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nonlinear Maxwell-Cattaneo heat transfer law
Fatah Aggoune, Kamel Hamdache, Djamila Hamroun
To cite this version:
Fatah Aggoune, Kamel Hamdache, Djamila Hamroun. Global weak solutions to magnetic fluid flows with nonlinear Maxwell-Cattaneo heat transfer law. 2014. �hal-01023053�
nonlinear Maxwell-Cattaneo heat transfer law
F. Aggoune
∗, K. Hamdache
†and D. Hamroun
‡Abstract
We discuss the equations describing the dynamic of the heat transfer in a magnetic fluid flow under the action of an applied magnetic field. Instead of the usual heat transfer equation we use a generalization given by the Maxwell-Cattaneo law which is a system satisfied by the temperature and the heat flux. We prove a global existence of weak solutions to the system having a finite energy.
Keywords: Navier-Stokes equations, Bloch-Torrey equation, magnetostatic equation, Maxwell-Cattaneo law, heat transfer, magnetic field, magnetization
AMS subject classifications: 76N10, 35Q35.
1 Introduction
1.1 Statement of the model
In this work, we study the heat transfer in a magnetic incompressible fluid flow under the action of an applied magnetic field. The temperature θ of the fluid is usually described by the linear heat transfer equation
∂tθ+U · ∇θ=−divQ (1)
related to the linear Fourier law
Q=−κ∇θ (2)
Qbeing the heat flux andUthe fluid velocity. To ovoid the paradox of the instantaneous heat propagation inherent to the parabolic type equation, another model was offered in the pioneering work of Vernotte [23] and Cattaneo [6]. In this model, the Fourier law (2)is replaced by the heat-flux equation
τ ∂tQ+Q=−κ∇θ (3)
∗Laboratoire AMNEDP, Faculté de Mathématiques. Université USTHB, Algérie (Email: ag- [email protected])
†Centre de Mathématiques Appliquées, CNRS UMR 7641 Ecole Polytechnique, 91128 Palaiseau cedex, France (Email: [email protected])
‡Laboratoire AMNEDP, Faculté de Mathématiques, Université USTHB, Algérie (Email: djam- [email protected])
1
where τ > 0 is the time relaxation parameter. For τ = 0, we recover equation (2).
Combining the temperature equation and the heat-flux equation we see thatθsatisfies an hyperbolic type equation. System(1)-(3)was generalized by Guyer and Krumhansl see [13] for example, by introducing a diffusion process in (3) so that the heat-flux equation becomes
τ(∂tQ−γ∆Q) =−Q−κ∇θ (4)
where γ > 0 is a diffusion coefficient. When the heat conductivity is enhanced by radiation effects see [12, 10, 11], the linear Fourier law is replaced by a nonlinear one which writes aqs
Q=−∇K(θ). (5)
In [11], the model of heat transfer by the nonlinear Fourier law in an incompressible fluid flow has been discussed.
In this work we are dealing with the nonlinear Maxwell-Cattaneo law for heat trans- fer which is a generalization of the nonlinear Fourier law, more precisely we consider that the dynamic of the couple(θ, Q) is governed by the system
∂tθ+U· ∇θ=−divQ τ(∂tQ−γ∆Q) =−τ
2curlU ×Q−Q− ∇K(θ). (6) The monotone functionK(θ) discussed in this work is given by
K(θ) =κ θ+α θ3 (7)
whereκ >0andα >0are the heat conductivity coefficients and we refer the reader to [19, 20] for the introduction of the rotation term 12curlU×Q. Notice that the power 3 used in the definition of the functionK is less than the values indicated in [12].
The Maxwell-Cattaneo system (6) is coupled to the incompressible Navier-Stokes equations satisfied by the fluid velocityU and the pressure p as well as to the Bloch- Torrey equation satisfied by the magnetization fieldM and the magnetostatic equation for the magnetic fieldH. Namely, we have
divU = 0
∂tU + (U.∇)U −η∆U +∇p=−ρ(θ)g+µ0(M.∇)H+µ20curl (M×H)
∂tM+ (U.∇)M−σ∆M+1
δ(M−χ0H) = 1
2curlU×H−β0M×(M×H) div (H+M) =F, curlH= 0
(8)
where the densityρ(θ) is given by the state of law
ρ(θ) =ρ0(1−β(θ−θ0)) (9) whereρ0 is the fluid density at the the temperature θ0 and β is a physical coefficient.
The function g represents the force of gravity, F is a function linked to the applied
magnetic field andη, µ0, σ, δ, χ0, β0>0are physical parameters.
When the magnetization M is assumed to be in equilibrium state meaning it is parallel to the magnetic fieldH, the model in consideration is quite different from the one studied in this work. The magnetization law writes in general as
M =χ(θ,|H|)H (10)
In that case, the Maxwell-Cattaneo system becomes
∂tθ+U· ∇θ+µ0θ∂M
∂θ ·(U · ∇)H=−divQ+ηΦ(U) τ
∂tQ−∆Q+ 12curlU×Q
=−Q− ∇K(θ)
(11)
whereµ0θ∂M
∂θ ·(U· ∇)H is the thermal power andΦ(U)is the energy dissipation. The heat transfer problem in an incompressible fluid flow under the above Maxwell-Cattaneo law in a magnetic fluid is an open problem.
LetD⊂R3be an open, bounded, regular and simply connected domain, with boundary Γ. For T >0 fixed, we set DT = (0, T)×D and ΓT = (0, T)×Γ. The equations (6) and (8) are set onDT with the following initial and boundary conditions
U(0) =U0, divU0= 0, M(0) =M0, inD
U = 0, M ·n= 0, curlM×n= 0, H·n= 0,on ΓT (12) θ(0) =θ0, Q(0) =Q0 inD
Q×n= 0, τ γdivQ− K(θ) = 0 on ΓT
(13) wherenrepresents the unit outward normal to the boundary Γ. Problem(6)-(8)-(12)- (13)will be labeled problem (P).
System(8) with the temperature equation (1) has been discussed in [1, 2]. The linear Maxwell-Cattaneo system (1)-(3) has been studied in [14, 15] in the case where the velocityU is fixed.
1.2 Notations and spaces
For1≤q ≤ ∞ands∈R, let Lq(D) and Ws,q(D) be the usual Lebesgue and Sobolev spaces of scalar functions. Ifq = 2, Ws,2(D) is denoted by Hs(D) and k · k and (·;·) denote the norm and the scalar product of the Hilbert spaceL2(D). For vector valued functions we use the notationsLq(D),Ws,q(D),Hs(D) and the notations of norm and the scalar product of L2(D) are unchanged. If V is a Banach space we denote by h·;·iV0×V (or simplyh·;·iif no confusion arises) the duality product whereV0is the dual space ofV. IfV is an Hilbert space with scalar product(·;·), we set
C([0, T];V weak) ={u: [0, T]→V; (u(·), v)∈ C([0, T]), ∀v∈V}.
Let D(D,R3) the set of functions f : D→ R3 which are infinitely differentiable with compact support in D and H10(D) its closure in H1(D). Now, we introduce the func- tional spaces used in the theory of Navier-Stokes equations, see [22, 7] for example
Ds(D) ={v∈ D(D,R3); divv= 0 inD}
U =closure of Ds(D) inH1(D), U0 =closure of Ds(D) inL2(D).
Then it is well known that
U ={v∈H10(D); divv= 0 inD}
U0={v∈L2(D); divv= 0 inD, v·n= 0 on Γ}
(14) and identifyingU0 with its dual, we get as usual the inclusionsU ⊂ U0 ⊂ U0.
For the Bloch-Torrey equation satisfied by M and the heat-flux equation satisfied by Qwe introduce the Hilbert spaces
H1t(D) ={M ∈H1(D); M ·n= 0 onΓ}
H1n(D) ={Q∈H1(D); Q×n= 0 onΓ}
equipped with the norm ofH1(D). Then (see [7] for example) there exists C >0 such that for allV in eitherH1t(D) or H1n(D) the following estimate holds
k∇Vk ≤C(kVk2+kcurlVk2+kdivVk2)1/2 (15) hence the norm of H1(D) is equivalent to the norm (kVk2+kcurlVk2+kdivVk2)1/2 on the spaces H1t(D) and H1n(D). We recall the relation −∆ = curl2− ∇div so that for regular vector fieldsΨand Φthe following Green formula holds
− Z
D
∆Ψ·Φdx= Z
D
curl Ψ·curl Φdx+ Z
D
div Ψ div Φdx +
Z
Γ
curl Ψ·(Φ×n)dΓ− Z
Γ
div Ψ(Φ·n)dΓ.
To deal with the magnetostatic equation, we set L2] ={ψ∈L2(D);
Z
D
ψ(x)dx= 0} andH]1 =H1(D)∩L2].
The Hilbert spaceH]1 is equipped with the normk∇ψkwhich is equivalent to the usual norm ofH1(D)thanks to Poincaré-Wirtinger inequality : there existsC >0such that for allψ∈H1] we have
kψk ≤Ck∇ψk. (16)
To end these notations, we point out that throughout this paper, C > 0 indicates a generic constant depending only on some bounds of the physical data, which takes different values in different occurrences. The dependency of the constants C >0 with respect to a parameter mis written as Cm.
Now, let us focus our attention on the magnetostatic equation to give some useful continuity results on the solution
1.3 The magnetostatic equation
LetM ∈L2(D) andF ∈L2], we consider the following problem Findϕ∈H]1; ∀ψ∈H]1,
Z
D
(∇ϕ+M)· ∇ψ dx=− Z
D
F ψ dx. (17) This problem admits a unique solution ϕinH]1 and we have
Z
D
∇ϕ.M dx=−k∇ϕk2− Z
D
F ϕ dx. (18)
then
k∇ϕk ≤(kMk+CkFk). (19)
In particular the application
H: (M, F)7→ϕ (20)
is continuous from L2(D)×L2] to H]1. Furthermore testing equation (17) with ψ− Z
D
ψ dx, ψ ∈H1(D), we see that Z
D
(∇ϕ+M)· ∇ψ dx=− Z
D
F ψ dx, ∀ψ∈H1(D) (21) andH =∇ϕsolves the problem
div (H+M) =F, curlH = 0 inD (H+M)·n= 0 onΓ.
Moreover using classical regularity results for elliptic problems, we conclude that if F ∈L2] and M ∈H1t(D), thenϕ∈H2(D)∩H]1 and we have
kϕkH2(D)≤C(kdivMk+kFk). (22) ThereforeH =∇ϕ∈H1t(D)and we have
kHkH1(D)≤C(kdivMk+kFk). (23) We can see thatH is also continuous from L2(DT)×L2(0, T;L2]) to L2(0, T;H]1) and from H1(0, T;L2(D))×H1(0, T;L2]) to H1(0, T;H]1). Moreover for F ∈H1(0, T;L2]) andM ∈H1(0, T;L2(D)), we have
Z
D
(∇(∂tϕ) +∂tM)· ∇ψ dx=− Z
D
∂tF ψ dx,∀ψ∈H1(D), t∈(0, T). (24)
2 Main results
Before stating our main result, let us give the formal energy estimates for problem (P).
2.1 Energy estimates
Let (U, M, H, θ, Q) be a regular solution to system (P). We proceed as in [1, 2] to obtain, forθfixed, the energy estimate satisfied by(U, M, H). Fort∈[0, T], we set
Ensbt(t) = 1
2kU(t)k2+ µ0
2 (kM(t)k2+kH(t)k2) Ensbt,0 = 1
2kU0k2+ µ0
2 (kM0k2+kH0k2)
(25)
whereH0 =∇ϕ0andϕ0 is the unique solution of the following problem (see subsection 1.3)
Findϕ0 ∈H]1 such that Z
D
(∇ϕ0+M0)· ∇ψ dx=− Z
D
F(0)ψ dx, ∀ψ∈H]1 (26) and
Fnsbt(t) =ηk∇U(t)k2+µ0σ(kcurlM(t)k2+ 2kdivM(t)k2) +µ0
δ kM(t)k2+ µ0
δ (1 + 2χ0)kH(t)k2+β0µ0kM(t)×H(t)k2.
(27) Then we get the energy estimate
Ensbt(t) + Z t
0
Fnsbt(s)ds≤ Ensbt,0+C Z t
0
kρ(θ(s))k2ds+C Z t
0
kG(s)k2ds (28) for allt≥0where
G(t) =kF(t)k2+k∂tF(t)k2. (29) Now we consider the Maxwell-Cattaneo system(6)satisfied by (θ, Q) for U fixed. Let
$the primitive function of K defined by
$(θ) = κ 2θ2+α
4θ4. (30)
Multiplying the temperature equation by K(θ) and the heat-flux equation by Q then integrating by parts and adding both results, we get the energy estimate associated with the Maxwell-Cattaneo system
Emc(t) + Z t
0
Fmc(s)ds≤ Emc,0 (31) for allt≥0with
Emc(t) = Z
D
$(θ(t))dx+ τ
2kQ(t)k2, Emc,0 = Z
D
$(θ0)dx+ τ
2kQ0k2 (32) Fmc(t) =τ γ(kcurlQ(t)k2+kdivQ(t)k2) +kQ(t)k2. (33) The total energy E and the total dissipation energy F of the full problem (P) are defined by
E(t) =Ensbt(t) +Emc(t), F(t) =Fnsbt(t) +Fmc(t) (34) and it holds
E(t) + Z t
0
F(s)ds≤ E0+C Z t
0
kρ(θ(s))k2ds+C Z t
0
G(s)ds. (35)
2.2 Statement of the result
We will use the following hypotheses
U0∈ U0, M0, Q0 ∈L2(D), divQ0 ∈L12/11(D), θ0 ∈L4(D) g∈L∞(DT), F ∈H1(0, T;L2(D)),
Z
D
F(t, x)dx= 0 for allt∈[0, T].
(36)
Let us give now the definition of a global weak solution to problem(P)
Definition 1 We say that (U, M, H, θ, Q) is a global weak solution with finite energy of problem (P) if the following conditions are fulfilled
U ∈L∞(0, T;U0)∩L2(0, T;U)
M ∈L∞(0, T;L2(D))∩L2(0, T;H1t(D)) H ∈L∞(0, T;L2(D))∩ L2(0, T;H1t(D)) Q∈L∞(0, T;L2(D))∩L2(0, T;H1n(D)) θ∈L∞(0, T;L4(D))
(37)
and
(i) the linear momentum equation holds weakly in the sense that for all v∈ U d
dt Z
D
U ·v dx+ Z
D
(U· ∇)U·v dx+η Z
D
∇U· ∇v dx=
− Z
D
ρ(θ)g·v dx+µ0 Z
D
(M· ∇)H·v dx+µ0
2 Z
D
M ×H·curlv dx U(0) =U0
(38)
(ii) the magnetization equation satisfies for allw∈H1t(D) the weak formulation d
dt Z
D
M·w dx+ Z
D
(U · ∇)M·w dx+σ Z
D
curlU ·curlw dx +σ
Z
D
divMdivw dx+1 δ
Z
D
(M−χ0H)·w dx= 1
2 Z
D
curlU×H·w dx−β0 Z
D
M×H·M×w dx M(0) =M0
(39)
(iii) the magnetic field is given by H =∇ϕ where ϕ∈L∞(0, T;L2]) and satisfies for all ψ∈H]1
Z
D
(∇ϕ(t) +M(t))· ∇ψ dx=− Z
D
F(t)ψ dx (40)
(iv) the couple (θ, Q) satisfies the Maxwell-Cattaneo system in the following sense Z
DT
θ(∂ta+U · ∇a)dxdt= Z
DT
divQ a dxdt− Z
D
θ0a(0)dx (41)
for all a∈ D([0, T[×D) and for all b∈H1n(D) with divb∈L4(D) τ d
dt Z
DT
Q·b dx+τ γ Z
D
(curlQ·curlb+ divQdivb)dx+
Z
D
Q·b dx+τ 2
Z
D
curlU ×Q·b dx= Z
D
K(θ) divb dx Q(0) =Q0.
(42)
Moreover the energy estimates (28) and (31) hold for all t∈(0, T).
Remark 1
1. As usual, we get the pressure p ∈ W−1,∞(0, T;L2(D)) by using the De Rham theorem.
2. From the weak formulations, we deduce that (∂tU, ∂tM, ∂tQ) ∈ L1(0, T;U0 × (Ht1(D))0 ×(Hn1(D))0) so that (U, M, Q) ∈ C([0, T];U0×(Ht1(D))0 ×(Hn1(D))0) and the corresponding initial conditions are meaningful and moreover U, M, Q∈ C([0, T];L2(D) weak).
3. The theory of transport equation leads to the result θ ∈ C([0, T];L4(D) weak)∩ C([0, T];Lp(D)), for all1≤p <4 (see [5] for example) which gives a sense to the initial condition.
Theorem 1 Under hypotheses (36), there exists a global weak solution with finite en- ergy of problem(P). Moreoverθ has the regularity
θ∈L36/11(0, T;L36/7(D)). (43)
Remark 2 One can relax the condition divb ∈ L4(D) on test functions b in (42) to the condition divb∈L12/5(D).
We will prove existence of solutions to problem (P) in several steps, using a regu- larization method and some compactness results. The paper is organized as follows.
In section 3, we introduce the regularized problem(Pν)obtained by adding an elliptic term −ν∇ ·(|∇θ|2∇θ) in the temperature equation, ν > 0 being a small parameter together to a regularization of the initial condition θ0. By using the Faedo-Galerkine method, we obtain a sequence of approximated solutions (Un, Mn, Hn, θn, Qn) which converge towards(Uν, Mν, Hν, θν, Qν) a global weak solution with finite energy of sys- tem(Pν).
In section 4, we prove Theorem 1. We first introduce an auxiliary problem satisfied by ζν =τ γdivQν − K(θν) and establish a compacity result verified by ζν which allows to get the limit of the nonlinear termK(θν). Then we get Theorem 1 by passing to the limit as ν→0.
3 The regularized problem (P
ν)
Letν >0be a small parameter and (θ0ν) such that
(θ0ν)⊂W1,4(D), θν0 →θ0 strongly in L4(D). (44) We define the regularized problem(Pν) as the system (8)−(12) coupled to the regu- larized Maxwell-Cattaneo system
∂tθ+ (U · ∇)θ−ν∇ ·(|∇θ|2∇θ) =−divQinDT τ(∂tQ−γ∆Q) =−τ
2curlU ×Q−Q− ∇K(θ) inDT ν|∇θ|2∇θ·n= 0, Q×n= 0, τ γdivQ− K(θ) = 0 on ΓT θ(0) =θ0ν, Q(0) =Q0 inD
(45)
Note that we use the nonlinear elliptic operator−ν∇·(|∇θ|2∇θ)instead of−ν∆θwhich is commonly used to regularize a transport equation, owing to obtain approximate solutionsθν belonging toW1,4(D) and therefore to L∞(D).
Proceeding as previously the energy associated with(45)takes the form Emc(t) +
Z t 0
Fmc(s)ds+ν Z t
0
R(s)ds≤ Emc,0ν (46) for allt≥0where
R(t) =κk∇θk4L4(D)+ 3α Z
D
θ2|∇θ|4 dx (47) which is well defined thanks to the Sobolev embeddingW1,4(D)⊂ C(D)and
Emc,0ν = Z
D
(κ
2|θν0|2+ Z
D
α
4|θ0ν|4)dx+kQ0k2
It is easy to verify that the energy estimate associated with the problem(Pν) writes as E(t) +
Z t 0
F(s)ds+ν Z t
0
R(s)ds≤C+C Z t
0
kρ(θ(s))k2ds+C Z t
0
kG(s)k2ds (48) whereC >0 does not depend on ν. We will prove the following existence result
Theorem 2 Under hypotheses (36), there exists a global weak solution(Uν, Mν, Hν, θν, Qν) of problem (Pν) such that
Uν ∈L∞(0, T;U0)∩L2(0, T;U)
Mν, Hν ∈L∞(0, T;L2(D))∩L2(0, T;H1t(D)) Qν ∈L∞(0, T;L2(D))∩L2(0, T;H1n(D)) θν ∈L∞(0, T;L4(D))∩L4(0, T;W1,4(D))
(49)
and satisfying the energy estimates (46) and (48) and the problem in the following sense
(i) Uν(0) =U0 and for all v∈ U d
dt Z
D
Uν·v dx+ Z
D
(Uν · ∇)Uν ·v dx+η Z
D
∇Uν · ∇v dx=
− Z
D
ρ(θν)g·v dx+µ0 Z
D
(Mν · ∇)Hν ·v dx+µ0 2
Z
D
Mν ×Hν·curlv dx (50) (ii) Mν(0) =M0 and for allw∈H1t(D)
d dt
Z
D
Mν·w dx+ Z
D
(Uν · ∇)Mν·w dx+σ Z
D
curlMν ·curlw dx +σ
Z
D
divMνdivw dx+1 δ
Z
D
(Mν−χ0Hν)·w dx= 1
2 Z
D
curlUν×Hν ·w dx−β0
Z
D
Mν ×Hν ·Mν×w dx
(51)
(iii) θν(0) =θ0ν and for all a∈W1,4(D) d
dt Z
D
θνa dx− Z
D
θνU · ∇a dx+ν Z
D
|∇θν|2∇θν· ∇a dx=− Z
D
divQνa dx (52) (iv) Qν(0) =Q0 and for all b∈H1n(D)
τ d dt
Z
D
Qν·b dx+τ γ Z
D
(curlQν ·curlb+ divQνdivb)dx+
τ 2
Z
D
curlUν ×Qν ·b dx=− Z
D
Qν·b dx+ Z
D
K(θν) divb dx
(53)
with Hν =∇ϕν where ϕν =H(Mν, F) is defined in (20).
3.1 Faedo-Galerkine approximation for (P
ν)
Letν >0be fixed, consider the weak formulation of problem(Pν) given in Theorem 2.
In order to solve this problem by the Faedo-Galerkine method, we introduce the Hilbert basis(Vj)j≥1,(Wj)j≥1,(Φj)j≥1 of the spacesU,H1t(D),H1n(D)respectively and a basis (vj)j≥1 ofW1,4(D). For simplicity, we assume these basis to be orthonormal inL2(D).
We seek for approximated solutions of the system(Pν)of the form Un(t) =
n
X
j=1
αj(t)Vj, Mn(t) =
n
X
j=1
βj(t)Wj, θn(t) =
n
X
j=1
aj(t)vj, Qn(t) =
n
X
j=1
bj(t)Φj
(54)
satisfying for alln∈N∗ and1≤j ≤n (i) d
dt Z
D
Un·Vjdx+ Z
D
(Un· ∇)Un·Vjdx+η Z
D
∇Un· ∇Vjdx=
− Z
D
ρ(θn)g·Vjdx+µ0 Z
D
(Mn· ∇)Hn·Vjdx+ µ0 2
Z
D
Mn×Hn·curlVjdx Un(0) =U0n
(55)
(ii) d dt
Z
D
Mn·Wjdx+ Z
D
(Un· ∇)Mn·Wjdx+σ Z
D
curlMn·curlWjdx +σ
Z
D
divMndivWjdx+1 δ
Z
D
(Mn−χ0Hn)·Wjdx= 1
2 Z
D
curlUn×Hn·Wjdx−β0
Z
D
Mn×Hn·Mn×Wjdx Mn(0) =M0n
(56)
(iii) d dt
Z
D
θnvjdx− Z
D
θnUn· ∇vjdx+ν Z
D
|∇θn|2∇θn· ∇vjdx=
− Z
D
divQnvjdx θn(0) =θ0nν
(57)
(iv) τ d dt
Z
D
Qn·Φjdx+τ γ Z
D
(curlQn·curl Φj+ divQndiv Φj)dx=
−τ 2
Z
D
curlUn×Qn·Φjdx− Z
D
Qn·Φjdx+ Z
D
K(θn) div Φjdx Qn(0) =Q0n
(58)
where
Hn=∇ϕn, ϕn=H(Mn, F)) U0n=
n
X
j=1
αj0nVj, M0n=
n
X
j=1
β0nj Wj, θ0nν =
n
X
j=1
aν,j0n vj, Q0n=
n
X
j=1
bj0nΦj. We assume that
(U0n, M0n, Q0n)→(U0, M0, Q0) strongly in (L2(D))3 θν0n→θν0 strongly in W1,4(D).
(59)
This problem will be labeled (Pνn).
3.2 Solving the system (P
νn)
Let the vector valued functionsαn= (α1,· · ·, αn),βn= (β1,· · ·, βn),an= (a1,· · ·, an) andbn= (b1,· · ·, bn), we consider the function
t∈[0, T]→γn(t) = (αn(t), βn(t), an(t), bn(t))∈(Rn)4 thenγn satisfies the ordinary differential system
γn0 +Anγn=Zn(t, γn), γn(0) =γ0n (60) whereγ0n= (α0n, β0n, aν0n, b0n)∈(Rn)4,Anis a n4×n4 constant matrix involving the terms
η Z
D
∇Vi· ∇Vj dx, σ Z
D
(curlWi· curlWj+ divWidivWj)dx τ γ
Z
D
(curl Φi·curl Φj+ div Φidiv Φj)dx+ Z
D
Φi·Φjdx
and the vector fieldZn= (Zn1, Zn2, Zn3, Zn4)∈(Rn)4 is defined as follows Znj1 (t, γn) =−
Z
D
(Un· ∇)Un·Vjdx− Z
D
ρ(θn)g·Vjdx +µ0
Z
D
(Un· ∇)Hn·Vjdx+µ0
2 Z
D
Mn×Hn·curlVjdx Znj2 (t, γn) =−
Z
D
(Un· ∇)Mn·Wjdx−1 δ
Z
D
(Mn−χ0Hn)·Wjdx +1
2 Z
D
curlUn×Hn·Wjdx−β0 Z
D
Mn×Hn·Mn×Wjdx Znj3 (t, γn) =
Z
D
θnUn· ∇vjdx−ν Z
D
|∇θn|2∇θn· ∇vi dx− Z
D
divQnvjdx Znj4 (t, γn) =−τ
2 Z
D
curlUn×Qn·Φjdx+ Z
D
K(θn) div Φjdx for 1≤j≤n.
Notice thatZnhas the same regularity in the time variabletas the functionF appearing in the magnetostatic equation and it is continuous and locally lipschitz continuous with respect to the variable γn. Hence there exists a unique maximal solution γn of (60) defined on a time interval[0;Tn]satisfying γn ∈H1(0, Tn; (Rn)4). We shall prove that Tn=T with the following estimate.
Let(Un, Mn, θn, Qn)be the solution of(Pνn)defined on(0, Tn). We want to verify that sup
t∈[0;Tn]
(kUnk2+kMnk2+kθnk4L4(D)+kQnk2)(t)<∞. (61) We multiply equation (58) bybj and add these equations for 1≤j≤n, we obtain
τ 2
d
dtkQnk2+τ γ(kcurlQnk2+kdivQnk2) +kQnk2= Z
D
K(θn) divQndx. (62) We use the equation (57) that we multiply by Θj(t) =
Z
D
K(θn)·vj dx and add the equalities for1≤j ≤nto obtain
d dt(κ
2kθnk2+α
4kθnk4L4(D)) +ν(κk∇θnk4L4(D)+ 3α Z
D
θ2n|∇θn|4 dx) =
− Z
D
divQnK(θn)dx.
(63)
Adding (62) and (63) lead to 1
2 d
dt(κkθnk2+α
2kθnk4L4(D)+τkQnk2) +νκk∇θnk4L4(D)
+3ναkθn|∇θn|2k2+τ γ(kcurlQnk2+kdivQnk2) +kQnk2 = 0
(64)
Therefore, integrating between 0 andtand using (59), we easily deduce that (κkθnk2+α
2kθnk4L4(D)+τkQnk2)(t) + 2ν Z t
0
κk∇θnk4L4(D)ds +2
Z t 0
(3ναkθn|∇θn|2k2+τ γ(kcurlQnk2+kdivQnk2) +kQnk2)ds= κkθν0nk2+α
2kθν0nk4L4(D)+τkQ0nk2 ≤C
(65)
withC independent of n. Similarly, we obtain from equations (55) and (56) 1
2 d
dtkUnk2+ηk∇Unk2=− Z
D
ρ(θn)g·Undx
−µ0 Z
D
(Un· ∇)Mn·Hndx+µ0
2 Z
D
(Mn×Hn)·curlUndx
(66)
1 2
d
dtkMnk2+σkcurlMnk2+σkdivMnk2+1
δkMnk2 = +χ0
δ Z
D
Hn·Mndx+ 1 2
Z
D
curlUn×Hn·Mndx
(67)
so (66) and (67) lead to 1
2 d
dt(kUnk2+µ0kMnk2) +ηk∇Unk2+µ0σ(kcurlMnk2+kdivMnk2) + µ0
δ kMnk2
=− Z
D
ρ(θn)g·Undx−µ0
Z
D
(Un· ∇)Mn·Hndx+µ0χ0
δ Z
D
Hn·Mndx.
Using equation (24) for unknownϕn and data Mn, and testing withψ=ϕn, we get Z
D
Hn·∂tMndx=−1 2
d
dtkHnk2− Z
D
∂tF ϕndx.
Now we multiply equation (56) by hj(t) = Z
D
Hn·Wj dx and add the equalities for 1≤j≤nto obtain
Z
D
∂tMn·Hndx+ Z
D
(Un· ∇)Mn·Hndx+σ Z
D
divMndivHndx +1
δ Z
D
(Mn−χ0Hn)·Hndx=−β0kMn×Hnk2
(68)
so Z
D
(Un· ∇)Mn·Hndx= 1 2
d
dtkHnk2+ Z
D
∂tF ϕndx−1 δ
Z
D
Mn·Hndx
−σ Z
D
divMn(F−divMn)dx+χ0
δ kHnk2−β0kMn×Hnk2.
(69)
>From (21), we see that Z
D
Hn·Mndx=−kHnk2− Z
D
F ϕndx therefore
Z
D
(Un· ∇)Mn·Hndx= 1 2
d
dtkHnk2+ Z
D
(∂tF+1
δF)ϕndx+σkdivMnk2
−σ Z
D
divMnF dx+ 1 +χ0
δ kHnk2−β0kMn×Hnk2.
(70)
so integrating between 0 andt, we get 1
2(kUnk2+µ0(kMnk2+kHnk2)(t) +η Z t
0
k∇Unk2ds +
Z t
0
(µ0σ(kcurlMnk2+ 2kdivMnk2) +µ0
δ kMnk2)ds +
Z t 0
µ0(1 + 2χ0)
δ kHnk2 ds+β0µ0
Z t 0
kMn×Hnk2 ds= 1
2(kU0nk2+µ0(kM0nk2+kH0nk2)+
Z t 0
Z
D
ρ(θn)g·Undxds−µ0(1 +χ0) δ
Z t 0
Z
D
F ϕn dxds
−µ0 Z t
0
Z
D
∂tF ϕn dxds+µ0σ Z t
0
Z
D
FdivMn dxds
(71)
where
H0n=∇ϕ0n, ϕ0n=H(M0n, F(0)). (72) Using the inequalities
| Z t
0
Z
D
ρ(θn)g·Undxds| ≤CT +C Z t
0
kθnk2 ds+ 1 2
Z t
0
kUnk2 ds,
µ0(1 +χ0)
δ |
Z t 0
Z
D
F ϕndxds|+µ0| Z t
0
Z
D
∂tF ϕndxds| ≤ C(kFk2L2(DT)+k∂tFk2L2(DT)) +µ0(1 + 2χ0)
2δ
Z t 0
kHnk2 ds,
µ0σ|
Z t
0
Z
D
FdivMndxds| ≤CkFk2L2(DT)+µ0σ Z t
0
kdivMnk2 ds.
We get
1
2(kUnk2+µ0(kMnk2+kHnk2)(t)+
Z t 0
[ηk∇Unk2+µ0σ(kcurlMnk2+ 2kdivMnk2) +µ0
δ kMnk2]ds +
Z t 0
[µ0(1 + 2χ0)
2δ kHnk2+β0µ0kMn×Hnk2]ds≤ An+CT +C
Z t 0
kθnk2ds+1 2
Z t 0
kUnk2 ds
(73)
where
An= 1
2(kU0nk2+µ0(kM0nk2+kH0nk2)≤C
with C independent of n in view of (59), (72) and (19). Thus thanks to (65) and Gronwall inequality, we deduce that
kUn(t)k2+kMn(t)k2+kHn(t)k2 ≤C+ exp(Ct) (74)
then 1
2(kUnk2+µ0(kMnk2+kHnk2)(t)+
Z t 0
[ηk∇Unk2+µ0σ(kcurlMnk2+ 2kdivMnk2) +µ0
δ kMnk2]ds +
Z t
0
[µ0(1 + 2χ0)
2δ kHnk2+β0µ0kMn×Hnk2]ds≤C+ exp(Ct).
(75)
This ends the proof of (61) so we conclude thatTn=T for alln≥1.
3.3 Convergence of the Faedo-Galerkine scheme
Letν be fixed, the estimates (65) and (75) show that Lemma 1
• (Un)n is uniformly bounded in L∞(0, T;U0)∩L2(0, T;U)
• (Mn)n andHn are uniformly bounded in L∞(0, T;L2(D))∩L2(0, T;H1t(D))
• (Mn×Hn)n is uniformly bounded in L2(0, T;L2(D))
• (Qn)n is uniformly bounded in L∞(0, T;L2(D))∩L2(0, T;H1n(D))
• (θn)n is uniformly bounded in L∞(0, T;L4(D))∩L4(0, T;W1,4(D)).
Notice that we get the uniform bound of(Hn)ninL2(0, T;H1t(D))using the bound of (Mn)n and (23). Hence we get the convergence
Lemma 2 Let ν > 0 be fixed. There exists subsequences still denoted (Un), (Mn), (Hn), (Qn) and (θn) such that when n→ ∞
Un* Uν weakly−? inL∞(0, T;L2(D))and weakly in L2(0, T;U)
Mn* Mν, Hn* Hν weakly−?in L∞(0, T;L2(D))and weakly inL2(0, T;H1t(D)) Qn* Qν weakly−? inL∞(0, T;L2(D)) and weakly inL2(0, T;H1n(D))
θn* θν weakly−?in L∞(0, T;L4(D)) and weakly inL4(0, T;W1,4(D)) Moreover, we have
|∇θn|2∇θn*Λν weakly inL43(DT). (76) In order to pass to the limit in the nonlinear terms, we need strong convergence for the sequences in some spaces. To apply compactness results, we need to estimate the time derivatives of the solutions.
Let us begin with(∂tθn)n. We multiply equation (57) by a0j(t) and add the resulting equalities for1≤j ≤nto get
k∂tθnk2+ Z
D
∂tθn∇θn·Undx+ν 4
d
dtk∇θnk4L4(D) =− Z
D
divQn∂tθn (77)
Since we have| Z
D
∂tθn∇θn·Undx| ≤ 1
4k∂tθnk2+k∇θnk2L4(D)kUnk2L4(D) we obtain k∂tθnk2+ν
2 d
dtk∇θnk4L4(D)≤2kdivQnk2+ 2k∇θnk2L4(D)kUnk2L4(D) (78) Therefore, integrating between 0 andt, using (59) and (65), we easily deduce that
Z t 0
k∂tθnk2ds+ν
2k∇θnk4L4(D)≤ ν
2k∇θν0nk4L4(D)+ 2
Z T 0
kdivQnk2ds+ 2 Z t
0
k∇θnk2L4(D)kUnk2L4(D)ds
≤C+ 2 Z t
0
k∇θnk2L4(D)kUnk2L4(D)ds
(79)
withC independent of n.
Settingy(t) = k∇θn(t)k4L4(D) and F(t) =kUnk2L4(D) then from (79), y(t) satisfies the integral inequality
y(t)≤Cν + 2Mν
Z t 0
py(s)F(s)ds.
Using the Gronwall-Bellman-Bihari inequality (see [3]) we deduce y(t)≤p
Cν +Mν
Z t 0
F(s)ds 2
. Hence we get for all t∈[0, T]the estimate
k∇θn(t)k2L4(D)≤p
Cν +Mν
Z t 0
kUn(s)k2L4(D)ds which leads to
Z T 0
k∂tθnk2ds≤C+ 2p Cν
Z T 0
kUn(s)k2L4(D)ds+ 2Mν
Z T 0
kUn(s)k2L4(D)ds 2
(80) and we conclude that(∂tθn)n is uniformly bounded in L2(DT) with respect to n.
To estimate ∂tUn, ∂tMn and ∂tQn we need some notations. For a function f defined on [0, T]with values in a space V, let febe the function equal to f on [0, T]and to 0 elsewhere and letfbbe its Fourier transform defined by
fb(τ) = Z
R
exp(−2iπtτ)f(t)e dt= Z T
0
exp(−2iπtτ)f(t)dt, τ ∈R. We will prove that for0< γ <1/4,
Z
R
|τ|2γkUbn(τ)k2 dτ ≤C. (81) Proceeding as in [22] (see also [16]) and since(Un)nis uniformly bounded inL2(0, T;U), it is enough to verify that
|τ| kUbn(τ)k2≤CkUbn(τ)kU +CkUbn(τ)k, ∀τ ∈R. (82)
We write the equation (55) ofUn in the form d
dt Z
D
Un·Vjdx=hLn, Vji, Un(0) =U0n (83) for all1≤j≤nwhere the linear form Ln is defined onU by
hLn, ϕi= Z
D
(Un· ∇)Un·ϕ dx+η Z
D
∇Un· ∇ϕ dx+ Z
D
ρ(θn)g·ϕ dx
−µ0 Z
D
(Mn· ∇)Hn·ϕ dx−µ0 2
Z
D
Mn×Hn·curlϕ dx
(84)
We haveLn∈ U0 p.p. t∈(0, T) and
kLnkU0 ≤C(kUnk2H1(D)+kUnkH1(D)+kρ(θn)k+
kMnkH1(D)kHnkH1(D)+kMn×Hnk)
and we conclude thanks to Lemma 1 that (Ln) is uniformly bounded in L1(0, T;U0).
Now we rewrite (99) as follows d
dt Z
D
Uen·Vjdx=hLfn, Vji+ Z
D
U0n·Vj dx
δ0−Z
D
Un(T)·Vj dx
δT (85) for 1≤j≤nwhereδadenotes the Dirac distribution at a∈R. Therefore, we obtain
2iπτ Z
D
Ubn·Vjdx=hLcn, vji+ Z
D
U0n·Vj dx−exp(−2iπT τ) Z
D
Un(T)·Vj dx (86) Next we multiply equality (86) byαcj(τ) the conjugate ofcαj(τ) and add the equalities for 1≤j≤nto get
2iπτkUbnk2=hLcn,Ubni+ Z
D
U0n·Ubn dx−exp(−2iπT τ) Z
D
Un(T)·Ubn dx (87) therefore since for allτ ∈R, we have
kLcn(τ)kU0 ≤ Z T
0
kLn(t)kU0dt≤C then using Plancherel identity we get (82).
Similar proofs work for∂tMn and ∂tQn. The above results are summarized in Lemma 3 There exists Cν >0 such that for all n
Z
R
|τ|2γ(kUbn(τ)k2+kMcn(τ)k2+kQbn(τ)k2) dτ ≤Cν (88) Moreover we have
k∂tθnkL2(DT)≤Cν (89) Combining the bounds of Lemma 1 and Lemma 3 and applying Lions compactness lemma for(Un, Mn, Qn) and and Aubin compactness lemma for θn we get the strong convergence results we get the strong convergence results