Division-ample sets and the Diophantine problem for rings of integers
par GUNTHER
CORNELISSEN,
THANASES PHEIDASet KARIM ZAHIDI
RÉSUMÉ. Nous demontrons que le dixième
problème
de Hilbertpour un anneau d’entiers dans un corps de nombres K admet une
réponse négative
si K satisfait à deux conditionsarithmétiques (existence
d’un ensemble ditdivision-ample
et d’une courbeellip-
tique de rang un surK).
Nous lions les ensemblesdivision-ample
à
l’arithmétique
des variétés abéliennes.ABSTRACT. We prove that Hilbert’s Tenth Problem for a ring of integers in a number field K has a negative answer if K satis-
fies two arithmetical conditions
(existence
of a so-called division-ample
set of integers and of anelliptic
curve of rank one overK).
We relate
division-ample
sets to arithmetic of abelian varieties.1. Introduction
Let K be a number field and let
©K
be itsring
ofintegers.
Hilbert’sTenth Problem or the
diophantine problem
for6’K
is thefollowing:
isthere an
algorithm (on
aTuring machine)
that decides whether anarbitary diophantine equation
with coefficients inBK
has a solution in©K.
The answer to this
problem
is known to benegative
for K =Q ([5])
andfor the
following
fields Kby
reduction to the field K =Q:
K ofcomplex degree
2 over atotally
real field(Denef and Lipshitz [6], (7J, [8]),
I~ withexactly
onepair
ofcomplex embeddings (Pheidas [9]
andShlapentokh [14 )
and subfields of all those
(including cyclotomic fields,
and hence all abeliannumber
fields; Shapiro
andShlapentokh [12]).
This reduction consists infinding
adiophantine
model(cf. [3])
forinteger
arithmetic overOK.
Theproblem
is open forgeneral
number fields(for
a survey see[10]
and[13]),
but has been solved
conditionally,
e.g.by
Poonen(11J (who
shows that theset of rational
integers
isdiophantine
over6’K
if there exists anelliptic
Manuscrit requ le 8 janvier 2004.
The authors thank Jan Van Geel for very useful help and encouragement. The third author
was supported by a Nlarie-Curie Individual Fellowship (HPrvIF-CT-200I-0I384).
curve over
Q
that has rank one over bothQ
andK) .
In this paper, wegive
a moregeneral
condition as follows:Theorem 1.1. The
diophantine problem for
thering of integers ®,~ o f a
numbers
field
K has anegative
answerif
thefollowing
exist:(1)
anelliptic
curvedefined
over Kof
rank one overK;
(2) a division-ample
set A C~.
Definition. A set A C
6’K
is calleddivision-ample
if thefollowing
threeconditions are satisfied:
~
(diophantineness)
A is adiophantine
subset of©K;
~
(divisibility-density) Any
E(JK
divides an element ofA;
~
(norm-boundedness)
There exists aninteger
>0,
such that for anya
E A,
there is aninteger a
E Z with adividing a
andProposition
1.1. A divisionample
set existsif
either(1)
there exists an abelianvariety
G overQ
such that(2)
there exists a commutative(not necessarily complete)
groupvariety
Gover Z such that
G(®K)
is,finitely generated
and such that rkG(Z) rkG(llK)
> 0.From
(1)
in thisproposition,
it follows that our theorem includes that ofPoonen,
but it isolates the notion of"division-ampleness"
and shows it canbe satisfied in a broader context. It would for
example
beinteresting
to construct, for agiven
number fieldK,
a curve overQ
such that its Jacobiansatisfies this condition.
As we will prove
below, part (2)
of thisproposition
is satisfied for the relative norm one torus G =ker(NKL)
for a number field Llinearly disjoint
from
K,
if K isquadratic imaginary (choosing
Ltotally real).
It would be
interesting
to know otherdivision-ample sets,
inparticular,
such that are not subsets of the
integers.
The
proof
of theorem 1.1 will usedivisibility
onelliptic
curves and aLemma from
algebraic
numbertheory
of Denef andLipshitz.
Some ofour
arguments
are similar to ones in~11J,
but we have avoided continuousreference both for reasons of
completeness
and because our results have been obtainedindependently.
2. Lemmas on number fields
In this Section we collect a few facts about
general
number fields which willplay a
role insubsequent proofs.
Fix K to be a numberfield,
let© _
OK
be itsring
ofintegers,
and let h denote the class number of 0.Let N =
N/1
be the norm from K toQ,
and let n =[K : Q]
denote thedegree
of K.Let ~ I
denote "divides" in 0.First of
all,
we will say a subset S C Kn is"diophantine
over 61" if its set ofrepresentatives
,S’ C(V
x(V - 101))n given by
is
diophantine
over (j. Recall that ‘’~~
0" isdiophantine
over 61([8] Prop.
1(b)),
hence S isdiophantine
over V if andonly
if it isdiophantine
over K.Recall that there is no
unique
factorisation ingeneral
numberfields,
butwe can use the
following
valuation-theoreticremedy:
Definition. Let x E K. If
xh = b
fora, b
E 61 with(a, b)
= 1(the
idealgenerated by
a andb),
we say that a = is a weak numerator and b = is a weak denominator for ~.Lemma 2.1.
(1)
For any x E K a weak nurraerator and a weak denorra- inator exists and isunique
up to units.(2) for
any valuation v,(3)
For a E(j,
x EK, "a
=wn(x)
" and "a =wd(x)
" arediophantine
over (j.
Proof.
Since 6 is a Dedekindring, (x)
has aunique
factorisation in frac- tional idealsWe let a be a
generator
for theprincipal
ideal(~1 ~ ~ ~
and b agenerator
for(qi "’ qs)h;
these areobviously
a weaknumerator/denominator
for x.Uniqueness, (2)
and(3)
are obvious. DLemma 2.2
(Denef-Lipshitz [8]). (1) If u
E Z -{0} and fl satisfy
the
divisibility
conditionthen
for
anyembedding
cr : K - C(2) If ii
E Z -f 01,
q E Zand ~
E 0satisfy (*)u for
anyembeddings
a : K ~ C q mod
u. then ~
E Z.Proof. Easy
to extract from theproof
of Lemma 1 in[8].
D3. Lemmas on
elliptic
curvesLet E denote an
elliptic
curve of rank one overK,
written in Weierstrass form aslet T be the order of the torsion group of
E(K),
and let P be agenerator
for the freepart
ofE(K).
Define Xn, Yn E Kby
nP =(xn,
Lemma 3.1. For any
integer
r the setrE(K)
isdiophantine
over Kand, if r is
divisibleby T,
thenrE(K) = (rP) 2-~~ (Z, +).
Proof.
Apoint (~, y)
E K x Kbelongs
torE(K) - {0}
if andonly
if3
(xo, yo) E E(K) : (~, y) = r(xo, yo).
As the addition formulae on E arealgebraic
with coefficients fromK,
this is adiophantine
relation. The laststatement is obvious. D
Lemma 3.2
([2]
for K= Q, [11]).
There exists aninteger
r > 0 such thatfor
any non-zerointegers
Proof.
We reduce the claim to a statement about valuationsusing
Lemma2.1(ii).
Thetheory
of the formal group associated to Eimplies
that ifn = mt and v is a finite valuation of K such that
0,
then2v(t) v(xrm) ([15] VII.2.2).
For the converse, we start
by choosing
ro in such a way thatroP
isnon-singular
modulo all valuations v on K.By
the theorem of Kodaira- N6ron([15], VII.6.1),
such ro exists and itactually
suffices to take ro =4
TIv V(AE),
whereAE
is the minimal discriminant ofE,
and theproduct
runs over all finite valuations on K for which
V(AE) 0
0. Note thatthen,
v(xron)
0 ~ronP
= 0 in the groupEv
ofnon-singular points
of Emodulo v.
We claim that for an
arbitrary
finite valuation v onK,
if 0and
0,
then0,
where(., .)
denotes thegcd
in Z.Indeed,
thehypothesis
meansromP
=ronP =
0 inE2;.
Since there existintegers a, b
E Z with(rom, ron)
= -~-bron,
we find(rom, ron)P
= 0in
Ev,
and hence the claim.The main theorem of
[1]
states that for anysufficiently large uT ( >
there exists a finite valuation v such that 0 but 0 for all i M. We choose r =
roMo.
Pick such a valuation v for All = Thehypothesis implies
thatv(xrn)
0 and hence 0. Butr(m, n)
rm and 0 for any i rm. Hencer(m, n)
= rrn so mdivides n. D
Lemma 3.3.
Any ~
divides the weak denominatorof
some x,n.Proof.
The set is finite but containsf nP
mod Hence thereTherefore, ~
divides DLemma 3.4. Let rrL, n, q be
integers
with n = mq. ThenProof.
The formal power seriesexpansion
for addition on E around 0([15], IV.2.3) implies
that xn =q xm
+O ( ( ) 2 ) ,
whence the result. Dyn ym
4. Proof of the main theorem
Let ~
E 61. Given anelliptic
curve E of rank one over K as in the maintheorem,
we use the notation from Section 3 for this E - inparticular,
choose a suitable r such that Lemma 3.2
applies;
we also choose £ whichcomes with the definition of A. We claim that the
following
formulaegive
a
diophantine
definition of Z in 6:4.1.
Any ~
E Z satisfies the relations.If ~
EZ,
then a usatisfying (2)
exists because A is division-dense.By
Lemma3.3,
there exists an msatisfying (3)
for this u. Define n =m~
for this m. Then(1)
is automaticand
(4)
is the contents of Lemma 3.4.4.2.
A ç satisfying
the relations is rational.Let q
E Zsatisfy
ra = qm(which
existsby (1)).
Then Lemma 3.4implies
thatwhich can be combined with
(4) using
the non-archimedeantriangle
in-equality
togive
By (3),
then alsoulç -
q.By
norm-boundedness of A we can find 11 E Z such that and We still haveCondition
(2) implies
that Lemma2.2(1)
can beapplied
with inplace of ,
so for anycomplex embedding (J
of K we findBecause of
(*)
and(**),
we canapply
Lemma2.2(2)
toconclude ~
E Z.4.3. The relations
(1)-(4)
arediophantine
over 0.By
2.1 and3.1,
for a E
0,
the relations 3n E rTZ : a =wn(xn)
and 3n E rTZ : a =wd(x,n)
are
diophantine. By
thediophantineness
ofA,
themembership u
E A isdiophantine, and u #
0 isdiophantine ([8], Prop. 1(b)).
Condition(1)
is
diophantine
because of Lemma 3.2. Conditions(2)-(4)
areobviously
diophantine using
2.1. D5. Proof of the
proposition
and discussion ofdivision-ample
sets5.1.
Rank-preservation
over(a. Suppose
there exists an abelianvariety
G of dimension d over
Q
such that rkG(Q)
= rkG(K)
> 0(note
thatG(K)
is
finitely generated by
the Mordell-Weiltheorem).
Let T denote the(finite)
order of the torsion of
G(K)
and consider the free groupTG(K) !I-’-
Z’~.The
assumption implies
thatG(Q)
is of finite index[G(K) : G(Q)]
inG(K).
The choice of anample
line bundle on Ggives
rise to aprojective embedding
of G in someprojective
space with coordinates where G is cut outby finitely
manypolynomial equations
and the addition on G isalgebraic
in those coordinates.Suppose {ti}
arealgebraic
function of thecoordinates,
and local uniformizers at the unit0 == (1 : 0 : ... : 0) of G (i.e., ~G,o = (~ ~~tl, ... , td~~).
DefineAG
:= P ET[G(K) : G(Q)] . G(K)
andti(P) = 1}.
We claim that
AG
isdivision-ample. Indeed,
the three conditions are sat-isfied :
(a) AG
isobviously diophantine
over 0(the diophantine
definition comesfrom the chosen
embedding
ofG).
(b)
Theanalogue
of Lemma 3.3 remainsvalid,
soAG
isdivisibility-dense.
Indeed,
it suffices to prove that agiven
non-zerointeger ~
dividest2(NP)
for some N
(where 1).
SinceG(Z/~)
isfinite,
there is a non-zeroN for wich NP = 0 mod
~,
and thent2(NP)
= 0 mod~.
(c)
Sinceby assumption,
all elements ofAG
are inZ,
we can set a = a,~ = n for any a E
AG
toget
therequired
norm-boundedness.Remark. From available
computer algebra,
the construction ofelliptic
curves which fit the above can be automated. One can compute ranks of
elliptic
curves overQ quite
fastusing
mwrankby
J. Cremona[4],
andover number fields
using
thegp-package
of D. Simon[16].
Michael Stollhas written a
MAGMA-package
thatcomputes
the rank of Jacobians of genus two curves overQ ([17]). Unfortunately,
the current state of affairs incomputational
arithmeticalgeometry
doesn’t include analgorithm
forthe rank of abelian varieties of dimension > 2 over
arbitrary
number fields(although
the necessary descenttheory exists).
We will therefore restrictto
examples involving elliptic
curves.Example.
In thestyle
of Poonen’sresult,
theelliptic curve y2
=.x,3
+ 8xhas rank one over
Q
and overQ (ij2)
and(a ( 4 2) . However,
thiscurve
acquires
rank two over(a( 5 2).
The
curve y2 = x3 +
14x has rank two overQ
and over(a( 5 2),
and thecurve y 2 = :c3
+ + 8x has rank one over(a( ’’ 2).
We conclude that the
diophantine theory
of thering
ofintegers
of(a( ’~ 2)
is undecidable for n 5
(n
3 also coveredby
knownresults).
Remark. We ask:
given K,
can one construct in some clever way a curve C overQ
such that its Jacobian satisfies the above conditions?5.2.
Rank-preservation
over Z. A similar construction(of
which weleave out the
details)
can beperformed
if there exists a commutative(not necessarily complete)
groupvariety
G over Z such thatG(0)
isfinitely generated
and such thatrk G(Z)
=rk G( 0)
> 0. We will work out an easyexample. Maybe
a variation of thisexample
canhelp
one eliminate thesecond condition in the main theorem.
Example.
Let L be another numberfield, linearly disjoint
from K. Let(ai)
denote a Z-basis forL/Q (this
is also a basis for6KL
over LetTL
denote the norm one torus = 1. Then°L
andhence
(by surjectivity
of the relativenorm)
=In
particular, TL(0k)
=TL(Z)
iffwhere rvl, denote the number of
real, respectively
half the number ofcomplex embeddings
of a number field M. If L and I~ arelinearly disjoint,
rKL = rKrL, and the condition
simplifies
toThe
only
non-trivial solution is =0,
sk~ = 1(i.e.,
I~complex quadratic) choosing
rL >1, sL
= 0.Remark. In all these
examples, division-ample
sets areactually
subsets ofthe
integers.
Can one find adivision-ample
set which does not consists ofjust ordinary integers?
Remark
(December 2005).
Mazur and Rubin have shown that there existinfinitely
many number fields over which the rank of everyelliptic
curvedefined over
Q
is even,assuming
theParity Conjecture.
Morespecifically, they
show that ifE/Q
is anelliptic
curve andK/Q
a Galois extension such thatGal(K/Q)
has anon-cyclic 2-Sylow
and such that the discriminant of E iscoprime
to that ofK,
then the root number ofE/K
is -~-1(compare:
Rubin,
talk atAIM-workshop (2005);
Rubin and Mazur in:Kazuya
Kato’sBirthday
volume of Doc. Math.(2003),
pp.585-607).
On the other
hand,
Poonen andShlapentokh
have remarked that theargument
in[11]
continues to hold under the weakerassumption
that thereexists an
elliptic
curve overQ retaining
itspositive
rank over the numberfield K
(not necessarily
of rankone),
see:Poonen,
talk atAIM-workshop (2005); Shlapentokh, Elliptic
CurvesRetaining
Their Rank in Finite Ex- tensions and Hilbert’s TenthProblem, preprint (2004).
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Gunther CORNELISSEN Mathematisch Instituut Universiteit Utrecht Postbus 80010
3508 TA Utrecht, Nederland E-mail : cornelissen@math.uu.nl
Thanases PHEIDAS
Department of Mathematics
University of Crete
P.O. Box 1470
Herakleio, Crete, Greece
E-mail : pheidas@math . uoc . gr
Karim ZAHIDI
Equipe de Logique Math6matique U.F.R. de Math6matiques (case 7012)
Universite Denis-Diderot Paris 7 2 place Jussieu
75251 Paris Cedex 05, France Adresse actuelle:
Departement Wiskunde, Statistiek & Actuariaat Universiteit Amtwerpen
Prinsstraat 13
2000 Antwerpen, Belgi6
E-mail : zahidi(Dlogique.jussieu.fr