C OMPOSITIO M ATHEMATICA
C HARLES A SMUTH C. D AVID K EYS
Supercuspidal representations of GSp
4over a local field of residual characteristic 2, part I
Compositio Mathematica, tome 79, n
o1 (1991), p. 109-122
<http://www.numdam.org/item?id=CM_1991__79_1_109_0>
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Supercuspidal representations of GSp4
over alocal field of
residual characteristic 2, part I
CHARLES
ASMUTH1
and C. DAVIDKEYS2
1 David Sarnoff Research Center, Princeton, New Jersey 08540;
2Department
of Mathematics andComputer Science, Rutgers University, Newark, New Jersey 07102
Received 7 December 1987; accepted 25 October 1990 (Q
1. Introduction
In this paper, and in one to
follow,
weanalyze supercuspidal representations
ofG =
GSp4(F)
where F is a local field of residual characteristic p = 2. We firstclassify
theserepresentations according
to characters which occur in their restrictions to certain opencompact subgroups.
As in the case ofGln(F),
thesecharacters may be
parametrized by
4 x 4 matrices over F.Accordingly,
we mayclassify
certainsupercuspidal representations
asoccurring
in the"nilpotent"
case. Theorem 3.9 states that these
representations
are allirreducibly
inducedfrom some open
compact-by-center subgroup
of G. Theremaining
cases will betreated in the
sequel.
The methods used are
suggested by
the constructiontechniques
forGln(F) developed by
Howe([H])
and exhaustiontechniques developed by
Kutzko andManderscheid
([K]
and[KM]).
These ideas work well when nowildly
ramifiedextensions of F are imbedded in the group in
question. Moy ([M])
has usedtechniques involving
Heckealgebra isomorphisms
toclassify supercuspidal representations
ofGSp4(F)
in the case of oddprimes
p.When wild ramification is
present (so p
=2),
these methods stillprovide
astarting point.
Arepresentation (n, V)
will fix a non-trivialsubspace V(L)
whenrestricted to a small
enough
opensubgroup
L. We willgenerally
take L to be amember of some normal filtration of a maximal
compact-by-center subgroup
ofG. We then consider certain groups A for which the
quotient A/L
is abelian. Weclassify
03C0by
charactersoccurring
in the restriction(niA, V(L)).
The occurrence of certain characters(cuspidal) immediately
forces n to beirreducibly
induced.Some characters are shown to be
(G, A)-principal
as defined in[K].
Some caseslead us to find an open
subgroup L’, larger
thanL, having
a fixed vector. Theremaining
cases areanalogous
to the alfalfa cases of[KM].
For these we mustuse the constructions in
[H]
todistinguish
betweenrepresentations
which areirreducibly
induced and those that containprincipal
characters.2Henry
Rutgers Research Fellow.Recall that the matrix coefficients of a
supercuspidal representation
havecompact support
mod the center of G. A(G, A)-principal representation
of asubgroup
A is one which cannot occur in the restriction to A of asupercuspidal representation
of G. Arepresentation
of an opencompact subgroup
of G may be shown to beprincipal by proving
that vectors in itsrepresentation
spacegive
rise to matrix coefficients of G whose
support
is notcompact
mod the center of G. Thefollowing
is a restatement of some of the lemmas in[K]
andgives
themethod we will use to demonstrate that certain
representations
areprincipal representations.
LEMMA 1.1. Let
(n, V)
be an admissiblerepresentation of
G. Let vo E V and let L be an open compactsubgroup fixing
vo.Suppose
there exist elements xij E G andconstants
N(i)
and cij,for
i =1, 2,
3 ... and1 j N(i),
such that(a)
each vi EV(L),
where(b)
Nosubsequence of
elementsof
theform
with j = j(i, n),
1j N(i) for all i,
and 1 i n,for n
=1, 2, 3,..., is
contained in a
compact-by-center
subsetof
G.Then vo
produces a
matrixcoefficient of (n, V)
whosesupport is
notcompact-by-
center.
Proof.
Since n isadmissible,
the spaceV(L)
of L-fixed vectors in V is finite- dimensional. Thus there exists a linear functionalv’0
onV(L)
such thatvn,v’0
0 forinfinitely
many n. Extendv’0
to be zero on thecomplement
ofV(L)
to define a smooth vector, also denotedv’0,
in thecontragredient
of KConsider the matrix coefficient
g 03C0(g)v0, v’0. For v"
in thesubsequence above,
which
inductively
is a linear combination of terms of the formfor j with
1j N(i).
Thus at least one such term must be non-zero.
Let sn
=03A0ni=1
1 x ij be such that03C0(sn)v0, v’0
0 for each such n.The
support
of the above matrix coefficient of 03C0 thus contains the set of such sn, which is notcompact-mod-center by hypothesis.
Hence arepresentation (n, V)
with theseproperties
cannot besupercuspidal.
A
representation
of A with such a vo in its space is thus a(G, A)-principal representation.
In ourapplications
of Lemma1.1,
the elements xj aregenerally products
of some fixed translation in the affineWeyl
group withappropriate unipotent
elements. It will then be immediate to check that condition(b)
of theLemma holds.
The authors would like to thank P. Kutzko and D. Manderscheid for
numerous
helpful
discussions on thissubject.
2. Structure and Notation
In this paper we will realize the group
GSp4(F)
ofsymplectic
similitudes as thoseelements g
ofGL4(F) satisfying
the relationgJtg
=cJ,
where c is a non-zero element of F andThe group
GSp4(F)
over a non-archimedean local field F has threeconjugacy
classes of maximal
compact-mod-center subgroups. See,
e.g.,[I].
We will definea filtration of each of the maximal
compact-mod-center subgroups
of Gconsisting
ofcompact
open normalsubgroups. First,
for n >0,
letKn
denote thenth congruence
subgroup
of the open maximalcompact subgroup Ko
=GSp4(O).
We will use thefollowing
notation to describeKn .
where the matrix entries denote the minimum valuation of entries of the difference between an element of
Kn
and theidentity
matrix.We define the
following
groups in the same manner:Let K =
KoZ(G).
Let H be the groupgenerated by Ho,o
and zH, and let J be the groupgenerated by Jo,o
and zj. HereThen the groups
K,
J and Hrepresent
the threeconjugacy
classes of maximalcompact-by-center
opensubgroups
of G.Let W be the
Weyl
group of G andWa
the affineWeyl
group. An element ofWa
may be
expressed
in the formwtr1ts2
wherew E W,
r and s areintegers,
andSet to = tlt2 as members of
Wa.
Then(modulo Z(G))
Let
{03B1, fil
be the base for the rootsystem (D
of G with/3
= e2 - el taken to be the short root and a =2e1
thelong
root. For any root03B3 ~ 03A6,
let Wy denote thereflection determined
by
y, andlet ty
be the translation in the affineWeyl
group associated to y. Recallthat t’,
acts on the standardapartment
of the Bruhat-Titsbuilding by sending
apoint
x to x +203B3v.
Note
that to
=t03B1+203B2
is the translation associated to a +2p,
andfurther,
that(t1)2
=t03B1t03B1+203B2
=t03B1+03B2
and(t2 )2 = tp.
Then we have thefollowing
double cosetdecompositions
ofGSp4(F).
LEMMA 2.1.
Let
(n, V)
be an irreducible admissiblerepresentation
of a reductivep-adic
group G. Let L be any open
compact-by-center subgroup
of G. Let(i, W)
be anirreducible
component
of(n, V)
restricted to L.Suppose
that i does not induceirreducibly
from L to G.Then, by Mackey theory,
there exists an x inG,
but notin
L,
which intertwines -r,i.e.,
there is an x outside of L for which the restrictions of i and itsconjugate Ad(x)-r
to the intersection L n xL have an irreduciblecomponent
in common.Thus for some
x E G - L,
thesubgroup
xker(03C4)x-1
n L of L has a fixedvector in W under r. Since
ker(i)
is normal inL,
theproduct kcr(r)(x ker(03C4)x-1
nL)
=ker(i)x ker(03C4)x-1
n L is asubgroup,
whichagain
has afixed vector under i.
More
generally,
let M cker(i).
If i does not induceirreducibly
toG,
thensome x~G - L intertwines i, and we know that
(the subgroup
of Lgenerated by) MxMx-1
n L has a fixed vector under i. If this(weaker)
conditionholds,
wesay that x intertwines i at M.
We
assign
apartial ordering
to the elements of Gby saying
thatx1
x2 when L nMx1Mx1-1
c L nMx2Mx2-1.
We may assume that such elements xbelong
to a chosen set of double coset
representatives
of L in G.Further,
if x2 intertwines i at M and x 1 x2 then xi will also intertwine i at M.Given such a group M and a set of double coset
representatives
of L in G weneed to know which
representatives
are minimal withrespect
to thisordering.
Ifa
representation T
of L does not induceirreducibly
toG,
then some minimal x intertwines i at M. We will prove that certainrepresentations
i induceirreducibly
to Gby showing
that no minimalrepresentative
x intertwines i at M.For any admissible
representation (n, Tl)
of G and any opensubgroup
L we letV(L)
denote the(necessarily)
finite dimensionalsubspace
of V fixedby
L.We now return to the case G =
GSp4(F)
LEMMA 2.2.
Using
the double cosetrepresentatives given
in Lemma 2.1 weobtain
the following
maximal setsof minimal (with
respect to"")
elements.(a) {t0, t1} for
L = K and M= Kn .
(b) (tl’
t2, tlt2,w03B1+203B2} for
L = J and M =Jn.j.
(c) {t0,
t1,w03B1+03B2} for
L = H and M =Hnj-
LEMMA 2.3.
The following
are abelianquotients:
(a) KmlKn for 2m
n.(b) Jm.iIJn-l.0 for
2m + i n - 1.(c) Hm.iIHn-l.0 for
2m + i n - 1.Let 0
be an additive character of F with conductor thering
ofintegers
lP.LEMMA 2.4. Characters
of
thequotients
in Lemma 2.4 aregiven by the formula
where x~ may be taken in the
form
subject
tothe following
conditions:(a)
For~~(Km/Kn)^ all
entries are inO/Pn-m,
(b)
For~~(Jm,i/Jn-1,0)^
we haveProof
Where convenient we mayalways
tensor theoriginal representation
ofG with a character of the determinant. We may also choose x~ to be any convenient coset
representative
modulo the annihilator of thesequotient
groupswhich is
given by
elements of the formThis
gives
thegeneral
formof xcp.
The conditions(a), (b)
and(c)
followeasily.
Weremark that we use the results of
(b) extensively
in the case 2m + i = n -1,
so thatn - m - 1 = m + i,
etc.Let L c G and let z E G. If i is a
representation
ofL,
we denoteby
Adz(i)
therepresentation
ofzLz-1
which for x~L isgiven by
If ç is a character of L
represented by
x~, then Adz(qJ)
is a character ofzLz-1 represented by zx~z-1.
In what
follows,
we assume that 03C0 is an irreduciblesupercuspidal
represen- tation ofGSp,
of level n. Thatis, n
is the smallestinteger
such thatV(Kn)
is non-zero. We also assume
(after possibly tensoring
03C0 with a characterthrough
thedeterminant)
that n is the minimal level among all such twists of n.3. The
Nilpotent
CaseIn this
section,
we consider the case in which 03C0 restricted toKn - 1 contains
acharacter 9 for which
03C0nx~
isnilpotent
mod P. We may then assume that x~ is ofthe form
where entries are taken modulo f71.
We seen,
then,
that thesubgroup
which is normal in the Iwahori
subgroup
B has a non-zero fixed vector in K Therefore(n, V),
when restricted to B has acomponent (i, Y)
whose kernel containsBn.
Recall that for the rest of the paper, we assume that 03C0 is anirreducible
supercuspidal representation
ofGSp4(F)
of minimal level n.DEFINITION 3.1. We say that such a
representation (03C4, Y) of nilpotent type
is obtuse if for every character ç contained in the restrictionof 03C4 to Bn-1,
both theentries a and d in x~ are units.
Let
LEMMA 3.2.
If (i, V) is
obtuse then(n, V)
isirreducibly
inducedfrom B, z.
Proof. Referring
to the remarks at the end of section2.,
let L =B, z)
andM =
Bn.
Asystematic
check of double cosetrepresentatives
ofB, z)
inG, (i.e.
elements of the affine
Weyl
groupWa),
shows that if any such element xintertwines 1" at
Bn,
then i cannot be obtuse.LEMMA 3.3.
If (i, V) is
notobtuse,
thenJn-l.0
has a non-zerofixed
vector in VProof.
Let v E Y be aneigenvector
for 9 with x~ as above.If (i, Y)
is not obtusethen there are three
possibilities.
If a = 0 we are done.
If a ~
0 and c = 0 then03C0(w03B1)v
is fixedby Jn-1,0.
If a ~
0 and c ~ 0 then03C0(u-03B1(ac-1))v
is fixedby Jn-1,0.
We may now assume that
V(Jn-1,0)
is a non-zerosubspace.
DEFINITION 3.4. Let
Ln-1j,k = (S03B1+03B2
nJi,k)(SO
nJi,k)Jn-1,0
where for any rooty,
Sy
denotes thecorresponding imbedding
ofSL2(F)
in G. Let2n-l(J)
denotethe set of those groups
L’J.; 1
which are normal in J.LEMMA 3.5.
Ln-1j,k~Ln-1(J) if
andonly if 2j+k n-1 and jn-1-val(2).
LEMMA 3.6. Let i be an irreducible
representation of
Joccurring
in therestriction
of
n. Then oneof
thefollowing
statements is true.(a)
03C0 =Ind Gr@
(b) v(Hn- 1.0) ~ {0}, (c) V(Kn-1)
~{0}, or
(d)
The restrictionof
n toJn,i
contains a character~ for
which we may assume thatProof.
LetLn-1j,k
be thelargest
member ofLn-1(J) having
a fixed vector. If2j
+ k = n - 1 then(d)
holds. We may therefore assume that2j
+ k > n - 1 and that(a)
does not hold. This means that some element x =w03C303B1+203B2tv11tv22
intertwines i atL’J./; 1
where 6 e{0, 1}
and v 1,v2
0. If neither(b)
nor(c) holds,
one can showthat Vl
= V2 so that x =w03C303B1+203B2tv00
withv0
0.Assume first that k = 0. Since x intertwines 03C4 at
Ln-1j,0,
it can be shown thatLn-1j-1,1
has a fixed vector. SinceLn-1j,0
was thelargest
elementof Ln-1(J) having
afixed vector, it follows
that j
= n - 1 -val(2).
We know thatwhere r, s, a, a’, c~Pn-j, c’~Pn-j+1,
andb,
b’~P. A Hensel’s Lemmatype argument
shows thatconjugation by
elements of the formu03B2(x), u03B1+03B2(x), u-03B2(x),
and
u-(03B1+03B2)(x)
in J willproduce
a matrixsatisfying
condition(d).
Now assume that k = 1. We know from Lemma 3.5 that
val(2) j - n
+ 1. Ifval(r ± s) j - n - 1,
then the fact that x intertwines ! atL’j.a 1
wouldproduce
avector fixed
by
thelarge
groupL’j.a 1.
Thereforeval(r
±s) = j - n
+ 1. As in theprevious
case, this fact allows us toproduce
a charactersatisfying
condition(d).
LEMMA 3.7. Assume that
V(Hn-1,0) ~ {0}.
Then either(n, V) is irreducibly
induced from
H or(n, V)
contains aKn-1-fixed
vector or(n, V)
contains aprincipal
character.
Proof.
Assume that 03C0 is notirreducibly
induced from H. From Lemma 2.2 and remarkspreceding it,
we see thatnlH
must have acomponent r
which is intertwined atHn-1,0 by
one of to, t 1, orw03B1+03B2.
It is easy to see that if to intertwines i at
Hn-1,0,
then the intersectionHn-1,0t0Hn-1,0t- 1 ~ H
is contained in ker i.Then, conjugating by t-10,
we seethat
V(Kn-1)
~{0}.
This contradicts theassumption
that n has minimal level n.Suppose
nextthat t
orw03B1+03B2
intertwines i atHn-1,0. Then,
in either case, therestriction of i to a suitable
subgroup (see
Lemma2.3(c))
will contain a characterç for which
with
We may assume that
val(a)
= 0 and thatval(a’)
= 1 or else we couldeasily produce
aKn-1-fixed
vector.Applying
Lemma1.1,
letHn-1,0 play
the role of L.Let vo E
V(L)
be aneigenvector
of 9. Letv’0 = 03C0(t0)v0.
There exist upperunipotent elements Uj
and constants c1,j such thatv"0 = 03A3c,j03C0(uj)v’0 is
aneigenvector
whose character isparametrized by
a matrix in the form above withThen one can find
u~u03B2(O)u03B1+203B2(P-1)u03B1+03B2(O)
such that v1= n(u)v" 0
is aneigenvector
with a charactersatisfying
the same conditions as theoriginal
9. In the terms of Lemma1. l,
let xi,j =uujt0
for i =2, 3, ....
Thus qJ is aprincipal
character.
It therefore remains to
analyze
the case(d)
of Lemma 3.6. Letsi = S03B1+203B2~Kj. Let Sj
=SjJm,i.
When thequotient Sh/Sj
isabelian,
we mayparametrize
its charactersby
matrices of the formwith
b, b’,
and SE lp.(When S, g Jm,i,
this is consistent with ourparametrization
of
(Jm,i)^).
Recall
that 0
is a fixed additive character of F with conductor thering
ofintegers
O. Since the residual characteristic of F is2,
we may choose p E (9 ’ with theproperty
that for x ~(9,
we have~(03C0-1x2) = ~(03C0-1 px).
LEMMA 3.8. Let k =
min{val(2), val(r
+s)l. Let j
be the smallestinteger
such that n restricted toSj
contains acharacter 0
which is trivial onS..
There arevarious cases that can occur.
(a) j
2k + 1: ~ may be extended toSj- 2jSj.
This situation mayalways
betransformed
into oneof the following
conditions.(i) If
SE (9 x andb,
b’ E9,
then qJ isprincipal.
(ii) If
SE9,
b EO ,
and b’ E 9 -92,
then n isirreducibly
inducedfrom
J.(iii) If
is irreducible mod
9, n
isirreducibly
inducedfrom
J.(b) j
= 2k and k =val(r
+s)
=val(r - s):
In this case, letis irreducible mod
Y,
then n isirreducibly
inducedfrom
J. Otherwise qJ isprincipal
and n isnon-supercuspidal.
(c) j
2kor j
= 2k =val(2) val(r
+s):
Here(n, V) is
neversupercuspidal.
Proof
In thisproof
we assume for convenience that n - 1 = 2m and that i = 0. The other case is handled in anearly
identical fashion.Since the illustration of
principal
characters in case(i)
of(a)
usesessentially
the same
arguments
as in Section 4. of[KM],
theproof
is left to the reader.Consider condition
(ii)
of case(a).
Assume that some x~G intertwinesIndGSj-2~.
We need to show that x E J. Let t = t1t2 so thatmod Z(G)
we may taket to be the translation
Let D = {w03B1+203B2tv|v 0} ~ {tv|v > 0}.
It isenough
to consider elementsg c- J-9J
sinceintertwining by
elements of other double cosets of J wouldproduce
vectors fixedby subgroups already
considered. We can writeJDJ =
J0{I, zJ}D{I, zJ}J0
where
Jo
=Jo,o.
Thearguments
for eachpiece
of this double coset areessentially
the same. Wegive
theproof
for g EJ otV Jo.
Let g = jltVj2
=nljtVn2
whereThis means that
and
We claim that neither ni nor n2 may have
w,
as a factor. Ingeneral, if g intertwines
then gqJ = ~ onxSj- 2x-1
nSj-
2. Thereforet"n2 = j-1n-11~
onJm,o n tV J m,at - V.
If n2 has w03B2 as afactor,
it is easy to see thattvn2~
has leveln + 2v on u-(03B1+203B2). This is a contradiction
since j-lnl1qJ
is trivial onJn-1,0.
Similar
reasoning
shows that ni cannot have wo as a factor either.Since j
may befactored,
we may write x =n-tvn+
where n+ and n - arerespectively
in the intersections ofJo
with thepositive
andnegative
root Borelsubgroups. Therefore,
onJm,0
ntvJm,ot-v
we haveThe left hand side of this
equation
is trivial onthe 03B2
and a +fi
root groups ofJm,0.
We now writewhere
One can
verify
that ~1is
also trivial onthe 03B2
and a+ /3
root groupsof Jm,o.
Itfollows that x
and y
are inf1jJm - k + 1.
The next
thing
to see is thatn-~1
still hasprecisely level j -
1 on u03B1+203B2. This is truebecause j >,
2k + 1 forces[u03B1+203B2(z), u-03B2(x)]~ker ~1
wheneverz~Pj-2
and
x~Pm-k+1.
A similarargument applies
to the effectof u-(03B1+03B2)(y)
on ~1.We conclude that
n-~ produces
a ramifiedcuspidal
character ofSi - 2
of thesame level as that
produced by
9. A similar check shows the same to be true forn+~.
It is evident that tv cannot send one to the other. Similararguments
for the other kinds of double cosets of J show that theonly
elements that can intertwine 9 are in J itself. Thus(n, V)
isirreducibly
induced from J. Theproof for
case(iii)
of
(a)
isquite
similar.We now consider case
(b).
We may extend 9 toS2k-2u-(03B1+03B2) (Pm)
so that ç istrivial on
u-(03B1+03B2)(Pm).
This is akey point
in the entireproblem
since this extension existsprecisely
because F has residual characteristic 2.For
p E f1jJm
andq~P2k-1
we may writewhere a and b are
integers.
Conjugation of qJ by u03B1+03B2(u)u03B1+203B2(z) changes ~ only
onu-(03B1+03B2)
andu-(03B1+203B2).
This action
changes
the coefficient of p in the formula aboveby 03C0-n(r + s)y + 03C0-(m+1)03C1z1/2.
Theq-coefficient
ischanged by
the amountn-n+ ly2 + 03C0-2k(b’z2 + sz).
9 is a
principal
character when there exist elements y and z to make the q- coefficient zero withoutmodifying
thep-coefficient.
Thisrequires
thatThus the modification to the
q-coefficient
isThus the new
q-coefficient
will beThis leads
immediately
to the condition of case(b).
When that conditionfails,
anargument
similar to the onegiven
in case(a)
shows that(n, V)
isirreducibly
induced from J.
We now consider case
(c).
LetThen ç may be extended to
Sju-03B3(Pm)
as before. As in the above cases, wegive
the
proof
for when n - 1 is even and y = a +03B2.
We may assume that the extended 9 is trivial on
u-(03B1+03B2)(Pm).
Note thatconjugating u-(a+b)(y) by u03B1+203B2(z) gives
When
y~Pm
andz~(O,
we have~(u03B2(zy))
= 1. Also(since
F has residual characteristic2)
we find that the map y~(u-03B1(zy2))
is an additive character ofPm/Pm+1. It
follows that z~O may be chosen so that ~1 =Ad(u03B1+203B2(z))(~)
is acharacter
extending
theoriginal
9 which is trivial on u-(03B1+03B2)(Pm).
Let
We will show that qJI 1 is a
principal
character. Let qJ2 be any extension toSju-(03B1+03B2)(Pm) of Ad(t)~1).
Let P be thepositive
root Borelsubgroup of S03B1+203B2
and set
Pj
= P nKj.
Then qJ2 is trivial onS2kPj.
We may choosey~Pm-k
suchthat
Ad(u03B1+03B2(y))(~2)
is a characterof Sj satisfying
the initial conditions of the lemma. This demonstrates that ~ is aprincipal
character.THEOREM 3.9. All
supercuspidal representations occurring
in thenilpotent
caseare
irreducibly induced from
some opencompact-by-center subgroup of
G.References
[H] R. Howe, "Tamely ramified supercuspidal representations of GLn." Pac. Jour. Math 73 (1977)
437-460.
[I] N. Iwahori, "Generalized Tits systems (Bruhat decomposition) on P-adic semisimple groups." in Algebraic Groups and Discontinuous Subgroups, Proc. Symp. Pure Math., vol. 9, Amer. Math. Soc., (1966).
[K] P. Kutzko, "On restriction of supercuspidal representations to compact open subgroups."
Duke Jour. Math. 52 (1985) 753-764.
[KM] P. Kutzko and D. Manderscheid, "On the supercuspidal representations of GL4, I." Duke Jour. Math. 52 (1985) 841-867.
[M] A. Moy, "Representations of GSp4(F) over a p-adic field, parts 1 and 2." Compositio Math. 66 (1988) 237-284, 285-328.