A NNALES DE L ’I. H. P., SECTION A
W AWRZYNIEC G UZ
Filter theory and covering law
Annales de l’I. H. P., section A, tome 29, n
o4 (1978), p. 357-378
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357
Filter theory and covering law
Wawrzyniec GUZ
Institute of Physics, Gdansk University, Gdansk, Poland
Vol. XXIX, n~4, 1978, Physique ’ théorique. ’
ABSTRACT. 2014 The main aim of this paper is to compare the
operational approach
to quantum axiomatics with the well-known lattice theoretic one, known under the name « quantumlogic approach
», and to show someadvantages
of theformer,
which consist inresolving
the old troubles connec-ted with quantum
logics :
thequestion
of thecomplete
lattice structure ofthe
logic,
theatomicity,
and thevalidity
of thecovering
law in thelogic
of
propositions. By
the way someequivalent
forms of thecovering
property in ageneral
orthomodularorthoposet
are established and itsgeometrical
sense is clarified in some details. Also the dimension
theory
for AC-ortho- posets isdeveloped.
1. INTRODUCTION
Among
main attempts to axiomatize quantumtheory (here
we have inmind the
C*-algebraic
and the quantumlogic
theoreticalframeworks)
theso-called «
operational approach » (1),
in which the basicsignificance
isattached to the set of states and the set of
operations transforming
the formerone into
itself,
seems to be verypromising and,
at the sametime, physically
natural.
It is not a purpose of this paper to describe the
operational approach
inits all aspects. Our aim is much more
modest ;
we want to compare it with the well-known quantumlogic
axiomaticscheme,
and to show some advan-(1) This axiomatic method has been advocated and developed (mainly) by Gunson [12], Pool [26], [27], Mielnik [21], [22], [23], Davies and Lewis [4], [5], [6], Edwards [7], [8], Srinivas [28], and others.
Annales de l’Institut Henri Poincaré - Section A - Vol. XXIX, nO 4 - 1978. 14
358 W . GUZ
tages of the
operational approach. Especially,
we are aimed here to showthat in the framework of the
operational
axiomatics we are in aposition
to resolve the well-known troubles of the quantum
logic approach. Namely,
we are able to answer the
questions concerning
thecomplete
lattice structure,atomicity,
and thevalidity
of thecovering
law in thelogic
ofpropositions.
It must be
emphasized
here thatalthough
thecomplete
latticeproperty
andatomicity
can also bejustified
in the framework of thequantum logic approach by
a suitable extension of thepropositional logic (see,
e. g.[3], [16]),
the
covering law,
as yet, do not admit aunquestionable physical justification, although
manyattempts
have been made toclarify
itssignificance (see,
e. g.
[17], t/L
Here(see
Section4)
it appears as a consequence of the assumedaxioms,
any of whichbeing
of a directphysical significance. By
the way, some
equivalent
forms of thecovering
law in ageneral
ortho-modular
orthoposet
areestablished,
and itsgeometrical
sense is clarified insome detail
(see
Section3). Also,
the dimensiontheory
forAC-orthoposets
is
developed (Section 3).
2.
AXIOMS, DEFINITIONS,
NOTATIONWith each
physical
system we shall associate atriple (B, F, d) consisting
of two non-empty sets : an abstract set
B,
whose members will beinterpreted
as and the set F
of filters,
whose members aremappings
from B intoitself
(i.
e., any filter transforms beams intobeams),
and the function dfrom B into
non-negative
reals(d :
B ~R+),
called theintensity (or strength)
functional. The
properties
that we shallrequire
for thetriple (B, F, a~
willbe formulated below as axioms.
A. Basic axioms
(the
firstgroup)
AXIOM 1 AXIOM 2
The two
postulates
above expressphysically
obvious facts that every filter must act on beams as anidempotent,
and that there is no any new beamproduced by
the filter aitself,
hence theintensity
of the beam am must benecessarily
not greater than that of m.AXIOM 3
It is convenient to
adjoin
to the set of beams some fictitiousbeam,
calledthe zero
beam,
theintensity
of which is zero. This is the content of the nextaxiom :
Annales de l’ Institut Henri Poincaré - Section A
AXIOM 4
By
axioms 2 and 3 the beam mosatisfying d(mo)
= 0 isnecessarily unique;
we denote it
by
0. Of course, a0 = 0 for all a E F.Also,
it will be useful toadjoin
to the set of filters theidentity
and zerotransformations from B to B :
AXIOM 5. The transformations
I,
0 : B -~ B definedby
1m = m andOm = 0 for all m E
B, respectively, belong
to F. We call them theidentity
and the zero
filter, respectively.
The beam m in the axiom above
is, owing
to axiom3, unique;
we denote itby
t1m1 + t2m2 and call the mixtureo.f’ml the proportion t1 :
t2.Axiom 6
imposes
on the set B the structure of a convex cone. From this axiom one finds thatin
particular,
if we put a =I,
we getfor all ml, m2 E B and all tl, t2 > O.
Hence
B. Partial
ordering
andorthogonality
By
anoperdtion
on the set B of beams we shall mean anymapping
from Bto B. Of
particular importance
for us will be the set ofidempotent operations
onB,
as it contains the set F of filters as a subset.For any two
idempotent operations
P,Q
E we defineThe above-defined relation
is,
of course, apartial ordering
inNote also that the definition of the
partial ordering
aboverequires
everycomparable operations
to becompatible (in
the sense thatthey commute), which,
forfilters,
isphysically
obvious.Further,
for P,Q
EOi(B)
we defineLet us note the
following properties
of the relation 1:i)
P 1 Pimplies
P =0,
Vol. XXIX, n° 4 - 1978.
360 W. GUZ
V is used to denote the least upper
bound,
iv) 0 implies where ’ A denotes the greater lower bound o in
I 1
C. Further axioms
(the
secondgroup)
AXIOM 7. For any two
orthogonal filters a, b
EF, a
+ b is also a filter.As a consequence of the axiom above one gets
immediately
thatNote also that
AXIOM 8 AXIOM 9
From the axioms above one
easily
finds that :(1 )
The filter b in the axiom 8 isunique:
we denote itby
a’.(6)
F isorthomodular,
that EF) implies b
= a v c for some(7)
Two filters a a and c arecompatible
e , a H b, if and only y it ab E r and ab = ba.Furthermore, b,
then ab = a A b and there exists also a V b.Therefore,
we find(F,
~,1, ’, 0, I)
to be an orthomodularorthoposet (the
abbreviation «orthoposet
» one should read :orthocomplemented partially
orderedset).
D. Last axioms
(the
thirdgroup)
AXIOM 10.
2014 f)
For every non-zero filter a E F there exists ahomogeneous
beam
(4) p
such thatd(ap)
=d(p) ;
moreover :(2) As we know (see, e. g. [29]), c is uniquely determined by a and b, as c = b A a’; we denote it by b - a.
(3) The compatibility relation ~ is defined, after Mackey [18], as follows : iff
a = a~ V c and b = bl V c for some mutually orthogonal c E F.
(4) A non-zero beam m is said to be homogeneous, if it cannot be written in the form
m = t1m1 + t2m2, where th t2 are positive real numbers, and mh m2 are two other non-zero
beams, being not proportional to one another.
Poincaré - Section A
ii) If,
at the sametime, ~ ~
a, then the beam p can be chosen in sucha way that > 0.
Formally,
the axiom 10 can be written as follows :where
Bh
stands for the set of allhomogeneous
beams.The first part of the axiom above assumes that
Bh,
the set ofhomogeneous beams,
is notonly
non-empty, but alsosufficiently large.
The second part of this axiom weeasily
find to beequivalent
to thefollowing
statement, whichwas taken as a
postulate by
Gudder[10] :
(*)
If for every pure state(5)
p with 1 we have also 1(where a, b
EF),
then a b.In
fact,
assume the first part of the statement(*)
and supposethat a
b.Then a
,,~. &’,
andby
axiom 10 there exists a pure state p with = 1 and>
0,
henced(bp) 1,
which contradicts ourassumption. Conversely,
assume the
validity
of the first part of the axiom10;
then(*) implies ii).
Indeed,
let a, a ~0 ; then a &’,
andby (*)
there exists a pure state p such that = 1 and1,
the latterbeing equivalent
to > 0(The
existence of at least one pure state p withd(ap)
= 1 isguaranteed by i)).
Therefore,
our axiom 10 may be formulated in thefollowing equivalent
form
(see [16]) :
AXIOM 10’.
2014 ~)
For every non-zero filter a E F there exists a pure state p such that =1;
moreover :ii)
If for each pure state p, for which =1,
one has alsoJ(&/?) =
1 forsome b E
F, then a
b.We
complete
our list of axiomsby postulating
thefollowing (compare [19]) :
AXIOM 11. For every
homogeneous beam p
EBj~
there exists a filtera E F such that
d(ap)
= and for allhomogeneous
beams q, which are notproportional
to p.The above axiom asserts that pure beams can be realized in the labora- tory : there exists a filter
(measuring device) a
E Fanswering
theexperimental question
« Is aphysical
system in the purestate/?/~(/?) ?
o.(5) By a state we mean any normalized beam m E B (that is, satisfying d(m) = 1 ). Any homogeneous state will also be called a pure state. For states we will also write m(a) instead of d(am).
Vol. XXIX, no 4 - 1978.
362 W. GUZ
3. COVERING LAW
AND THE MINIMAL SUPERPOSITION PRINCIPLE
Suppose
F to be an atomicorthoposet.
We shall say that thecovering
law holds inF,
or that F possesses thecovering
property, ifi )
for any a E F and any atom e E F there exists a V e inF,
V e > & ~ ~
implies
either b = a or b = a V e(that is, a
V e covers a,provided e a).
THEOREM. Assume the condition
i)
to hold inF,
Fbeing
an atomicorthomodular
orthoposet. Then,
thefollowing
statements about Faremutually equivalent (6) :
(1)
Minimalsuperposition principle (abbreviated
toMSP;
compare Gudder[77]):
(2)
MSP restrieted(brieHy: MSPR;
see[15]) :
(3)
Weak MSP + Weak AEP(7) (abbreviated
to WMSP andWAEP, respectively) :
ii)
Weak AEP : If e g Vh,
h(e,
g, hbeing atoms),
then+ e (8).
(4)
condition(see
Jauch and Piron[17]) :
For any a E F and any atom e E F not contained in a, a V e - a is also an
atom.
(B) For the case, where F is a complete lattice, the equivalence of the conditions (1), (4), (5), (6) and (7) was shown by Bugajska and Bugajski [2].
(1) The abbreviation « AEP » one should read : « Atomic Exchange Property)).
(a) The symbol + is used to denote the least upper bound for orthogonal elements.
Annales de l’Institut Henri Poincaré - Section A
(5) Varadarajan’s Property (see Varadarajan [30]) :
For any a E
F,
0 aI,
and any atom e E F there exist two atoms el,e2 E F
such that a, e2 1 a and e el V e2.(6) Covering Law :
For any a E F and any atom
implies
either b = a orb = a V e.
(7)
Zierler’s Condition(see
Zierler[31 ]) :
For any three finite elements
(9)
a,b,
c E F such that b A c = 0 and a cone has a =
(a
Vb)
A c,provided (a
Vb)
A c there exists in F(1°).
Remark 1. - Note that the Weak MSP
implies
thefollowing property
of F :(**)
Vg, e ~ h (e, g, h being atoms), then g
e V h.Also,
it will be useful to note thefollowing
consequence of theCovering
Law
(6),
which is known under the name AtomicExchange Property (AEP,
in
short) :
f
e Va(a
EF ; e,f being atoms) => ~ ~ f
V a.Rernark 2. - Note that
(2)
admits asimple geometrical interpretation.
To see
this,
two cases should be considered(compare [7~]):
CASE I : e2.
Then f
= el and the property(2)
reduces to thefollowing :
which means that the line
( )
el V e3 is also determinedby
anotherpair
ofits
points ( = atoms),
e and e3.CASE II : e2.
As, according
to(2),
V e2 V e3and e e1
we have
e3 ,~
el V e2(in particular,
el, e2, e3 are alldistinct). By (2)
thenf
el V e2and f
e V e3 for someatom/ (This
means that any two distinct lineslying
in the sameplane (here,
the lines el V e2 and e V e3, which lie onthe
plane el
V e2 Ve3)
havealways
a commonpoint (When
the lines el V ~2 and e V e3 areparallel, f
becomes thepoint
atinfinity).
In otherwords,
case II tells us that two lines in the same
plane always
cut.Proof o, f ’
the theorem. Theimplications ( 1 )
=>(2)
=>(3)
arestraight-
forward. To prove the
implication (3)
=>(4),
let us consider an elemente V a - a E
F,
where a EF, e
EA(F), e ,~ a (A(F)
stands for the set of allatoms of
F). Then,
of course, e V a - a ~0, and, therefore,
there existsat least one atom contained in e V a-a. Let us suppose, in contrary to the
statement
(4),
that there are two distinct atoms such that el, e2 e V a - a, and consider theelement el
V e2 V e. One can assume, without any loss ofgenerality, that e a’,
as theinequality e a’ implies, by
the(9) A filter a E F is said to be finite, if it is a join of a finite number of atoms.
(1°) Note that a U b always exists for finite a, bE F.
(") By lines we mean such elements of F which cover atoms.
Vol. XXIX, no 4 - 1978.
364 W. GUZ
orthomodularity of
F, that e V a - a = e EA(F).
Note thate ~
ei as theinequality e
el V e2 wouldimply e a’,
which contradicts ourassumption.
Note furtherthat, owing
to theorthomodularity
ofF, el
V e2 V eV
0, hence, by
theatomicity of F,
there is an atom V e2 V e- el V e2, hence e3 el V e2 V e and
e3 e1 V e2.
Let us nowapply (4)
tothe
set {
e3, el,~2.~ }’
Note that e ~ e3, asrequired
in(4),
since e = e31 el
V e2 would
imply e
V a - a to contain an atomorthogonal
to e forinstance),
which isimpossible.
Infact, and e1
1 eimply
el 1 e V a
(as e1 a),
a contradictionwith e1 e
V a.By (4)
we see thatthere is an atom e4 such that
e4 e3
V eand e4 e1
V e2. Note thate41
e3,as el V e2 1 e3, and that e4 ~ e,
as e
elObviously,
e4 el Ve2, since theequality
e4V e2 leads
to el, e3 V e(where el
1 e3,e), hence, by WAEP,
e e3 V el,hence e2
e3 V e e3 Vel(where e2
1 e3, e2 ~ whichleads, by (**),
to a contradiction with e3 1 el Note furtherthat, by orthomodularity,
el V e2 - e4 ~ 0, thus there exists(by atomicity)
an atom e~ V e2 - e~., hencees 1
e4. Alsoe5
e3, as el V e2and el
V e21 e3. But, by WAEP,
e4 e3 V e(where e41
e3, e4 ~e) implies
e ~ e3 V e4, where e3 Ve41
e5(as
e3 and e4 are bothorthogonal
toes),
hence e 1 es. Also el V e V a - a, and therefore we have shown that e V a - a contains an atom e5orthogonal
to e,
which,
as wealready proved,
isimpossible.
Thiscompletes
theproof
of the
implication (3)
=>(4).
We shall now show that
(4) implies (5).
Lete E A(F), a E F, ~0, I;
then, by {4), e
V a - a EA(F)
or = 0(the
latter iswhen ~ =~ a).
Whene V a - a =
0,
one gets e a(by orthomodularity),
and we thus havee e +
f,
wheref
is anarbitrary
atom ~ a’. When e V ~ 2014 ~ 5~0,
wemeet two
possibilities:
and
then e e +/ where f is
anarbitrary
atom a; andIn the case
b)
wehave, by (4), e
V a’ - a’ EA(F).
Infact, e
V ~ - ~ = 0 wouldimply e a’,
hence e V a - a = e, which contradicts our assump- tionb). Applying
now(twice)
the dual version(12)
of thefollowing
lemmadue to
Varadarajan [29] :
LEMMA l. - Let L be an orthomodular
orthoposet,
and leta, a1, a2, ... E L. if a +-+ ai for each i = 1,
2,
... , and ifVai
and nai)
(12) The dual form of the lemma 1 one obtains by replacing the symbols V and A by A
and V, respectively.
de Poincaré - Section A
and
one
easily
finds thatwhich proves the
implication (4)
=>(5).
Now,
we shall show that(6)
is a consequence of(5).
This will be done intwo
steps :
first we shall prove that(5) implies (4),
and next that(4) implies (6).
Suppose (5)
to hold inF,
and let e EA(F), a
E a. One can assume,without any loss of
generality,
that ~ 5~ 0.Then, by (5),
there exist two atomssuch that V e2; hence e V a
(el
Ve2)
V a = e2 + a,and therefore
by
the lemma1,
hence This proves theimplication (5)
=>(4).
Assume now the
validity
of(4)
and then prove(6).
One needs to showthat e V a covers a,
provided e
a. Let e V a > b > a; thenhence,
as we find e V a - a to be an atomby (4),
hence,
by orthomodularity,
This proves that e V a covers a
indeed,
and therefore theimplication (4)=>(6)
is established.
Before
proving
the nextimplication,
theimplication (6)
=>(7),
one needsto
develop
the dimensiontheory
for an atomic orthomodularorthoposet
Fwith the
covering
lawholding
in it. Such anorthoposet
will be called below the AC -orthoposet.
Let A ~
A(F).
We shall say that the subset A isindependent,
if for everyLEMMA 2. Let el, ... , en be a finite set of distinct atoms of
F,
wheren > I.
Then {
el,..., ~ }
isindependent
if ansonly
iffor each i = 2, 3, ..., n.
Vol. XXIX, nO 4 - 1978.
366 W. GUZ
Proo, f.
2014 It needs to be shownonly
the « if »part
of thelemma,
as the part «only
if » is an immediate consequence of the definition ofindepen-
dence. To prove it we use arguments of
Varadarajan (see [30],
Lemma2. 6).
Assume the
validity
of(3.1)
for the...,~}
and suppose, in contrary, that this set is notindependent,
i. e.that ej Vei
forsome j,
1
j
n.By (3.1)
one findsthat j ~
n.We set, for any m n,
note
that ej fn.
Let k be the smallestpositive integer n
such that(In
viewof (3 .1 )
one finds k> j ) . Then ~ ~ But,
as k - 1 ~j,
a contradiction. The lemma is thus
proved.
As a consequence 0 Lemma 2 one gets :
LEMMA 3. - Let a E F be
finite,
say a =ei, where ei
are atoms, andi=1
be an
independent
set of atoms a. Then m h.Proof.
-Apply
the arguments used in theproof
of Lemma 2 . 7 in[30] .
As an immediate consequence of the lemma 3 we obtain :
COROLLARY 1.
.... ~ }
..., are twoindependent
n m
COROLLARY 2. - If a E F is finite and b a, & 5~
0,
then also b is finite..Proof. Apply
theorthomodularity
and theatomicity
ofF,
and nextuse the lemma 3.
COROLLARY 3.
Any
finite element of F is ajoin
ofindependent
atoms.Moreover,
these atoms can be chosen aspairwise orthogonal.
Proof. Apply
theorthomodularity
and theatomicity
ofF,
and nextuse the lemma 3.
For any finite element a E F we define its dimension to
be,
asusually,
theAnnales de l’Institut Henri Poincaré - Section A
number of elements of any
independent
set of atoms, whose lattice sum is a.By Corollary
1, this numberdepends only
on a, and not on theindependent
set in
question.
We write for thisnumber,
and call d the dimensionfunction
onFr, F~. denoting
the set of all finite elements of F. For a = 0 weset,
by definition,
= 0. Note that when ~ 7~0,
thereis, by
theatomicity,
at least one atom contained in a, so that then
~) ~
1.By
Lemma 3 we see that for any finite a E F one hasWe shall now prove that d is a true dimension function on i. e., that
except
the obvious propertythe
following
holds for d:ii)
d isstrictly increasing,
i. e., ab(a,
b EF ) implies
d(a
Vb)
+ Ab)
= + for all EFy,
for which there exists a Ab(a
11 b is thenfinite, by Corollary 2, provided a
A & 7~0).
Note that
ii)
is a consequence of the fact that > 0 for a ~0,
and of Infact, a
bimplies, by orthomodularity,
b = a + c for somenon-zero c, c 1 a, hence
by
andi)
It
now
remains to prove This will be done in three steps.First,
let~ b E
F f
beorthogonal : a
1b ;
we shall show thatLet
are
independent
sets of atoms. To prove(3 . 2)
it is now sufficient to note that theset {
el, ...,f’~,
... ,fm ~, having a
V b as its lattice sum, isindepen-
dent.
Indeed,
otherwise some member of this set has to be contained in the lattice sum of thepreceding
members(by
Lemma3),
but since such a member cannotbelong to {
el, ..., en},
as the latter set isindependent,
one then has(13) Also 0 will be regarded, by the definition, as finite, i. e. 0 E F~:
Vol. XXIX, no 4 - 1978.
368 W. GUZ
as 1 a
(in fact,
to prove(3.3)
one needs to use thefollowing simple
i=1 J-1
implication: ~ ~ ~ ~ 1
z => x =(x
Vz)
11 y, in which one puts x -j i = 1
y =
B/ /~~ = ~)?
which contradicts theindependence
of the... ~ }.
i=1
Thus the
set {
el, ...,... , fm }
isindependent indeed,
and therefored(aV b)
= n + m =d(a)
+COROLLARY 4. For any
Unite ~ ~
E >b,
also a - b isfinite,
andProof.
Finiteness of a - b follows fromCorollary
2.Further, by
ortho-modularity
of F one has a =(a - b)
+b,
which allows to beapplied
theorthoadditivity (3 . 2)
of the dimensionfunction d, by
which =d(a - b)
+ which proves the
corollary.
Our second
step
consists in theproof
of theinequality :
for finite a, b. Before
proving it,
one needs to show thefollowing
statement:n
LEMMA 4. For two filters a >
b,
if a = b Vet, where ei
are atoms,i= 1
there exist at most n
atoms~ ~
aorthogonal
with each other andorthogonal
to b such that a = b +
B//~.
f
Proof (by induction).
- Let n =1,
and let a = b el EA(F). Let fi
beatoms such
that ~ ~ ~ fi
1 b and suppose thatfz
arepairwise orthogonal.
Then,
as b b+/~ ~
one deduces from thecovering
law thatb V e1 - b
+ f~, hence, by
theorthomodularity, Ii
= b V for all i,and thus we see that i cannot be greater than 1.
Suppose
now the lemma to be true for n, and show that it is true for n + 1.Since
nr i
there
exists,
as weproved above,
at most oneatom f0 b
VVei orthogonal
Annales de , l’Institut enrz Poincaré - Section A
which
implies, owing
to thecovering law,
Now, by
the inductiveassumption
one can find at most nmutually orthogonal atoms fi, being,
at the sametime, orthogonal
tob,
such thatand therefore
where,
of course, the atoms from the’-’ }
aremutually orthogonal
and allorthogonal
to b.Thus,
we haveproved
the lemma forn +
1,
as desired.COROLLARY 5. For finite a, b E F one has
~roof. 2014 JLet a, E
r~,
an let c = a V ~ 2014 ~.suppose
c ; then,by Corollary 2,
c is finite(as
e a V b E and fromCorollary
3 we knowthat c can be written as
a j oin of pairwise orthogonal
atoms, whosenumber, being
the dimension of c, isby
Lemma 4(as a
V b = b +c)
not greater thand(a).
When c =0,
the statement(3 . 4)
is trivial. Thecorollary
is thusproved.
From aVb =
(a V b - b) + b, where a,
one findsby (3 . 2)
hence, by Corollary 5,
as claimed.
In the
last,
third step, we prove that for finite a, b E Fprovided a
A b there exists.Let c = a A
b ;
we have onapplying
twice the lemma 1as a, b ~
c’,
and at the same timeVol. XXIX, n° 4 - 1978.
370 W. GUZ
Hence, by using (3.5)
andCorollary
4 we findwhich leads to
and,
at the sametime,
hence
which is the
inequality opposite
to(3.6). Summarizing,
we have shown theproperty iii).
COROLLARY 6
(Zierter’s
condition(7)).
For anyfinite a, b,
csatisfying
a c and b A c = 0 we have a =
(a
Vb)
n c,provided (a
Vb)
n c thereexists in F.
Proof
-Applying
andtaking
into account that b = 0 andb 11 c =
0,
we findhence
Hence, by
the propertyii)
of the dimension function d we get a =(a
Vb)
A c.To close the
proof
of the theorem it remains to be shown theimplication (7) ~ ( 1 ).
Suppose (7)
tohold,
and assume that eG B/ (GrB{ ej })
for
ally =1,2,...,~
whereG={~...,~}, ~~~...,~eA(F).
Suppose
next, in contrary to( 1 ),
that there is no anatom f such
that....
I u J
being
somepartition
of the indexset {
1,2,
..., n},
I n J == 0, i. e.that
/ B/B v /B/B _
B
Then,
if weapply (7)
toAnnales de l’Institut Henri Poincare - Section A
we shall obtain
t~
hence
which contradicts the
assumptions
of( 1 ).
This proves theimplication (7)
=>( 1 ) and,
at the sametime, completes
theproof
of the theorem.4. FILTERS AS PURE OPERATIONS
It is
physically
reasonable to assume for filters thefollowing
property : AXIOM 12.Any
filter a E F transformshomogeneous
beams into homo- geneous ones.As a consequence of the axiom above one obtains :
LEMMA 5. Let
p E Bh, Bh being
the set ofhomogeneous
beams(14),
and a E F. Then :
i)
ap isproportional
to a pure state q such thatq(a)
=1,
withd(ap)
asthe coefficient of
proportionality,
i. e.where q
EB~
satisfies = = 1.ii)
ep e = pe,where p e
denotes theunique
pure state, whose carrier is e(1 s),
that
is,
pe =carr-1
e.iii) Every
atomic filter e E F is apositively-homogeneous mapping
of theset
Bh
intoitself,
i. e.for
all p
EBh
and sProof.
- Ad.i). 2014 By
axiom 12 one can write ap = sq,where q
is a pure state and s ER+,
whichimplies s
=d(ap),
as = 1. If0,
then0 and we
have q
=apjd(ap),
henceq(a)
=d[a(apjd(ap))]
=1;
ifap = 0,
then q
may be chosen as anarbitrary
pure state such thatq(a)
= 1.Ad.
ii). 2014 By i)
we get epe = = q, = 1. Hence ==
d(epe)
= = 1, hence carr q = e = carr pe, whichimplies q
(14) We put, by definition, 0 E Bh for the zero beam 0.
(15) See Section 5.
Vol. XXIX, n° 4 - 1978.
372 W . GUZ
as the
mapping
carr is one-to-one(see
Section5).
Thus we have indeed pe.where q
is a pure statesatisfying
=1,
hence(see
Section5~ q
= pe, and thereforeas claimed.
THEOREM. - Let a E
I,
and let e be anarbitrary
atom not containedin a.
Then,
there exists a V e, a V e - a is an atom, andwhere pe
is theunique
pure state with carrier e.Proof -
To prove thata V e
thereexists,
let us assume for some c E F tosatisfy
c > a, e.Then,
as peby
Lemma 5ii),
we havehence
since a’ H
e(16) (see
the property(7)
on page360).
Hence,
asby
Lemma 5i )
for some pure state p with = 1
(hence
carr pa’),
one findshence,
afterapplying
the functional d to(4.1),
one gets hencesince 0
(Indeed,
= 0 would lead to e = carr a, which contradicts ourassumption that ~ ~ a).
Theequality (4. 3)
leadsimmediately
to carr /? ~ c.
Note now that there exists a V carr j9, as a 1 carr p
(see above),
and thata V carr
p c, c and carr p c. Since(carr p)’
~ a’(16),
one findsby
the property(7)
on page 360 thatThis follows from the well-known facts (see, " e. g. [29]) that in any orthomodular orthoposet x y implies x ~ y, implies x ~ y’.
Annales de l’Institut Henri Poincare - Section A
hence, by applying
the functional d to(4 . 4)
we get~
which
implies
Collecting
theinequalities
carr p + a c = any upper bound for a and e, we find that carr /? + a
= ~ V ~, hence ~ = carr p E
A(F).
Finally, using
theinequality carry? ~ ~
and the Lemma 5 and 5~’)
one finds that
(carr p)pe
= =or that
as claimed.
COROLLARY 7. F is an
AC-orthoposet.
COROLLARY
8(~).2014If~eF~~ 0,
and if e is anyatom 1;. a’,
then there exists e Va’, e
V a’ - a’ is an atom, andProo,f: 2014 Only
the lastequality
has to beproved. By
Lemma 5i)
we getfor some pure state/?
satisfying ~)
=1, hence ~
as= wmcn completes the proot.
We thus see that the action of a filter a E F on pure states may be
equi- valently
described as the action on atomic filters e EA(F)
definedby
theformula :
This is the so-called Sasaki
projection
on the filterlogic
F.5. TWO EMBEDDINGS OF THE FILTER LOGIC
We shall say that two states ml and m2 are
mutually
exclusive or ortho-gonal [10],
and write m 1 1 m2, if for some filter a E F one has = 1 andm2(a)
= 0. Thisorthogonality
relationis, obviously, symmetric.
(17) Under another axiom system a similar theorem was proved by Gunson [12].
Vol. XXIX, no 4 - 1978.