A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
K. H ULEK
C. O KONEK
A. V AN DE V EN
Multiplicity-2 structures on Castelnuovo surfaces
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 13, n
o3 (1986), p. 427-448
<http://www.numdam.org/item?id=ASNSP_1986_4_13_3_427_0>
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Multiplicity-2
K. HULEK - C. OKONEK - A. VAN DE VEN
0. - Introduction.
In this paper we
study
« nice »multiplicity-2 structures ?
on smoothsurfaces YC
P4
=P4(C). Every multiplicity-2
structures in this sense isgiven by
aquotient N*
-->-QJy(l)
and vice versa. The existence of sucha
quotient
forgiven
Iimposes
ratherstrong topological
conditions on Y.Under suitable conditions the non-reduced structure
f
leads to a rank-2 vector bundle E onP4
with a section s, such that:Y= {8
=0} (com-
pare
[7]).
Here we are interested in the case where E
splits,
in otherwords, where Y
is a
complete
intersection. We areparticularly
interested in the casewhere Y is a Castelnuovo surface. These surfaces can be characterized
by
the factthat,
forgiven degree d,
theirgeometric
genus is maximal(at
least if
d > 6).
If d is even, then Y is acomplete
intersection[3],
so weonly
consider Castelnuovo surfaces of odd
degree
d = 2b+
1. Our main result(Theorem
13below)
is aprecise description
of those Castelnuovo surfaces Y which admitmultiplicity-2
structures in our sense;then ?
is acomplete
intersection of
type (2,
2b+ 1). Many
such surfaces exist.The third author is very much indebted to A. Sommese for useful discussions.
1. -
Multiplicity-2
structures.Let Y C
P,
be a smooth surface with ideal sheafIp.
We consider certain non-reducedstrucutres f
onY,
i.e. idealsIi ç Iy,
with thefollowing
properties:
1) ?
is alocally complete intersection,
Pervenuto alla Redazione I’ll
Giugno
1985.2) ?
hasmultiplicity 2,
i.e. for everypoint
P E Y and ageneral plane E through
P the local intersectionmultiplicity
DEFINITION. A non-reduced strucutre
r
on Y withproperties (1 )
and
(2)
will be called amultiplicity-2
structure on Y.LEMMA 1.
If
Y andr
are as above then near apoint
P E Y there are.ZocaZ coordinates and I
PROOF. Let E be a
general plane through
P. Then we can find localcoordinates 1 such that = and.
Now look
at
the ideal. It isgenerated by
two functionssay We can write
Because of
(2)
it follows that at least one of the functions10, f 1,
go, g, is a unit at P. We may assume10(P) =f=.
0 andintroducing xo fo + Xl Is
as a newlocal coordinate we find that
If
isgenerated by
functions of the formwhere gl =
gl (x1,
7 X2 ,x3 ) .
Now g EIy
since otherwiser
would be gener-ically
reduced which contradicts(2).
Hence we haveg = X2 192
with91 =
g2 (xl ,
x2 ,x3 ) .
Itagain
follows from(2)
that g2 is a local unit and hencewe are done.
Next we observe that
J2
CI,
and that we have an exact sequencewhich can be
interpreted
as a sequence of vector bundles on Y. In par-ticular ?
defines aquotient N*yIP4 --*L*. Conversely
every suchquotient
defines a non-reduced
structure ? by setting
Clearly Y
fulfills conditions(1)
and(2).
Hence we can stateLEMMA 2. To
define
amultiplicity-2
structureY
on Y isequivalent
tode f ining
ac subbundleL ç N Y/P4 .
Since
is alocally complete
intersection it has adualising
sheaf co:k which isgiven by
From now on we assume the
following
additionalproperty:
LEMMA 3.
If (3)
holds thenPROOF. We have an exact sequence
Applying
weget
Tensoring
withOp, (1)
weget
Restricting
this sequence to Y the secondmorphism gives
us an iso-morphism
which
implies
REMARKS:
(i)
The converseimplication (3)’
=>(3)
is more diincult. It holds for1 > 0
and if(see [7]). /
The latter isautomatically
satisfiedfour I
by
Kodaira’svanishing
theorem.(ii)
If there exists aquotien , then
This is
equivalent
towhere d is the
degree
of Y.(iii)
There areonly
a few surfaces which admit aquotient
>for
1 > 0. They
are thecomplete
intersections oftype (a, b)
with 2a = b51
the cubic ruled surface and the
quintic elliptic
scroll(see [7]).
2. -
Locally
free resolutions.Let Y C
P,
be a smooth surface and assume that its ideal sheafIy
hasa
locally
free resolutionDualising
this sequence andtensoring
it with0p,(1 - 5)
weget
a resolu-tion for the twisted canonical bundle
wy(l)
which reads as followsWe are interested in
epimorphisms Iy
->wy(l). Every
suchepimorphism
defines a
quotient Njp,= my(1).
LEMMA 4.
If
there is anepimorphism diagram
such that the
commutes,
then l’ induces anepimorphism
PROOF. Let ci: =
c,(E,)
and r: = rankE,.
From(4)
and(5)
weget
the
following
« standarddiagram
»:Here X is the
hypersurface
definedby
theequation
g.REMARK. Assume that H is defined
by (4)
and that there is anepi- morphism
y: . Let _then y can be lifted to
give
a commutativediagram
such that y is induced
by
7B Note that if h isgenerically surjective
thenker-PC
kery
is invertible. This follows from[4, Prop.
1.1 andProp. 1.9].
We now want to consider surfaces with a
special resolution, namely
where r > 1 and
1 a b.
If r = 1 then Y is acomplete
intersection oftype (a, b).
If r > 1 then Y is in liaison with a surface Y’ definedby
aresolution
The union Y U Y’ is a
complete
intersection oftype
(See [11]).
The map is
given by
anmatrix
where A is an r x r matrix with entries and
PROPOSITION 5.
If
A issymmetric
then there exists amultiplicity-2
structure
f
on Y suchthat f’
is acomplete
intersectionof type (ar,
2bPROOF. Let Since A is
symmetric
weget
a commutative
diagram:
Here T is the
projection
map.By diagram chasing
one sees thatwhere Hence Y
is acomplete
intersection of det A with ahypersurface
ofdegree
REMARK. Since for afl 1 it follows from
[7],
that there exists a vector bundle Etogether
with a section s EHO(E)
such thatUsing
the sequenceand the section
g E H° (IY (ar))
one finds a section i . Sincethis defines a subbundle which must
necessarily split
off.We want to
give explicit equations
for thecomplete intersection ?
(Compare [13], [14]).
PROPOSITION 6. The
complete
intersectionY
isgiven by
theequations
where
PROOF. We first want to show the
equality
of sets:The surface Y is the set of all
points
x EP4
whereSince A is
symmetric
it is at anygiven point equivalent
to adiagonal
matrix. We can,
therefore,
writeFrom this
description
it is obvious that(8)
isequivalent
toWe have
already
seenthat j
Next we want to show thatTo see this note that the map
is
given by
where A
i is the r X r matrix which onegets
from the matrixby deleting
the i-th row. HenceSince
it follows that Hence g and h define a
complete
intersection
Y
ofdegree
0 Since both varieties have the samedegree
it follows that .3. - Castelnuovo surfaces.
We now consider surfaces with a
special
kind of resolution i.e. we-consider resolutions of
type (7)
with r =2, q
= 1:LEMMA 7. The numerical invariants
o f
Y arePROOF. This is a
straightforward
calculationusing
the resolution(9)
and its dual.
In
[3]
Harrisinvestigated
so called Castelnuovo varieties. These arenon-degenerate
irreducible varietiesVa
clPn
of dimension k anddegree
dwith
d > k(n - k) +
2 whosegeometric
genus pg is maximal withrespect
to all varieties of this
type.
For surfaces inlP4
he showed thatwhere
Here
[x]
denotes thegreatest integer
less than orequal
to x. Harrisshowed that every Castelnuovo
surface
inP4
of evendegree 2b:> 6
is the com-plete
intersection of ahyperquadric
with ahypersurface
ofdegree
b.Moreover every Castelnuovo surface of odd
degree
2b+
1> 6 istogether
with a
plane
acomplete
intersection of ahyperquadric
and ahypersurface
of
degree b +
1.PROPOSITION 8. The Castelnuovo
surfaces of
odddegree:> 6
arejust
thesurfaces defined by a
resolutionof type (9).
PROOF. If Y is defined
by (9)
itsgeometric
genusis
B /
If Y is a Castelnuovo surface then there is a
plane E
such that Y u E isa
complete
intersection oftype (2, b + 1).
Theplane E
has the resolutionHence it follows from
[10,
Cor.1.7]
that Y has a resolution:which
gives
the desired result.We call every surface Y with a resolution of
type (9)
a Castelnuovo surface.REMARK. Okonek
proved
in[8], [9]
that(i)
Theonly
Castelnuovo surface ofdegree
3 is the cubic ruledsurface,
i.e.P2
blown up in apoint
xo and embeddedby
the linearsystem
(ii)
For d = 5 the surface Y is aP2
blown up in 8points
i.e.I
embeddedby
(iii) Every
Castelnuovo surface ofdegree
7(where
is anelliptic
surface overPl
with Kodaira dimensionLet us now return to the resolution
(9).
The maps(b + 2)
isgiven by
a matrix
where the entries aij of the 2 X 2 matrix A are linear forms and where In
particular
Y is contained in thehyperquadric : (det A
If the
degree
of Y is at least 5 then this is theonly hyperquadric through
Y. For the cubic ruled surface thef
are also linear forms and Y is contained in a net ofquadrics.
DEFINITION. A Castelnuovo surface Y is called
symmetric
if7y
has aresolution
(9)
withsymmetric
matrix A.PROPOSITION 9. Y is
symmetric if
andonly if it is
contained in a corank 2hyperquadric Qy.
Thishyperquadric iv unique.
PROOF.
Clearly
if A issymmetric
thenQy
==fdet A
=o}
has corank 2.Now assume that
Q,
==fdet
A ==0}
has corank 2.Then’
there are coor-dinates xi on
P,
such that A isequivalent
towhere 1 = I (x,,,, x,., x2)
is a linear form.By elementary
transformations A isequivalent
toThe
uniqueness
is clear ford> 5. Every
ruled cubic surface isprojectively
equivalent
to the surface definedby
the matrixHence the net of
quadrics
isspanned by
and
Qy
is theonly
corank 2quadric
in this net.Our next purpose is to show that there are many smooth
symmetric
Castelnuovo surfaces of
given degree
d = 2 b+
1. This will follow from:PROPOSITION 10. Let Y be the Castelnuovo
surface defined by
where
depend only
on X3 and x.. Then Y is smoothif
thecomplete
intersection is smooth and does not intersect the linePROOF. Y is defined
by
theequations
We
put 8;f,:
=afilax,:
Sincef
1 and/2 only depend
on x,, and x, the Jacobian matrix isY is smooth if and
only
if rankJ>2
for allpoints
x E Y. For apoint
x e Y we have rank
J
1only
in two eases,namely
whenor when
(xo , xl , XI)
=A 0 andSince here the matrix has rank
1,
thisimplies
thatgrad f 1
andgrad I.
arelinearly dependent
and issingular
at x.4. - The main theorem.
Dualising
the resolution(9)
weget
the exact sequenceThis shows that
my(3 - b)
isgenerated by
2 sections and hence every Castel-nuovo surface Y admits a fibration
By
construction the class of the fibre I’ isLEMMA 11. The
following
two conditions areequivalent (i)
There exists a lineLo
on Y withL’ 0
= 1- 2b.(ii)
There is a lineLo
on Y which is a b-sectionof
99.PROOF. Let
Lo
C Y be a line. SinceH. Lo
= 1 the conditionF. Lo
= bis
equivalent
toK - L,,
= 2b - 3. Butby
theadjunction
formula this isequivalent
toLl 0
= 1 - 2b.Our main aim is to characterise those Castelnuovo surfaces Y which possess a
multiplicity-2
structureY,
such thatY
is acomplete
inter-section.
We start with
PROPOSITION 12. Let Y be a smooth Cagtelnuovo
surface of
odddegree
2b
+
1.If
Y has amultiplicity-2
structurer
with induced canonical bundle (,Oi then this structure isgiven by
aquotient N;/P4
-->-wy(2 - 2b).
In this caseY is a
complete
intersectionof type (2,
2b+ 1).
Thehyperquadric through
Yis
itnique
and issingular along
a lineLo
c Y.PROOF.
By
lemmas 2 and 3 everymultiplicity-2
structure with inducedcanonical bundle comes from a
quotient N*
-coY(Z).
Theinteger
I mustfulfill the
quadratic equation
Using
lemma 7 thisequation
becomesThere are two solutions
It is easy to check
that 1+ 0 Z
unless b = 1 in which case 1- -1+
= 0.One can now use the remark after lemma 4 to construct a
diagram
similar to
(6’).
Theonly
difference is thatT*(1 - 5)
has to bereplaced by
some
arbitrary
map F’. Nevertheless it follows from thisdiagram
thatf
is a
complete
intersection oftype (2,
2b+ 1).
Inparticular f
is contained in ahyperquadric.
This isclearly unique
ifd > 5.
For the case d = 3see
[7].
We now have to show thatQy
has corank 2.Again
we can restrictourselves to the case
d >
5. Let us assume that corankQy
1. Let C = Yr1 H
be ageneral hyperplane
section. Its genus isb (b - 1)
> 0 ifb > 2.
The curveC lies on the smooth
quadric Q,
=Qy
n H. On the other hand we havean exact sequence
We claim that this sequence
splits
whichgives
a contradiction to[5,
theorem
1].
To show thesplitting
it isenough
to see thatBut this follows from
deg (
Hence we have seen that corank
Qy
= 2. LetLo
be thesingular
line. Then.Lo
must lie onY,
otherwiseprojection
fron ageneral point
ofZo
wouldimmediately give
a contradiction to the fact that thedegree
of Y is odd.Now we are
ready
to prove the main result of this paper.THEOREM 13. Let Y C
P4
be a smooth Castelnuovosurface of degree
2b+
1.Then the
following
conditions areequivalent:
(i)
Y issymmetric.
(ii)
Y is contained in a corank 2quadric Qy.
(iii)
There is a lineLOCY
which is a b-sectionof
thefibration Y---> P,.
(iv)
Y contains aprojective
line.Lo
withsel f -intersection Lo
= 1- 2b.(v)
There exists amultiplicity-2 structure r
on Y suchthat
is acomplete
intersectionof type (2,
2b+ 1).
PROOF.
(I)«(it)
isproposition 9; (i) +(v)
follows fromproposi-
tion 5 and
(v)
=>(ii)
isproposition
12.(iii)
=>(iv)
isnothing
but lemma 11.(ii)
=>(iii).
Assume that Y is contained in the corank 2quadric Q,.
The
singular
line.Lo
mustnecessarily
lie on Y. Thequadric Qy
defines asection in
N*,p,,(2)
which vanishesalong Lo.
Hence weget
adiagram
Since
(ii)=>(v)
it follows thatQycHO(Ii(2)) hence q
factorsthrough
M*(2). Since q
isinjective
outsideLo
there must be aninteger k>l
such thatThis
implies
Since
it follows that k = 1 and hence
From this it is
straightforward
tocompute
(iii)
=>(ii).
We assume that there is a lineLO C Y
which is a b-section of the fibration 92: Y -Pl .
Sincethe fibres F are curves of
degree
b which intersect the line.Lo
in bpoints.
This
implies (look
at allhyperplanes through .Lo)
that each fibre F is con-tained in a
unique plane
Ethrough Lo.
In this way weget
aninjective
map
Pulling
back the universal bundle weget
a threefold W which is aP,,-bundle
over
lP1
and a map from W onto a threefold V which contains Y. Moreover there is a surfaceY C 9
which ismapped isomorphically
onto Y. LetIV C r
be the inverseimage
ofLo
in9.
The fibres of$/-Lo
are all iso-morphic
to a rational curve R.Since 17
is aPa-bundle
overPl
we haveHence the class of
Y in 9
is of the formSince the intersection of Y with each
plane P2
is a curve ofdegree
b wefind m = b.
Moreover, since Y
meets each curve Rtransversally
in onepoint
we find n =1,
i.e.-
Then
This
implies
H3 = 2 and V must be aquadric. Clearly
V issingular along Zo .
5. - Castelnuovo surfaces of
degree
5.According
to Okonek[8]
every Castelnuovo surface ofdegree 5
is aPa
blown up in 8
points:
embedded
by
the linearsystem
LetEo,
...,E7
be the,,-....
exceptional
curves on Y. ThenEo
is aconic,
whereasE1,
...,E?
are lines.PROPOSITION 14. The Cagtelnuovo
surface
Y issymmetric if
and on2yif
thepoints
xl , , .. , X7 lie on ac smooth conic C.PROOF. We first note that if such a C exists it must
necessarily
besmooth. Otherwise at least 4 of the
points
x1, ... , x? would lie on a line L andH-LO.
It then follows fromthat C does not pass
through
x, and that it ismapped
to a line.Lo
çy.Since
Lg
= - 3 the surface Y issymmetric by
theorem 13.Now assume that Y is
symmetric.
Thesingular
lineLo
ofQy
lies on Y.It intersects the lines
E1, ... , E?
as can be seenby projecting
from ageneral point
of.Lo .
This alsoimplies Lo 0 Ei
andE(, - Ei = 1
fori=I,...,7.
Let
Eo
be theexceptional
conic. SinceLo - Eo 2
andH. Lo
= 1 there aretwo
possibilities :
In the first case
L:
= - 2 whereas in the second case.Lo = -
3. Weknow, however,,
from theproof
of theorem 13 thatL2 0
= - 3 and hence we aredone.
REMARK. The number of moduli for Castelnuovo surfaces of
degree
5 is2 #points
blown up -dim PGL(3, C)
= 16 - 8 = 8 .The condition that x,,, ..., X7 lie on a conic is 2-codimensional hence the
symmetric
Castelnuovo surfacesdepend
on 6 moduli.6. - Castelnuovo manifolds.
We call a codimension 2 manifold
YeP n+2
a Castelnuovomanifold
ofdimension n if Y has a resolution of
type (9),
i.e.Here we want to
point
out thefollowing
remarkable fact.PROPOSITION 15. The
only
Castelnuovomanifold
Yof
dimensionn> 3
which admits amultiplicity-2
structurer
suchthat -f
is acomplete
intersection isPn
embeddedlinearly.
PROOF. It is
enough
to prove this for Castelnuovo 3-folds Yc P. Justas in lemma 2 we see that every
multiplicity-2
structure comes from asubbundle
ECNy,p,.
If Y admits amultiplicity-2 structure I
which isa
complete intersection, then f
must be the intersection of ahyperquadric Q
with ahypersurface
ofdegree
2b+ 1.
Thequadric Q
must be of corank 3 and thesingular plane
V ofQ
must be contained in Y. This can be seenby taking hyperplane
sections andapplying proposition
12 and theorem 13.Our claim now follows from
LEMMA 16.
If
Y clP5 is a
smooththreefold
such that(i)
Y contains aplane
V(ii)
There exists a sub bundleLCNyp.IV
then Y isP3
embeddedlinearly.
PROOF. Let
Njly
=0.,(a).
From the sequencewe find
Now suppose
Ny,p.IV
has a 1-subbundle0v(b).
Thenand
looking
at this as aquadratic equation for b,
thisimplies
which
implies
a =1. SinceH.’(Oy) -
0by
Barth’s theorem([1,
Th.III])
wesee
that IVI
is a linearsystem
ofplanes
on Y of(projective)
dimension 3.Now choose two different
points x, y E Y.
There is(at least)
a 1-dimensional linearsubsystem IV 10 9 [ V[ I
ofplanes
which contain the line Lspanned by
xand y. Let
Vi ,
IV2 E [ V[°
be two differentplanes containing
.L.They
spana space
Pa. By
constructionPa
istangent
to Yalong
L. Hence allplanes
in I Vlo
are contained in thisPgy
i.e. their unionequals
this space. Hence1’3
s Y and we are done.7. - A remark on normal bundles.
In this section we want to say a few words about the normal bundle of Castelnuovo and
Bordiga
surfaces. We first consider a Castelnuovo surfaceyç: P4
of odddegree.
When we
speak
ofstability,
wealways
meanstability
withrespect
tothe
hyperplane
section H.PROPOSITION 17..Let Y ç
P4
be a smooth Castelnuovosurface of
odddegree
d.Then the
following
holds:(i) If
Y is the cubic ruledsurface
then its normal bundleN Y/Pc
issemi-stable but not stable.
(ii) I f d> 5
then the normal bundleNy/p4
isproperly
unstable.(iii)
The normal bundleof
Y isalways indecomposable.
PROOF.
(i )
If Y is the cubic ruled surface we have anepimorphism
N*
- coy. Sinceit follows that
N YIP,
cannot be stable. On the other hand thegeneric hyperplane
section C of Y is a rational normal curve ofdegree
3. Since.Nclps
=Opl(5)EB Opl(5)
issemi-stable,
it follows thatNylp,
must be semi-stable too.
(ii) Every
Castelnuovo surface lies in aquadric,
i.e. there is a section 0 # s EHO(N;/P,(2)).
Sincefor
d> 5
the normal bundleNy/p,
isproperly
unstable.(iii)
If Y is notsymmetric
then thegeneric hyperplane
sectionC = Y n H is a smooth curve
lying
on a smoothquadric Q.
Since C is neither rational nor ahypersurface
section ofQ
if follows from[5,
Theorem1]
that
Nclp.
and hence alsoNy/p,
isindecomposable.
Now let Y besymmetric
and consider the sequence
We claim that
NY/P4 splits
if andonly
if(10) splits.
If Y is the cubic ruled surface this follows fromlooking
at therulings
of Y. Let us now assumed>5.
For every smoothhypersurface
section C we saw in theproof
of pro-position
12 thatand this is the
only
wayNÓ’H
candecompose.
Hence ifN;’P4 = Ll EÐ L2
we can assume that
L1IO "’-J M*IO
and(o,(2 - 2b)IC.
Sinceq(Y)
= 0 # n we can
apply
a result of A.Weil, (compare [12,
prop.0.9])
toconclude that
1,, -
-M* andL2 "’-J coy(2 - 2b)
and we are done. Henceit remains to show that
(10)
does notsplit.
For this purpose we restrict(10)
to the line
.Lo
withEl 0
= 1- 2b. Then(10)
becomesIf this sequence
splits
thenIn
particular
we have aquotient NYIP,(- l)/Lo
-OLo
and we can argueas in
[6]
to conclude that there is ahyperplane
.H which contains all thetangent planes
of Yalong .Lo .
But this cannotbe,
since thesetangent planes
form the corank 2
quadric Q
which contains Y.Let us now turn to
Bordiga
surfaces[8].
These are rational surfaces Y CP4
ofdegree
6.They
can be constructedby blowing
upP,.
in 10points
and
embedding
this surface with the linearsystem
These surfaces have a resolution
One checks
easily
thatLEMMA. 18.
If
Y has amultiplicity-2
struct2creY
which is acomplete intersection,
thenY
isgiven by
aquotient N;’P4
-->(Oy(- 2).
In this caser-
is a
complete
intersectionof
a cubic and aquartic hypersurface.
PROOF.
Every multiplicity-2 structure ?
which is acomplete
inter-section is
given by
aquotient N*ylp,
-coy(l).
The conditionreads
or
equivalently
Hence I = - 2. On the other hand if we have a
quotient .
it follows from the remark after lemma 4 and the
proof
ofproposition
5that
Y
is acomplete
intersection oftype (3, 4).
PROPOSITION 19. Let Y C:
lP4
be a smoothBordiga surface.
Then thefollowing
conditions areequivalent:
(i)
There exists acmultiplicity-2
structuref
on Y suchthat
is acomplete
intersectionof type (3, 4).
(ii)
There exists aquotient (iii) N*
is not stable.PROOF. The
equivalence (i )
=>(ii )
is lemma 18.(ii )
=>(iii )
follows sinceTo prove
(iii)
=>(ii)
we look at the normal bundleNO/PI
of smoothhyper- plane
sections C = Y n H of Y. C is a curve ofdegree
6 and genus 3. The normal bundle of such curves wasinvestigated thoroughly by
Ellia in[2].
Now assume that
Nyp,
is unstable. Then there is a mapN;/P4
-->- E to a line bundle Z which issurjective
outside a finite number ofpoints
such thatIf we restrict this map to a
generic hyperplane
section weget
aquotient
Nc*,H --> -L I C
which makesNCIH
unstable.By [2,
prop.7]
thisimplies
thatAgain
we can use Weil’s result[12,
prop.0.9]
to conclude that Since
c2(Ny,p,, & o-)y(- 2))
= 0 it followsthat the map must indeed be
surjective everywhere
andwe are done.
REMARK. Since
NCIH
isalways
semi-stable[2],
it follows thatNylp,
must be semi-stable too.
We want to conclude with the
following
COROLLARY 20. The normal bundle
of a Bordiga surface Y k P4
isindecomposable.
PROOF. Assume that
Nylp. splits.
Then the same is true for allhyper- plane
sections C = Y u H.If, however,
C is smooth andNCIH
is decom-posable
thenUsing
once moreWeil’s result it follows that But this is a
contradiction,
y sinceREMARK. We don’t know if there exist smooth
Bordiga
surfaces with theproperties
ofProp.
18.REFERENCES
[1] W. BARTH,
Transplanting cohomology
classes incomplex projective
space, Amer.J. Math., 92 (1970), pp. 951-967.
[2] PH. ELLIA,
Exemples
de courbes de P3 àfibré
normal semi-stable, stable, Math.Ann., 264 (1983), pp. 389-396.
[3] J. HARRIS, A bound on the
geometric
genusof projective
varieties, Ann. Scuola Norm.Sup.
Pisa Cl. Sci., Ser. 4, 8 (1981), pp. 35-68.[4] R. HARTSHORNE, Stable
reflexive
sheaves, Math. Ann., 254 (1980), pp. 121-176.[5] K. HULEK, The normal bundle
of a
curve on aquadric,
Math. Ann., 258 (1981),pp. 201-206.
[6] K. HULEK - G. SACCHIERO, On the normal bundle
of elliptic
space curves, Arch.Math., 40
(1983),
pp. 61-68.[7]
K. HULEK - A. VAN DE VEN, TheHorrocks-Mumford
bundle and the Ferrand construction,Manuscripta
Math., 50 (1985), pp. 313-335.[8]
C. OKONEK, Modulireflexiver
Garben und Flächen von kleinem Grad inP4,
Math. Z., 184
(1983),
pp. 549-572.[9] C. OKONEK,
Über
2-codimensionaleUntermannigfaltigkeiten
vom Grad 7 in P4und
P5,
Math. Z., 187 (1984), pp. 209-219.[10]
C. OKONEK, Flächen vom Grad 8 imP4,
Math. Z, 191 (1986), pp. 207-223.[11]
C. PESKINE - L. SZPIRO, Liaison des variétésalgébriques
I, Invent. Math., 26(1974),
pp. 271-302.[12]
A. J. SOMMESE,Hyperplane
sectionsof projective surfaces.
I: Theadjunction
mapping,
Duke Math. J., 46(1979),
pp. 377-401.[13]
G. VALLA, On determinantal ideals which are set-theoreticcomplete
intersections,Comp.
Math., 42(1981),
pp. 3-11.[14] G. VALLA, On set-theoretic
complete
intersections.Complete
intersections, LNMno. 1092, pp. 85-101,
Springer (1984).
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