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THE AFFINE SOBOLEV INEQUALITY

GAOYONG ZHANG

1. Introduction

The Sobolev inequality is one of the fundamental inequalities con- necting analysis and geometry. The literature related to it is vast (see, for example, 1], 5], 7], 3], 6], 11], 12], 19], 22], 20], 21], 23], 25], 27], 28], 37], and 45]). In this paper, a new inequality that is stronger than the Sobolev inequality is presented. A remarkable feature of the new inequality is that it is independent of the norm chosen for the ambient Euclidean space.

The Sobolev inequality in the Euclidean space Rn states that for any C1 functionf(x) with compact support there is

(1:1) Z

R n

jrfjdx n!

1=n

n kfkn;1n

wherejrfjis the Euclidean norm of the gradient off,kfkp is the usual

Lp norm of f in Rn, and!n is the volume enclosed by the unit sphere

Sn;1 in Rn. The best constant in the inequality is attained at the characteristic functions of balls.

It is known that the sharp Sobolev inequality (1.1) is equivalent to the classical isoperimetric inequality (see, for instance, 2], 8], 13], 14], 33], 35], 40], and 41]). We prove an ane Sobolev inequality which is stronger than (1.1). This inequality is proved by using a generalization of the Petty projection inequality to compact sets that is established in this paper (see 30], 31], 16], 26], 38] and 42] for the classical Petty projection inequality of convex bodies).

Received February 2, 2000. Research supported, in part, by NSF Grant DMS- 9803261

183

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Theorem 1.1.

If f is a C1 function with compact support in Rn, then

(1:2) 1

n Z

Sn;1k rufk;n

1

ducnkfk;n

n

n;1

whereruf is the partial derivative off in directionu,duis the standard surface measure on the unit sphere, and the constant cn =;2!!n;1n

n is best.

The inequality (1.2) isGL(n) invariant while the inequality (1.1) is only SO(n) invariant. Thus, inequality (1.2) does not depend on the Euclidean norm of Rn. The best constant in (1.2) is attained at the characteristic functions of ellipsoids. Applying the Holder inequality and Fubini's theorem to the left-hand side of (1.2), one can easily see that inequality (1.2) is stronger than the Sobolev inequality (1.1). For radial functions, the inequality (1.2) reduces to (1.1). It is worth noting that the left-hand side of (1.2) is a natural geometric invariant. Specif- ically, for a C1 functionf(x), there is an important norm of Rn given by

kuk=krufk1 =

Z

R n

jhurf(x)ijdx u2Rn

where h i is the usual inner product in Rn. The volume of the unit ball of this norm is exactly the left-hand side of (1.2).

We will also prove a generalization of the Gagliardo-Nirenberg in- equality.

Theorem 1.2.

Let fuigm

1 be a sequence of unit vectors in Rn and let figm

1 be a sequence of positive numbers satisfying

jxj

2 =Xm

i=1

ihxuii2 x2Rn:

If f is a C1 function with compact support in Rn, then

m

Y

i=1

k ruifk1ni 2kfkn;1n :

2. Basics of convex bodies

A convex body is a compact convex set with nonempty interior in

Rn.

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A convex body K is uniquely determined by its support function dened by

hK(u) = maxx

2Khuxi u2Sn;1:

IfK contains the origin in its interior, the polar bodyK ofK is given by

K

=fx2Rn :hxyi1 for ally2Kg:

Denote by V(K) the volume of K. The mixed volume V(K L) of convex bodiesK and L is dened by

V(K L) = 1

n

"lim!0+

V(K+"L);V(K)

"

:

There is a unique nite measure SK on Sn;1 so that

V(K L) = 1

n Z

Sn;1hL(u)dSK(u):

The measure SK is called the surface area measure of K. When K has a C2 boundary @K with positive curvature, the Radon-Nykodim derivative of SK with respect to the Lebesgue measure onSn;1 is the reciprocal of the Gauss curvature of @K.

An important inequality of mixed volume is the Minkowski inequal- ity,

(2:1) V(K L)n V(K)n;1V(L) with equality if and only if K and L are homothetic.

For a convex body K, let Kju? be the projection of K onto the 1-codimensional subspaceu? orthogonal to u. The projection function v(K u) of K is dened by

v(K u) = voln;1(Kju?) u2Sn;1:

The projection function v(K u) ofK denes a new convex body K whose support function is given by

h

K(u) = v(K u) = voln;1(Kju?) u2Sn;1:

The convex body K is called the projection body of K. The volume of the polar of the projection body K is given by

V(K) = 1

n Z

Sn;1v(K u);ndu:

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The Petty projection inequality is (see 30] and 36]) (2:2) V(K)n;1V(K)

!n

!n;1

n

with equality if and only ifK is an ellipsoid.

It was shown in 32] that the Petty projection inequality is stronger than the classical isoperimetric inequality of convex bodies.

Letu1u2:::unbe an orthonormal basis ofRn. For a convex body

K inRn, the Loomis-Whitney inequality is (see 29] and 8, p. 95])

V(K)n;1Yn

i=1v(K ui):

The Loomis-Whitney inequality was generalized by Ball 4]. Let

fuigm

1 be a sequence of unit vectors inRn, and letfcigm

1 be a sequence of positive numbers for which

m

X

i=1

ciuiui =In

where uiui is the rank-1 orthogonal projection onto the span of ui, and In is the identity on Rn. Then, for a convex body K in Rn, Ball proved the inequality

(2:3) V(K)n;1 Ym

i=1v(K ui)ci: The condition onui and ci is equivalent to

jxj

2 =Xm

i=1

cihxuii2 x2Rn

:

For details of convex bodies, see 16], 38] and 42].

3. Inequalities for compact domains

In this section, we generalize inequalities (2.1){(2.3) to compact do- mains. In this paper, a compact domain is the closure of a bounded open set. The generalization of the Minkowski inequality to compact

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domains can be obtained from the Brunn-Minkowski inequality. This appears to be standard. See 10] and 8].

IfM andN are compact domains inRn, then the Brunn-Minkowski inequality is

(3:1) V(M +N)n1 V(M)1n +V(N)1n with equality if and only if M and N are homothetic.

LetM be a compact domain with piecewiseC1 boundary@M, and letKbe a convex body inRn. The mixed volume ofMandK,V(MK), is dened by

(3:2) V(MK) = 1

n Z

@MhK((x))dSM(x)

where dSM is the surface area element of @M, and(x) is the exterior unit normal vector of @M at x.

If K is the unit ball Bn inRn, then nV(MBn) is the surface area

S(M) of M.

Lemma 3.1.

IfM is a compact domain with piecewiseC1 boundary

@M, andK is a convex body in Rn, then (3:3) nV(MK) = lim"

!0 +

V(M+"K);V(M)

"

:

WhenM is not convex, the limit of the right-hand side of (3.3) may not exist. Equation (3.3) holds whenMis a convex body or is a compact domain with piecewise C1 boundary. We give a proof of Lemma 3.1 in the Appendix.

Lemma 3.2.

IfM is a compact domain with piecewiseC1boundary, and K is a convex body in Rn, then

(3:4) V(MK)n V(M)n;1V(K) with equality if and only if M and K are homothetic.

Proof. For " 0, consider the function

f(") =V(M +"K)n1 ;V(M)1n ;"V(K)n1:

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From the Brunn-Minkowski inequality (3.1), the functionf(") is non- negative and concave. By Lemma 3.1, we have

"lim!0+

f(");f(0)

"

=V(M)1;nn V(MK);V(K)n1 0:

This proves the inequality (3.4). If the equality holds, f(") must be linear, andM and K are homothetic. q.e.d.

Lemma 3.2 was proved in 10] whenM has a C11 boundary.

LetM be a compact domain inRn with piecewiseC1 boundary@M and exterior unit normal vector(x). For any continuous functionf on

Sn;1, dene a linear functionalM on the space of continuous functions

C(Sn;1) on Sn;1 by

(3:5) M(f) =

Z

@Mf((x))dSM(x)

where dSM is the surface area element of M. The linear functional

M is a non-negative linear functional on C(Sn;1). Since the sphere is compact,M is a nite measure onSn;1. The measureM is called the surface area measureof the compact domainM.

The Minkowski existence theorem states that for every nite non- negative measureon Sn;1 such that

(3:6)

Z

Sn;1ud(u) = 0 and

Z

Sn;1jhuvijd(v)>0 u2Sn;1 there exists a unique convex bodyK (up to translation) whose surface area measure is. See 38], pp. 389-393.

We verify that the surface area measure M of a compact domain

M dened above satises (3.6). By Green's formula, for anyC1 vector eld (x) inRn, there is

Z

@Mh (x)(x)idSM(x) =

Z

Mdiv (x)dx:

Choose (x) =ei,i= 12n, the coordinate vectors, then div = divei =0. Therefore, Green's formula yields

Z

@Mhei(x)idSM(x) = 0:

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Let f(u) =heiui. Then (3.5) gives

Z

Sn;1heiuidM(u) =

Z

@Mhei(x)idSM(x) = 0: Since M has non-empty interior, one has

Z

@Mjhu(x)ijdSM(x)>0

that is, Z

Sn;1jhuvijdM(v)>0: Hence,M satises the condition (3.6).

LetM be a compact domain inRnwith piecewiseC1 boundary@M. A convexication M ofM is a convex body whose surface area measure

S

M is dened by

(3:7) SM =M:

Note that a convex body is determined by its surface area measure only up to translation. Therefore, the convexication M is unique up to translation.

LetM be a compact domain inRnwith piecewiseC1 boundary@M. The projection function v(Mu) of M on Sn;1 is dened by

v(Mu) = 12

Z

@Mjhu(x)ijdSM(x)

= 12

Z

Sn;1jhuvijdM(v) u2Sn;1 where (x) is the exterior unit normal vector ofM at x.

The following lemma is obvious.

Lemma 3.3.

IfM is a compact domain with piecewiseC1boundary, and M is a convexication of M, then

v(Mu) = v( Mu) u2Sn;1

V(MK) =V( MK) for any convex body K in Rn.

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Lemma 3.4.

If M is a compact domain in Rn with piecewise C1 boundary, and M is its convexication, then

(3:8) V( M) V(M)

with equality if and only ifM is convex.

Proof. From Lemma 3.3, for any convex bodyK, we have

V(MK) =V( MK): LetK= M. Then

V(MM) =V( M)

and the generalized Minkowski inequality (3.4) yields

V( M) =V(MM) V(M)n;1n V( M)1n: This proves (3.8). q.e.d.

The convexication in Rn was introduced in 9]. Lemma 3.4 for polytopes was proved in 9] see also 43].

LetM be a compact domain inRn with piecewiseC1boundary@M. The projection body M of M is dened by

h

M(u) = v(Mu) u2Sn;1:

It is easily seen that M is an origin-symmetric convex body. Let

`u be a line parallel to the unit vector u, and let d`u be the volume element of the subspaceu? orthogonal tou. Then

h

M(u) = 12

Z

#(M\`u)d`u:

This is the projection that counts (geometric) multiplicity. For the projection bodies of more general compact sets, see 39].

The volume of the polar projection body M is

V(M) = 1

n Z

Sn;1v(Mu);ndu:

Note that the arithmetic average of the projection function v(Mu) over Sn;1 is the surface area of M, up to a constant factor. One can view theSL(n)-invariantV(M);1=n as an ane surface area ofM.

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Lemma 3.5.

If M is a compact domain in Rn with piecewise C1 boundary, then

(3:9) V(M)n;1V(M)

!n

!n;1

n

with equality if and only if M is an ellipsoid.

Proof. By (3.8), Lemma 3.3, and the Petty projection inequality (2.2) for convex bodies, we have

V(M)n;1V(M)V( M)n;1V(M)

!n

!n;1

n

with equalities if and only if M is convex and M is an ellipsoid, and hence M is an ellipsoid. q.e.d.

As noted earlier for convex bodies, the generalized Petty projection inequality (3.9) is stronger than the classical isoperimetric inequality for compact domains. From the Holder inequality, one can easily see

S(M) n!1+

1

n n

!n;1 V(M);n1

which and (3.9) imply the classical isoperimetric inequality

S(M) n!n1=nV(M)n;1n :

Lemma 3.6.

Let fwigm

1 be a sequence of non-zero vectors in Rn which are not contained in one hyperplane. Then for any compact do- main M in Rn

(3:10) Ym

i=1v(Mwi)i cV(M)n;1 where i = hA;1wiwii, c = (detA)12=Qmi=1pjwij

i i

, and A is the positive denite matrix given by hAxxi=Pmi=1hxwii2:

Proof. First, we show the case that M is a convex bodyK. Let Q be a non-singular matrix so that A=QTQ, and lety=Qx. Then

jyj

2 =hAxxi=Xm

i=1

hwixi2 =Xm

i=1

ihuiyi2

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whereui =;i 12Q;Twi.

It can be easily veried that

v(QTK wi)jwij= det(Q)v(K Q;Twi)jQ;Twij:

From (2.3), we have

V(K)n;1 Ym

i=1v(K ui)i =Ym

i=1v(K Q;Twi)i

=Ym

i=1v(QTK wi)i

jwij

jQ

;TwijdetQ

i

=Ym

i=1v(QTK wi)i

jwij

p

idetQ

i

:

Using the fact thatV(QTK) =V(K)detQand Pmi=1i =nwe obtain the inequality (3.10) for convex M.

WhenM is not convex, let M be a convexication ofM. By Lemma 3.3, M and M have the same projection function. From (3.8) and the convex case it follows that

cV(M)n;1cV( M)n;1Ym

i=1v( Mwi)i

=Ym

i=1v(Mwi)i: q.e.d.

4. The ane Sobolev inequality

In this section , we prove the results stated in the Introduction.

Theorem 4.1.

If f is a C1 function with compact support in Rn, then

(4:1) 1

n Z

Sn;1krufk;n

1

du

;

!n

2!n;1

n

kfk

;n

n

n;1 :

Proof. Fort>0, consider the level sets of f inRn ,

Mt=fx 2Rn :jf(x)j>tg

St=fx 2Rn :jf(x)j=tg:

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Sincef is of classC1, for almost allt>0,St is aC1 submanifold which has non-zero normal vector rf. LetdSt be the surface area element of

St. Then one has the formula of volume elements, (4:2) dx=jrfj;1dStdt:

We have

(4:3)

k rufk1=

Z

R n

jruf(x)jdx

=

Z

1

0 Z

Stjhrfuijjrfj

;1

dStdt

= 2

Z

1

0

v(Mtu)dt:

On the other hand,

(4:4)

Z

R n

jfj n

n;1

dx=

Z

R n

Z

jfj

0 n

n;1t

1

n;1

dt

!

dx

= n

n;1

Z

1

0 t

1

n;1 Z

Mtdx

dt

= n

n;1

Z

1

0 t

1

n;1

V(Mt)dt:

SinceV(Mt) is decreasing with respect to t, it follows that

t 1

n;1

V(Mt) =tV(Mt)n;1n n;11 V(Mt)n;1n

Z t

0

V(M)n;1n d

1

n;1

V(Mt)n;1n

= n;1

n d

dt Z t

0

V(M)n;1n d

n

n;1

so that (4:5)

Z

1

0 t

1

n;1

V(Mt)dt n;1

n Z

1

0

V(Mt)n;1n dt

n

n;1

:

Combining (4.4) and (4.5) gives (4:6)

Z

R n

jfj n

n;1

dx Z

1

0

V(Mt)n;1n dt

n

n;1

:

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By the generalized Petty projection inequality (3.9), we obtain

(4:7)

V(Mt)n;1n !n

!n;1V(Mt);1n

= !n

!n;1

1

n Z

Sn;1v(Mtu);ndu

; 1

n

:

From (4.6) and (4.7), it follows that

kfk n

n;1

!n

!n;1

Z

1

0 1

n Z

Sn;1v(Mtu);ndu

; 1

n

dt:

Thus Minkowski's inequality for integrals yields

Z

1

0 Z

Sn;1v(Mtu);ndu

; 1

n

dt

Z

Sn;1

Z

1

0

v(Mtu)dt

;n

du

!

; 1

n

:

By (4.3) and the last two inequalities, we nally obtain

kfk n

n;1

!n

2!n;1

1

n Z

Sn;1k rufk;n

1 du

; 1

n

which proves the Theorem. q.e.d.

We observe that inequality (4.1) is stronger than the Sobolev in- equality (1.1). Indeed, the Holder inequality and Fubini's theorem to- gether yield

(4:8)

1

n!n

Z

Sn;1krufk;n

1 du

; 1

n

1

n!n

Z

Sn;1k rufk1du

= 1

n!n

Z

Sn;1

Z

R n

jhrfuijdxdu

= 1

n!n

Z

R n

Z

Sn;1jhrfuijdudx

= 2!n;1

n!n

Z

R n

jrfjdx:

Thus inequalities (4.1) and (4.8) are combined to give the Sobolev in- equality (1.1).

Let us show that the generalized Petty projection inequality (3.9) can be proved by using the inequality (4.1).

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For compact domainM and for small">0, we dene

f"(x) =

(0 dist(xM) "

1;dist("xM) dist(xM)<":

If "is small and dist(xM) <", then there exists a uniquex0 2@M so

that dist(xM) =jx0;xj:

Let

(x0) = x0;x

jx 0

;xj :

Consider

M" =fx2Rn : 0<dist(xM)<"g and its closure M". One has

rf"(x) =

(

"

;1

(x0) x2M"

0 x2=M": It follows that

Z

R n

jhrf"uijdx=";1

Z

M"jh(x0)uijdx:

Lett= dist(xM), 0<t<". Then dx=dSMdt+o(t):Therefore, as

"! 0, we have

"

;1 Z

M"jh(x0)uijdx;!

Z

@Mjh(x0)uijdSM(x0) = 2v(Mu): On the other hand, sincef" converges to the characteristic function

M of M, we have

Z

R n

jf"jn+1n dx;!V(M): It follows that (4.1) implies (3.9).

We have seen that the ane Sobolev inequality (4.1) is equivalent to the generalized Petty projection inequality (3.9). The constant in the inequality (4.1) is sharp. It is attained at the characteristic functions of ellipsoids.

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5. A generalization of the Gagliardo-Nirenberg inequality

Letf be aC1 function with compact support inRn. Gagliardo 15]

and Nirenberg 34] proved the inequality

(5:1) Yn

i=1

k rxifk11n 2kfkn;1n :

This inequality implies the Sobolev embedding theorem. See 1, p. 38].

We give a generalization of inequality (5.1) which is equivalent to the inequality (3.10) for compact domains.

Theorem 5.1.

Let fwigm

1 be a sequence of vectors in Rn not con- tained in one hyperplane. Iff(x) is aC1 function with compact support in Rn, then

(5:2) Ym

i=1

krwifk1ni ckfkn;1n

where the constants i = hA;1wiwii and c = 2detAQmi=1ii2n1 depend only on the sequence of vectors, and A is the positive denite matrix given byhAxxi=Pmi=1hxwii2:

Proof. We use the notation in Theorem 4.1. From (4.6), we get

kfk n

n;1

Z

1

0

V(Mt)n;1n dt:

Using (3.10), Pmi=1i=n, and the Holder inequality, we have

c 1

n Z

1

0

V(Mt)n;1n dt

Z

1

0

m

Y

i=1v(Mtwi)nidt

m

Y

i=1

Z

1

0

v(Mtwi)dt

i

n

where the constantc is from (3.10). Thus

(5:3) cn1kfkn;1n

m

Y

i=1

Z

1

0

v(Mtui)dt

c

i

n

:

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Similar to (4.3), one has

krwifk1 = 2jwij

Z

1

0

v(Mtwi)dt:

From this and (5.3), inequality (5.2) follows. q.e.d.

Corollary 5.2.

Let fuigm

1 be a sequence of unit vectors in Rn and let figm

1 be a sequence of positive numbers satisfying

jxj

2 =Xm

i=1

ihxuii2 x2Rn:

If f is a C1 function with compact support in Rn, then

m

Y

i=1

kruifk1ni 2kfkn;1n :

Similar to the equivalence of (3.9) and (4.1), the geometric inequality (3.10) is equivalent to the analytic inequality (5.2). A similar argument can also be carried out. The constant of the inequality (5.2) is best it is attained at the characteristic functions of parallelepipeds.

6. Appendix

Proof of Lemma 3.1. Let k be a positive integer. Since @M is compact and of class C1 piecewise, one can choose >0 such that

jhx;x 0

(x0)ijk;1jx;x0j j(x);(x0)jk;1

jhK((x));hK((x0))j<k;1 xx0 2@M jx;x0j<:

Forx 2@M, consider a point y 2=M buty2x+"K. We estimate the distance of y to @M. Let x0 2@M be the point which attains the distance. Then

jy;x 0

j=jhy;x0(x0)ij=jhy;x(x0)i+hx;x0(x0)ij

=jhy;x(x)i+hy;x(x0);(x)i+hx;x0(x0)ij (6.1)

jhy;x(x)ij+jy;xjj(x0);(x)j+jhx;x0(x0)ij:

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