SOME EXAMPLES OF 1-CONVEX NON-EMBEDDABLE THREEFOLDS
GIOVANNI BASSANELLI and MARCO LEONI
We construct a family of 1-convex threefolds with exceptional curveC of type (0,−2), which are not embeddable in Cm×CPn. In order to show that they are not K¨ahler, we exhibit a real 3-dimensional chain A whose boundary is the complex curveC.
AMS 2000 Subject Classification: Primary 32F10.
Key words: embeddable variety, exceptional curve, threefold.
1. INTRODUCTION
In general, a 1-convex manifold with 1-dimensional exceptional set is embeddable, that is, it can be realized as an embedded subvariety ofCm×CPn, for suitablem and n. The only possible exceptions are given by the following result.
Theorem 1.1 (see Theorem 3 in [C1]). Let X be a non-embeddable, 1- convex manifold whose exceptional setC has dimension 1. Then dimCX= 3 andC has an irreducible component which is a rational curve of type(−1,−1), (0,−2) or (1,−3).
As regards the existence of the quoted exceptions, in [C1] there is an example of type (−1,−1). In [V1], p. 242 B there is an example of type (0,−2), but the argument is dubious (see [C1], Remark 4, but see also [V2]
and [C2]). For the case (1,−3) nothing is known.
Indeed, the first two cases are easier and we shall show
Theorem 1.2. For every integer k ≥ 1 there is a non-embeddable 1- convex threefoldX˜k having as exceptional set a smooth rational curveCwhose sequence of normal bundles is
(0,−2), . . . ,(0,−2)
k−1
,(−1,−1).
In particular,NC|X˜
1 =O(−1)⊕ O(−1) andNC|X˜
k =O(0)⊕ O(−2) fork≥2.
REV. ROUMAINE MATH. PURES APPL.,52(2007),6, 611–617
For k = 1 we retrieve Colt¸oiu’s example. We point out that our con- struction is explicit and elementary. In order to see that ˜Xk is not K¨ahler, we shall exhibit a real 3-chainA whose boundary is the exceptional curveC.
2. THE PROOF OF THEOREM 1.2 Definition 2.1. Letk≥1 be an integer. The equations (2.1)
w= 1z
y1 =z2x1+zxk2 y2 =x2
in the coordinates (z, x1, x2) and (w, y1, y2), define a fiber bundleWk onCP1, with fiberC2.
The following results holds.
Proposition 2.2 (see [L], p. 263 and [P], p. 234). The null section of Wk is an exceptional rational curve C of type (−1,−1) for k= 1, or (0,−2) for k≥2.
There is a geometrical description of these threefolds.
Proposition2.3. Letk≥1be an integer. LetNk−→fk C4be the blow-up with center at the complex smooth surface
(2.2) Sk:={z∈C4;z1−iz2 =z3−z4k= 0}. ThenWk is the strict transform of the hypersurface (2.3) Yk:={z∈C4;z12+z22+z32−z42k = 0},
which is singular only at the origin Pk = 0; the null section of Wk is Ck = fk−1(Pk).
Proof. It is enough to follow the outline of [P], Example 2.14.
Now, we shall investigate in more detail this geometric construction and build a suitable commutative diagram
(2.4)
N0 −→h1 N1 −→ · · ·h2 h−→k−1 Nk−1 −→hk Nk
f0 f1 fk−1
fk
M0 −→g1 M1 −→ · · ·g2 g−→k−1 Mk−1 −→gk Mk=C4.
Step 1. Applying the desingularization process to the hypersurface Yk ⊂ C4 :=Mk we get the sequence
M0−→g1 M1 −→ · · ·g2 g−→k−1 Mk−1 gk
−→Mk=C4.
More precisely, this sequence is defined by induction: Mk−1−→gk Mk=C4 is the blow-up atPk:= 0. Then we define the chart (Uk−1;u1, . . . , u4) ofMk−1 by requiring that in these coordinates the mapgk has the equations
(2.5)
zj =uju4, forj = 1,2,3 z4 =u4.
LetYk−1 ⊂Mk−1 be the strict transform ofYk: we get that the only singular point ofYk−1 isPk−1:= 0∈Uk−1 and
(2.6) Yk−1∩Uk−1 ={u21+u22+u23−u2(4k−1) = 0}.
Comparing (2.6) with (2.3), we notice that we can iterate the process: the map Mj−1 −→gj Mj is the blow-up at Pj and Yj−1 is the strict transform of Yj. Finally, sinceY0∩U0={u21+u22+u23−1 = 0}, Y0 is smooth, so that the process ends.
Next, we need the following result, which is probably well known. Never- theless, for lack of reference, we shall give the proof.
Proposition 2.4. Let M be a complex manifold. Assume that S is a complex submanifold ofM andP is a complex submanifold ofS. The diagram
N −→h N
f f M −→g M
is commutative. Here,g is the blow-up with center P, S the strict transform of S in M, f (resp. f) the blow-up with center S (resp. S), h the blow-up with centerf−1(P).
Proof. The problem is local, therefore we may assume P = Cl× {0} ⊂ S=Cl+m× {0} ⊂M =Cl+m+n. Moreover, it is enough to consider the case l= 0, thus P is a point of S, which is ak-plane of M =Cn. Now, it sufficies to prove the following
Claim. Proposition2.4holds ifP is a point of ak-planeS ofM =CPn. Proof of the claim. Assume 2 ≤ k ≤n−2, otherwise the statement is obvious. Fix a (n−k−1)-plane L of CPn such that L∩S = ∅. Thus, L parametrizes the family{Rx}x∈Lof all (k+ 1)-planes containing S.
LetRx⊂N be the strict transform ofRx underg◦f. ThenN is the disjoint union∪x∈LRx and an holomorphic projectionτ :N →Lis naturally defined.
LetEg ⊂N be the strict transform of the exceptional set Eg CPn−1
of M →g M =CPn. The mapτ induces a projection Eg −→τ L whose fibers Rx ∩Eg are biholomorphic to CPk. Moreover, for each line r of Rx ∩Eg,
we get r.NEg = −1. It follows that N can be contracted to a manifold Q which contains L and this contraction N −→α Q is the blow-up of center L.
Moreover,α and τ agree on Eg.
LetEf ⊂N be the exceptional set of N −→f M. Thus τ⊗f :Ef → L×S is a biholomorphism (since each fiber ofEf τ
−→L intersects each fiber of Ef f
−→ S in only one point). But (τ ⊗f)(Eg ∩Ef) = L× E, where E CPk−1 is the exceptional set of S −→g S. Therefore, the mapα acts on Ef as the projectionL×S→L×S. Thus,E :=α(Ef)L×S is a complex manifold.
As before, for every q ∈ S and every line s of L× {q} ⊂ E we have s.QE = −1. Therefore, Q can be contracted to a manifold T which contains S and this contraction is the blow-up Q→T. But now T and M =CPn are bimeromorphic and biholomorphic outside ofS, therefore they are biholomor- phic.
Now, recalling Proposition 2.3, we complete our construction.
Step 2. Define Sj−1 as the strict transform of Sj by means of the map Mj−1 −→gj Mj, 1 ≤ j ≤ k. Let Nj −→fj Mj be the blow-up of center Sj, 0≤j ≤k−1. Moreover, let Cj :=fj−1(Pj) and Nj−1 hj
−→ Nj be the blow-up of center Cj, 1≤j≤k. Then diagram (2.4) is commutative.
Proof. By Proposition 2.4, it is enough to check thatPj ∈Sj,j= 0, . . . , k.
But, as noted above,Pj = 0∈Uj and, using the chartUj, it is straighforward to check that
(2.7) Sj∩Uj ={u1−iu2=u3−uj4}.
Corollary 2.5. Let Xj be the strict transform of Yj under the map Nj −→fj Mj, 0 ≤ j ≤ k. Considering restrictions of maps, from (2.4) we get the commutative diagram
(2.8)
X0 −→h1 X1 −→h2 . . . h−→k−1 Xk−1 −→hk Xk=Wk
↓f0 ↓f1 ↓fk−1 ↓fk
Y0 −→g1 Y1 −→g2 . . . g−→k−1 Yk−1 −→gk Yk. Moreover,
(i) Xj is smooth, the rational curve Cj (which is the center of hj) is contained in Xj and there is a neighbourhood ofCj in Xj biholomorphic to a neighbourhood of the null section ofWj, 1≤j≤k;
(ii)Cj+1=hj+1(Cj), j≥1;
(iii) X0−→f0 Y0 is a biholomorphism;
(iv)the exceptional divisor E0 of h1 is biholomorphic toCP1×CP1 and the induced map E0 CP1 ×CP1 −→h1 C1 CP1 is one of the canonical projections.
Proof. Diagram (2.8) is well defined, because diagram (2.4) is commu- tative. Comparing equations (2.3) and (2.6), (2.2) and (2.7), we can ap- ply Proposition 2.3 for j = 1, . . . , k. Thus, we get that Wk = Xk, Wj = Xj ∩fj−1(Uj) and Cj is its null section, for 1 ≤ j ≤ k−1. By Proposition 2.2, NC1|X1 = (−1,−1), while NCj|Xj = (0,−2) for j ≥ 2. Thus, the excep- tional divisorEj−1 ofhj is a rational ruled surface: E0=F0 (this proves (iv)) and Ej = F2 for j ≥ 1. Now, the curve Cj is not a fiber of F2, otherwise NCj|Xj = (0,−1), thus Cj is a section of Ej F2. This shows (ii). Finally, sinceS0 and Y0 are smooth, X0 −→f0 Y0 is a biholomorphism.
Remark 2.6. In the rational ruled surface F2, there is only one curveC with negative self-intersection: C.F2C =−2. Since Cj is not a fiber ofEj, it follows easily from the exact sequence
0→ O(Cj.EjCj)→NCj|Xj → O(Cj.XjEj)→0
thatCj is the curve ofEj with negative self-intersection. This means that the sequenceX0 → · · · →Xk is the sequence of the blow-ups associated with the curveCk.
Let us now state the following elementary result.
Lemma2.7. Let Q:={z∈CP3;z02+z12+z22−z23 = 0}. Every line ofQ has a real point.
Proof. Let r ⊂ Q be a line and let P ∈ r. If P is not a real point, consider the linespassing throughP andP. Now,sis a real line ands∩RP3 is external to the real sphereQ ∩RP3, therefore there are exactly two planes passing throughs and tangent to Q, and the tangent points are real. One of these planes must be the planeα defined by the lines r and s(in fact, α∩ Q contains r and is thus a degenerate conic), therefore it is tangent to Q at a real pointQ, which must belong to r.
By the detailed description of the map Xk −→fk Yk given in (2.8), the following statement is a simple consequence.
Corollary 2.8. Let B := {z ∈ Yk ∩R4;z4 > 0} and A := fk−1(B).
ThenA is a real threefold with boundary ∂A=Ck.
Proof. LetD:= (gk◦ · · · ◦g1)−1(B). Since diagram (2.8) is commutative and hj is surjective, for every j, A = hk◦ · · · ◦h1(f0−1(D)). It follows from
(2.5) thatgk−1(B) ⊂ Uk−1, and iterating this argument we get that D ⊂U0, more precisely,
D={x∈R4;x21+x22+x23−1 = 0, x4>0}.
Therefore, the boundary∂D={x∈R4;x21+x22+x23−1 =x4 = 0}is contained in{z ∈C4;z21+z22 +z23 −1 = z4 = 0} =E0∩U0. By Corollary 2.5(iv), the fibers of the mapE0 f0−1(E0) −→h1 C1 are one of the two familyies of lines on the quadricE0. By Lemma 2.7, each of these lines intersect∂D, therefore h1(f0−1(∂D)) =C1. Thus, by Corollary 2.5(ii), we have ∂A=Ck.
In order to obtain our example ˜Xk, we must perturb Yk outside the origin.
Lemma 2.9. For every fixed integer k ≥1 there exist an integer N > k and0< ε≤1such that the origin is the only singular point of the hypersurface (2.9) Y˜k:={z21+z22+z23−z42k+ε(z12N +z22N +z32N +z24N) = 0}.
The equationswj :=zj(1+εzj2N)1/2, 1≤j≤3 andw4 =z4(1−εz24N)1/2k define a biholomorphic map V −→Φ V˜ between two neighbourhoods of the origin of C4. Thus, we can define ˜Xk gluing fk−1(V)∩Xk and ˜Yk\ {0} by means of Φ. The maps ˜Xj−1 →X˜j and ˜Yj−1 →Y˜j are defined as above since nothing is changed nearPj and Cj while the maps ˜Xj →Y˜j are defined by a gluing process (these maps are not blow-ups).
Proposition 2.10. X˜k is not embeddable.
Proof. Let ˜B := R4 ∩Y˜k ∩ {x4 > 0}. It follows from (2.9) that ˜B is relatively compact and from the definition of Φ that ˜B∩V˜ = Φ−1(B ∩V).
Thus, the preimage ˜A of ˜B is again a 3-chain with boundary Ck. Hence the exceptional curveCk=∂A˜ is a boundary in ˜Xk, which is not K¨ahler.
Acknowledgement.Research partially supported by the GNSAGA of the INdAM.
REFERENCES
[C1] M. Colt¸oiu,On 1-convex manifolds with 1-dimensional exceptional set. Collection of Papers in Memory of Martin Jurchescu: Rev. Roumaine Math. Pures Appl.43(1998), 1–2, 97–104.
[C2] M. Colt¸oiu, Some remarks about 1-convex manifolds on which all holomorphic line bundles are trivial.Bull. Sci. Math.130(2006),4, 337–340.
[L] H.B. Laufer,OnCP1 as an exceptional set.In: Recent Developments in Several Com- plex Variables (Proc. Conf., Princeton, NJ 1979), pp. 261–275. Ann. of Math. Stud.
100, Princeton Univ. Press, Princeton, NJ 1981.
[P] Th. Peternell,Pseudoconvexity, the Levi problem and vanishing theorems. Encyclopedia Math. Sci.74,Several Complex Variables,VII, pp. 221–257. Springer, Berlin, 1994.
[V1] Vo Van Tan, On certain non–K¨ahlerian strongly pseudoconvex manifolds. J. Geom.
Anal.4(1994),2, 233–245.
[V2] Vo Van Tan,On the quasi-projectivity of compactifiable strongly pseudoconvex mani- folds.Bull. Sci. Math.129(2005) 501–522.
Received 17 September 2006 Dipartimento di Matematica Universit`a degli Studi di Parma
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