C OMPOSITIO M ATHEMATICA
D. B ÄTTIG B. G RÉBERT
J. C. G UILLOT
T. K APPELER
Foliation of phase space for the cubic non- linear Schrödinger equation
Compositio Mathematica, tome 85, n
o2 (1993), p. 163-199
<http://www.numdam.org/item?id=CM_1993__85_2_163_0>
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
Foliation of phase space for the cubic non-linear Schrödinger equation
D.
BÄTTIG*~~,
B.GRÉBERT*(1),
J. C. GUILLOT*and T.
KAPPELER**~
*Départment de Mathématiques URA 742, CNRS, Université Paris-Nord, 93430 Villetaneuse, Trance
**Department of Mathematics, Ohio State University, Columbus, Ohio 43210-1174, U.S.A.
(1)Current address: Instituto de Investigaciones en Matematicas Aplicades y en Sistemas, Universidad Nacional Autônoma de Mexico, Apartado Postal 20-726, Mexico D.F., 0100 Received 25 September 1991; accepted 15 November 1991
© 1993 Kluwer Academic Publishers. Printed
1. Introduction and theorems
Consider the
defocussing
cubic non-linearSchrôdinger equation (NLS)
for
complex
valuedfunction 03C8
withperiodic boundary
conditions03C8(x
+1, t)
=03C8(x, t).
It is well known that(NLS)
is acompletely integrable
infinite dimensional Hamiltonian
system.
Theperiodic eigenvalues
of thecorresponding self-adjoint AKNS-system
are invariant under the flowof (NLS),
where the
AKNS-system
isgiven by
with
qi(x, t)
=p(x, t) - iq(x, t).
Define for N ~ NFor N 1 the Liouville tori of
(NLS)
in thephase
spaceye Nare
theisospectral
sets
tPartially supported by NSF.
tfsupported
by Swiss National Fund.For every
N, IsoN( p, q)
iscompact,
connected andgenerically
an infiniteproduct
of circles.
For
(p, q) ~ XN (N
=0, 1) let {03BBk(p,q)}k~Z
be theperiodic
andantiperiodic spectrum
ofH( p, q).
One knows that the gaplength
map y fromX1 into l’N
defined as
is continuous
(but
notanalytic),
onto and03B3-1(03B3(p,q))=Iso1(p,q),
wherel2N = {(ak)k~Z/03A3k~Zk2N|ak|2 ~} (N 0). (see [Gre-Gui]).
In
Appendix
A we proveTHEOREM 1.1.
(1)
Thegap-length
map03B3: X° l2 is
continuous and(2) ~(p, q)~X0
is aspectral invariant,
i.e. constant onIsoo( p, q).
Knowing
theDirichlet-spectrum {03BCk(t)}k~Z
of theoperator H( T p, 1;q),
where(T,f )(x)
=f (x
+t)
one can reconstruct p and qby
the trace formulasHere
{k(t)}k~Z
is theDirichlet-spectrum of H(T q, - T p).
Thedependence
of t of{03BCk(t)}k~Z
isgiven (see [Gre-Gui]) by
asystem of singular
differentialequations.
For finite gap
potentials ,uk(t)
can beexplicitly
calculatedby geometric
methods(see [Pre]).
In this article wecompute
theimage
of03BCk(·),
orequivalently
theimage
of the flowby
translationTt
onIso(p, q),
for non-finite gappotentials.
Todo this we introduce the space
and a map
detN
fromAN into l’
defined asWe will prove
THEOREM 1.2. For N =
0,
1 there exists a realanalytic
one-to-onemap 4) from
yeN
intoJltN
with03A6(IsoN(p, q))
=detN 1(det,«D(p, q))).
For N =1,
03A6 is onto andbianal ytic.
This theorem
gives
ageometrical description
of the "foliation"IsoN(p, q)
inye N.
A similar theorem for the Kd Vequation
has beenproved by
T.Kappeler
in[Kp].
In section 2 we construct themap 4Y using
results from[Gre-Gui]
and[Kp].
Theorem 1.2 followsimmediately
as in[Kp] using arguments
from[Gar- Tru, 1, 2]
andTHEOREM 1.3. The
derivative of 03A6
at(p, q)
is anisomorphism from eN
toJIN (N
=0, 1).
Theorem 1.3 is proven in section 3.
Let (D =
(03A6k)k~Z.
The above mentioned resultconcerning
the flowby
trans-lation is now a consequence of Theorem 1.2 and
proved
at the end of Section 2:THEOREM 1.4.
Suppose (p, q) ~ X0 (resp. el).
Thenfor
every k withÀ,2k-l(P, q) À,2k(P, q)
there exists a continuous(resp.
cont.differentiable) function
~k(·): R ~ R
such thatThis shows that the
image
ofJlk(.) by
the flow of translationconsists,
for allk e 0,
of the whole gap[03BB2k-1(p, q), 03BB2k(p, q)].
Similarly
as in[Kp]
for Kd V Theorem 1.2 can beapplied
to the so calledfinite gap
potentials. Define,
for a finite subset J gZ,
Elements in
GapJ,r
are calledregular J-gap potentials.
It is well known that thepotentials
inGapj
are, infact,
realanalytic. Further,
observe thatGapj
=03A6-1{R
=(Rk)k~Z ~ M0 : Rk = 0 ~ k ~ J }
and thusGap,
is a 2N dimen-sional manifold where N = # J.
Clearly GapJ,r
is open inGapj
and(diffeomorphically)
whereR+:= {x:x > 0}
andT N
denotes the N-torus
(Sl)N. Obviously Gapj,,
is invariantby
NLS.Therefore,
with the
symplectic
structurecoming
fromNLS,
it follows from Theorem 1.2 that(R+)N
xTN
is asymplectic
manifold of dimension 2N with a trivial fibrationby Lagrangian
toriTN.
We thus obtain(cf. [Dui])
COROLLARY 1.5. When restricted to
Gapj,,,
NLS admitsglobal action-angle
variables.
2. Global coordinates on
ye N
We first define the
map 03A6
mentioned in the introduction.If
03BB2k-1(p, q) ~ 03BB2k(p, q) (k E Z)
one denotesby F2k-1(·; p, q)
andF2k(· ;
p,q)
the two
corresponding eigenfunctions
ofH( p, q)
suchthat, for j = 2k - 1,
2kIf À2k-l(P, q) = Â2k (p, q)
thenF2k-1( ·; p, q)
andF2k(· ; p, q)
are two orthonormaleigenfunctions
such thatAs the
eigenvalues îj
areperiodic
orantiperiodic
one hasLet
E, (p, q)
be the two-dimensionalsubspace of L2 generated by F 2k-l
andF2k.
As in
[Kp],
in order to introduce an orthonormal basis(G2k-1(·;p,q), G2k(·;p,q))
ofEk(p,q) depending analytically
on(p,q)~X0
one needs thefollowing
lemma.LEMMA 2.1. For
( p, q)~X0
andfor
every k ~ Z the mapfrom Ek( p, q)
intoR2 is
a linearisomorphism.
Before
proving
Lemma2.1,
let us introduce some more notations and a fewelementary
results from[Gre-Gui]
which will be used later.Denote
by
the fundamental solutions to
H( p, q)Fj = À-Fj
such thatThe
03BCk(p, q)’s (resp. 03BDk(p, q)’s)
are thesimple
zeroes ofZ1(1, ·;
p,q) (resp. Y2(l, -;
p, q))
in C.(03BCk(p, q))k~Z(resp. (03BDk(p, q))k~Z)
is astrictly increasing
sequence of realnumbers.
Further
Denote
by 0394(03BB)
the discriminantThe collection of
periodic
andantiperiodic eigenvalues (Â-k(p, q))k~Z
written inincreasing
order and withmultiplicities
have thefollowing asymptotics
and
where the error terms are uniform on bounded sets of
potentials (p, q) ~ L2([0, 1])2.
It follows that
for j
= 2k -1,
2kand
Finally,
forA,2k - 1 (p, q) 03BB2k(p, q)
one hasJ
= 2k -1, 2k)
where
03B5j(p, q) =
+ 1.Proof of
Lemma 2.1.Fix k and
( p, q).
It suffices to show thatwhere
is the Wronskian of
F2k
andF2k-1. Using
theequation H(p, q)Fj = 03BBjFj
onederives
(cf. [Gre-Gui]).
Thus,
ifÂ2k
=Â2k-l’
we conclude thatW(F2k, F2k-1)
is constant. AsF2k
andF2k -
1 arelinearly independent,
this constant is different from zero. In the casewhere
Â2k-l 03BB2k
we first show thatW(F2k, F2k - )(x)
has at mostsimple
zeroes. Assume that this is not the case. Then there exists
0 x0
1 and0 ~(x0)
21t such thatand
where
here 1.1 denotes
the Euclidean norm inR2.
But both
|F2k(x0)| ~
0 and|F2k-1(x0)| ~
0 which leads to a contradiction.Let us consider the smooth
path (tp, tq)
inX0.
Denoteby
to =
max(0 5 t 5 1; À,2k(tp, tq) = À,2k-l(tp, tq)l.
Then0
to 1. ChooseL2-
normalized
eigenfunctions F2k( ’ ,
tp,tq)
andF2k -1( ’ ,
tp,tq)
such that for t =1,
2k(·,
p,q) = F2k(·,
p,q)
andF2k-1(·, p, q) = F2k-1(·,
p,q)
andF2k
andF2k-1
are continuous in t, i.e.
f2k
andF2k-l
EC([to, 1], (H1[0, 1])2).
Inparticular
we conclude that
2k(·; t0p, t0q)
andF2k-1(·;t0p,t0q)
areL2-normalized
orthogonal eigenfunctions
for03BB2k(t0p, t0q).
We conclude that for t = toW(2k, 2k-1)
is constant and différent from zero.Clearly W(t, x):=
W(F2k( ’ , tp, tq), 2k-1(·,tp,tq))(x)
is continuous in0 x 1 and t0
t 1. To
simplify
notation assume thatW(to, x)
> 0(0
x1).
For fixedt0 t 1, W(t, x)
can have at mostsimple
zeroes and thusby
a classicalargument from
homotopy theory
we conclude thatW(t, x)
can never vanish for0
x 1and t0 t 1
and Lemma 2.1 isproved.
We use Lemma 2.1 to define
G2k -1( ’ ;
p,q)
as theunique
function inEk( p, q) satisfying
G2k(·; p, q)
is then defined to be theunique
function inEk( p, q)
such thatClearly, G2k
andG2k-1
can beexpressed
in terms ofF2k
andF 2k-l.
Thereexist a
unique 03B8k(p, q)
E[0, 2n)
such thatwhere Ex = sign W(F2k(·; p, q), F2k-1(·; p, q»(0).
Using
aperturbation argument (cf. [Ka])
one proves as in[Kp]
thatG2k(·; p, q)
andG2k-1(·; p, q)
are bothanalytic
functions of(p, q)
as maps from(L2([0, 1]))2
into(H’([O, 1]))2.
F2x
andF2k-1
areeigenfunctions
ofH(p, q)
butthey
cannotdepend analytically
on(p, q)
due topossible multiplicity
of theeigenvalue À2k. G2k
andG2k - 1
are notnecessarily eigenfunctions
butthey depend analytically
on(p, q).
For
(p, q)
EXN (N
=0, 1)
and for k E Z definewhere 1:k =
(03BB2k
+À2k-l)/2.
Oneeasily
shows thatwhere
03B3k(p, q) = Â2k(p, q) - Â2k-l(P, q).
The matrix
03A6k(p,q)
issymmetric
and its trace is zero. Itseigenvalues
are+
[03B3k(p, q)/2].
Forevery k
EZ, 03A6k(·, ·)
is acompact
map fromJe°
into the space of realsymmetric
trace free matrices.(See [Kp]
for aproof.)
Furthermore it is
proved
in[Gre-Gui]
that(03B3k(p, q»)kEZ
El2(Z) (resp. l21(Z))
for(p, q)~X0 (resp. Yf 1) and,
for N =0, 1, Lk 03B3k(p, q)2k2N
00uniformly
onbounded sets of
potentials
inXN.
DEFINITION 2.2. For
(p,q)~XN
setIt follows that
03A6( ., .)
is a bounded map fromyeN (N
=0, 1)
intoJIN.
As in
[Kp]
one shows that03A6(., .)
is realanalytic.
Furthermore03A6(., .)
preserves
isospectrality
in thefollowing
sense:(D(p, q)
and(D(p’, q’)
areisospec- tral, i.e., spec 03A6k(p, q) = spec 03A6k(p’, q’)
forevery k,
if andonly
ifYk (P, q)
=03B3k(p’, q’)
for every k. It is shown in[Gre-Gui] that,
for( p, q)
and(p’, q’)
in
X1, Yk(p, q)
=Yk(p’, q’)
for every kimplies 03BBk(p, q) = 03BBk(p’, q’)
for every k. For(p, q)
and(p’, q’)
inX0
the same conclusion follows fromAppendix
A(see Corollary A.4) by
the sameargument given
for the case N = 1 in[Gre-Gui].
REMARK 2.3.
M0 (resp. M1)
can be identified with1’(;Z) (resp. 1’(Z» by
themap
It then follows that for
(p, q) ~ XN
with N =0,1
In
particular 03A6( ., .)
coordinatizesXN globally.
It follows that for
( po, q0) ~ XN
One recovers the well-known result that
IsoN(po, qo)
is acompact
set,generically
an infinite
product
ofcircles,
the radii of which are inl2N(Z).
We now prove Theorem 1.4.
Following [Kp,
Thm.4]
oneeasily
shows thatthere exists a continuous
(resp. continuously
differentiable in the case(p,q)~X1)
functiont/1k(t, s)
such thatfor
(t, s) ~ [0, 1]2 where,
fors0 s 1, F2k( ’ ; sp, sq)
and2k-1(·;sp, sq)
arechosen as in the
proof
of Lemma 2.1 withs0 = max{0 s 1;
03BB2k(sp,sq) = 03BB2k-1(sp,sq)}. Taking possible crossings
of theeigenvalues 03BB2k(sp, sq)
and03BB2k-1(sp,sq)
into account(cf. [Ka]), 2k(·; sp, sq)
and2k-1(’ ;
sp,sq)
can be chosen todepend smoothly
on s,0
s so, if one allowsF2k(’; sp, sq)
to be either a(normalized) eigenfunction
for03BB2k(sp, sq)
or03BB2k-1(sp, sq)
andsimilarly
for2k-1(·; sp, sq).
Define
~k(t):=03C8k(t, 1 )
and thewinding
numbershk(s):=
(03C8k(1
+t, s)
-t/1k(t, s»In, hk(· ) being
a continuous function of s with values in Z. Thereforehk(s) = hk(0) = k
for everys ~ [0,1]
and thus~k(1+t)
-
lfJk(t)
= k1t.REMARK 2.4. For
(p,q) ~ X1
one shows thatThen, for |k| sufficiently large,
one hasi.e.
03A6k(Ttp, Ttq)
windsIkl
times around theorigin
withoutstopping,
clockwise ifk 0 and counterclockwise if k > 0.
3. The derivative ouf (D
In this section we
compute
the derivative of O and show that it is a linearisomorphism
fromXN
ontoMN
for N =0,
1.As in
[Kp]
it is convenient to write C in aslightly
different form. One writes Oas a map T from
ye N
intol2N(Z) (see
Remark2.3)
with03A8(p, q) = (03A8k(p, q))k~Z
where
Let
d(p,q) ’JI 2k (resp. d(p,q) ’JI 2k -1)
denote the derivative of03A82k(·,·) (resp.
THEOREM 3.1.
Suppose (u, v) ~ X0.
Thenwhere ’·’ denotes the scalar
product
in1R2.
Proof of
Theorem 3.1. The derivatived(p,q)03A82k-1[(u, v)]
isgiven by
The chosen normalization of
G, imply
thatFurther
One then
gets
Hence one
finally
obtainsLet us now
compute d(p,,)Tk 1(u, v)].
Define,
for fixedk ~ Z,
the open setUk ~ X0
À2k(.’ .)
andÀ2k-l(., .)
arecontinuously
differentiable onOkk.
Using H(p,q)Fj=03BBj(p,q)Fj (j=2k-1,2k)
one obtains for(p,q)~Uk
Thus
Expressed
in terms of theGk’s
we obtainNow Okk
is dense inJe°
and both sides of the leastequality
are continuousfunctions
of (p, q)
ine’.
Thus thisequality
expressesd(p,q)03C4k
in terms of theGk’s
on
YCO. d(p,q)Bf! 2k
is calculated in the same way asd(p,q)03A82k-1.
The derivatives
d(p,q)Bf! 2k
andd(p,q)03A82k-1
can beexpressed
in aslightly
different way as follows.
COROLLARY 3.2.
Suppose (u, V)EJe°.
Thenwhere Ek = sign W(F2k( ’ ; p, q), F2k-1(·;
p,q»(0).
We now
study
theasymptotics
ofd(p,q)03C82k
andd(p,q)03C82k-1.
First of all it will be useful tobring
into another form.
LEMMA 3.3.
The
proof
of Lemma 3.3 follows as in[Kp;
Lemma5.3].
In order to bound
F2k-1(·)
andF2k(·) uniformly
withrespect
to k we use thefollowing
lemma.LEMMA 3.4. For
(p, q) ~ X0
and K ~ Z denote1 k( .)
theunique function
inEk(p, q)
such that~Ik(·)~L2([0,1])2
= 1 withI(1)k(0)
> 0 andI(2)k(0)
= 0. Thenfor
The error terms are
uniform
with respect to0
x 1 and( p, q)
in any boundedset
of X0.
REMARK. We
present
aproof
of Lemma 3.4 whichgeneralizes easily
to asituation encountered in Lemma 3.14 below.
Proof of
Lemma 3.4.(1)
Assumethat j
= 2k. Observe that(see [Gre-Gui])
Existence and
uniqueness
ofIk(·)
follow from Lemma 2.1. Then there exist Otkand 03B2k satisfying
with 03B12k + 03B22k
= 1.Further
with
(akYk)keZ
E12(Z).
Define
Then
fk(-)
satisfieswith
Set
We then obtain
It follows from the estimates of
F1(·, 03BB)
andF2(-, 03BB)
in[Gre-Gui;
Section1]
thatthere is a constant C > 0
independent
of k such thatTherefore we
get
Further we
get
from[Gre-Gui;
Section1]
Thus
and
(i)
isproved with j
= 2k. Thecase j
= 2k - 1 followsexactly
in the sameway.
To prove
(ii)
remark thatFurther
Thus
(ii)
follows in the same way as(i)
and Lemma 3.4 isproved.
Let us deduce from Lemma 3.4 that
uniformly
withrespect
to k.Consider
F2k.
For|k| sufficiently large
it follows from Lemma 3.4 thatW(Ik, G2k-1)(·) ~
0 becauseW(F1(·, Â2k), F 2(.’ 03BB2k)) =
1.Therefore
for
|k| sufficiently large.
From
~F2k(·)~L2([0,1])2
= 1 we deduce thatuniformly
withrespect
to k.(3.1)
then follows from Lemma 3.4.We now
study
theasymptotics
ofd(p,q) 03C82k
andd(p,q)BP 2k-l.
Oneeasily
showsthat
where the error terms are uniform with
respect
to0
x 1. Furthermore sinceG2k( ’ ; p, q)
andG2k-1(·;
p,q)
are realanalytic
functions of(p, q)
as maps from£0
intoH1R([0,1])2
it follows thatd(p,q) G2k(·; p, q)
andd(p,q) G 2k - 1 ( . ; p, q)
arebounded linear maps from
£0
intoH’([O, 1])2
which are still realanalytic
functions of
(p, q).
It follows from Lemma 3.3 and
(3.1)
that the norm of the linear mapis
uniformly
bounded withrespect
to(p, q)
on bounded sets of:Yf°
and to k E Z(See [Kp; Prop. 5.4]).
It then follows from Theorem 3.1 and from the fact that
(03C8k(p, q))k~Z
is inl2(Z)
that we obtain THEOREM 3.5.
where the error term is bounded
uniformly
with respect to(u, v)
and( p, q)
in anybounded subset
of X0.
We need to introduce some more notation. For
( p, q)
EJfo
setThen,
for k EZ,
defineFor
k ~ J
setand for k E J define
Then,
fromCorollary 3.2,
it follows thatTHEOREM 3.6.
Suppose ( p, q)E.Yt°.
Thend(p,q) 03A6
is a linearisomorphism form
eo
ontoM0.
The
proof
of Theorem 3.6 is ratherlong
and severalsteps
are needed.Theorem 3.5 shows that
d(p,q) 03C8
is a Fredholmoperator
of index zero.Therefore it suffices to show that
d(p,q) 03C8
is one to one in order to prove Theorem3.6.
Assume that
d(p,q) 03C8[(u, v)]
= 0 where(u, v)
E£0.
From the above formula weconclude that
(Hk(·; p, q), (u(·), v(· )))
= 0 forevery k
E Z.Therefore,
in order toprove that
d(p,q) 03C8
is one to one, one must prove that{Hk(·;
p,q)lk.Z
is a Rieszbasis of
£0. Using
the definition of theHk’s
and theasymptotic
behavior of theGk’s
one shows that{Hk(· ;
p,q)}k~Z
isquadratically
close to the orthonormal basis(Tk(·; p, q))
ofeo
whereThus to prove that
(Hk(·;
p,q))kEZ
is a basis ofyeO
it remains to prove that theHk’s
arelinearly independent, i.e.,
if(ak)kEZ
is a sequence of real numbers such thatthen ak = 0 for all k.
First,
let us recall that the setIsoo( p, q)
ofisospectral potentials
is a countableintersection of manifolds and that one can define the normal space
N(p, q)
andthe
tangent
spaceT(p, q)
ofIsoo( p, q)
at(p, q). Using
results of[Gre-Gui],
aneasy
computation
shows that{H2k(·;
p,q)}k~Z
and{H2k-1(·;
p,q)}k~J belong
tothe normal space
N(p, q)
of theisospectral
setIsoo( p, q)
at(p, q).
Set for k’ ~ Z
where
(a, b) = ( - b, a), (vk’(p, q))k’EZ
is one of the two Dirichletauxiliary spectra
defined in section 2.Clearly ( pk,, qk’)
is in thetangent
spaceT(p, q)
ofIsoo( p, q)
at(p, q).
Hence it follows that forevery k’
The
proof of Theorem
3.6 consists of threesteps.
In the first one we show that03B12k -1 = 0 for k E J. In the second one we prove that a2k = (X2k -1 = 0 for
k e
Jand in the third one we
finally
show that a2k = 0 for every k in J.3.1. The first
step
Let us
begin
with acomputational lemma.
LEMMA 3.7.
If (u, v) E T( p, q)
and k in J such thatÂ2k -,(p, q) vk( p, q) A2k(P, q),
thenProof of
Lemma 3.7. We first prove that for(u, v) ~ T(p, q)
as follows:
Using H( p, q)Fj = 03BBjFj
onegets
Thus
(3.4)
follows from the definitionof H 2k-l.
Tocompute d(p,q) 03B8k[(u, 03BD)]
takethe derivative of
0 = G(1)2k-1(0) = sin 03B8k F(1)2k(0) + 03B5k cos 03B8k F(1)2k-1(0)
and use asimilar
argument
as in[Kp,
Lemma6.8]
to obtainIn the case where
Vk(P, q) ~{03BB2k(p, q), 03BB2k-1(p, q)}
thefollowing
result holds.LEMMA 3.8.
If
k E J withvk(p, q) ~ {03BB2k(p, q), À2k-l(P, q)l, then, for k’ ~Z, (H2k’-1(·; p, q), (pk(·), qu( - )))
=Ôk’kCk
withCk ~
o.The
proof
of Lemma 3.8 follows as in[Kp,
Lemma6.10],
once thefollowing
result is
proved:
"Every (p, q) ~X0
withVk(P, q)
E{03BB2k(p, q), À2k - 1 (p, q)l,
for some k EJ,
is the limit of a sequence(Pj, qj)jeN
inIso°( p, q)
with03BB2k-1(p, q) 03BDk(pj, qj) îy2k(P, q)."
This result
easily
follows fromAppendix
A.Thus
using (3.3)
and Lemma 3.8 onegets
a2k -1 = 0 forevery k
E J -J where J1
={k ~ Z; 03BB2k-1(p,q) vk(p, q) 03BB2k(p, q)}. We now prove that 03B12k-1
= o fork ~ J1.
For that purpose definewhere
(p,,, qk’)
isgiven by (3.2).
Definewhere
bk’,k
denotes the Kronecker delta function.Let A
(resp. B, C)
be the linearoperator
associated with the matrix(Ak’,k)(k’,k)~J1 J1
1(resp. (Bk’k), (ek’k)O
T’hen A(resp. B, C) ~B(l2(J1))
has thefollowing properties.
LEMMA 3.9.
(i)
B isof
trace class.(ii)
C is invertible with a bounded inverse.(iii)
A is one-to-one.It then follows that 03B12k-1 = 0 for k E
J1
sinceProof of
Lemma 3.9. Use[Gre, part
IIChap
3 Th.5]
to conclude thatFrom Lemma
3.7,
it follows thatMoreover as we have
already
observed(see
thebeginning
of section2). Using
Lemma B.3(Appendix B)
we then obtain the estimateFurther
(cf. [Gre,
PartII,
Ch.3,
Th.5])
where we used for the last
equality
therepresentation
of03942 -
4by
an infiniteproduct (cf. Appendix B). Thus,
from(3.5),
one obtains thatIAk’kl
isgiven by
From the
asymptotic
behavior of theÂk’s
andvk’s
it follows thatwhere
(ak’)k’ ~ J1 and (bk)keJ are in l2(J1).
To prove(i)
one must show thatBy
well knownproperties
of the convolution this follows from the estimateFrom
(3.6)
we learn thatFurthermore
Akk
is different from zero for anyk ~ J1.
Thus(ii)
follows.Towards
(iii)
we first observe thatC-1 A = Id + C - 1B
is a Fredholmoperator
of index zero. Thus in order to prove the firststep
we must show thatC -1 A
is one to one, orequivalently,
that the Fredholm determinant ofC -1 A
is different from zero. Let detC -1 A
be this Fredholm determinant which is a limit of determinants of finitematrices, i.e., det C-1 A
=limJ2~J1 det(C-1 A)J2
where(C -1 A)J2
denotes theJ2
XJ2
matrix(C -1 A)k,k’eJ2
withJ2
a finite subset ofJ1.
AsC -1
isdiagonal,
one hasAs in
[Kp]
one considers the sequence x =(Xk)keJ2
withxk ~ {-03BB2k-1, -03BB2k}
and e =
(ek)keJ2
with Ek = 0 if Xk= - A,2k-l
and03B5k = 1 if xk = - 03BB2k.
From[P-S
p.
98] (cf.
also[Mck-Tru,
p.207])
it follows thatThen
Note that
Furthermore
Dkk’
is of the formwith
(ak)kEZ
and(bk’)k’EZ
inl2(Z).
Thusand there exists an
integer
N > 0independent
ofJ2
such thatOne deduces that
On the other hand one has
These two estimates lead to
where K does not
depend
on the finite subsetJ2
ofJ1.
MoreoverThis
implies together
with(3.7)
and(3.8)
thatdet(C-1 A)J2
Kuniformly
withrespect
toJ2
cJ,.
Thusdet C-1 A
K > 0 and A is one-to-one.3.2. The second step
We must show that a2k = a2l - 1 = 0 for every
k e
J.The main
ingredient
of theproof
is thefollowing
LEMMA 3.10.
(i) (H2k(·; p, q), H2k’(·;
p,q)) = 0, k,
k’~Z.Proof of
Lemma 3.10. Theproof
is the same as in[Gre-Gui,
Th.1.7,
assertions
(i)
and(ii)].
To prove
Step
2 we argue as follows. Fork’ ft
J one deduces from the firststep
and Lemma 3.10 thatAs
W(F 2k’, F2k’ - 1)(0)
~ 0(Lemma 2.1)
we conclude that CC2k’- 1 = 0 for every k’ E J.Next, again
fork’ ~
Jand therefore (X2k’ = 0 for
k’e
J. Thusstep
2 isproved.
3.3. The third step
Here we show that a2k = 0 for every k E J. One
already
knows thatThus it suffices to show that
{H2k(·;
p,q)lk.J
islinearly independent.
Note thatH2k(x; 1;p, Ttq) = H2k(x + t; p, q).
Therefore it suffices to prove that(H 2k( ., Ttp, 1;q))keJ
islinearly independent
for some t. Thefollowing
result is easy to prove.LEMMA 3.11. There exists to such
that for
all k E JTo make notation
easier,
we assume that to = 0.It remains to prove that
(X2k = 0
fork ~ J1 = {k ~Z; 03BB2k-1(p, q) Vk(P, q) Â,2k(P, q)l.
Define
A
straightforward computation using [Gre-Gui]
and[Gre]
leads toDefine
Let A
(resp. B, C)
denote the linearoperator
associated with the matrix(Ak’,k)(k’,k)~J1 J1 (resp. (Bk’,k), (Ck’,k)).
Then A(resp. B, C) ~ B(l2(J1)).
Theproof
ofthe third
step
follows fromLEMMA 3.12.
(i)
B is a Hilbert-Schmidt operator.(ii)
C is invertible with a bounded inverse.(iii)
A is one-to-one.Proof of
Lemma 3.12.Clearly
Thus
and
Ak’,k
isgiven by
Using
formulasexpressing
theFk’s
in terms ofF,
andF2 (see
thebeginning
ofSection
2)
andAppendix
B one shows thatFurther
and hence
It follows from the
asymptotic
behavior ofÂk,
J1k and Vk forlarge Ikl
that fork’ ~ k
Thus,
for k’ ~k,
we obtainand therefore
Thus
(i)
isproved.
To show
(ii)
observe thatHence
As
Akk
is different from zero for everyk ~ J1, (ii)
follows.In order to prove
(iii)
we must show thatC-1 A
is one-to-one. Lemma 3.10 shows thatC-1 A
= Id +C -1 B
whereC -1 B
is a Hilbert-Schmidtoperator.
In order to show thatC-1 A
is one-to-one it suffices to prove that theregularized
determinant
det2 C-1 A
is different from zero(see [Sim]
for the definition andproperties
ofdet,).
As in the firststep
one estimatesdet2 C-1 A by
theregularized
determinants of finite matrices(C-1 A)J,
associated with a finite subset J’ ofJ 1.
First,
recall thatbecause
Tr(C-1 B)J,
= 0by
the definition of B. Furtherand,
similar asabove,
where x =
(xk)k~J’,
e =(ek)keJ’
andlel
are defined as in the firststep.
For det
CJ.
we obtain thefollowing expression
As in the first
step using (3.12)-(3.14)
we concludefor every finite subset J’ c
J1,
where K isindependent
of J’. ThereforeTheorem 3.6 can be
improved
in the case where( p, q)
EX1.
THEOREM 3.13. For
( p, q)EJe1 d(p,q) 03A6
is a linearisomorphism form Jtl
ontoM1.
For this purpose we need the
following
LEMMA 3.14.
If ( p, q)EJe1
thenand
where the error terms are
uniformly
bounded in0
x 1 and with respect to( p, q)
in an y bounded set
of X1.
Proof of
Lemma 3.14. From[Gre-Gui;
Section1]
weget for j ~ {2k - 1, 2kl
and
Then
for j ~ {2k - 1,2k}
andfor k ~
0and
Further
Following
theproof
of Lemma 3.4 we now obtainfor j ~ {2k - 1, 2k}
The error terms are in
l21(Z) because,
for(p, q) ~ X1, (03B3k(p, q»k.z
Ell’(Z).
Define for
|k| sufficiently large
Thus
Lk(·) ~ Ek(p, q)
and~Lk(·)~L2([0,1])2
= 1. It follows from(3.19), (3.21), (3.22)
and
(3.24)
thatfor
|k| sufficiently large.
Thus for
Ikl sufficiently large,
there exist akand fik
such thatFrom
II G2k( ’ ) II -
1 and(G2k(·), G2k-l(.))
= 0 we deduce thatand
It then follows from
(3.25)
thatWe then obtain
Finally (3.15)
and(3.16)
are deduced from(3.17)-(3.23)
and(3.26)
and Lemma3.14 is
proved.
We then obtain
LEMMA 3.15.
If ( p, q)EJe1
and(u, v) ~ X0
thenwhere the error terms are
uniform
with respect to(u, v)
on any bounded setof X0.
Proof of
Lemma 3.15. As(p, q) E X1,
the gap sequence(03B3k)k~Z
is inl21(Z).
Lemma 3.15 then follows from Theorem 3.1 and the
asymptotic
estimates(3.15)
and
(3.16).
Proof of
Theorem 3.13. It follows from Theorem 3.6 thatd(p,q) 03A6
is one-to-one.To prove that
d(p,q) 03A6
is onto it isequivalent
to show that the linear mapd(p,q) 03C8
from
X1
into1’(Z)
x1’(Z) given by
is onto.
Let
(ak)kEZ
and(bk)k~Z
be in1’(Z).
From Theorem 3.6 it follows that there existu(·)
andv(·)
inL2([0, 1])
such thatIt is to prove that
(u, v)
is inX1.
Lemma 3.15 shows that each of the sequencesare in
1’(N). Then,
as in theproof of Theorem
I.18 of[Gre-Gui],
thisimplies
thatM(-)
and03BD(·)
are inH1([0,1])
withu(1) - u(O)
=v(1) - v(O)
= 0.Appendix
AIn this
appendix
wegeneralize
Theorem 3.7 of[Gre-Gui].
Let
1t( ., .)
be the map frome’
intoIRz
xRZ
definedby
where the
03BCk(p, q)’s
are the zeroes of themap 03BB ~ Z1(1, 03BB; p, q)
andXk(P, q) = log{(-1)kY1(1, 03BCk(p, q))}1.
Let for( p, q) ~X0
THEOREM A.1.
Suppose (po, qo)
EX0.
Then7r(-, -)
is ahomeomorphism from Isoo(po, qo)
onto5(PO,Qo).
In
[Gre-Gui]
Theorem A.1 isproved
for( po, qo)
Eyel using
theisospectral
flows
(k
EZ)
where
According
to[Gre-Gui],
theordinary
differentialequation (A.1)
has aunique
solution in
H1([ -t0, t,], X0)
for initial values inX0
with to > 0 chosensufficiently small,
and for this solution to existglobally in t,
it suffices to prove thefollowing
LEMMA A.2. Let
(p(·, t), q( - , t))
be a solutionof (A.1) defined
on a compact interval I ~R, 0 El,
inH1(I; X0).
ThenREMARK A.3. If the
potentials (p0(·). q0(·)~X1, it
is easy to show that~(p(·, t), q(·, t)) ~X0
isindependent
of t as thisquantity
is aspectral
invariantappearing
in theasymptotic expansion
of the03BBk’s (cf. [Gre-Gui]).
Proof of
Lemma A.2. Defineu(x, t)
=( p(x, t), q(x, t))
anduo(x) = (p0(x), q0(x)).
Choose a sequence
(u(n)0)n0
inX1
which converges to uo inX0. According
to[Gre-Gui]
there exists aunique
solutionu(n)(x, t)
of(A.1)
inH1(1R; X1).
Moreover these solutions
satisfy
for a.e t:where
03B2(·)
is apositive
function on R which isindependent
of n and t.(See [Gre;
Thm.
2,
p.132]).
Thus
(u(n))n0
is a bounded sequence inH1(I; X0).
Hence there exists asubsequence, again
denotedby (u(n))n0,
which convergesweakly
inH1(I, J(O)
toa function v E
H1(I; X0), i.e.,
Furthermore it follows from
[Gre,
PartII, Chap. 3,
Th.2]
and[Pô-Tru]
thatthe vector
fields vk
arecompact
onX0.
Thus(Vk(u(n))n1
convergesstrongly
toVk(v)
inL2(I, X0).
HenceThe trace theorem
guarantees
theweak-convergence
of(u(n)(·, 0))n0 weakly
in
A"
tov(.,0)
as n tends toinfinity
and(u(n)(·,0))n0=(u(n)0(·))n0
converges to
uo(-) strongly
inX0.
Thusv(x, 0)
=uo(x)
for a.e. x in[0,1].
By
theuniqueness
of the solution to(A.l)
weget u(x, t)
=v(x, t)
for a.e.x e
[0,1]
and for every t ~ I. Since(u(n)(·, t))n0
converges tou(·, t) weakly
inX0
and
(- t)
converges to du( - , t) strongly
inYeo
for every t c-I,
dufor a.e. t in I.
Furthermore
and it follows from Remark A.3 that
Therefore
and Lemma A.2 is
proved.
As a
corollary
we obtain thefollowing generalization
of Theorem 3.7 in[Gre- Gui].
COROLLARY A.4.
Suppose
that( p, q)
Ee’.
Then(i) Iso0(p, q) = {(p’, q’) ~ X0; 03B3k(p’, q’)
=Yk(P, q), k
EZ}
(ii) 11(p, q)~X0 is a spectral invariant,
i.e. is constant onIso0(p, q).
In
particular,
this proves Theorem 1.1 as stated in the introduction.Appendix
BIn this
appendix
we prove theasymptotic expansions
used in theproof
ofTheorem 3.4. The first result concerns certain
asymptotic properties
of thediscriminant
0394(03BB).
Proof of
Lemma B.1. Weonly
prove(i).
Assertion(ii)
followsby
a similarargument.
In[Gre-Gui]
it is shown thatwhere
flkeZ*
ak meansflkeN*
ak. a_k.Thus,
fork ~ Z*,
Since
0394(03BB2k)
=2(-1)k
this leads toFurther, using
that the Hilbert transform is a boundedoperator
on1’(Z),
where the error term satisfies
|r(k, l)| l2(k)
for everyl ~ Z*, l ~
k.Using
the wellknown
product
formulawe
finally
obtainLEMMA B.2. Let
(p, q)
be inX0.
For every k ~ Z(i) Y2(1, 03BB2k(p, q)) = (-1)k(03BB2k(p, q) - 03BDk(p, q))(1
+l2(k)) (ii) Y1(1, Â2k-l(P, q)) = (-1)k(03BB2k-1(p, q) - 03BDk(p, q))(1
+l2(k)).
Proof of
Lemma B.2. In[Gre-Gui]
it isproved
thatThus for k E Z*
and j ~ {2k - 1, 2kl
we obtainfrom which one deduces Lemma
B.2, using
similararguments
as in theproof
ofLemma B.1.
Combining
the two lemmas we obtainLEMMA B.3. Let
( p, q)
be ine’. Then for
every k withÂ2k-l 03BB2k,
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