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Central limit theorem for stationary products of toral automorphisms

Jean-Pierre Conze, Stéphane Le Borgne, Mikaël Roger

To cite this version:

Jean-Pierre Conze, Stéphane Le Borgne, Mikaël Roger. Central limit theorem for stationary products

of toral automorphisms. Discrete and Continuous Dynamical Systems - Series S, American Institute

of Mathematical Sciences, 2012, 32 (5), pp.1597-1626. �10.3934/dcds.2012.32.1597�. �hal-00681695�

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Volume

32

, Number

5

, May

2012 pp.1597–1626

CENTRAL LIMIT THEOREM FOR STATIONARY PRODUCTS OF TORAL AUTOMORPHISMS

Jean-Pierre Conze, St´ ephane Le Borgne and Mika¨ el Roger

IRMAR, UMR CNRS 6625, Universit´ e de Rennes I Campus de Beaulieu, 35042 Rennes Cedex, France

(Communicated by Carlangelo Liverani)

Abstract. Let (A

n

(ω)) be a stationary process in M

d

(Z). For a H¨ older func- tion f on T

d

we consider the sums P

n

k=1

f (

t

A

k

(ω)

t

A

k−1

(ω) · · ·

t

A

1

(ω) x mod 1) and prove a Central Limit Theorem for a.e. ω in different situations in par- ticular for “kicked” stationary processes. We use the method of multiplicative systems of Koml` os and the Multiplicative Ergodic Theorem.

1. Introduction. Let (M n ) n ≥ 1 be a sequence in the set M d (Z) of d × d non singular matrices with coefficients in Z. It defines a sequence of endomorphisms of the torus.

The general question of the central limit theorem (CLT) for S n f = P n

k=1 f ( t M k .), for a regular real function f on T d , covers different particular cases. If d = 1, it corresponds to arithmetic sums P n − 1

k=0 f (q k x) and, for lacunary sequences of positive integers (q n ), it has been studied by several authors (Fortet, Kac, Salem, Zygmund, Gaposhkin [11], Berkes [5], recently Berkes and Aistleitner [1]).

Another situation is for d > 1 the action on T d of a product t M k = t A 1 ... t A k , with A k ∈ M d (Z). The sequence of maps obtained by composition of the transfor- mations

1

τ n x = t A n x mod 1 can be viewed as a non autonomous or “sequential”

dynamical system.

Analogous examples of sequential dynamical systems on a probability space have been studied, for example in [17] for transformations chosen at random in the neigh- borhood of a given one, in [4] for a non perturbative case with geometrical assump- tions on the transformations, in [9] for expanding maps of the interval.

Here we will mainly consider different examples of stationary, not necessarily independent, processes (A k (ω)) in M d (Z) and address the question of the CLT with respect to the Lebesgue measure λ on T d for almost every ω (and the non degeneracy of the limit law) for

S n f (ω, x) =

n

X

k=1

f ( t A k (ω) t A k − 1 (ω) · · · t A 1 (ω)x mod 1). (1) In Section 2 we give sufficient conditions on (A n ) for the convergence of the distri- bution of k S 1

n

k

2

S n f toward a normal law with a small rate. The proof is based on

2000 Mathematics Subject Classification. 60F05, 37A30, 60G10, 37D99.

Key words and phrases. Toral automorphisms, central limit theorem, multiplicative system, kicked stationary process, Lyapunov exponents.

1

For simplicity of notations, it is convenient to act on the torus by transposed matrices.

1597

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the method of “multiplicative systems” (cf. Koml` os [12]). We give also an example where a coboundary condition leads to a non standard normalisation.

Section 3 is devoted to the stationary case and the question of the CLT for a.e. ω for the sums (1). We consider an ergodic dynamical system (Ω, µ, θ), where θ is an invertible measure preserving transformation on a probability space (Ω, µ) and the skew product defined on (Ω × T d , µ × λ) by θ τ : (ω, x) 7→ (θω, t A(ω)x mod 1), where ω → A(ω) is a measurable map from Ω to a finite set A of matrices in M d ( Z ).

Under some conditions we obtain a strong mixing property for this skew product and show that for regular functions the variance exists and is not zero.

The abstract results are then applied to explicit models. When the elements of A are 2 × 2 positive matrices, the CLT holds for every sequence under a variance condition. In particular the CLT holds for a.e. ω in the stationary case. There the invariant positive cone plays an essential role like in [2] where analogous problems have been studied. In dimension 2 we consider also “kicked systems” introduced by Polterovich and Rudnick, who proved a stable mixing property for this model. For stationary kicked processes, which can be viewed as a perturbation of the iteration of a single automorphism, we obtain a CLT for a.e. ω. In a last subsection we show the non nullity of the variance for “stationary” arithmetic sums in dimension 1.

2. Multiplicative systems and CLT.

2.1. Preliminaries, a criterion of Koml` os for multiplicative systems.

Notation. Let d be an integer ≥ 2 and k · k be the norm on R d defined by k x k = max 1 ≤ i ≤ d | x i | , x ∈ R d . We denote by δ(x, y) := inf n

Zd

k x − y − n k the distance on the torus. The characters on T d are χ n : x → χ(n, x) := e 2πi h n,x i , n = (n 1 , ..., n d ) ∈ Z d . Often C will denote a “generic” constant which may change from a line to the other.

The Lebesgue measure λ on T d is invariant by surjective endomorphisms of the torus. The space of functions f in L 2 (T d , λ) such that λ(f ) = 0 is denoted by L 2 0 ( T d ) and the Fourier coefficients of f ∈ L 2 ( T d ) by ˆ f (p) or f p , p ∈ Z d . The degree of a trigonometric polynomial g on T d is less than D (notation deg(g) ≤ D), if ˆ g(p) = 0, for k p k > D. In what follows all trigonometric polynomials will be centered.

We denote by H 0 (T d ) the space of bounded functions f in L (T d ) with null integral such that, for a constant C and α ∈ ]0, 1], k f (. − t) − f (.) k 1 ≤ C k t k α ,

∀ t ∈ T d .

The α-H¨older functions for some α ∈ ]0, 1], as well as the characteristic function of regular sets belong to H 0 (T d ) (a subset E ⊂ T d is regular if there exists C > 0 and α ∈ ]0, 1] such that λ( { x ∈ T d : δ(x, ∂E) ≤ ε } ) ≤ Cε α , ∀ ε > 0.) Therefore the statements about functions in H 0 (T d ) below are valid in particular for the usual H¨ older functions.

We will use the following approximation result:

Proposition 1. For every f ∈ H 0 (T d ), there exist α ∈ ]0, 1] and a sequence of

trigonometric polynomials g n such that deg(g n ) ≤ n, k g n k ∞ ≤ k f k ∞ , k g n k 2 ≤ k f k 2

and k g n − f k 2 = O(n α ).

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Proof. a) Let K n (t) = K n (t 1 )...K n (t d ) be the Fej´er kernel in dimension d ≥ 1, where K n (t 1 ) = n 1 sin sin

22

(πnt (πt

11

) ) . For every β ∈ ]0, 1], there exists a constant C such that

Z

K n (t) k t k β dt = [ Z

k t k≥

1n

+ Z

k t k <

n1

] K n (t) k t k β dt

≤ C n

d

X

i=1

Z

| t

i

|≥

n1

| t i | β 2 dt i + n β

≤ 2Cd n

n 1 β

1 − β + n β = O(n β ).

For f in H 0 , K n ∗ f is a trigonometric polynomial of degree ≤ n such that k K n ∗ f k ∞ ≤ k f k ∞ , k K n ∗ f k 2 ≤ k f k 2 . There is β ∈ ]0, 1] such that:

k K n ∗ f − f k 1 ≤ Z Z

K n (t) | f (x − t) − f (x) | dt λ(dx)

= Z

K n (t) k f (. − t) − f (.) k 1 dt

= O(

Z

K n (t) | t | β dt) = O(n β ).

Therefore we obtain, with α = β/2: k K n ∗ f − f k 2 ≤ (2 k f k ∞ )

12

k K n ∗ f − f k 1

12

= O(n α ).

Recall the notation M d (Z) for the set of d × d invertible matrices with coefficients in Z. In what follows, (M k ) is a sequence in M d (Z). For a function f on T d we denote by S n f (x) or simply S n (x) the sums S n f (x) = P n

k=1 f ( t M k x).

A special case (product case) is when M k is a product: M k = A 1 ...A k , where (A k ) is a sequence in M d (Z). To the action of a product of matrices in M d (Z) on T d corresponds a dual action on the characters by the transposed matrices with composition on the right side. For simplicity of notations, we choose to act on T d by the transposed matrices t M k . For j ≥ i ≥ 0, with the convention A 0 = A 0 0 = Id, A j 0 = A j 1 , we write

A j i := A i . . . A j . (2)

A function f in L 2 0 (T d ) satisfies the decorrelation property, if there are constants C(f) and 0 < κ(f ) < 1 such that

| Z

Td

f ( t M ℓ+r x) f ( t M ℓ x) dx | ≤ C(f ) κ(f ) r , ∀ r, ℓ ≥ 0. (3) A criterion of Koml` os

In the proof of the central limit theorem for products of toral automorphisms we use the following lemma on “multiplicative systems” (cf. Koml`os [12]) (see [14]

for another application of this method). The quantitative formulation of the result yields a rate of convergence in the CLT.

Lemma 2.1. Let u be an integer ≥ 1 and a be a real positive number. Let

(ζ k ) 0 ≤ k ≤ u − 1 be a sequence of length u of real bounded random variables defined

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on a probability space (X, λ). Let us denote, for t ∈ R:

Z(t, .) = exp(it

u − 1

X

k=0

ζ k (.)), Q(t, .) =

u − 1

Y

k=0

(1 + itζ k (.)),

Y =

u − 1

X

k=0

ζ k 2 , δ = max

0 ≤ k ≤ u − 1 k ζ k k ∞ .

Under the conditions | t | δ ≤ 1, | t |k Y − a k 2

12

≤ 1, λ[Q(t, .)] ≡ 1, k Q(t, .) k 2 = O(e

12

a t

2

), there is a constant C such that

| λ[Z(t, .)] − e

12

a t

2

| ≤ C(u | t | 3 δ 3 + | t |k Y − a k 2

12

). (4) Proof. 1) Setting ψ(y) = (1 + iy)e

12

y

2

e iy = ρ(y)e iθ(y) , where ρ(y) = | ψ(y) | , we have

ln ρ(y) = 1

2 [ln(1 + y 2 ) − y 2 ] ≤ 0, tan(θ(y)) = y − tan y 1 + y tan y . An elementary computation gives the upper bounds

| ln ρ(y) | ≤ 1

4 | y | 4 , | θ(y) | = O( | y | 3 ), ∀ y ∈ [ − 1, 1]. (5) Let us write: Z(t, .) = Q(t, .) exp( − 1 2 t 2 Y ) [ Q u − 1

k=0 ψ(tζ k )] 1 . As ln ρ(tζ k ) ≤ 0, we have:

| Z(t, .) − Q(t, .) exp( − 1

2 t 2 Y ) | = | Z(t, .) − Z(t, .)

u − 1

Y

k=0

ψ(tζ k ) |

= | 1 −

u − 1

Y

k=0

ψ(tζ k ) | ≤ | 1 − e

Pu−1k=0

ln ρ(tζ

k

) | + | 1 − e i

Pu−1k=0

θ(tζ

k

) |

u − 1

X

k=0

| ln ρ(tζ k ) | +

u − 1

X

k=0

| θ(tζ k ) | .

If | t | δ ≤ 1, where δ = max k k ζ k k ∞ , we can apply (5) and obtain for a constant C:

| Z (t, .) − Q(t, .) e

12

t

2

Y | ≤ C | t | 3

u − 1

X

k=0

| ζ k | 3 ≤ Cu | t | 3 δ 3 . (6) 2) For 0 ≤ ε ≤ 1, let A ε (t) = { x : t 2 | Y (x) − a | ≤ ε } . Using (6) and λ[Q(t, .)] ≡ 1, we get

| λ[Z(t, .) − e

12

a t

2

] | ≤ | λ[1 A

ε

(t) (Z(t, .) − Q(t, .)e

12

a t

2

)] | + 2λ(A c ε (t))

≤ C u | t | 3 δ 3 + λ[1 A

ε

(t) e

12

a t

2

| Q(t, .) [e

12

t

2

(Y a) − 1] | )]

+2λ(A c ε (t)).

From the inequality | 1 − e s | ≤ (e − 1) | s | ≤ 2 | s | , ∀ s ∈ [ − 1, 1], we have k 1 A

ε

(t) [e

t22

(Y a) − 1] k 2 ≤ ε.

Choosing ε = | t |k Y − a k 2

12

, we get λ(A c ε (t)) ≤ ε 2 t 4 k Y − a k 2 2 ≤ t 2 k Y − a k 2 ; hence

| λ[1 A

ε

(t) (Z(t, .) − e

12

a t

2

] | ≤ C [u | t | 3 δ 3 + | t | e

12

a t

2

k Q(t, .) k 2 k Y − a k 2

12

+t 2 k Y − a k 2 ].

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Thus, with the assumptions of the lemma, we obtain (4).

2.2. Separation of frequencies and growth of the matrices. In order to ap- ply Lemma 2.1 to S n f(x) = P n

k=1 f ( t M k x), we need a property of “separation of frequencies” which is expressed in the following property.

Property 1. Let D, ∆ be positive reals. We say that the property S (n, D, ∆) holds for a set (M 1 , . . . , M n ) of n ≥ 1 matrices in M d (Z) if the following condition is satisfied:

Let s be an integer ≥ 1. Let 1 ≤ ℓ 1 ≤ ℓ 1 < ℓ 2 ≤ ℓ 2 < ... < ℓ s ≤ ℓ s ≤ n be any increasing sequence of 2s integers, such that ℓ j+1 ≥ ℓ j + ∆ for j = 1, ..., s − 1.

Then for every vectors p 1 , ..., p s and p 1 , ..., p s in Z d such that k p j k , k p j k ≤ D, for j = 1, ..., s, we have

M ℓ

s

p s + M ℓ

s

p s 6 = 0 ⇒

s

X

j=1

[M ℓ

j

p j + M ℓ

j

p j ] 6 = 0. (7) Property S (n, D, ∆) for (M 1 , . . . , M n ) implies in particular the following. Let ℓ 1 < ℓ 2 < ... < ℓ s ≤ n be an increasing sequence of s integers such that ℓ j+1 ≥ ℓ j +∆

for j = 1, ..., s − 1; then, for every family p 1 , ..., p s ∈ Z d such that k p j k ≤ D for j = 1, ..., s,

p s 6 = 0 ⇒

s

X

j=1

M ℓ

j

p j 6 = 0. (8)

Conditions on the growth of k M n p k

We introduce conditions on the growth of M n . Condition 1 ensures a decorre- lation property. Condition 2 (or Inequality (11) for products) is used for the sep- aration of frequencies property. Condition 3, which is uniform with respect to the choice of the blocks, is satisfied by two families of examples, matrices in SL(2, Z + ) and “kicked” processes.

Condition 1. There is C 1 > 0 such that, for every D ≥ 1, for every q, p ∈ Z d \ { 0 } with k q k , k p k ≤ D,

M ℓ+r q 6 = M ℓ p, ∀ r > C 1 ln D, ∀ ℓ ≥ 0. (9) In the product case, i.e. when M n = A 1 ...A n , (9) reads:

A ℓ+r q 6 = p, ∀ r > C 1 ln D, ∀ ℓ ≥ 0. (10) Condition 2. (M n = A 1 ...A n ) There are constants γ > 1 and C 1 , c > 0 such that

k A 1 q k ≥ cγ r k A 1 r k , ∀ ℓ ≥ r ≥ C 1 ln k q k , ∀ q ∈ Z d \ { 0 } . (11) Condition 3. There are constants γ > 1 and δ, C 1 , c > 0 such that

∀ A 1 , ..., A r ∈ A , k A 1 ...A r q k ≥ c k q k δ γ r , ∀ r > C 1 ln k q k , ∀ q ∈ Z d \ { 0 } . (12) Note that (11) and (12) imply (10). The following condition is a reinforcement of the previous conditions and expresses the “superlacunarity” of the sequence (M n ).

Condition 4. There are positive constants δ, C 1 , c and a sequence (γ ℓ ) ℓ ≥ 1 of num- bers > 1 with lim ℓ γ ℓ = + ∞ such that, for every q ∈ Z d \ { 0 } ,

k M ℓ+r q k ≥ cγ r k M ℓ k , ∀ ℓ ≥ 1, ∀ r ≥ C 1 ln k q k . (13)

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In the scalar case d = 1, the matrices M n are numbers q n . This corresponds to the hypothesis lim n q n+1 /q n = + ∞ . Condition 4 implies the following one:

Condition 5. There is a sequence (c 2 (ℓ)) ℓ ≥ 1 of positive numbers with lim ℓ c 2 (ℓ) = 0 such that, for every D ≥ 1, for every q, p ∈ Z d \ { 0 } with k q k , k p k ≤ D,

M ℓ+r q 6 = M ℓ p, ∀ ℓ ≥ 1, ∀ r > c 2 (ℓ) ln D. (14) Decorrelation

The next proposition shows that Condition 1 implies the decorrelation property (3).

Proposition 2. 1) Assume Condition 1 (i.e. (9) or, in the product case, (10)). If g is a trigonometric polynomial of degree D, then we have:

Z

Td

g( t M ℓ+r x) g( t M ℓ x) dx = 0, ∀ r ≥ C 1 ln D, ∀ ℓ ≥ 0.

For f, f ∈ H 0 ( T d ) there are constants C and κ < 1 such that

| Z

Td

f ( t M ℓ x) f ( t M ℓ+r x) dx | ≤ Cκ r , ∀ r, ℓ ≥ 0, (15) k S n f k 2 2 = k

n

X

k=1

f ( t M k .) k 2 2 = O(n). (16) 2) If Condition 5 holds, then for every f ∈ H 0 ( T d )

lim n

1

n k S n f k 2 2 = k f k 2 2 . (17) Proof. 1) Let g(x) = P

0< k p k≤ D g p χ(p, x) be a trigonometric polynomial of degree D ≥ 1. By Condition 1 we have for all ℓ ≥ 0:

h g ◦ t M ℓ , g ◦ t M ℓ+r i λ = X

0< k p k , k q k≤ D

Z Z

g p χ(M ℓ+r p, x))(g q χ(M ℓ q, x)) dx

= X

0< k p k , k q k≤ D

g p g q 1 M

ℓ+r

p=M

q = 0, ∀ r ≥ C 1 ln D.

Let f ∈ H 0 (T d ). Let c 1 > 1 be such that ln c 1 < 1/C 1 . Proposition 1 shows that there exist C = C(f ), α ∈ ]0, 1] and for every r ≥ 1 a trigonometric polynomial g r with deg(g r ) ≤ c r 1 such that k g r − f k 2 ≤ Cc 1 αr . The choice of c 1 implies h g r ◦ t M ℓ+r , g r ◦ t M ℓ i = 0. Hence

|h f ◦ t M ℓ+r , f ◦ t M ℓ i| ≤ |h (f − g r ) ◦ t M ℓ+r , f ◦ t M ℓ i|

+ |h g r ◦ t M ℓ+r , g r ◦ t M ℓ i| + |h g r ◦ t M ℓ+r , (f − g r ) ◦ t M ℓ i| ≤ 2C k f k 2 c 1 αr . Therefore we get (15) with κ = c 1 α when f = f. In the same way we obtain (15) for f, f in H 0 ( T d ). For the variance we have

1

n k S n f k 2 2 = 1 n

n − 1

X

ℓ=0 n − 1

X

=0

Z

Td

f ( t M ℓ x) f ( t M ℓ

x) dx

= k f k 2 + 2 n

n − 1

X

r=1 n − 1 − r

X

ℓ=0

Z

Td

f ( t M ℓ x) f ( t M ℓ+r x) dx

≤ k f k 2 2 + 2C(f ) k f k 2

n − 1

X

r=1

(1 − r

n )κ r ≤ k f k 2 2 + 2C(f )κ

1 − κ k f k 2 < + ∞ .

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2) Let us consider the superlacunary case and suppose (14) of Condition 5. Let f ∈ H 0 (T d ). Let θ(ℓ) > 1 with lim ℓ θ(ℓ) = + ∞ be such that ln θ(ℓ) < 1/c 2 (ℓ), where c 2 (ℓ) is given by (14). Proposition 1 shows that there is α ∈ ]0, 1] such that, for every r ≥ 1, there exists a trigonometric polynomial g r of degree less than θ(ℓ) r such that k g r − f k 2 ≤ C(f ) θ(ℓ) αr . The choice of θ(ℓ) implies h g r ◦ t M ℓ+r , g r ◦ t M ℓ i = 0.

Hence

|h f ◦ t M ℓ+r , f ◦ t M ℓ i| ≤ |h (f − g r ) ◦ t M ℓ+r , f ◦ t M ℓ i|

+ |h g r ◦ t M ℓ+r , g r ◦ t M ℓ i| + |h g r ◦ t M ℓ+r , (f − g r ) ◦ t M ℓ i|

≤ 2C(f ) θ(ℓ) αr . Thus we have, since lim ℓ θ(ℓ) = + ∞ ,

| 1

n k S n f k 2 2 − k f k 2 | ≤ 2 n

n − 1

X

r=1 n − 1 − r

X

ℓ=0

2C(f ) θ(ℓ) αr

≤ 4C(f) 1 n

n − 1

X

ℓ=0

θ(ℓ) α 1 − θ(ℓ) α n

→∞ 0.

For further use we give another consequence of Condition 1.

Proposition 3. Assume Condition 1. For J ⊂ I ⊂ N, denote by S n I f, S n J f the sums

S n I f = X

k ∈ [1,n] ∩ I

f ( t A k 1 x), S n J f = X

k ∈ [1,n] ∩ J

f ( t A k 1 x).

Then, for f ∈ H 0 (T d ), k S n I f − S J n f k 2 2 ≤ O(Card([1, n] ∩ J c )).

Proof. Using (15), we get

k S n I − S n J k 2 2 = X

k,k

∈ I ∩ J

c

∩ [1,n]

| Z

f ( t A k 1 x)f ( t A k 1

x) dx |

≤ C(f ) k f k 2 X

k ∈ I ∩ J

c

∩ [1,n]

[ X

k

∈ I ∩ J

c

∩ [1,n]

κ | k k

| ]

= O(Card([1, n] ∩ J c )).

Separation of frequencies

Proposition 4. (Product case) Under Condition 2 for (A 1 ) ℓ=1,...,n , there is a con- stant C S such that S (n, D, ∆) holds if ∆ ≥ C S ln D.

Proof. Let ρ > 0 be such that c 1 D γ ρ < 1/2 and ρ ≥ C 1 ln D, i.e ρ > max( ln(2c 1 D)

ln γ , C 1 ln D).

Let C 2 := ln max A ∈A k A k . Recall that the constants γ, c and C 1 were introduced in Condition (2). In the proof we will need that ∆ satisfies the inequalities

∆ ≥ C 1 (C 2 ρ + ln D) and 2c 1 D

(1 − γ ) γ < 1

2 . (18)

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This is equivalent to ∆ > max( ln(1+4c ln γ

−1

D) , C 1 (C 2 ρ + ln D)). There is a constant C S depending only on c, C 1 , C 2 such that ∆ satisfies (18) if ∆ ≥ C S ln D.

Now we show that the separation property holds if ∆ satisfies (18). We use the notations of Condition S (n, D, ∆). For s ≥ 1, let 1 ≤ ℓ 1 ≤ ℓ 1 < ℓ 2 ≤ ℓ 2 < ... < ℓ s ≤ ℓ s ≤ n be a sequence of 2s integers, such that ℓ j+1 ≥ ℓ j + ∆ for j = 1, ..., s − 1.

Let p 1 , p 2 , ..., p s , p 1 , p 2 , ..., p s be vectors such that k p j k , k p j k ≤ D, j = 1, ..., s. We have to show that the equation

A 1

s

p s + A 1

s

p s +

s − 1

X

j=1

[A

′ j

1 p j + A 1

j

p j ] = 0, (19) with A 1

s

p s + A 1

s

p s 6 = 0 is never satisfied. Assume the contrary. We can suppose p s 6 = 0 (otherwise p s 6 = 0 and we consider k A 1

s

p s k instead of k A 1

s

p s k ).

Write q s = A

ss

+1 p s + p s . We have 1 ≤ k q s k ≤ 2De C

2

(ℓ

s

s

) .

1) Assume ℓ s − ℓ s ≤ ρ. Then, by (18), we have ∆ ≥ C 1 [C 2 (ℓ s − ℓ s ) + ln D], so that we can apply (11) (replacing q by q s in (11)), and obtain for ℓ = ℓ j , ℓ j and p = p j , p j , j = 1, ..., s − 1, since ℓ s − ℓ j , ℓ s − ℓ j ≥ ∆:

k A 1 p k ≤ D k A 1 k ≤ Dc 1 γ (ℓ

s

ℓ) k A 1

s

q s k , for ℓ = ℓ j , ℓ j , p = p j , p j , 1 ≤ j ≤ s − 1;

therefore k

s − 1

X

j=1

[A

′ j

1 p j + A 1

j

p j ] k ≤ c 1 D k A 1

s

q s k

s − 1

X

j=1

(ℓ

s

j

) + γ (ℓ

s

j

) ]

≤ 2c 1 D [

s − 1

X

j=1

γ j∆ ] k A 1

s

q s k ≤ 2c 1 D

(1 − γ ) γ k A 1

s

q s k < 1

2 k A 1

s

q s k . We obtain a contradiction, since by Equation (19):

k A 1

s

q s k = k A 1

s

p s + A 1

s

p s k = k

s − 1

X

j=1

[A

′ j

1 p j + A 1

j

p j ] k .

2) Now consider the case ℓ s − ℓ s ≥ ρ. Then, since ℓ s − ℓ s ≥ ρ ≥ C 1 ln D, we have:

k A 1

s

p s k ≤ c 1 D γ (ℓ

s

s

) k A 1

s

p s k and k A 1

s

p s +

s − 1

X

j=1

A

′ j

1 p j +

s − 1

X

j=1

A 1

j

p j k

≤ c 1 D [γ (ℓ

s

s

) +

s − 1

X

j=1

γ (ℓ

s

j

) +

s − 1

X

j=1

γ (ℓ

s

j

) ] k A 1

s

p s k

≤ [c 1 (ℓ

s

s

) + 2c 1 D

(1 − γ ) γ ] k A 1

s

p s k < k A 1

s

p s k . Hence again a contradiction, since by (19): k A 1

s

p s k = k A 1

s

p s + P s − 1

j=1 [A

′ j

1 p j +

A 1

j

p j ] k .

(10)

Remark 1. The previous result is valid for the “product case”. In the general case of a sequence (M n ) the lacunarity condition analogous to Condition 2 does not imply the frequency separation property, even for the one dimensional case when (M n ) = (q n ) is an increasing sequence of positive integers such that inf n>1 q n+1 /q n > 1 (for the counter example of Fortet and Kac q n = 2 n − 1, see [1], [7]). The superlacunarity growth condition of q n is a sufficient condition and this extends easily in dimension d > 1.

Proposition 5. (Non product case) Under Condition 4 for (M 1 , . . . , M n ) there is a constant C S such that S (n, D, ∆) holds if ∆ ≥ C S ln D.

2.3. Application to the CLT. Now we focus on the characteristic function t → λ[e it

kSnkSn2

] for a real trigonometric polynomial g. Recall that S n (x) = S n g(x) = P n

k=1 g( t M k x). We suppose that k S n k 2 6 = 0. First we give the general bound (20).

When the sums k S n k 2 are of order √ n, it implies (21) or (22) from which a rate of convergence toward the normal law can be deduced (see also 2.4 for a non standard example related to the coboundary condition). The generic constant C below is independent of g and of the parameters n, D, ∆.

Lemma 2.2. Let n be an integer, and let β ∈ ]0, 1[, D > 0, ∆ > 0 be such that

∆ < 1 2 n β . Suppose that S (n, D, ∆) holds for the matrices (M 1 , . . . , M n ). Let g be a centered real trigonometric polynomial with deg(g) ≤ D. Put M = k g k ∞ , q = k g k ∞ / k g k 2 . Then for | t | ≤ M 1 k S n k 2 n β , the sums S n = S n g satisfy:

| λ[e it

kSnSnk2

] − e

12

t

2

| ≤ C[ M k S

3

| t |

3

n

k

32

n 1+2β + k M S

n

| t k |

2

n

1+3β4

+ k S t

2

n

k

22

( k S n k 2 n

1−β2

M ∆ + 2n 1 β M 22 )]. (20) If k S n k 2 ≥ C k g k 2 n 1/2 , 2q∆ ≤ n β/2 and Cq | t | ≤ n

1−3β4

, we have

| λ[e it

kSnkSn2

] − e

12

t

2

| ≤ C[q 3 | t | 3 n

4β−12

+ q | t | n

3β−14

+ qt 2 ∆ n

β2

]. (21) If the decorrelation property (3) holds, then the previous inequality can be replaced by

| λ[e it

kSnkSn2

] − e

12

t

2

| ≤ C[q 3 | t | 3 n

4β−12

+ q | t | n

3β−14

+ q 2 t 22 n β ]. (22) Proof. A) Replacement of S n by a sum with “gaps”.

In order to apply Lemma 2.1, we replace the sum S n by a sum of blocks separated by intervals of length ∆.

For β ∈ ]0, 1[, D, ∆ and g as in the statement of the lemma, we set, for ≤ k ≤ u n − 1:

v n := ⌊ n β ⌋ , u n := ⌊ n/v n ⌋ ≤ 2n 1 β ,

L k,n := kv n , R k,n := (k + 1)v n − ∆, I k,n := [L k,n , R k,n ].

The sum with “gaps” S n (x) is defined by restriction to the intervals I k,n : T k,n (x) := X

L

k,n

<ℓ ≤ R

k,n

g( t M ℓ x), S n (x) :=

u

n

− 1

X

k=0

T k,n (x).

The interval [1, n] is divided into u n blocks of length v n − ∆ separated by intervals

of length ∆. The number of blocks is almost equal to n 1 β and their length almost

equal to n β . The integers L k,n and R k,n are respectively the left and right ends of

the blocks.

(11)

Expression of | T k,n (x) | 2

| T k,n (x) | 2 = ( X

∈ I

k,n

X

p

Zd

ˆ

g(p )χ(M ℓ

p , x)) ( X

ℓ ∈ I

k,n

X

p ∈

Zd

ˆ

g(p)χ( − M ℓ p, x))

= X

p,p

Zd

X

ℓ,ℓ

∈ I

k,n

ˆ

g(p )ˆ g(p)χ(M ℓ

p − M ℓ p, x) = σ k,n 2 + W k,n (x), with

σ 2 k,n :=

Z

| T k,n (x) | 2 dx = X

p,p

Zd

ˆ

g(p )ˆ g(p) X

ℓ,ℓ

∈ I

k,n

1 M

p

=M

p , W k,n (x) := X

p,p

Zd

ˆ

g(p )ˆ g(p) X

ℓ,ℓ

∈ I

k,n

:M

p

6 =M

p

χ(M ℓ

p − M ℓ p, x).

B) Application of Lemma 2.1. Now we apply Lemma 2.1 to the array of random variables (T k,n , 0 ≤ k ≤ u n − 1) on the space ( T d , λ). For a fixed n, using the notations of the lemma, we take u = u n , ζ k = T k,n , for k = 0, ..., u n − 1, (so that δ ≤ M n β ) and

Y = Y n =

u

n

− 1

X

k=0

| T k,n | 2 ; a n = λ(Y n ) = X

k

σ 2 k,n ; Q n (t, x) =

u

n

− 1

Y

k=0

(1 + itT k,n (x)) . First let us check that λ[Q n (t, .)] = 1, ∀ t. The expansion of the product gives

Q n (t, x) = 1 +

u

n

X

s=1

(it) s X

0 ≤ k

1

< ··· <k

s

≤ u

n

− 1 s

Y

j=1

T k

j

,n (x).

The products Q s

j=1 T k

j

,n (x) are linear combinations of expressions of the type:

χ( P s

j=1 M ℓ

j

p j , x), with ℓ j ∈ I k

j

,n and k p j k ≤ D. So we have P s

j=1 M ℓ

j

p j 6 = 0 by (8) and therefore R Q s

j=1 T k

j

,n (x) dx = 0, so that R

Q n (t, x) dx = 1. By orthogonality of (T k,n ), we have also:

k S n k 2 2 = λ( | S n | 2 ) = λ( |

u

n

− 1

X

k=0

T k,n | 2 ) =

u

n

− 1

X

k=0

λ( | T k,n | 2 ) =

u

n

− 1

X

k=0

σ k,n 2 = a n . (23) B1) Bounding λ | Q n (t, .) | 2 .

Z

| Q n (t, x) | 2 dx =

Z u

n

− 1

Y

k=0

(1 + t 2 | T k,n (x) | 2 ) dx (24)

=

Z u

n

− 1

Y

k=0

[1 + t 2 σ 2 k,n + t 2 W k,n (x)] dx (25)

=

u

n

− 1

Y

k=0

[1 + t 2 σ k,n 2 ]

Z u

n

− 1

Y

k=0

[1 + t 2

1 + t 2 σ 2 k,n W k,n (x)] dx (26) The products W k

1

(x)...W k

s

(x), 0 ≤ k 1 < ... < k s < u n , are linear combinations of expressions of the form χ( P s

j=1 [M ℓ

j

p j − M ℓ

j

p j ], x), where ℓ j , ℓ j ∈ I k

j

,n , M ℓ

j

p j 6 = M ℓ

j

p j , j = 1, ..., s, and p j , p j are vectors in Z d with norm ≤ D.

As S (n, D, ∆) is satisfied, the choice of the gap in the definition of the intervals I k

j

,n implies P s

j=1 (M ℓ

j

p j − M ℓ

j

p j ) 6 = 0 and so the integral of the second factor in

(12)

(26) reduces to 1. Now it follows from (26) and the inequality 1 + y ≤ e y , ∀ y ≥ 0:

e a

n

t

2

Z

| Q n (t, x) | 2 dx = e a

n

t

2

u

n

− 1

Y

k=0

[1 + t 2 σ 2 k,n ] ≤ e a

n

t

2

e t

2Punk=0−1

σ

2k,n

= 1.

B2) Bound for S n . First we have u n δ 3 n = u n max

0 ≤ k ≤ u

n

− 1 k T k,n k 3 ∞ ≤ CM 3 n 1 β n = CM 3 n 1+2β . (27) Then for k Y n − a n k 2 , observe that E[(T k,n 2 − E T k,n 2 )(T k 2

,n − E T k 2

,n )] = 0, ∀ 1 ≤ k <

k ≤ L, so that the following inequality holds (with L = u n , recall that u n is of order n 1 β ):

k X

k

T k,n 2 − X

k

σ k,n 2 k 2 2 = k

L − 1

X

k=0

T k,n 2

L − 1

X

k=0

E [T k,n 2 ] k 2 2

=

L − 1

X

k=1

E [(T k,n 2 ) 2 ] − (

L − 1

X

k=0

E [T k,n 2 ]) 2

L − 1

X

k=0

E [T k,n 4 ] ≤ u n n M 4 , hence:

| t |k Y n − a n k 2

12

≤ M | t | n

1+3β4

. (28) Now we can apply (4) of Lemma 2.1 if M | t | n β ≤ 1 and M | t | n

1+3β4

≤ 1, which reduces to M | t | ≤ n

1+3β4

. We obtain from (27) and (28):

| λ[e itS

n

] − e

12

k S

n

k

22

t

2

| ≤ C(M 3 | t | 3 n 1+2β + M | t | n

1+3β4

), (29) C) Bound for k S n − S n k 2 .

k S n − S n k 2 2 = Z

|

u

n

− 1

X

k=0

X

R

k,n

<ℓ ≤ L

k+1,n

g( t M ℓ x) | 2 dx

=

u

n

− 1

X

k=0

Z

| X

R

k,n

<ℓ ≤ L

k+1,n

g( t M ℓ x) | 2 dx

+2 X

0<k<k

≤ u

n

− 1

Z X

R

k,n

<ℓ ≤ L

k+1,n

g( t M ℓ x) X

R

k′,n

<ℓ

≤ L

k′+1,n

g( t M ℓ

x) dx.

The length of the intervals for the sums in the integrals is ∆. The second sum in the previous expression is 0 by (8), since n β − ∆ > ∆. Each integral in the first sum is bounded by M 22 . It implies:

k S n − S n k 2 2 ≤ M 22 u n ≤ 2n 1 β M 22 . (30) Using the previous inequality we have, since R

(S n − S n ) dλ = 0,

| λ[e itS

n

− e itS

n

] | ≤ λ[ | 1 − e it(S

n

S

n

) | ] ≤ C | t | 2 k S n − S n k 2 2 ≤ C | t | 2 M 22 n 1 β . (31) By (30) and the mean value theorem, we have

| e

12

k S

n

k

22

t

2

− e

12

k S

n

k

22

t

2

| ≤ 1

2 t 2 |k S n k 2 2 − k S n k 2 2 |

≤ 1

2 t 2 (2 k S n k 2 + k S n − S n k 2 ) k S n − S n k 2

≤ Ct 2 ( k S n k 2 n

1−β2

M ∆ + n 1 β M 22 ). (32)

(13)

D) Conclusion. Now if M | t | ≤ n

1+3β4

, we can use the previous bounds (29), (31), (32):

| λ[e itS

n

] − e

12

k S

n

k

22

t

2

|

≤ | λ[e itS

n

] − λ[e itS

n

] | + | λ[e itS

n

] − e

12

k S

n

k

22

t

2

| + | e

12

k S

n

k

22

t

2

− e

12

k S

n

k

22

t

2

|

≤ C[t 2 M 22 n 1 β + | t | 3 M 3 n 1+2β + M | t | n

1+3β4

+t 2 ( k S n k 2 n

1−β2

M ∆ + n 1 β M 22 )]

= C[ | t | 3 M 3 n 1+2β + M | t | n

1+3β4

+ t 2 ( k S n k 2 n

1−β2

M ∆ + 2n 1 β M 22 )].

Then, replacing t by t k S n k 2 1 , we obtain, if | t | ≤ M 1 k S k 2 n β ,

| λ[e it

kSnkSn2

] − e

12

t

2

| ≤ C[ | t | 3 M 3 k S n k 2 3 n 1+2β + | t | M k S n k 2 1 n

1+3β4

+t 2 k S n k 2 2 ( k S n k 2 n

1−β2

M ∆ + 2n 1 β M 22 )].

Suppose now that k S n k 2 ≥ C k g k 2 n

12

and 2q∆ ≤ n β/2 . We obtain, if Cq | t | ≤ n

1−3β4

:

| λ[e it

kSnSnk2

] − e

12

t

2

| ≤ C[ | t | 3 q 3 n

4β−12

+ q | t | n

3β−14

+ t 2 (n

−β2

q∆ + 2n β q 22 )]

≤ C[q 3 | t | 3 n

4β−12

+ q | t | n

3β−14

+ qt 2 ∆ n

−β2

].

This finish the proof of the lemma, when the decorrelation property is not as- sumed.

When the decorrelation property (3) holds, we can write

|k S n k 2 2 − k S n k 2 2 | ≤ Cn 1 β M 22 , (33) and the mean value theorem gives by (33),

| e

12

k S

n

k

22

t

2

− e

12

k S

n

k

22

t

2

| ≤ 1

2 t 2 |k S n k 2 2 − k S n k 2 2 | ≤ Ct 2 n 1 β M 22 . (34) We obtain (22), with the same condition on t.

Rate of convergence in the CLT

The inequalities (21) or (22) and the inequality of Esseen give a way to obtain a rate of convergence in the CLT.

Recall that if X, Y are two real random variables defined on the same probability space with probability Q, their mutual distance in distribution is defined by:

d(X, Y ) = sup

x ∈

R

| Q(X ≤ x) − Q(Y ≤ x) | .

Let H X,Y (t) := | E

Q

(e itX ) − E

Q

(e itY ) | . Take as Y a r.v. with a normal law N (0, σ 2 ).

The inequality of Esseen (cf. [10] p. 512) tells us that if X has a vanishing expec- tation and if the difference of the distributions of X and Y vanishes at ±∞ , then for every U > 0,

d(X, Y ) ≤ 1 π

Z U

− U

H X,Y (x) dx x + 24

π 1 σ √

2π 1 U .

Let Y 1 be a r.v. with standard normal law. Suppose, for instance, that (21)

holds with a fixed gap ∆ and that k S n k 2 > Cn

12

. Taking X = S n / k S n k 2 , we

(14)

have | H X,Y

1

(t) | ≤ C P 4

i=1 n γ

i

| t | α

i

, where the constants are given by (21). Thus d(X, Y 1 ) is bounded by

C U + C

4

X

i=1

n γ

i

1 α i

U α

i

.

In order to optimize the choice of U = U n , we take U n = n γ with γ = min i γ

i

α

i

+1 . This gives the bound d(S n / k S n k 2 , Y 1 ) ≤ Cn γ . Then we have to chose the param- eter β ∈ ]0, 1[.

Theorem 2.3. Let (A k ) k ≥ 1 be a sequence of matrices taking values in a set A of matrices in M d (Z) such that Condition 2 holds. Let f ∈ H 0 (T d ) be such that k S n f k ≥ Cn

12

, for a constant C > 0, for n big enough. Then S n f satisfies the CLT with a rate d( k S S

n

f

n

f k

2

, Y 1 ) = O(n ρ ), for every ρ < 1/32 (for every ρ < 1/20 with the decorrelation property (3)).

Proof. Proposition 1 shows that there exist an integer L and a uniformly bounded sequence (g n ) of trigonometric polynomials such that k g n k ∞ ≤ k f k ∞ , deg(g n ) ≤ n L and k S n f − S n g n k 2 ≤ n 4 . For n big enough, k S n g n k 2 > 1 2 Cn

12

. This implies:

| λ[e it

kSnfSnfk2

] − λ[e it

kSngnSngnk2

] |

≤ C | t | 2 λ( | S n f

k S n f k 2 − S n g n

k S n g n k 2 | 2 ) ≤ Ct 2 k S n f − S n g n k 2 2

k S n f k 2 k S n g n k 2 ≤ Ct 2 n 9 . By Proposition 4, Property S (n, n 4 , 4C S ln n) holds and we can apply Lemma 2.2 to the trigonometric polynomial g n . We obtain:

| λ[e it

kSnfSnfk2

] − e

12

t

2

| ≤ C[ | t | 3 n

4β−12

+ | t | n

3β−14

+ | t | 2 (ln n) 2 n

β6

+ t 2 n 9 ].

Now we apply the method recalled a few lines above. When (21) holds, we compute min( 1 8 , 1 8 , β 6 ε , 3), for ε > 0 small. Choosing β = 16 3 + ε 4 , we obtain the rate of convergence 32 1ε 8 .

With the decorrelation property (22), we compute min( 1 8 , 1 8 , β 3 ε , 3). Tak- ing β = 20 3 + 2 5 ε, we obtain the rate of convergence 20 1ε 5 .

Application to superlacunary sequences

In dimension 1 the superlacunary growth condition of (q n ) is a sufficient condition (Salem-Zygmund) for the CLT and this extends to d > 1.

Theorem 2.4. Let f ∈ H 0 . Under Condition 4 5 the asymptotic variance σ 2 (f ) = lim n 1

n k S n f k 2 2 exists, σ 2 (f ) = k f k 2 and the CLT holds if k f k 2 6 = 0.

Proof. By Proposition 2, Condition 5 (which follows from Condition 4) implies lim n 1

n k S n f k 2 2 = k f k 2 . By Proposition 5 the separation of frequencies is satisfied.

We conclude as in the previous theorem.

2.4. A non standard example. Now we illustrate the questions of variance and coboundary by a simple example. Let A, B be two matrices in SL(2, Z) with positive coefficients (hence the corresponding automorphism τ A : x 7→ Ax mod 1 is ergodic on (T 2 , λ)) such that AB 1 is hyperbolic. Let J = (n k ) be an increasing sequence and let (A j ) j ≥ 1 be the sequence of matrices defined by

A j = A if j / ∈ J, = B if j ∈ J.

The following proposition shows how the behavior of the sums P n

k=1 f (A k . . . A 1 x)

can depend on the coboundary condition.

(15)

Proposition 6. Let f be a non zero function in H 0 (T 2 ), (n k ) k ≥ 1 = ( ⌊ k L ⌋ ) k ≥ 1 , for L ≥ 1. If f is not a coboundary for τ A , then we have the convergence in distribution with a constant σ > 0:

1 σ √ n

n

X

k=1

f (A k . . . A 1 x) → N L (0, 1).

If f = h − h(A · ) then, g( · ) = h( · ) − h(AB 1 · ) is not zero and 1

k g k 2 n

2L1

n

X

k=1

f (A k . . . A 1 · ) → N L (0, 1).

Proof. 1) Let us compare the variance of S n f (x) = P n

k=1 f (A k . . . A 1 x) with the variance of the ergodic sums associated to the action of A. We have

E((S n f(x)) 2 ) = n Z

Td

f 2 (x)dx + 2 X

k<ℓ

h f (A 1 · ), f (A k 1 · ) i .

Condition 3 is satisfied by matrices with positive coefficients (see subsection 3.2), hence by (15) Proposition 1.9, for κ < 1: h f (A 1 · ), f (A k 1 · ) i = h f (A k+1 · ), f ( · ) i ≤ Cκ k , so that

| E (S n f (x)) 2 − [n Z

Td

f 2 dx + 2 X

k<ℓ and ℓ − k ≤ n

α

h f (A 1 · ), f (A k 1 · ) i ] | ≤ Cκ n

α

n 2 .

Let r n := #(J ∩ [1, n]). If k is at distance ≥ n α from J and ℓ − k ≤ n α , then A k+1 = A k . The number of blocks A k+1 containing B with k < ℓ and ℓ − k ≤ n α is less than r n n . Thus we have

| E((S n f(x)) 2 ) − [n Z

Td

f 2 dx + 2 X

k<ℓ,ℓ − k ≤ n

α

h f (A · ), f (A k · ) i ] | ≤ C(κ n

α

n 2 + n r n ),

and if n 1 r n tends to 0, then n 1 E((S n f (x) 2 ) − 1 n E(( P n

k=1 f (A k x)) 2 ) → 0.

If n k = ⌊ k L ⌋ for L > 1, then r n is equivalent to n 1/L . Taking α < 1 2 (1 − L 1 ) we get

lim 1 n E((

n

X

k=1

f (A k . . . A 1 x)) 2 ) = σ 2 :=

Z

Td

f (x)dx + 2 X ∞

k=1

h f, f (A k · ) i .

Thus, if f is not a coboundary for the action of A, we have k S n f k ≥ Cn

12

for some C > 0. Moreover, as A and B have positive coefficients, Corollary 2 in section 3 ensures that Condition 2 holds for products of matrices A and B. This implies that Theorem 2.3 applies. In particular we have σ1 n

P n

k=1 f (A k . . . A 1 x) → N L (0, 1).

2) Now let us assume that f is a coboundary for A: f ( · ) = h( · ) − h(A · ). As f

is H¨ older continuous, it is known that h is also H¨ older continuous. Putting n 0 = 0,

(16)

we can rearrange the sums S n f(x) = P n

k=1 f (A k . . . A 1 x):

S n f (x)) =

r

n

X

k=1 n

k

− 1

X

j=n

k−1

f (A j . . . A 1 x) +

n

X

j=n

rn

f (A j . . . A 1 x) − f (x)

=

r

n

X

k=1

n

k

− 1

X

j=n

k−1

h(A j . . . A 1 x) −

n

k

− 1

X

j=n

k−1

h(AA j . . . A 1 x)

+

n

X

j=n

rn

h(A j . . . A 1 x) −

n

X

j=n

rn

h(AA j . . . A 1 x) − f (x).

For k = 1, . . . , r n , j = n k − 1 , . . . , n k − 2 and j = n r

n

, . . . , n − 1, we have the equality h(AA j . . . A 1 x) = h(A j+1 A j . . . A 1 x). Thus

S n f (x) =

r

n

X

k=1

[h(A n

k−1

. . . A 1 x) − h(AA n

k

− 1 . . . A 1 x)]

+h(A n

rn

. . . A 1 x) − h(AA n . . . A 1 x) − f (x).

Define g( · ) = h( · ) − h(AB 1 · ) and M j = BA n

j

n

j−1

1 . The function g is not

≡ 0 because otherwise, since AB 1 is ergodic, h would be constant and f ≡ 0.

As f(x) = h(x) − h(Ax) and A n

k

. . . A 1 = BA n

k

− 1 . . . A 1 , we can rearrange the expression above and get

S n f (x) =

r

n

X

k=1

[h(BA n

k

− 1 . . . A 1 x) − h(AA n

k

− 1 . . . A 1 x)]

+h(Ax) − h(AA n . . . A 1 x)

=

r

n

X

k=1

g(M k . . . M 1 x) + h(Ax) − h(AA n . . . A 1 x).

For the asymptotic variance of the sums associated to the sequence (M j ), we have : E((

n

X

k=1

g(M k . . . M 1 x)) 2 ) − n Z

Td

g 2 (x)dx = 2 X

k<ℓ

h g(M 1 · ), g(M 1 k · ) i

= 2 X

k<ℓ

h g(M k+1 · ), g( · ) i . When n k = ⌊ k L ⌋ with L > 1, M k+1 is a product of ⌊ ℓ L ⌋ − ⌊ k L ⌋ matrices A or B, we have |h g(M k+1 · ), g( · ) i| ≤ Cκ

L

k

L

, so that

| X

k<ℓ

h g(M k+1 · ), g( · ) i| ≤ C

n − 1

X

k=1 n

X

ℓ=k+1

κ

L

k

L

≤ C

n − 1

X

k=1

κ Lk

L−1

< ∞ , and lim n 1

n E(( P n

k=1 g(M k . . . M 1 x)) 2 ) = R

Td

g 2 (x)dx. When n k = ⌊ k L ⌋ with L >

1, Condition 4 (hence Condition 5) holds for M 1 n and Theorem 2.4 implies the convergence in distribution

1 k g k 2 √ r n

r

n

X

k=1

g(M k . . . M 1 · ) → N (0, 1).

This proves the second assertion of the proposition.

(17)

3. Stationary products, examples. In this section we consider a sequence (M k ) in M d (Z) and the sums S n f (x) = P n

k=1 f ( t M k x). When the matrices M k are positive, this can be viewed as a generalization of the trigonometric sums S n f (x) = P n

k=1 f (q k x) (cf. references in the introduction).

Remark that there are examples of sequences (M k ) of positive matrices with an exponential growth for which the convergence in law to a standard normal law does not hold. This is the case in dimension 1 with the sequence q n = 2 n − 1, n ≥ 1, an example due to Fortet and Erd¨ os, and in higher dimension examples can be constructed (see [7]).

In the study of the behavior of the sums S n f , the following questions arise:

- decorrelation property of the sequence (f ( t M k x)) k ≥ 1 , for a control on the variance, - non nullity of the variance for the non degeneracy of the limit.

The latter question seems to be out of reach outside the superlacunary case, even for arithmetic sums in dimension 1, where generally non degeneracy is assumed, but difficult or impossible to check. The reason is that in general, given a sequence (M n ) and a regular or polynomial function f , it is difficult to know if the variance is non zero, even in dimension 1 for a sequence of (q n ) and even when the sequence is obtained as a product.

Nevertheless, the situation is much better in the stationary case, when the se- quence (M n ) is obtained as a product of stationary matrices, or integers. Then some information can be obtained on the non nullity of the variance.

A special case is when the matrices A k (ω) are chosen at random and indepen- dently (see [3] for toral automorphisms). The case of SL(d, Z) extends to the fol- lowing general setting: let G be a group of measure preserving transformations on a probability space (X, λ) and let µ be a probability measure on G. If a spectral gap is available for the convolution by µ on L 2 0 (X × X, λ ⊗ λ), then a “quenched”

CLT for functions f in L p 0 (µ), p > 2, can be shown (cf. [8]). Moreover the spectral gap implies the non degeneracy of the CLT. Therefore we will not consider here specifically the independent case, but nevertheless remark that the method which is used here applies to the independent case for the action of matrices in SL(d, Z) on the torus and a CLT with rate for H¨ older functions can be obtained in this way.

We consider here different situations where a CLT can be proved for stationary, not necessarily independent, sequences of automorphisms.

3.1. Stationary products. Ergodicity, variance

In this section we consider a stationary process (A k (ω)) with values in M d (Z) and the corresponding products t M k = t A k (ω)... t A 1 (ω). Stationarity can be expressed via a measure preserving transformation.

Let θ be an invertible measure preserving ergodic transformation on a probability space (Ω, µ). Let A be a set of matrices in M d ( Z ).

Notation. Let ω → A(ω) be a measurable map from Ω to A . Let τ be the map ω → τ(ω) from Ω to the semigroup of endomorphisms of T d where τ(ω) x = t A(ω) x.

We define the skew product θ τ on the product space Ω × T d equipped with the product measure ν := µ ⊗ λ by θ τ : (ω, x) 7→ (θω, τ (ω)x).

For ω ∈ Ω and f a function on T d , we write S n (ω, f)(x) = P n

k=1 f ( t A k 1 (ω)x), where

A j i (ω) = A(θ i 1 ω)A(θ i ω)...A(θ j 1 ω), j ≥ i ≥ 1.

Références

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