C OMPOSITIO M ATHEMATICA
M. J. T OMKINSON
Extraspecial sections of periodic FC-groups
Compositio Mathematica, tome 31, n
o3 (1975), p. 285-302
<http://www.numdam.org/item?id=CM_1975__31_3_285_0>
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285
EXTRASPECIAL SECTIONS OF PERIODIC FC-GROUPS
M. J. Tomkinson
Noordhoff International Publishing
Printed in the Netherlands
1. Introduction
A group G is an
FC-group
if each element of G hasonly finitely
manyconjugates.
We shall be concerned with the class Xof periodic FC-groups.
X is well known to coincide with the class
of locally
finite-normal groups and could be defined as the classof locally
finite groupssatisfying
either:Let F
denote the class of finite groups and Q, s, D the usual closureoperations;
it is clear thatQSDF ~
X. Infact, QSDF
seems to be alarge
subclass of X as P. Hall
[3]
showed that every countableX-group
is aQSDF-group
and Ju. M. Gorëakov[2]
has shown that everyresidually
finite
X-group
is aQSDF-group.
P. Hall also gave anexample, generalized
in
[6],
of anX-group
which is not aQSDF-group.
Our aim here is togive
further information about
X-groups
which are not in the classQSDF.
To present our results more
clearly
we introduce two further subclasses of Xusing
conditions similar to(1.1)
and(1.2).
Wedefine B
to be the classof locally
finite groups G whichsatisfy:
(1.3) if
m is aninfinite
cardinal and H G such thatIHI
m, then|G: CG(H)| m.
We let
Y
denote the classof locally
finite groups Gsatisfying:
(1.4) if
m is aninfinite
cardinal and H G such thatIHI
m, then|G: NG(H)| m.
It was
proved by
P. Hall[3]
andagain by
Gorcakov[2] that QSDF ~ 3.
It is clear
that B ~ Y
and theexamples
mentioned above areX-groups
not in the class
Y. (Hall
used condition(1.3)
to show that these groupswere not in
QSDF
but itis just
as easy to see thatthey
are not9)-groupes).
Thus we have
Our main result shows that the
examples
mentioned above are insome way
typical
of thoseX-groups
notsatisfying (1.4);
we prove:THEOREM A: Let G be an
X-group.
Then G is aY-group if
andonly if
each
extraspecial
sectionof
G is aY-group.
A section of a group G is a factor group
H/K,
where K « H G.An
extraspecial
p-group E is one in which03B6(E)
= E’ has order p andE/E’
iselementary
abelian. Theextraspecial Y-groups
are moreeasily
identified
by
thefollowing
characterization :THEOREM B: Let E be an
extraspecial
p-group. Then E is aD-group if
andonly if, for
eachinfinite subgroup
Hof E
and each maximal abeliansubgroup
Aof
H,lAI = IHI.
Apart
from theexample
in[6],
a rather worseextraspecial
group not inY
has been constructedby
A. Ehrenfeucht and V.Faber [1].
Theirexample
is uncountable but every maximal abeliansubgroup
is countable.The
class ?)
also has a connection with anotherproblem concerning FC-groups.
It wasproved
in[7]
andagain
in[2]
that if A is asubgroup
of the
QSDô-group G,
thenLcl(A)
=Cl(A)
if andonly
ifCl(A)
is finite.(Here Lcl(A)[Cl(A)]
denotes the set of allsubgroups
of G which arelocally conjugate [conjugate]
toA.)
However this result can beproved
much more
easily
for the(possibly) larger
class ofY-groups.
In theproof
of Theorem B of
[7]
it is shown that ifCl(A)
isinfinite,
then G has a countable normalsubgroup
N such thatLcl(A
nN)
is uncountable.If
Lcl(A)
=Cl(A),
thenLcl(A
nN)
=Cl(A
nN)
and so A n N is acountable
subgroup
withIG: NG(A
nN)j
uncountable. Thus G is nota
9)-groups
and we have :THEOREM C : Let A be a
subgroup of
theD-group
G. ThenLcl(A)
=Cl(A)
if
andonly if Cl(A)
isfinite.
Theorem A indicates that in
investigating X-groups
which are not in theclass
QSDF,
we shouldbegin by considering extraspecial
groups. The main results that we prove may be summarized as:THEOREM D:
(i) If
E is anextraspecial D-group of cardinality
then E is a
3-group.
(ii)
There is anextraspecial 3-group of cardinality 1,
which cannotbe embedded in the central direct
product of
groupsof
orderp3.
It seems
unlikely
thatD(i)
can be extended to showthat Y
and3
coincide for
extraspecial
groupsof arbitrary cardinality
but the construc-tion of a
counterexample
wouldnecessarily
be verycomplicated.
Theexample
ofD(ii)
was intended to show thatQSDF ~ B
but we have notbeen able to prove that this group is not a
QSDF-group.
However it doesshow that a
possible
strongerconjecture
is false. In[3],
P. Hallactually proved
that if G is a countableX-group,
then G EQSD(F
n5B( G)),
where5B( G)
is thevariety generated by
G. The next result shows that theexample
G in
D(ii)
is not in the classQSD(S
n5B( G)).
THEOREM E:
(i)
Let E be anextraspecial QSD(F
n zp’l1p)-group
whereZp9îp
denotes thevariety of
groups which are(central of
exponentp)-by- (abelian of
exponentp).
Then E can be embedded in the central directproduct of
groupsof
orderp3.
(ii)
There is anextraspecial subgroup of
a central directproduct of
groups
of
orderp3
which is notitself
a central directproduct of
groupsof
orderp3.
We
begin by proving
the characterization ofextraspecial Y-groups given
in Theorem B as this willsimplify
laterproofs.
Our mainresult,
Theorem
A,
isproved
in Section 3. The remainder of the paper consists of the resultsconcerning extraspecial
p-groups. These results are all obtained in termsof symplectic
spaces,using
the well knownrelationship
between
extraspecial
p-groups andnon-degenerate symplectic
spacesover
GF(p).
The results wegive
do notdepend
on theunderlying
fieldof the
symplectic
spaces.Although
theexample
ofD(ii)
indicatesthat 3
isprobably
alarger
class than
QSDS?
we shouldemphasize
that we have still notdefinitely
constructed any
exainples
of groups outsideQSDF
other than the knownexamples
mentioned earlier.Apart
from this obviousquestion
it wouldalso be
interesting
to know whether theseinvestigations
can be reducedentirely
tostudying extraspecial
groupsby showing
thatQsDô-groups
and
3-groups
can berecognized by
theirextraspecial
sections.Our
terminology concerning symplectic
spaces isslightly
different from that used in[5].
We call asubspace
Aisotropic
if(x, y)
=0,
for allx, y ~ A;
the termtotally isotropic
is usedby Kaplansky.
Ahyperbolic plane
issimply
a 2-dimensionalnon-degenerate symplectic
spaceH;
that
is,
H has a basis{x, yl
such that(x, y)
= 1. Theexpression
A E9 B denotes the direct sum ofsubspaces A
and B in the usual sense.If,
inaddition the
subspaces
A and B areorthogonal (i.e. (a, b)
=0,
for alla E
A,
b EB)
then we refer to theorthogonal
sum of A and B. In whatfollows,
it isusually
clear when a direct sum is anorthogonal
sum asone of the
subspaces
will be contained in theorthogonal complement
of the other.
(The orthogonal complement
of asubspace
U is defined to beU~ = {x
EV ; (x, u)
= 0 for all u~ U}.)
Theonly
occasion on whichwe stress the
orthogonality
is whenconsidering
anorthogonal
sum Vof
hyperbolic planes Hi.
We denote thisby
Kaplansky [5]
refers to such a space ashaving
asymplectic
basis.2.
Extraspecial Y-Groups
LEMMA
(2.1): Y and 3
areQs-closed
classes.PROOF : Let
G ~ Y
and U G. If H is an infinitesubgroup
of U, then1 G : NG(H)| |H|
andso |U : NU(H)| 1 G : NG(H)| IHI and Y
iss-closed.
Now let N « G and
H/N
be an infinitesubgroup
ofG/N.
Then thereis a
subgroup U
of G suchthat |U| = |H/N|
and H = UN.NG(H) NG( U)
and so
|G/N : NG/N(H/N)| I G : NG(U)| |U| = IHINI I
and so
G/N ~ Y.
To prove
that
is Q-closed we follow a similarargument, noting
thatCG(H/N) CG( U).
PROOF OF THEOREM B: Let E be an infinite
extraspecial 9)-groups
andlet A be a maximal abelian
subgroup
ofE;
thenCE(A)
= A. IflAI lEI
then
JE : CE(A)|
>lAI.
Since A has finite exponent it is a directproduct
offinite abelian groups and so may be
expressed
as A = B x Y where Y is afinite group
containing
Z =«E).
Then|B| = lAI
andso that
JE: CE(B)|
>IBI.
But since B n E’ =1,
we haveCE(B)
=NE(B)
and so
lE: NE(B)I
>|B|,
contrary to Ebeing
a’1)-groups.
ThereforeJAI
=IEI.
Now let H be any infinite
subgroup
of E and A a maximal abeliansubgroup
of H. If H n Z =1,
then H is abelian andclearly lAI
=’IHI.
So we may assume that H > Z. Let the elements of
«H)IZ
bexi, i ~ I.
For each
i ~ I,
there is an elementYi E E
such that[xi, yi] ~
1. LetH1 = H, yi; i ~ I>;
then|H1/H| |03B6(H)| lAI
andRi
isextraspecial.
Also, by (2.1), H1
is aY-group.
LetA1
be a maximal abeliansubgroup
of
Ni containing
A. Then|A1| JAI |H1/H| |A|2 = IAI and, by
theabove, IA11 = IH11.
Therefore|A| = |A1| = |H1| = |H|,
asrequired.
Conversely,
let E be an infiniteextraspecial
group with an infinitesubgroup
U such that|E : NE(U)| > |U|.
Then U n Z = 1 and soNE( U)
=CE(U)
UZ and U is abelian. SinceE/ UZ
iselementary abelian,
there is asubgroup
H of E such thatHCE( U)
= E andH n
CE( U)
= UZ. Now let A be a maximal abeliansubgroup
of Hcontaining
UZ. Then ACH(U)
= UZ and soJAI
=|UZ|
=lUI.
But1 HIA = |H/UZ| = |E : CE(U)| > 1 Ul and
we obtainlAI | |H|,
asrequired.
3. Proof of Theorem A
It follows from
(2.1)
that if G is aY-group
then every section of G is aY-group.
So we assume that G is not a9)-group
and show that there is anextraspecial
section of G which is notin Y. Starting
with the group G we shallrepeatedly replace
G with either asubgroup
or factor group thusimposing
more and more restrictions on G until we are left with anextraspecial
group not inY.
Let U be an infinite
subgroup
of G such thatI G : NG( U)I | > 1 UI. Clearly
we may assume that core
G( U)
= 1.Let Z =
«G). G/Z
ER ô
~ X ~QsDô
~3 ([2],
Theorem2).
Therefore!G. : CG(UZ/Z)| |UZ/Z| lUI
and soReplacing
Gby UCG(UZ/Z)
we may assume:If c ~ C then Uc
UZc,
whereZc = [U, c]
is a finitesubgroup
of Z.Zc UG
n Zand |UG| = UI
sothat UG
nZ| |U|.
Thus there areat
most |U|
finitesubgroups
of UG n Z. Therefore there is a finitesubgroup
F of UG n Z such that UF contains morethan |U| conjugates
of U. We choose F to have minimal order.
If Uc
UF, then [U, c]
F and soc ~ CG(UF/F).
Nowwriting
Gfor
UCG(UF/F),
C forCG(UF/F),
we have(2)
UFG, F
Z,CG( UF/F) = C, C : Nc(U)| > |U|,
U n F = 1.( U
n F = 1 since F Z and core U =1.)
There is a
subgroup
D S F such thatF/D
iscyclic
ofprime
order p, say.By
theminimality
ofF,
U has atmost |U| conjugates
contained inUD but has more
than 1 Ul
contained in UF. It follows that UD hasmore
than |U| conjugates
contained in UF.Replacing
Gby G/D,
Uby UD/D
etc., we haveLet u ~
U, c E C;
then[c, u] ~ F
and soi.e. C centralizes UP. Also
and so C centralizes U’.
Therefore U’ Up UC = G.
Factoring
outU’UP,
we may assume that U iselementary
abelian and so UCG(UF/F).
We may also assume that G =CG(UF/F)
and soobtain
(4)
F has order p, FZ,
UF is a normalelementary
abelian p-group U n F= 1,
G =CG(UF/F) and G : N,,(U)l
>|U|
.Let
D = CG(U),
so thatD = CG(UF) G.
Letg1, g2 ~ G ;
then[gi, u] ~ F
and soand
Therefore
G/D
is anelementary
abelian p-groupand,
since DNG( U),
we
have IGIDI > lUI.
We may nowclearly replace
Gby
aSylow p-subgroup
and so assume that(5)
G is a p-group, FZ, IFI
= p, U n Z =1,
U andGICG(U)
areelementary
abelian p-groups, UF G and1 G : N G(U)I > |U|.
Let No G be maximal
subject
to N n UF = 1. Then if UxUN,
we have Ux UN n UF =
U(N
nUF)
= U and so U’ = U. ThusNG( UN)
=NG( U)
and we canreplace
Gby GIN. Thus,
in addition to(5),
we also have
(6)
F is theunique
minimal normalsubgroup of G and,
inparticular,
Z is
locally cyclic.
We now construct an
ascending
chain ofsubgroups
(where
p is the least ordinal such thatIpl > |U|)
such thatThen, letting
A =~03B103C1 A03B1,
we see thatAIF
isabelian,
A n Z = Fand
JA : NA(U)L
>1 UI.
We construct the
Aa inductively.
The limit ordinal case is clear as(i)
and
(ii)
followimmediately
from(iv).
So we may assume thatAa-1
hasbeen constructed. Let
Ca-1
=CG(Aa-1IF);
then sinceA03B1-1/F ~ Aa-1 ZIZ
and
GIZE3,
wehave |G/C03B1-1| IAa-11 = 1 Ul.
Thereforeand so
C03B1 - 1
>C03B1 - 1
nA03B1 - 1 NG( U).
Let
Z>
be theunique subgroup
ofA03B1- 1 Z/A03B1-
1 of order p, and leta1 ~ C03B1-1 - A03B1-1 NG(U).
Thena1, z>
is a finite abelian group and so|C03B1-1 : C03B1-1 ~ CG(a1, z>)|
is finite. Therefore there is an elementa2 ~ Cc03B1-1(a1, z>) - A03B1-1 NG(U).
Thusa1, a2, z>
isagain
a imitea2 ~ Cc03B1-1(a1, z>) - A03B1-1 NG(U). is not a1, a2, z> is again not cyclic.
abelian group and since
a1, a2>
is notcyclic, a1, a2, z>
is notcyclic.
Therefore
a1, â2, z)
contains an element no power of which isequal
to z. That
is,
there is an elementa ~ C03B1 - 1 - A03B1-1 NG(U)
such thatA03B1-1 Z/A03B1-1
has trivial intersectionwith (à ) .
Let
A03B1 = A03B1-1, a>. Clearly Aa/F
isabelian, |A03B1| = IAcx-11 1
andAcxN G(U)
>Acx-1 NG( U).
AlsoReplacing
Gby
A, we have :(7)
G is a p-group,G/F is abelian, IFI
= p, U iselementary
abelian and|G : NG(U)| > |U|.
If x, y E
G,
then[x, y]
E F and so[xP, y] = [x, y]P
= 1 and so xP E Zi.e.
G/Z
iselementary
abelian. We can also repeat the argumentpreceding (6)
so that we may assume(7) together
with(8) G/Z is elementary
abelian and Z islocally cyclic.
Let X be maximal
subject
toX >, U,
X n Z = F so thatG/X
is finiteif Z is finite or is countable if Z is infinite. In either
case |G/X| 1 UI
and so
|X : N x(U)1 > |U|.
AlsoX/F ~ XZIZ
iselementary
abelian and so,replacing
Gby X,
we have(9)
G is a p-group such thatIG’l
= p andGIG’
iselementary abelian,
U ~ G’ = 1
and |G : NG(U)|
>JUI.
It is now
possible
that Z > G’.If so,
then there is asubgroup
Y > UG’such that
G/F
=Y/F x Z/F
andclearly 03B6(Y)
= G’.Replacing
Gby Y,
we obtain the
required
result.Although
thisproof
reliesheavily
on the fact thatG/Z
is a3-group (and
notjust
aY-group)
it does not seem to bepossible
toadapt
themethods to
give
thecorresponding
result for3.
It ispossible
to prove that anX-group
which is notin 3
has a section G which is a p-group, contains a centralsubgroup
F of order p and a normalsubgroup
U > F suchthat 1 CG(UIF) : CG(U) > |U|.
The maindifficulty
inmaking
furtherreductions is that when one considers centralizers it is not
usually
possible
to factor out normalsubgroups.
4.
Extraspecial QSD%-groups
We
begin by giving
a reduction theorem forarbitrary extraspecial QSDF-groups.
LEMMA
(4.1):
Let G be anextraspecial
sectionof DrieI Di,
where eachDi is finite.
Then G isisomorphic
to a sectionof DrieI Ei,
whereE,
EQs{Di}
andEi is a
monolithic p-group.[A
group is monolithic if it has aunique
minimal normalsubgroup.]
PROOF : Let G =
H/K
where K « H K D =DrieI Di.
Let T be aSylow p-subgroup
of H so that TK = H and G xéTI(T
nK).
If S is aSylow p-subgroup
of Dcontaining
T, then S =DrieI Si,
whereSi
is aSylow p-subgroup
ofD,,
and G isisomorphic
to a sectionT/U
of S.We may assume that the index set I is well-ordered. For each i ~ I choose
Ni
«Si
maximal with respect towhere
Mi
=Nj; j i>.
Define N =
Dric, Ni
=UieI Mi.
We show that N n T U so that Gis
isomorphic
to the sectionNT/NU of S/N ~ Dric, Si/Ni. Suppose
thatMi
n TU ;
thenTherefore, by induction, Mi
n T U for all i e I and soEi
=Si/Ni
is a p-group andEi
EQs{Di};
it remains to show thatEi
ismonolithic. Let
XilNi
be a normalsubgroup of Si Ni. If X
~ TN UN thenand so,
by
themaximality
ofNi ,
we getX
=Ni. Writing H/K again
for G as a section of
Dric, Ei
this means that for every non-trivial normalsubgroup X
i ofEi,
we haveX
riH
K. LetL/K
=«HIK)
andZi
=03B6(Ei).
Then(Zi
nH)K
= L and soZi
n H =Zi
n L has order p.If Y
is a minimal normalsubgroup
ofEi,
then(Y
nH)K
= L and soYi
L nZi
and we musthave Y
=Zi
n L. ThusZi
n L is the monolithof Ei.
To obtain Theorem
E(i)
we first need to consider thesymplectic
space associated with anextraspecial
group. We state thisexplicitly
asTHEOREM
(4.2):
Let G be anextraspecial
p-group with«G) = z>.
(i)
G =G/((G)
becomes anon-degenerate symplectic
space overGF(p) if
wedefine (x, y)
= a, where ac =x«G), y
=y«G)
and[x, y]
= z’.(ii)
G is a central directproduct of
groupsof
orderp3 if
andonly if
the
symplectic
space G is anorthogonal
sumof hyperbolic planes.
It is well-known
(e.g. [5],
p.45)
that anon-degenerate symplectic
space of countable dimension is anorthogonal
sum ofhyperbolic planes
so we see
immediately
that every countableextraspecial
p-group is acentral direct
product
of groups of orderp3.
PROOF OF THEOREM
E(i):
By
Lemma(4.1)
we may assume that G =H/K
whereand each
Ei
is a monolithic p-group. LetL j K
=03B6(H/K), Zi
=((Ei)
and
Ni
be the monolith ofEi.
If N =Dric, Ni ,
then(N
nH)K
= L.HI(N
nH) ~ NHIH
iselementary
abelian and so there is asubgroup
M such that ML = H and M n L = N n H. Thus
HIK -- M/(H
nN) and, replacing H/K by M/(H
nN),
we may assume that K N and hence H n N = L.N is
elementary
abelian and so there is asubgroup
X such that N =Lx,
K = L n X and so
HIK -- HX/KX. Replacing H/K by HX/KX
wemay now assume that L = N.
Let Z =
03B6(E)
=Dri~I Zi.
Since H n Z =N,
there is asubgroup
U H such that UZ =
E,
U n Z = N. We show that theextraspecial
group
U/K
is a central directproduct
of groups of orderp3.
For eachi c- I,
there is a finiteextraspecial subgroup Vi
such thatZi Vi
=Ei,
Zi n v
=Ni.
Let Tl =Dri~I Vi
so that Z V = E and Z n V = N. Thenthe
extraspecial
groupV/K
is the central directproduct
of the groupsVi
and so the associatedsymplectic
spacev/K
is anorthogonal
sum ofhyperbolic planes.
But thesymplectic
spacesU/K
andV/K
areclearly isomorphic
under themapping
which takes U EU/K
to itsprojection
on
V/K
in thesymplectic
spaceZ/K
~V/K.
ThusU/K
is anorthogonal
sum of
hyperbolic planes
andH/K
is embedded in the centralproduct U/K
of groups of orderp3.
5.
Symplectic
spaces associated with-groups
andY-groups
We
begin by defining 9)-espaces
and3-spaces
in such a way that anextraspecial
p-group G is a9)-group (-group)
if andonly
if its associatedsymplectic
space G is a9)-espace (3-space). For 3
we cansimply
translate(1.3)
into thelanguage
ofsymplectic
spaces so that anon-degenerate symplectic
space V over a field f is a3-space
if it satisfies :if
m is aninfinite
cardinal and U ~ V such that dim U m, then dim(V/U~)
m.For Y
we need to use the characterization ofextraspecial Y-groups given
in Theorem B. Thus anon-degenerate symplectic
space V over a field t is a9)-espace
if it satisfies:for
eachinfinite-dimensional subspace
Uof
V andfor
each maximalisotropic subspace
Aof U,
dim A = dim U.We also
require
a rather strongercondition, calling
V a3B-space
if itsatisfies :
if
xtt is aninfinite
cardinal and U g V such that dim U m, then there is asubspace
W ;2 U such that dim W m and V = W Et) W~.It is clear that an
orthogonal
sum ofhyperbolic planes
isa 3B-space
and that every
non-degenerate subspace
of aM-space
is a3-space.
We shall show that every
3-space
ofdimension Ni
can be embedded in aM-space.
First we embed in alarger
space so that agiven subspace
is contained in an
orthogonal
summand of the same dimension.LEMMA
(5.1) :
Let U be aninfinite-dimensional subspace of
the3-space
E Then V can be embedded in a
3-space
il =V(V U)
such thatdim V = dim V and V contains a
subspace
U =U(U) ~
U such thatdim U = dim U and V = U ~ U*.
Furthermore, if
W ~ U and V = W ~W1.,
then V = W ~ W*.[Here
X* denotes theorthogonal complement
of X in v and X~ theorthogonal complement
inV.]
PROOF :
By adjoining
elements toU, if necessary,
we may assume that Un U 1. =
0. Let V = U ~ U~ CX ;
since V isa 3-space,
dim X dim Uand we can choose a basis
{xi;
i EIl
of X sothat |I|
dim U.Let V be
spanned by
V and basis elements yi, i El. Define an alternateproduct
on TVby
Let LI be the
subspace
of Vspanned by
U and the yi,~ I ;
then dim CI = dim U.Since
we
have yi E
W E9 W * and so W E9 W * = EIt remains to show that TV is a
3-space. Writing
Yfor yi; i ~ I>,
we have
V = U ~ U~ ~ X ~ Y.
Let S g V and dim S = m, where m is an infinite cardinal. Let
A,
B and C denote theprojections
of S onU, U~
E9 Xand Y, respectively.
Since V is a
3-space,
we have dim(V/A~)
m and soSince
xi - yi ~ A*,
for alli ~ I,
it follows thatTherefore
B* ;2 Y and so
dim (V/B*)
=dim (V/B~)
m. C* ;2Ul
Et) X Et) Y andso dim
(PIC*)
= dim(VI(V
nC*)). If 0
Y - X is themapping
whichtakes yi
to xi, for each i~ I,
then V n C* =(C~)~.
SinceCo
is asubspace of the 3-space V,
we have dim(V/(C~)~)
m and hence dim(V/C*)
m.S* ;2 A* n B* n C* and so we obtain dim
(QS*) 5
m.THEOREM
(5.2): A 3-space
V such that dim V is aregular
cardinal can beembedded in a space Y
satisfying
the condition :if
U ç Y and dim U dim V then there is asubspace
W ;2 U such that V = W Et)W~
and dim W dim V.PROOF : Let p be the least ordinal with
cardinality
dimV ;
then V hasa basis
{xi;
ipl. Let Va
=(x;;
ia)
so that V =Uap v:.
We construct spaces
V(03B1) ~
V andsubspaces F,,,
ofV (a)
such thatThen we may define V =
~03B103C1 V(03B1)
=~03B103C1 V03B1.
Since dim f is aregular cardinal,
anysubspace
of V with dimension less than dim V is contained insome V03B1 (a p) and V - E9 f:.l
and the result follows.The spaces
V (a)
andV03B1
are constructedinductively.
We may suppose thatY(03B2) and g
have been constructed foreach fl
a.as in Lemma
(5.1)
andBy
theLemma, whenever 03B2
a,V03B2
is anorthogonal
summand ofV(a).
V(a)
=V(03B3) + f7., by construction,
and the inductionhypothesis gives V(a)
=V + V03B3 + V03B1 = V + V03B1.
ThusV(a) and V03B1 satisfy
the conditions(1)
and
(2).
Case
(ii):
a a limit ordinal.r --
For
each fl
a and for each y withf3
y a;and
so %
is anorthogonal
summand ofV0(03B1). By
Lemma(5.1), Po
is anorthogonal
summand ofV(a). By construction,
Thus
V(a)
andTVa again satisfy
conditions(1)
and(2).
Since the space V in the theorem is
clearly
aW-space
if its dimension is1,
this shows that every3-space
ofdimension 1
can be embedded in aM-space. Combining
this with TheoremD(i),
which we prove now,gives
THEOREM
(5.3):
AY-space of dimension 1
can be embedded in aM-space.
PROOF : It remains
only
to show that a9)-espace
ofdimension 1
is a3-space.
Suppose
that V has asubspace
U of dimensionNo
such thatdim
(V/U~) = 1.
Then U =A + B,
the sum of twoisotropic subspaces,
and
U~ =
A~ n B~.Therefore V has an
isotropic subspace A,
say, such that dim A =No
and dim
(V/A~) = 1.
There isa subspace
W of V such that V = W E9A’.
Let X =
A + W;
then A.l n X = A and so A is a maximalisotropic subspace
of Xalthough
dim X= 1
and dim A =No.
6. The
counterexamples
We
begin by giving
anexample
of anon-degenerate subspace V
of anorthogonal
sum ofhyperbolic planes
which is not aM-space.
Inparticular
itself is not anorthogonal
sum ofhyperbolic planes.
Let
where xi, yi>
is ahyperbolic plane
such that(xi , Yi)
= 1 and 03C91 is the least uncountable ordinal.Let V be the
subspace
of Xspanned by
theelements xi
and yi - yj with 0i, j
W1.Writing
zi for yi 2013 y0, we see that(xi, zi)
= 1 and(zi, xo)
= 1.Let
and suppose that V = U (B
U~
where U ~Uo.
We show that U has uncountable dimension.For each i W1, xi E U ~ U1 and so there is an element u E U such that u - xi ~ U1. Let u =
kxo + w,
where k ~ andFor each n cv
with n ~
i,(zn, u - xi)
= 0 and so(zn, w) = -k,
forinfinitely
many n. It follows that k = 0 and so w - xi ~U~.
Thatis,
for each i W1, there is an element wi E W n U such that wi 2013 xi ~ U~.
Similarly,
there is anelement vi
E W n U such that 03BDi 2013 Zi ~ U1.Now
(wi , 03BDj 2013 zj)
= 0 and(03BDj, Wi-Xi)
= 0. Therefore(wi , Vj)
=(wi , zj)
and
(vj, wi) = (vj, x;)
and hence(wi , zj) = (xi, 03BDj).
If w;
and vj
are written as linear combinations of x’s and z’s then the above shows that the coefficient of xj in wi isequal
to the coefficient of zi in Vj. Since(x0, 03BDj 2013 zj)
=0,
we have(x0, 03BDj)
=1,
foreach j,
and sothere is some zi
having
a non-zero coefficient in 03BDj.Therefore,
foreach j,
there is a Wi in which the coefficient
of xj
is non-zero. It follows that thereare
uncountably
many differentw’is
anddim ( W
nU)
is uncountable.It should be noted that an
orthogonal
summand V of anorthogonal
sum
of hyperbolic planes
is also anorthogonal
sumof hyperbolic planes.
The method used
by
I.Kaplansky [4]
for modules shows that V is anorthogonal
sum of spaces of countable dimension. The structure ofsymplectic
spaces of countable dimension thengives
therequired
result.We saw in Section 5 that every
Y-space
of dimension1
can beembedded in a
M-space.
BecauseM-spaces
seem to be very close toorthogonal
sumsof hyperbolic planes
onemight hope
to prove a strongerembedding
theorem. However our nextexample
is aW-space
of dimen-sion 1
which cannot be embedded in anorthogonal
sumof hyperbolic planes.
Let V have a basis
consisting of xi , yi
and z03B1, where i takes all ordinal values less than W1 and a takes all limit ordinal values less than W1. We define an alternateproduct
on Vby
For each 8 03C91, let
clearly V
=~03B503C91 V03B5.
Each countable dimensionalsubspace
of V iscontained in
some V,
and so to show that Tl is aM-space
it is sufficientto show that
V = V03B5 ~ V~03B5. Certainly v~03B5 ~ xj, yj; j B)
and ife = a + n, where a is a limit ordinal and 1 n cv, then Z03B1 + Y03B1 + Y03B1+1 + ...
+ Y03B1+n-1 - Z03B2 ~ V~03B5,
forall 03B2
> e.If e is a limit ordinal then zE - zo E
V~03B5,
for all03B2
> e. In both casesZo C-
V03B5 + V~03B5
andhence V
~V~03B5 = V,
asrequired.
Now suppose that
where
Hi = ai, bi>
and(ai, bi)
= 1. WriteLet i be any ordinal less than w1; then there is a least
ordinal j(i)
W1such
that Vi ~ Kj(i)(~ V). If j 03C91,
then there is a least ordinali(j)
such that
Kj
n v 9Vi(j).
Given an ordinal i OJ 1, we defineThen
Let a =
lub{jn}
andf3
=lub{in};
then we haveWe shall call a limit
ordinal 03B2
for which there exists a limit ordinala =
03B1(03B2) satisfying (*)
afi-ordinal.
We have shown that if i is any ordinal less than cv 1, then there is a03B2-ordinal 03B2
such that i5 fl
W1. Inparticular,
there areuncountably
many03B2-ordinals.
If 03B2
is a03B2-ordinal
and a =03B1(03B2),
thenKa
contains anelement k,,,
suchthat
k03B1 - z03B2 ~ K~03B1. Suppose,
ifpossible,
that there is no element k E H such thatk - z03B2 ~ K~03B1(03B2)
foruncountably
many03B2-ordinals 03B2. Then,
for each a W1, there is a smallest
fi-ordinal 03B2(03B1)
suchthat,
for eachelement k E
Ka
and for each03B2-ordinal
03B303B2(03B1), k - z03B3 ~ K~03B1(03B3).
Choose some
03B2-ordinal 03B20
and define ao =03B1(03B2) and,
for eachinteger
n
1, 03B2n
=03B2(03B1n-1), 03B1n
=03B1(03B2n). Let 03B2
=lub{03B2n}
and a =lub{03B1n};
thenso
that p
is ap-ordinal
and a =03B1(03B2).
If k EKa,
then k EKan
for some nand so k -
z, 0 K~03B1(03B3)
for any03B2-ordinal 03B3 03B2n+1.
Inparticular
there is noelement k E
Ka
such that k - zo EK~03B1.
This contradiction shows that there is some element k E H such thatk - z03B2 ~ K~03B1(03B2),
foruncountably
manyfl-ordinals 03B2.
It follows that
We now consider the
subspace
V = V +k>
of H.Letting f7,
=V
+k>,
we
clearly
have V =~03B503C91 V03B5.
This allows us to repeat the argumentsabove, defining
a03B2-ordinal
to be a limit ordinalfi
for which there existsa limit ordinal a zzi
a(f3)
such thatWe are then able to show that there is some element h E H such that
h - xp E K~03B1(03B2),
foruncountably
many03B2-ordinals fl.
It follows that
Suppose
that h EK03B4
and let y be afi-ordinal
such thata(y)
>ô,
and
k 2013 Z03B3 ~ K~03B1(03B3).
But(h, k - z03B3) =
1 and this is a contradiction toh e Kô z K03B1(03B3).
Thus V cannot be embedded in anorthogonal
sum ofhyperbolic planes.
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[1] A. EHRENFEUCHT and V. FABER: Do infinite nilpotent groups always have equipotent
abelian subgroups? Kon. Nederl. Akad. Wet. A 75 (1972), 202-209.
[2] Yu. M. GOR010CAKOV: Locally normal groups. Sibirski~ Mat. 017D. 12 (6) (1971), 1259-1272 (Russian).
[3] P. HALL: Periodic FC-groups. J. London Math. Soc. 34 (1959), 289-304.
[4] I. KAPLANSKY: Projective modules. Ann. Math. 68 (1958), 372-377.
[5] I. KAPLANSKY: Linear Algebra and Geometry. Allyn and Bacon, 1969.
[6] M. J. TOMKINSON: Local conjugacy classes. Math. Zeit. 108 (1969), 202-212.
[7] M. J. TOMKINSON: Local conjugacy classes (II). Arch. der Math. 20 (1969), 567-571.
(Oblatum 6-1-1975 & 22-V-1975) Mathematics Department University of Glasgow Glasgow G12 8QW