMp i (G) = Di (G). 0
The next two lemmas
present
a fewoperations
which serve to de-rive new exact power
margin
elements from old ones.L E MMA 3.4. For any group G we have:
(a) If a
EEPM(G)
and a EAut (G),
thena " a -1
more gener-ally a t for (t, lal)
= 1 are elements inEPM(G).
(b) If a, be EPM(G)
and(Ial,
=1,
then a. bE EPM(G)
andlabi =
(c) Suppose
a, b EEPM(G)
andlal I = pi
ipi where p
is aprime
and Thenab,
ba EEPM(G),
andI ab I ba ~ I
PROOF. We omit the
proof
of(a).
To prove(b),
let kb 1.
Be-cause a E
EPM(G), (ab)k
=b k
= 1. Hencelab I
divides k. On the otherhand,
since and(Ial, by
Lemma3.1
(c)
we have[a, b] = 1.
Thus But(a) n
= 1 and b labl
=1,
and so k divides This shows thatb ~ . Thus, by
Lemma 3.1(a),
a, b E
Mlabl (G),
and hence ab E(G).
To prove
(c),
let n =PJ
and m =~’ -1. Then, by (a)
of Lemma3.1,
a E
M~ (G)
cMn (G).
Thus both ab and ba are elements inMn (G),
andtheir orders divide n. On the other
hand, (ab)m
= 1. Henceab I
== n, thus ab E
EPM(G),
andsimilarly,
ba EEPM(G).
For finite groups we have in addition:
LEMMA 3.5. Let G be a
finite
group.(a) If n
= exp(G), and g
E GI
= n,then g
EEPM(G).
Inparticular if
G is a p-group, thenEPM(G)
contains all elementsof
maximal
order,
thusEPM(G) ~
1.(b) Z(G)
cEPM(G).
(c)
Let p be aprime. If 1 ~ g
E1 (G) I = p ; then g
EE
EPM(G).
Inparticular, if
G is a p-group,Zp -
1(G)
gEPM(G).
(d) If
G is a p-group, andN ~ I p ~
thenN c EPM(G).
PROOF. The
proofs
of(a)
and(b)
are trivial and omitted here. For(c),
we notethat,
for anarbitrary
element x inG, H
=~Zp _ 1 (G), x)
is anilpotent
group of class at most p - 1. Let P be theSylow p-subgroup of H,
and let x = u ~ v, where u E P and(Ivl p)
= 1. Because H isnilpo- tent, ( gr~P’ = vpt. Since g
EZp -
1(G)
fl P cZp _ 1 (P),
Lemma 3.3implies Consequently,
Toprove
(d),
we note that Henceby (c),
N ~c EPM(G)..
We conclude this section with an
expansion
formula for powers and commutators in metabelian groups which can be found in[5,
Lemma
1].
LEMMA 3.6. Let G be a metabelian group, n E
N,
and v, w E G.Then
4. The set of exact power
margin
elements.In this section we
investigate
the set of exact powermargin
ele-ments,
and inparticular
torsion groups in which every element is anexact power
margin
element. Our first theorem describes the behavior of exact powermargin
elements in case of a directproduct.
THEOREM 4.1.
Let A,
B be groups and G = A x B their directproduct.
Then:(a) EPM(A)
xEPM(B)
cEPM(A
xB).
(b)
There exist groupsA,
B such thatEPM(A)
xEPM(B)
is aproper subset
of EPM(A
xB).
(c)
Let A and B befinite
groupsof relatively prime
order.Then
PROOF. The
proofs
of(a)
and(c)
arestraightforward
and omitted here. To show(b),
let A = B =S3 ,
thesymmetric
group on three let- ters. It is easy to see that consistsonly
of theidentiy.
How-ever, as shown in
Example 4.2, EPM(S3
xS3 )
is nontrivial.Thus, by (a), EPM(A)
xEPM(B)
is a proper subset ofEPM(A
xB).
The
question
may be rasied on whether the set of exact power mar-gin
elementsalways
forms asubgroup.
Thefollowing example
answersthis
question
in thenegative.
EXAMPLE 4.2. Let G =
S3
xS3.
ThenEPM(G) # 1,
whereasx = 1 and
EPM(G)
is not asubgroup of
G.PROOF. Since =
1,
it follows thatConsider g
E G withg ~ I
= 6. Sinceexp (G)
=6,
Lemma 3.5(a) implies that g
EEPM(G),
thus 1. AssumeEPM(G)
is asubgroup.
Then 1 ~
g 2
EEPM(G). However, g 2
iscompletely
contained in one of thecomponents,
and thus should be an exact powermargin
elementwith
respect
to the elements in thiscomponent.
SinceEPM(S3)
=1,
this is acontradiction,
henceEPM(G)
is not asubgroup.
Even if G is a finite p-group,
EPM(G)
does not have to be a sub- group, asExample
6.3 demonstrates. In the nextexample
wegive
a fi-nite p-group, p any
prime,
in whichEPM(G)
is a propersubgroup
of in-dex p. For p
odd,
theseexamples originate
in a paperby Cody [1,
Theo-rem
2],
wherethey
occur as thegeneric
groups for the lowest values of theparameters,
in which theHp-subgroup
has index p. Note that for any group G with 1 we haveHp (G) = (g e 1),
andHp (G) =
=
1,
if Gp = 1. These groups could likewise be obtained ashomomorphic images
of the p-groups inExample
6.1.EXAMPLE 4.3. Let p be a
prise.
For p =2, define
K =D4,
the di-hedral group
of
order8,
andfor
p odd wedefine
K asfollows:
Let B =_ (b) x A,
wherelbl ] = p2
and x ... x(a P-2),
anelementary
abelian p-group
of
rank p - 2.Moreover, define
K =[B]. (c)
to be asemidirect
product of
Bby a cyclic
group(c),
whereThen
for
everyprime
p, the group K is afinite
metabelianof
order which is a proper
subgroup of
index p.PROOF. First let p = 2. It follows from
(a)
in Lemma 3.5 and the fact thatM2 (G) c Z(G)
for any group G thatEPM(D4 ) _ (c),
where(c)
is the
cyclic subgroup
of order 4 inD4.
Now
let p
be an oddprime. According
to[1]
we haveand
c(K)
= p.Moreover,
= B and K’ -(b P)
x A thus K’ cHp (K)
and K’ consists of all elements of order
dividing p
inHp (K).
We claim
EPM(K)
=Hp (K),
and thusEPM(K)
is asubgroup
of in-dex p in K. We first show that
Hp (K) c EPM(K).
Let Iflhl ] _ ~ 2,
then h EEPM(K) by (a)
in Lemma 3.5. Thus. we can assumeI h I
= p, hence h E K’by
the above. ButI
=pp -1. Thus, by
Lemma3.5 (d), K’ c EPM(K).
HenceHp (K) c EPM(K),
as claimed. Let g f/.f/.
Hp (K).
Thengb -1 f/. Hp (li~,
and hence 1 =(gb -I)p.
Thus b -pfor all such g. This
implies EPM(K) g Hp (K),
and our claim fol- lows.We conclude this section with a characterization of those torsion groups, in which every element is an exact power
margin
element.THEOREM 4.4. Let G be a torsion group. Then G =
EPM(G) if
andonly if
G is an exact powermargin
group.Moreover, if
G =EPM(G),
then G is the direct
product of
itsSylow subgroups.
Inparticular, if
Gis
finite,
then G isnilpotent.
PROOF.
Suppose
G =EPM(G).
First we show that G is the directproduct
of itsSylow subgroups.
Let x, y E G with(I x I, I y I)
= 1. Sincex E Mlxl (G)
and it followsby (c)
of Lemma 3.1 that[x, y]
= 1. Hence elements ofrelatively prime
order commute inG,
andour claim follows.
To show that G is an exact power
margin
group, we need to showG[n]
=Mn (G)
for all n E N. SinceMn (G)
cG[n]
holdsalways,
it sufficesto prove the other inclusion.
Suppose Obviously x ~ I
dividesn. Since x is an exact power
margin element,
we obtainby (a)
of Lem-ma 3.1 that
X E M I x I (G) c M,,, (G).
ThusG[n]
cMn (G).
Conversely,
if G is an exact powermargin
group, then for anyx E G,
Hencex E EPM(G).
This shows G == EPM(G).
The
following
theorem is an immediate consequence of Lemma 3.2 and Lemma 3.3:THEOREM 4.5. A
regular
p-group is an exact powermargin
group.
Thus, being
an exact powermargin
group is one of the conse-quences of
regularity.
But the class ofregular
p-groups isproperly
con-tained in the class of the exact power
margin
groups, as can be seenfrom
Example
6.1. On the otherhand, since,
for any group G and anyinteger
n, is asubgroup
ofG,
we conclude:THEOREM 4.6. An exact power
margin
group isexponent
closed.That
is,
Theorems 4.5 and 4.6
specify
boundaries for exact powermargin
groups. These boundaries will be further elaborated in the
following
sections.
5.
Comparison
of power structure conditions for finite p-groups.In this section we
give
acomplete analysis
of theinterrelationships
of the classes
9t, 6, 9N, 0152, and $
in the case of finite p-groups. For aclass X
of groups and p aprime
we denoteby 36(p)
the sublcass of finite p-groups inX. Furthermore,
denotes the class of finiteregular
p-groups. The
following proposition
is crucial for theinvestigation.
Itallows us to establish
membership
in the classes25(p), 3K(p), ~( p)
and~3( ~) by just checking
the relevant p-powers.PROPOSITION 5.1. Let G be a
finite
p-group and let 36 eE
6, 0152, ~3 ~.
Then G e £if
andonly if
G EIpi for
all i.PROOF. One of the directions in each case follows
immediately
fromthe
definitions, namely
if G EN,
thenobviously
G EIpi
for all i. Thus it suffices to establish in each case that G E£pi
for all iimplies
G EX.
Incase G E
l0lpi
for alli,
we obtain as an immediate consequence of Lemma 3.2 that G E3K.
Assume G E6pi
for all i.By
Theorem 2.5 and Definition 2.2(a)
it follows that G EPpi
for alli,
andthus, by
theabove,
G E3K.
Therefore,
it suffices to show that a n =b n implies (ab -1 )n
= 1 for a, b E E G and n E N. Let n = with(k, p)
= 1. Then there existintegers
a,f3
such that 1 = «k +
f31 G I.
Assume a n =b n,
then(a rJ.k)pt
=(b
ak)pt. By
ourassumption,
thisyields
= 1. Since ak =1 - f31 G I,
this im-plies = 1,
the desired result. In case G E~pi
for alli,
theproof
follows in a similar manner as in the
preceding
case.Finally,
we have to show that G E~~
for all iimplies
G E for alln E N.
Again
let n =kp
with(k, p)
= 1 andintegers
a,B such
that ak ++ 1.
By
ourassumption
we obtain a n ~ b n = =c P’ for
some c E G. Now c E
(c ") by
theabove,
and hence an. bn =(Cx )n,
the de-sired result.
With the
help
ofProposition
5.1 and the results of the second sec-tion,
we establish now astronger
and moregeneral
version of Xu’s re-sults, quoted
in the introduction. It also shows that Xu’s definition ofregular
power structure and our definition coincide in the case of finite p-groups. Thefollowing
theorem shows that condition(ii)
in Xu’s defi- nition is redundant.THEOREM 5.2. Let G be
a finite
p-group withgGp
-g Pi
a well-defined bijection of GIG p
i ontofor
all i. Then G isexponent
closed.
PROOF.
Proposition
2.7implies
that G E for all i.By Proposi-
tion 5.1 it follows that G E
0152,
the desired result.The above theorem and the
following
onejustify
to defineregular
power structure in terms of semi-n-abelian.
THEOREM 5.3. Let G be a
finite
Then G isstrongly
semi-abelian
if and only
is awell-defined bijection of G/Gpi
onto
PROOF.
By
Theorem2.8,
G E6pi
if andonly if gGpi--+gPi
is awell-defined
bijection
ofG/Gpi
ontoObviously
if Ge Q5,
thenG E
Cpi
for all i.Conversely, if
G E forall i,
then G E6 by Proposi-
tion 5.1.
We conclude our
investigations
with acomplete comparison
ofpower structure conditions for finite p-groups.
First,
wepresent
thefollowing:
THEOREM 5.4.
Let p
be aprime.
Thenand
PROOF. Let G be a finite
regular
p-group. If p =2,
then G isabelian,
and it is trivial to show that G EIf p
isodd,
thenHaupt-
satz
10.5(b)
and Satz10.6(a)
of[6]
show that G EBpi n Cpi
=Mp.
for alli.
Thus, Proposition
5.1yields
G E Hence(p)
c The restof the
proof
followstrivially
fromCorollary
2.9.REMARK.
By Proposition
5.1 we can claim that the set-inclusion or- der of Theorem 5.4 isequivalent
to the order ofimplications
shown in(1.0.2).
Each arrow in thisgraph
means that the conditions of thesource node
imply
the conditions of thetarget
node. There are24 - 1 non-empty
combinations for the four basic conditions(i), (ii), (iv)
and(v) specified
in Section 1. It can beeasily
seen that each combination isequivalent
to therepresentative
conditions of aparticulr
node in thegraph.
We now show that the set inclusions of Theorem 5.4 are all proper
inclusions, i.e.,
thegraph (1.0.2)
cannot be further reduced. Here strict inclusion is denotedby «c».
THEOREM 5.5.
Let p
be aprime.
ThenPROOF. That the inclusions hold is an immediate consequence of Theorem 5.4. It suffices to show here that the inclusions are
strict.
Case
1: p
> 2. In[2],
Grovesgives
aregular
p-groupH( p), p ~ 3,
such
that,
for anyregular
p-groupG,
which is notp-abelian,
the directproduct H(p)
x G is notregular. However, by
Theorem 5.4 and Theo-rem
2.10, H(p)
x G has aregular
power structure. Thus fi*(p)
cTo show that the other inclusions are
strict,
we turn to theexamples
ofSection 6. The group G in
Example
6.1 isstrongly
semi-abelian but not power closed. Hence c6(p),
n~(p)
cl%(p)
ns(p)
cc
@(p)
and~(p).
To show that c n~(p),
we use thegroup of
Example 6.6,
which is power closed and an exact power mar-gin
group, but notstrongly
semi-abelian. This same group also showsc
Next,
consider the group F ofExample
6.5. We have F E (Sbut
F o Tt.
Thus c~(~)
and ns(p)
c@(p)
n~(p). Finally,
we consider the
group K
ofExample 6.4,
which is power closed but notexponent
closed. Hence~(~)
n$(p)
c~(~)
andCase 2: p = 2. In
[9,
Theorem3],
Xugives
anexample
of a non-abelian
2-group
with aregular
power structure. This proves fi*(2)
cc
fi(2),
becauseregular 2-groups
are abelian. Now consider the group U ofExample 6.7,
which isstrongly
semi-abelian but notpower-closed.
Hence
fi(2)
c@(2), 8ll(2)
n~(2)
c?(2), @(2)
n~(2)
c@(2)
andG(2) ~(2).
Now we consider the
quaternion
groupQ
of order 8.Obviously, Q
ispower closed and not
strongly
semi-abelian.Moreover, by (a)
and(b)
ofLemma
3.5, Q
is an exact powermargin
group.Hence, fi(2)
cik(2)
nn $(2)
and15(2)
cIDl(2).
Next we consider the group V of
Example 6.8,
which is shown to beexponent closed,
powerclosed,
but not an exact powermargin
group.Thus c
@(2)
and?(2)
n~(2)
c@(2)
n~(2).
Finally,
to show thate(2)
n~(2)
c~(2),
we observe that the dihe- dral group D of order 8 is power closed but notexponent
closed. Thus it also shows that~(2) ~ @(2). a
6.
Examples.
This section is
comprised
of twoparts,
the firstassuming
an oddprime
p. The group exhibited in the firstexample
of thispart
can beconsidered
generic,
since all the groupspresented
in the other exam-ples
of thispart
are eitherhomomorphic images,
or in one case an ex-tension of the group at hand.
semidirect
product of
Xby
acyclic
group(b),
whereI b I
=p Z
andThen G is a
strongly
semi-abelian groupof
order andnilpotency
class p and which is not power closed. Hence G has not a
regular
powerstructure,
inparticular
G is notregular.
PROOF. We note that the
mapping
inducedby
b on X is an auto-morphism
of order p onX,
hence bP EZ(G).
Infact,
It is also easy to see that G’ = x ... x with
exp (G ’ )
= p, andc(G) = p
as well asIGI [ = p ~ + 3
.We first show that G E
3K. By Proposition
5.1 and the fact that it suffices to showG[p]
=Mp (G).
For anarbitrary
ele-ment u in G the class of
(G B u)
is at most p - 1. Hence(G ’ , u)
is regu-lar,
and soby
Theorem 4.5 it is an exact powermargin
group. This shows that G ’ cEPM(G).
For anarbitrary element g
inG,
there existintegers i, j
and y E G’ suchthat g
=Xi b - j y. By
the above we obtainSince G is
metabelian,
we mayapply (3.6.1).
Thisyields
Observing exp (G ’ )
= p andusing
the relations ofG,
we obtainNow
consider g E G[p]BG’.
Then(6.1.2) implies i = j
=0 mod p,
thusE
Z(G). So,
for any element w EG,
thistogether
with the fact thatG ’ c EPM(G) yields
Hence g
EEPM(G).
It follows that G E3K.
Next we show that G is
strongly
semi-abelian.By Proposition
5.1and the fact that
exp (G)
=p 2,
it suffices to show that G E6p. Using
Theorem
2.5,
Definition 2.4(a)
and the fact that G is an exact powermargin
group, it suffices to show thatg p
= h pimplies
= 1 forg, h E
G. There existintegers i, j,
and u, v E G’ suchthat g
=for some w E G’ . This
implies
~ (b~ -’~ ~’
= 1. It follows that G E6.
Finally
we show thatG lPl
is not asubgroup
ofG,
hence~3.
As-sume to the
contrary,
and considerBy (6.1.2)
we obtain= -P. This
implies
yp - 1 =gP
for some g =Xi bj U, U
EeGB
Again, by (6.1.2),
it followsThis together
E G’.
Again, by (6.1.2),
1 followsyp -
1 xPbiP - Yp -
1 18 oge erwith
(6.1.1 ) yields i = j = 0 mod p.
Thus a contradiction.Since 9t
= 6 ns,
it follows now that G does not have aregular
powerstructure, and,
inparticular,
G isirregular.
To show that
being
power closed is not inherited tosubgroups,
weuse an extension of the group in the
preceding example.
EXAMPLE 6.2. Let H = G ~
(z),
where G is the groupof Example
6.1with
[ g, z]
= 1for all g
E G and z P = yp _ 1. Then H is power closed but thesubgroup G c
H is not.Moreover,
H has aregular
power structure.But it contains a
subgroup
and aquotient
group which do not have aregular
power structure.PROOF. It was shown in
Example
6.1 that G is not p-power closed.In view of
Proposition
5.1 and the fact that it suffices to show that =T,
where T = cZ(H).
For h E H we have where and k aninteger.
Thus Now g ==
Xi b -j u
for some u E G’ andi, j integers. By (6.1.2)
it follows h p = HP c T.Conversely,
let t = with
integers
a,/3,
y be anarbitrary
element in T. If{3
= 0modp,
then t =If (3$Omodp,
then leth = x " b -~ z r - ".
It follows thatz ~°~Y - ") = t.
Therefore henceHEPI
=HP,
and we conclude that H is power closed.Next we prove that H E
6. Again,
it suffices to prove that for allg, h E H gp = hp if and only (gh-1)p = 1. Let g = xi · bj · u · zk and h =
= v’
z t,
where u, v E G’ andi, j, k,
r,s, t
areintegers.
Theng p
==
for some
If
gP=hP,
then i= r mod p, j = s mod p,
and k =t mod p.
Hencex x
(yp -1 ) _ ~1 (Z(G)),
and thereforeOn the other
hand,
if( gh -1 ~" = 1,
then1 mod G ’ . Hence and so 1
= ( gh -1 ~’ _ - z ~k - t)p.
t. In otherwords,
i= r mod p, j == s modp
and k =- So