A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
R. G. M. B RUMMELHUIS
A Bochner-Martinelli formula for vector fields which satisfy the generalized Cauchy-Riemann equations
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 15, n
o4 (1988), p. 555-566
<http://www.numdam.org/item?id=ASNSP_1988_4_15_4_555_0>
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Satisfy the Generalized Cauchy-Riemann Equations
R.G.M. BRUMMELHUIS*
We prove a Bochner-Martinelli
type
formula for vector fields u on whichsatisfy
thesystem
ofgeneralized Cauchy-Riemann equations proposed by
M. Riesz: curl u =
0,
div u = 0.As an
application
it is shownthat,
forsmoothly
bounded open 11 in R~such that all
components
of aresimply connected,
thetangential part
of theboundary
values of such"Cauchy-Riemann
vector fields" is characterizedby
the conditiond (i * u)
= 0. Here u is considered as a 1-form -->denotes the inclusion. This result extends work of
Koranyi
andVagi
for theunit ball in 0. - Introduction
Let 11 be an open subset of A vector field u =
( u 1, ..., un )
onfl,
u E
C1 (11; II~ n ),
is said tosatisfy
thegeneralized Cauchy-Riemann equations (abbreviated: GCRE)
if(cf. [5],
p.234).
We will also say, in this case, that u is aCauchy-Riemann
vector field on 11.
The
system (i)+(ii)
is called the M. Rieszsystem
in[5].
Note that ifn =
2,
satisfies(i)+(ii)
iff u 1 -iu2
isholomorphic.
* Author
supported by
the NetherlandsOrganization
for the Advancement of Pure Research (ZWO).Pervenuto alla Redazione il 5 Ottobre 1987.
If we introduce the one-form on
0, (i)
is thesame as
Depending
on which of the twopoints
of view seemsexpedient,
we willalternately
consider vector field or a one-form.Note that a u E satisfies the GCRE
iff, locally,
it is thegradient
of a harmonic function. In
particular,
theuk’s
are harmonic then.In this paper we prove a Bochner-Martinelli
type
formula forCauchy-
Riemann vector
fields,
see theorem 1.1 below.As an
application,
we characterize(theorem 4.5)
thetangential parts
of theboundary
values of aCauchy-Riemann
vector field u on asmoothly
boundeddomain 11 in R"
by
the conditiond(i*u) =
0, where i : 8Q - is theinclusion,
and i * u is thepullback
of u considered as a one-form. In thespecial
case of a ball in this result is due to
Koranyi
andVagi [4],
who used therepresentation theory
ofSO(n).
1. - A Bochner-Martinelli
type
formula forCauchy-Riemann
vector fields.Let be a fundamental solution with
pole
in x of theLaplacian
For
instance,
we can takethe standard fundamental
solution,
where wn is the surface area of the unitsphere
in R’~. In this section we will derive thefollowing
Bochner-Martinellitype
formula.THEOREM 1.1.
Let n
C open,bounded,
with an. Letu =
(ti~...tt~)
Esatisfy
thegeneralized Cauchy-Riemann equations.
Then
for x
En,
1k
n,(The
means, asusual,
that the termdy3
isomitted.)
For a
given
vector field u on u =(ui , ... un )
E say, we letT(u)
denote the vector field(or one-form)
whosecomponent
is definedby
theright-hand
side of(1.2).
For the sake of concreteness, we willassume that is
given by (1.1),
but much of thefollowing
remains truewith other fundamental solutions.
If we substitute formula
(1.1)
forEz (y)
in(1.2),
we obtainREMARK 1.2. In case n =
2, (1.3)
is theCauchy integral
formula(in
realvariable
notation).
Note
that,
unlike the Poisson formula for uk and like the Bochner-Martinelli formula in severalcomplex
variables(cf. [1]), (1.3)
is universal: the kernel is the same for all Q.Also,
unlike therepresentation
of uk as a sum of two surfacepotentials (cf. (1.5) below), (1.3)
does not involve derivatives of theu; ’s.
The derivation of
(1.2)
starts with one of Green’s formulas which we nowrecall in differential form notation. Let w =
dx1
A... ndxn
be the volume formon If V =
(Vl,
...,V n)
is aCl-vector field,
letThen c
Let u, v C Let V denote the
gradient operator:
Then
PROOF OF THEOREM 1.1. Let u E
satisfy
the GCRE in n and letx From
(1.4), applied
to u and v =Ex, and Auk
= 0 we obtainNow it turns out
that VUklw
is the d ofan (n - 2 ) -form.
LEMMA 1.3.
Suppose
that u =( u 1, ..., un ) satisfies
the GCRE. LetPROOF.
We continue with the
proof
of theorem 1.1.By
theprevious
lemma and Stokes’theorem,
formula(1.5)
becomesA
straightforward computation
now shows thatThis proves theorem 1.1.
_
We now derive a
Pompeiu-type
formula forarbitrary C 1-vector
fields onn, by applying
Stokes’ theorem tothe (n - 1 ) -form
on theright-hand
side of(1.2).
THEOREM 1.4. Let 11 C Rn be open,
bounded,
with Let Thenfor
PROOF. Let x c
0,
and letB(x,e) denote
the closed ball around x with radius e.Apply
Stokes’ theorem onsufficiently small,
to the(n - l)-form
+ = as in lemma 1.3(cf.
formula(1.7)).
Now
since
Hence,
One
easily
shows that the left-hand side of(1.9)
converges touk (z)
ife - 0. For
instance,
one canexpand
theui’s
to first order in aTaylor
seriesaround x, and then use theorem 1.1 with n = and uj
identically equal
to
u~ (x~, 1 j
n.To finish the
proof
we must show thatThis is
again
astraightforward computation,
left to the reader.2. - The case n = 3
In the
special
case n = 3 it ispossible
tore-interpret
formula(1.8)
interms of the
operations
·, x(inner
and exteriorproduct)
andcurl( ) = V x ( )
from vector calculus. This may be of interest in
applications.
Let n
C
=( u 1, u2 , u3 )
be as in theorem 1.4. Letn ( y)
denote theoutward unit normal to an at y E and let 0’ denote the volume-form on
an induced
by w (i.e.
0’ is the surfacemeasure).
Formula
(1.8)
can be shown to beequivalent
toOne can prove
(2.1 ) by checking
that theintegrands
of(2.1 )
agreepointwise
on
respectively,
with those of(1.8).
For theintegrand
of the volumeintegral
in(2.1 )
this isstraightforward.
For the
boundary
term it isprobably
easiest to introduce suitable coordinatesdepending
on thepoint
of if yo E choose Euclideancoordinates x 1, x2 , x3 )
ofR 3
such that yo -0, n ( yo ) = 0, 0, -1 ) .
Thenor(yo)
= and considered as a one-form on is 0 in yo(locally
around yo, an isgiven by
anequation
Y3 = so thatIt is now
again straightforward
to check that theintegrands
of theboundary
integrals
of(1.8)
and(2.1)
agree in yo.3. -
Interpretation
of(1.2)
in terms of differential forms.Let n ç Rn be
bounded,
withC 1-boundary
Let u E Wewould like to rewrite the formula for
T(u) given by (1.3)
in thelanguage
ofdifferential forms. This is
possible,
but ingeneral
the outward unit normal to all will enter theresulting expression explicity, making
the kernel non-universal.Suppose,
from now on,that 0 x
E1 on =
0} (so that Vp
is the outward unit normal to We candecompose
a u E in itstangential
and normalpart
at eachwith
0(y)
ER,
andv(y) I Vp(y);
vand 0
are continuous.If we extend u in a
C 1
way to aneightbourhood
of8Q,
and if we let i : be theinclusion,
then = v(u, v
considered asone-forms),
andv is a one-form on the
C’ 1-manifold
an.Define the
( n - 2 ) -forms for Y 1= x by
and define the double form on I
8(y, x)
is an(n - 2)-form
in y and a one-form in x.THEOREM 3.1. All notation as above.
Then,
as aone-form
in x oncan be written as
PROOF.
T(u)
=T(v)
+ First weinvestigate T(v).
The conditionin
(3.1)
can beexpressed
asv =
(vl,..., v,,). (This
caneasily
be checkedpointwise
on 8Qby introducing
suitable linear coordinates of R n at each
point
ofan;
cf. the end of section2.) Hence,
Substitute this in the
defining expression
forT(v)k(x),
which thenbecomes,
We now turn to
T(~Vp).
Sincedp =
0 on811,
Take the
wedge product
with , Thenand
hence,
4. - Characterization of the
tangential parts
ofboundary
values ofCauchy-
Riemann vector fields.
Let n =
{ x
E R" :0}
bebounded,
with p eC2 (I~ n ) , ~
= 1 onand let i : denote the inclusion map.
Suppose
that u Esatisfies the
generalized Cauchy-Riemann equations
on n. Thenobviously
= 0.
We will say that u E
C1 R n)
satisfies the inducedCauchy-Riemann equations
if dv =0,
with u = v + as in(3.1).
THEOREM 4.1.
If u
Esatisfies
the inducedCauchy-Riemann equations,
thenT(u) satisfies
thegeneralized Cauchy-Riemann equations
on1ft nBan.
PROOF. To
begin with,
for any vector field u onT(u)
satisfiesdiv
T(u) =
0.Write w =
T (u)
and evaluateaaWk by differentiating
under theintegral
xk
sign;
use . Thena ~,
The coefficient of A
... [k] ....
A in theresulting integral
formula for- div w is
equal
tosince = 0 on
To prove that
dT(u)
= 0 we use theorem 3.1. We will need thefollowing
result.
LEMMA 4.2. There exists a double
form A( y, x)
on R n x 1R nB { ( y, y) :
y Ewhich is an
(n - 3)-form
in y and a2-form
in x, such thatPROOF.
By (3.2),
Combining
the terms for a fixedpair
of indices l andk,
with lk,
say, the coefficient ofdxi
ndxk becomes, neglecting
thesign (-1) n-1 ,
Since AEx
= 0 on the last term of(4.1)
becomesWe claim that
(4.1)
isequal
to whereThis is left to the reader to
verify.
Nowput ~4(~,~) = ~
Adzk .
~
’
We now finish the
proof
of 4.1. Write u = v +0 V p
as in(3.1).
Thenby (3.3)
and Stokes’theorem,
ifx o a 11,
since u satisfies the induced
Cauchy-Riemann equations.
The
following proposition corresponds
to aspecial
case of thePlemelj-
Sokhotskii formulas from one-variable
complex analysis.
PROPOSITION 4.3.
Let n
C be bounded withc1-boundary
an. Putfl+
=fl,
fl- Let u E anddefine u+,
u- on0+,0-, respectively, by
Then ~
For the
proof
one can imitate theproof
of lemma 1.4 inAizenberg
andYuzhakov
[ 1 ] .
Formula
(4.2)
also shows some resemblance to a formula frompotential theory (which
can be attributed toGreen,
cf. Burkhardt andMeyer [2],
pp.470, 471),
which asserts that thejump
across 8Q of the normal derivative of thesingle layer potential
ofa 0
EC(8Q)
isequal to 0. (Recall
thatCauchy-
Riemann vector fields are,
essentially, gradients
of harmonicfunctions.)
Thereare
differences,
however: the normal derivativeis,
for(x, y )
Eless
singular
than the kernel ofT(u).
REMARK 4.4. If 8Q is of class E
N,0
a1)
and if u Ethen
u±
ECk (11::1:).
This follows frominspection
of theproof
ofproposition 4.3, using
theorem 2 inchapter II, §20
of Gfnter[3].
We now arrive at the characterization
promised
in the title of this section.THEOREM 4.5. Let Q C
R n , n >
3,be bounded,
open(not necessarily connected)
such that eachcomponent
issimply
connected.Suppose
thatclass some 1~ >
1,0 o.:S;
1 and that v Eis a
tangential
vectorfield
on an whichsatisfies
the inducedCauchy-Riemann equations
dv = 0. Then v is thetangential part of
the restriction toof
aCauchy-Riemann
vectorfield
onfi, {3
aarbitrary.
In the
special
case where 0 is a ball this result is due toKoranyi
andVagi [4].
PROOF. Let v E dv = 0. It is sufficient to show that there exists
a ~
such that for u : := on= 0 on 11- = For then
u+
satisfies thegeneralized Cauchy-
Riemann
equations
on11, by
theorem 4.1 andu+ = v+§Vp
on a11by proposition
4.3. That
u+
E follows from theorem3.1,
combined with remark 4.4applied
tov +
and[3],
theorem 4 of§ 19, chapter
IIapplied
toConsider v- =
T ( v) 111-.
Since eachcomponent
of 11- issimply
connected there exists a harmonic function V on 11- such that v - - VV on n’. We can choose V such
that ]
=x ~ 1
- oo, since= I x 2013~
oo . Inparticular, V x)
is harmonic at oo .It would now be sufficient to show that on each
component
V differs at most a constant from asingle layer potential
For then
by
formula(3.3), T(v
+0 V p) = V(V - P(~)) =
0 on S~-.Let
8V/8n
denote the outward normal derivative of V on = 8Q.Since v E
certainly avlan
E for 0{3
a; cf. remark 4.4.The solution to the exterior Neumann
problem
withboundary
value of thenormal derivative
equal 8V/8n
can be written as asingle layer potential P(~)
for
some 0
Ep
0.arbitrary,
cf. Günter[3],
inparticular
the lemmain § 18
ofchapter
III.By uniqueness
of the solution to the exterior Neumannproblem
we are done.REFERENCES
[1]
L.A. AIZENBERG - A.P. YUZHAKOV,Integral representations
and residues in multi- dimensionalcomplex analysis,
Translationsof
mathematicalmonographs,
vol. 58, American Math. Soc., 1983.[2]
H. BURKHARDT - W.F. MEYER, Potential theorie,Encyklopädie
der Mathematischen Wissenschaften II A 7b,Leipzig,
1915.[3]
N.M. GÜNTER, Potentialtheory
and itsapplications
to basicproblems of
mathematicalphysics,
FrederickUngar publishing
Co., New York, 1967.[4]
A. KORÁNYI - S. VAGI,Group
theoretic remarks on Riesz systems on balls, Proc.Amer. Math. Soc.