A NNALES DE L ’I. H. P., SECTION B
C. D ONATI -M ARTIN
M. Y OR
Fubini’s theorem for double Wiener integrals and the variance of the brownian path
Annales de l’I. H. P., section B, tome 27, n
o2 (1991), p. 181-200
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181-
Fubini’s theorem for double Wiener integrals
and the variance of the Brownian path
C. DONATI-MARTIN
M. YOR
Universite de Provence, U.R.A. 225, 3, place Victor-Hugo,
13331 Marseille Cedex 3, France
Universite Pierre-et-Marie-Curie, Laboratoire de Probabilités, 4, place Jussieu, 75252 Paris Cedex 05, France
Vol. 27, n° 2, 1991, p. -200. Probabilités et Statistiques
ABSTRACT. -
Using
Fubini’s theorem for double Wienerintegrals,
it ispossible
to show that certainquadratic
functionals of Brownian motion have the same law. This isapplied
to the variance of the Brownianpath,
which has the same law as the
integral
of the square of the Brownianbridge.
Key words : Fubini theorem, double Wiener integrals, Brownian path.
RESUME. - A l’aide d’un theoreme de Fubini pour des
intégrales
deWiener
doubles,
onpeut
montrer que certaines fonctionnellesquadratiques
du mouvement brownien ont meme distribution. Ce résultat est
applique
a la variance de la
trajectoire brownienne, qui
a meme loi quel’intégrale
du carre du pont brownien.
Classfication A.M.S. : Primary: 60 J 65, 60 J 55. Secondary: 60 H 05, 60 G 44.
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques - 0246-0203 Vol. 27/91/02/!81/20/$ Gauthier-Villars
182 C. DONATI-MARTIN AND M. YOR
1. INTRODUCTION
(1 .1)
We denote thequantity
for Let(ZS = ~S + i ~$, s >__ o)
be thecomplex
valued Brownianmotion,
withZo = 0,
1
and let G= be its centre of
gravity
over the time interval[0,1].
Duplantier [3]
obtained the distribution ofma the computation ot its characteristlc function:
A
This formula
(1 a)
may be derivedsimply (see
Yor[13])
from the celebratedLevy
formula(see Levy [7]; (1950)):
"
where A=
Jo Z.xJZ,.
It has been remarked that:
where
and this
identity ( 1 c)
may be used as astep
towards theproof
of( 1 b), reducing
thisproof
to acomputation involving only
the radial(Bessel)
process
(I ZS I,
s1 ) (see
Williams[ 11 and
Yor[ 12]
fordetails).
(1.2) Following
thepublication
of[ 13],
the second author(M. Y.)
wasthen asked
by
K. Jansons(personal communication; September 1989), following
thecomputation
made in[5],
whether thecomputation
of theLaplace
transform of:"’1
might
also follow fromLévy’s
formula(1 b). Actually,
P. Malliavin hasbeen interested for
quite
some time in the distribution of~‘~~ (see [8])
andhad also asked M. Y. in 1980 to
compute
itsLaplace
transform. However,Annales de Henri Poincaré - Probabilités et Statistiques
in December
1989,
we came across the work ofChiang,
Chow and Lee[2]
from which it follows inparticular
that:where
s __ 1 )
is astandard, complex-valued,
Brownianbridge.
One ofthe
proofs given
in[2]
isparticularly simple,
andprovides
an affirmativeanswer to K. Jansons and P. Malliavin’s
questions;
here is thisproof:
thenext formula
( 1 e)
follows fromLévy’s
formula( 1 b) by integrating
withrespect
to the law ofZ~
The left-hand side of
(1 e)
is alsoequal
to:(the
reader may also check that these formulae are inagreement
with themore
general
formula(2 k),
in the case d = 2 anda=0,
in Pitman-Yor[10])
andintegrating
both the latterexpression
and theright-hand
side of(1 e)
withrespect
to theLebesgue
measure dz[R2,
one obtains:from
which, put together
with( 1 b)
and( 1 c),
one deduces( 1 d).
However,
in the secondparagraph
of thepresent
paper,yet
anotherquite elementary proof
of(1 d)
isgiven,
whichessentially
follows from Fubini’s theorem. Thisargument
allows us to derive ageneral
extensionof
(1 d).
( 1. 3)
We take thisopportunity
to mention two estimates on theLaplace
transform of
1/ G
which weremade,
on one handby
P. Malliavin[8], p. 328, and,
on the otherhand, by
Ikeda-Watanabe[4],
Lemma 8. 6(this
has become Lemma 10.6 in the second edition of
[4]).
From
(1/),
we have:r / , , -.’" " /~B 4
and it seems
interesting
to remark that P. Malliavinmajorizes
the left-hand side of
(!/’) by 201420142014,
, whereas Ikeda-Watanabe’smajorization
iscosh
~ sinh03BB
°
Vo!.27, n° 2-1991.
184 C. DONATI-MARTIN ANU M. YUR
Independently
ot this, our interest In thesequestions
was turther arousedby
thecomputation,
made atCambridge by
T. Chan and C.Rogers (Personal
communication of K. Jansons[5])
of thejoint Laplace-Fourier
transform of the law of
(1/ G, G, Zl).
Thisprompted
us to work out acomplement
to thedevelopment
of Brownian motionalong
theLegendre polynomials orthogonal
basis ofL2 [0,1]),
and itsrelationship
toLévy’s
formula
(1 b),
as doneoriginally by
Biane and Yor([ 1 a], [ 1 b]).
This
complement
consists inobtaining
a simultaneousorthogonal
devel-opment of E,
andZ,
twoindependent
2-dimensional Brownianmotions,
and to
represent
terms of thisdevelopment.
This is doneprecisely
inparagraph 3,
where we also derive another simultaneousorthogonal development of ç
andZ,
and expressIi df;s
xZS
in terms ofthis
development.
In both cases, theLegendre polynomials again play a
fundamental role.
( 1 . 4)
Inparagraph 4,
we return to our extensions -presented
in para-graph
2 - of theidentity
in law(1 d).
We show that those identities in lawcan also be derived
by remarking
that certainpairs
ofoperators
onL2 ([0,1])
have the sameeigenvalues, thereby connecting
our work withthe time-honoured
diagonalization procedure,
which goes back toLévy’s original
paper[7]
and has been usedagain
andagain
in most of thecomputations
of the laws ofquadratic
Brownian functionals(examples already quoted
above are[1 b], [2], [3],
but see also Kree[6]
andMcAonghusa
and Pulé[9]
for otherexamples
in the recentliterature).
2. SOME IDENTITIES IN LAW BETWEEN BROWNIAN
QUADRATIC
FUNCTIONALS(2 . 1 )
Theidentity
in law( 1 d), and,
moregenerally,
alarge
class ofidentities in law between two Brownian
quadratic functionals,
are imme-diate consequences of the
following
Fubinitype identity
between double Wienerintegrals:
let p:[0, 1]2
- R be a deterministic function such that,, i , 1
i nen, me almost sure identify noios:
... 1 /* ~ 1 ,.. 1
where, here,
forsimplicity, ç
and Z denote twoindependent
one-dimen-sional Brownian
motions, starting
from 0.From
(2 a)
and theindependence of ~
andZ,
we now deduce thegeneral identity
in law:where s~i) denotes here again a 1-dimensional Brownian motion.
Remark. - The
identity (2a)
and theidentity
in law(2b)
extendobviously
to apair
of d-dimensional Brownianmotions ~
and Z on onehand,
and a d-dimensional Brownian motion B on the otherhand,
pro- vided theproducts dZ~
andd~u
in(2 a)
are scalarproducts,
andthe squares in
(2 b)
are squares of the euclidean norm. DApplying
theidentity (2 b)
to someparticular integrands
(p, we obtain thefollowing
PROPOSITION 1. - 1.
Let f: [0,1] ] --~
RThen,
we have:~1 / ~1
In
particular, i f ’ f ( 1 )
=I ,
we obtain:~. t,et we nave:
Proof - (2 c’) immediately
follows from(2c),
and(2c")
is obtainedfrom
(2 c) by taking f(u) =
au.It remains to prove
(2 c).
This follows from(2 ~),
when it isapplied
to:Indeed,
with thisparticular
(p, weobtain,
on one hand:27. n° 2- 1991 .
186 C. DONATI-MARTIN AND M. YOR
whereas:
The second
identity
in law in(2 -e) follows
from the firstby using:
- (law)_- - _ _ _
(2.2)
We now strive to obtain another extension 01 the identity in law(1 d),
whichcorresponds roughly
to thecomputations
of T. Chan and C.Rogers [see ( 1 . 3) above] and,
moreimportantly,
shallput
us on theright
road to the infinite dimensional extension which wedevelop
inparagraph
3.In this
paragraph, ~
and Z are twoindependent
2-dimensional Brownian motionsstarting
from 0. We recall some notation from[13]:
consider thedecomposition
1’B. r-y ~ . r-~r ~ ~- 1 B
(Zs, s~1) ls a Browman
bridge
which ls mdependentof Z1. Usmg
the1
decomposition (2 d),
wedevelop
~ = X and we find:ana
An
integration by parts
shows that:so that, with our premous notation tor tne
barycentre,
we obtain:i w n~ e~ .~ w ~. - =
1 ne resi 01 tms paragrapn is devoted io snowing me Ioiiowmg identity m law:
io prove (2~), we shall use some independence properties between certain
r.v’s, together
with thefollowing
almost sureidentity,
which is aparticular
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques
case of
(2 a):
(the
lastequality
is obtainedby integration by parts).
We now remarkthat,
on the left-hand side of(2 g),
thepair (j~, p)
isindependent of Z ~,
since,
from(2 f ), P
= - 2G
is measurable withrespect
to2. Likewise,
onthe
right-hand
side of(2 g),
we see that thevariable 03BE1
isindependent
from the
pair (10 d03BEs.(Zs-G), G , by using
theidentity (2 h). Hence,
inorder to prove
(2 g),
it is now sufficient to proveWe shall derive this
identity
in law from:/ 18 -i ,
the
proof
of which wepostpone.
Assuming
for the moment that(2 j) holds,
we derive thefollowing equality,
for every and zeC:r /*1 -,
We deduce from
(2 e)
that the left-hand side of(2 j’) equals:
whIle the
right-hand
side of(2 j’ )
isequal
to:r-- ~ A~ ’- ---,
thanks to the
independence
of theright-hand
side of(2 i)
andÇ,1.
Theequality
in law(2 i )
now follows from theequality
of(2 k)
and(2 1)
andthe invariance
by
rotation of the law of the Brownianbridge
Z.It now remains to prove
(2 j). By linearity,
it is sufficient to show that for any zeC:1 his follows from tne fact that eacn oI processes:
Vol 27. n° 2-1991.
188 C. DONATI-MARTIN AND M. YOR
is a real-valued Brownian
motion,
which isindependent
ofJ,
s ~0).
The
proof
of(2 g)
is nowcomplete.
(2.3)
Inparagraph 3,
we shallgive
an infinite dimensional extension of theidentity
in law(2 g). However,
beforedoing
so, it may be of someinterest to compare, for any a e
R,
the characteristic function ofand the
Laplace
transform of(03B1)~ |Zs -
aG|2 ds,
thusshowing
that0
the
identity:
which is a consequence
of (1 c)
has anadequate,
butnon-trivial,
extensionfor any 03B1 ~ R. We prove the
following
PROPOSITION 2. - Let Z
and 03BE
be twoindependent
2-dimensional BrownianI
starting from
o. Wedefine : (03B1)
=10 d03BEs. (Zs-03B1Gj.
we
for
every 03BB ~ R:r i ~~ »
Proof -
On onehand,
we deduce from formula(2 e)
that:Un the other
hand,
wehave,
from the definition of::/(B1.):
and we deduce from
(2 g)
that:Comparing mis wim me aoove expression 01 , we obtam 1 ), and
(2n 2) follows,
with thehelp
of formula(2.8) in [13],
for theexplicit computation
in terms of cosh and sinh. DAnnales de l’Institut Henri Poincaré - Probabilités et Statistiques
3. A SIMULTANEOUS ORTHOGONAL DECOMPOSITION OF TWO INDEPENDENT BROWNIAN MOTIONS
(3.1)
Thedecomposition (2 e) s/ = §7
+Z1 J3
arises as the firststep
ina series
development
of~,
which is obtained whendeveloping
s_ ~ ~ along
theLegendre polynomials orthogonal
basis ofL2 [0, 1].
Morepreci- sely,
we have thefollowing
THEOREM 3
(Biane
and Yor1 a], [1 b]).
- LetP (t)
-1 2m n!dn dtn t2 -1 n
be the sequence
of Legendre polynomials.
Consider the
orthogonal decomposition of
Brownian motion:00 / /8+ t ,
where:
Then:
(i)
The stochastic area ~ may berepresented
as:where the convergence holds both in
L2
and a.s.(ii)
For any p eN,
we have:, I t 0 ,
where:
(3 . 2)
We insist that theidentity (2 ?)
is the firststep
in thedecomposition (3~),
since andWe took this
remark, put together
with theidentity
in law(2~)
as anindication
for, possibly,
the existence of aninteresting decomposition
of‘~.‘3s - Zs.
In
fact,
the rest of thisparagraph
shall be devoted toproving
thefollowing companion
to Theorem 3.Vo!.27.n° 2-1991.
190 C. DONATI-MARTIN AND M. YOR
THEOREM 4. -
Let 03BE
and Z be two independent Brownianmotions, starting from
o.Consider the two
orthogonal decompositions:
00 00
where:
and is the sequence
Legendre polynomials.
Define:
and, Jor every p, we have:
or
equivalently : (~3k;
0__ h
0 _ k(0).
Finally, the following , formula
holds :~.~here
hp
andkp
have the samemeaning
as in Theorem 3.(3.3)
To prove Theorem4,
we now mimick theproof
of Theorem3, given
in Biane-Yor[1 a].
We first define a sequence of Gaussian processes t _ Gaus- sian variables
yp,
via the recurrence formula(3 c)
below.Annales de l’Institut Henri Poincaré - Probabilités et Statistiques
Since for the even
(resp. : odd) indices, (resp. : 1l2p+ 1 )
is measurable withrespect to ç,
resp. :Z,
we shall write:These recurrence formulae are:
{
with the initial conditions:
Ç,o (s) = Ç,s
andZ1 (s)
=ZS,
and the additionalrequirement that,
for every s, isorthogonal
to yk. We define:Now,
from(3 c),
we deduce:In order to prove the theorem
completely,
it now remams to show that, for anyk,
y~ andBk
have the samecovariance,
thatis,
thanks to[1 a]:
and,
moreover, toidentify
the function vk, thatis,
moreprecisely,
to showthe formulae
(3 b).
From now on, we
shall,
as we may, assumethat ç
and Z are two real-valued, independent,
Brownian motions. We shallproceed
in 5steps.
Step
1. isabsolutely continuous,
and the sequence:(v2 p,
p>__ 0),
resp.:an
orthogonal
sequence inL2 [0, 1 ] . Proof. - admits
the Wienerrepresentation:
03B32p+1 = {I Cf>p (s) dZs,
for some function inL2 [0,1].
Since the variables
(03B32p+
l’p~ 0)
areorthogonal,
the functions are alsoorthogonal
inL2 [0,1].
From the
orthogonal development (3 c),
we deduce:Vol. 27, n° 2-1991.
192 C. DONATI-MARTIN AND M. YOR
hence:
anu consequently:
ine proot tor tne oad mtegers IS identical.
Step
2. - We prove thefollowing
relations : fork ~ 2,
which may be written, using
integration by
parts, as:/* -
using:
me iasL reiauon romows from me oruiogonainy 01 and
Proof of (3 e).
- Note that as defined in(3 c),
can be written asP1
(s)=
~k + 2q + 2(s) +
vk + 2 p + 1(s)
03B3k+ 2 p, therefore:p=0
Finally, (3 e)
follows from theorthogonality
of7~+2. ’ - ’~+2r
andllk+2q+2.
~Annales de l’Institut Henri Poincaré - Probabilités et Statistiques
Step
3. - Wecompute
the two covariancesof
the processes~~~
andZ2p+ 1.
From the formulae:we deduce:
where:
~,k
= E[yf].
Step
4. - Recurrenceformulae for the functions
vp. Let k >_2;
we have:using (3 e)
and V1(s)
= s.Hence,
we obtain:using (s)
ds =o,
which follows from theorthogonality
of ~y 1=G,
and0
Y2k - r ~ for
k ~
2.1
Formula
(3 j)
is also valid for k =l, using v2 (s)
ds =1. For k>__ l,
we also show in a similar way:For
A- == 0,
we have:Vol. 27, n° 2-1991.
194 C. DONATI-MARTIN AND M. YOR
These formulae
show, by
a recurrenceargument,
that vp is apolynomial
of
degree
p,for p >__
1.Step
5. - Conclusion. We define a sequence ofpolynomials
k >_1 ) by:
men, (v2k,
k ~1).
resp.: 1 ~k ~ 0),
is anorthogonal family
of L‘[0, 1 ].
Now,
formulae(3 j)
and(3 k)
can bewritten,
in terms ofv,
as oneformula:
and
From the classical recurrence formula between
Legendre polynomials:
it is easy to deduce that
?~ - I and, finally:
2p+
1(3 . 4) Starting
from theidentity
in lawinstead of
(2 g),
where theonly
difference lies in theright-hand sides,
withthe scalar
product.
in(2 g) replacing
the exteriorproduct
x in(2 g’),
weobtain the
following
Theorem.THEOREM 5. -
Let ~
and Z* be two(~2-valued independent
Brownianmotions, starting from
0.Consider the two
orthogonal decompositions:
where:
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques
Define:
Then, for
every the stochasticintegral
may berepresented
as:and we have:
or,
equivalently:
Proof -
We introduce the matrixA = ( -1 0 1 which
satisfies:for x,
y ER2,
and another Brownian motionZ,
which we defineby:
Z* = AZ.Using
the notation introduced in Theorem 4 for thepair (~ Z),
we find that:and Theorem 5 now follows from Theorem 4 thanks to the above identities
since,
for every m, we have: = D4. AN EIGENVALUE INTERPRETATION OF THE ABOVE IDENTITIES IN LAW
(4 .1 )
Our main aim in thisparagraph
is to show how theidentity
inlaw
where (p is a
general
function ofL 2 ([0, 1]2,
duds)
could also have been derivedusing
thediagonalization procedure
initiatedby
P.Levy [7].
Vol. 27, n° 2-1991.
196
We first use Itô’s formula to
develop (1 s));
we obtain:(4a) (I s))2 =2 s)s0 dBh03C6(u, h)+t0 ds03C62(u, s).
Taking t=1,
andintegrating
both sides of(4a)
withrespect
to we obtain thefollowing
a.s. identities:where:
and
As a consequence of
(4 b),
theidentity
in law(2 b)
isequivalent
to:(4.2)
We now recall the main facts aboutLévy’s diagonalization
proce- dure andapply
them to prove(4 c).
To any function
a : (s, h) - a (s, h) belonging
toL2([O,
onecan associate an Hilbert-Schmidt
operator A,
which is definedby:
r, 1
We now remark
that,
if 0 denotes the Hilbert-Schmidtoperator
thus associated to p, then 4Y*1>,
resp.: is the trace-class(and,
conse-quently, Hilbert-Schmidt) operator
associated toH,
resp.:K,
where A*denotes the
adjoint
of A.The
key
to theproof
of(4 c)
is now that 1>* 1> and have the sameeigenvalues,
with the same orders ofmultiplicity.
Indeed,
with this fact inhand,
it remains to use thefollowing
well-known arguments:
if a is a
symmetric
function ofL2 ([0, 1 ]2),
and if A is a trace-class operator, then A isdiagonalizable
in an orthonormal basis ofeigenvectors
Annales de Henri Probabilités et Statistiques
of
L 2 ([0, 1]), corresponding
to theeigenvalues
so that:A a1= Jli ~i
The function a may be
represented
as:and we have:
where
(10 dBs aj(s); j~N)
is a sequence of N(0,1) indepen-
dent random variables.
In our
application,
if we call(cpi)
the sequence(a;)
associated toA=C*~,
resp. :($J
the sequence(Jj
associated to(~),
we obtain:~ ~~.r. , ~ -m- ~~ -~ ~ N
and,
from(4 d):
which
implies (2 b).
(4.2)
We end thisparagraph
with a few more remarksconcerning
theidentity
in law(2 b).
(i )
It istempting,
whenconsidering
theidentity (2 b),
to wonder whethera
"polarized"
versionmight
also be true, that is: for anypair
of functionsp
and 03C8 belonging
toL2 ([0, 1]2,
dsdu),
does thefollowing:
(1 j The tilda notation should not cause any confusion, since we use the notation B* for the transpose of the operator 0.
27, n° 2-1991.
198 C. DONATI-MARTIN AND M. YOR
hold?
We now prove
that,
even for some veryparticular
p andBj/, (4 f?)
may not be true.Indeed,
if we take:~/~. ~B2014~/..BL/~B..),/. ~2014 ~/,B
and denote:
then, the lett-hand side, resp.: the right-hand side, 01 (4 J°1) is equal to:
aBD,
resp.:f3AC,
where:Hence,
in thisexample, (4 f ?)
is trueif,
andonly
if:it is easy to snow that (4g?) noias 11 ana only n:
. -~ "- ~t~.--~~--
where
~=h(A ), {!3‘),
and so on...(ii)
We go backagain
to thebeginning
of our discussion of(4 f?);
if(4 f ’‘~)
were true, thenby linearity
in p and theidentity
in law would holdjointly
for both sides of(4 f?),
considered as two families of random variables indexedby
thepairs (cp, ~/).
In
particular, going
back toProposition 1,
the law of the process :n~ i v
However,
this is nonsense, sincereplacing a by a’
+ 1 anddeveloping
bothsquares in the above
integrals,
we would arrive at theidentity
in lawbetween:
Annales de Henri Poincaré - Probabilités et Statistiques
and:
which
is,
of course, absurd as far as the middle terms are concerned. In the samevein,
weremark
that it is also easy to show thefollowing:
thetwo
pairs
and
are identical in law
if,
andonly
if: a = b.ACKNOWLEDGEMENTS
It is a
pleasure
to thank Dr. K. Jansons and Professor Malliavin forraising
theoriginal question.
M. Y. should also like to thank Michel Ledoux formultiple
conversations about Wiener chaos.Note added in proof: - Since we submitted our manuscript in March 1990, we have
received the preprint of the paper [14] by T. Chan, where the computation of the law of
10 ds
(BS -G)2
is obtained as a particular case of a more general computation for Gaussianprocesses.
*
A very recent work of J. J. Prat [15] also contains this computation, which plays an important role in the study of oscillating integrals.
REFERENCES
[1] (a) Ph. BIANE and M. YOR, A Relation Between Lévy’s Stochastic Area Formula, Legendre Polynomials and Some Continued Fractions of Gauss, Tech. Report n° 74, Dpt. of Statistics, University of California, Berkeley (1986). (b) Ph BIANE and M.
YOR, Variations sur une formule de Paul Lévy. Ann. Inst. H. Poincaré, Vol. 23, 1987, pp. 359-377.
[2] T. S. CHIANG, Y. CHOW and Y. J. LEE, A formula for
Ew[exp-2-1a2~x+y~22],
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(Manuscript received March 1, 1990.)
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques