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UNCONDITIONAL CHEBYSHEV BIASES IN

NUMBER FIELDS

Daniel Fiorilli, Florent Jouve

To cite this version:

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UNCONDITIONAL CHEBYSHEV BIASES IN NUMBER FIELDS

DANIEL FIORILLI AND FLORENT JOUVE

Abstract. We study densities introduced in the works of Rubinstein–Sarnak and Ng which measure the Chebyshev bias in the distribution of Frobenius elements of prime ideals in a Galois extension of number fields. Using the Rubinstein–Sarnak framework, Ng has shown the existence of these densities and has computed several explicit examples, under the as-sumption of the Artin holomorphy conjecture, the Generalized Riemann Hypothesis, as well as a linear independence hypothesis on the zeros of Artin L-functions. In this paper we show the existence of an infinite family of Galois extensions L/K and associated conjugacy classes C1, C2⊂ Gal(L/K) for which the densities can be computed unconditionally.

1. Introduction and statement of results

For a given Galois extension L/K of number fields and a congugacy class C ⊂ G = Gal(L/K), define the Frobenius counting function

π(x; L/K, C) := X

p/OK unram.

N p≤x Frobp=C

1,

where Frobp denotes the Frobenius conjugacy class associated to the unramified ideal p, and

N p = |OK/p| denotes its norm. The Chebotarev density theorem asserts that π(x; L/K, C) ∼ |C|

|G|

Rx

2 dt

log t. As a generalization of their work on the discrepancies of primes in arithmetic

progressions, Rubinstein and Sarnak [RS] suggested to study the distribution of primes in Frobenius sets. More precisely, one is interested in understanding the size of the sets

PL/K;C1,C2 := {x ∈ R≥1 : |C2|π(x; L/K, C1) > |C1|π(x; L/K, C2)}.

Ng [N] has shown under Artin’s holomorphy conjecture, GRH, as well as a linear indepen-dence hypothesis on the set of zeros of Artin L-functions, that the set PL/K;C1,C2 admits a logarithmic density, that is the limit

δ(PL/K;C1,C2) := lim X→∞ 1 log X Z 1≤x≤X x∈PL/K;C1,C2 dx x

exists. Moreover, he computed this density in several explicit extensions, under the same hypotheses.

The goal of this paper is to show unconditionally the existence of the density δ(PL/K;C1,C2) in some families of extensions and for specific conjugacy classes. More precisely, we will exhibit a sufficient group-theoretic criterion on G = Gal(L/K) which implies in particular that δ(PL/K;C1,C2) = 1. This will involve the class function rG: G → C defined by

rG(g) := #{h ∈ G : h2 = g}.

Date: December 24, 2020.

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We will require L/Q to be Galois, and for a conjugacy class C ⊂ G we will denote by C+ the unique conjugacy class of G+ := Gal(L/Q) which contains C. Explicitly,

C+:= [

aG∈G+/G

aCa−1. (1)

Theorem 1.1. Let L/K be an extension of number fields for which L/Q is Galois. As-sume that the conjugacy classes C1, C2 ⊂ G = Gal(L/K) are such that C1+ = C2+, but

rG(gC1) < rG(gC2), where gCi is a representative of Ci. Then, for all large enough x we have the inequality |C2|π(x, L/K, C1) > |C1|π(x, L/K, C2). In particular, the set PL/K;C1,C2 has natural (and logarithmic) density equal to 1.

It turns out that one can explicitly construct families of abelian extensions L/K satisfying the hypotheses of Theorem 1.1. For n ≥ 8, consider the permutations g1 := (12)(34) and

g2 := (57)(68) as elements of Sn. Let G := h(12)(34), (5678)i < Sn. If L/Q is an Sn

extension, then we claim that the degree-8 abelian extension L/K, where K := LG, as

well as the choices C1 = {g1} and C2 = {g2}, satisfy the required properties. Indeed,

C1+ = C2+ = C(2,2), where C(2,2) is the set of elements of Sn of cycle type (2, 2). Moreover,

an enumeration of the elements of G shows that rG(g1) = 0 and rG(g2) = 4. For the group

Sn, the inverse Galois problem over the rationals has been known since Hilbert, and thus we

reach the following conclusion.

Corollary 1.2. There exists infinitely many Galois extensions L/K and pairs C1, C2 ⊂

Gal(L/K) for which δ(PL/K;C1,C2) = 1.

It is also possible to numerically verify Theorem 1.1. It would be computationally very expensive to work with the full group S8. However, it turns out that one can replace

S8 with a relatively small subgroup which has the required properties. Consider G+ :=

h(12)(34), (5678), (15)(27)(36)(48)i; let us show that G+ is isomorphic to the wreath

prod-uct of Z/4Z and Z/2Z, which is of order 32. Denote the permutations appearing in the generating set of G+ by τ , σ, and γ, respectively, and note that G+ = hσ, γσγ, γi (since γσγ = (1324), and thus (γσγ)2 = τ ). The subgroup hσ, γσγi is clearly isomorphic to (Z/4Z) × (Z/4Z). Moreover, conjugating by γ on hσ, γσγi amounts to exchanging the two factors Z/4Z, which is the definition of the wreath product.

Consider also the abelian subgroup G := h(12)(34), (5678)i < G+as well as the conjugacy

classes C1 := {(12)(34)} and C2 := {(57)(68)}. In the group G+, one has that γ−1C1γ = C2,

that is C1+ = C2+. It follows from Theorem 1.1 that for any Galois number field L/Q such that Gal(L/Q) ' G+, the sub-extension K = LG has the property that for all large enough

x,

π(x; L/K, C1) > π(x; L/K, C2)

(recall that |C1| = |C2| = 1). Bill Allombert has kindly provided us with the pari/gp code

allowing for a numerical check of this inequality up to x = 1010, for a particular1 number

1

Explicitly, L = Q[x]/(f (x)), where f (x) = x32 − 128x30 + 5680x28 − 120576x26 + 1386352x24

9267712x22+ 38233408x20− 101305344x18+ 176213088x16− 202610688x14+ 152933632x12− 74141696x10+

22181632x8−3858432x6+363520x4−16384x2

+256. For the full code, see https://www.math.u-bordeaux. fr/~fjouve001/UnconditionalBiasCode.gp

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field L/Q of Galois group G+. In Figure 1 we have plotted the difference π(x; L/K, C1) −

π(x; L/K, C2), normalized by the function

R(x) := x 1 2 log x+ Z x 2 du u12(log u)2 ∼ x 1 2 log x,

which can be shown following the proof of Lemma 2.1 below to be the "natural approxima-tion" for the order of magnitude of this difference.

Figure 1. The normalized difference (π(x; L/K, C1) − π(x; L/K, C2))/R(x)

with 1 ≤ x ≤ 1010 (data due to B. Allombert)

Acknowledgments

Experiments presented in this paper were carried out using the PlaFRIM experimental testbed, supported by Inria, CNRS (LABRI and IMB), Université de Bordeaux, Bordeaux INP and Conseil Régional d’Aquitaine (see https://www.plafrim.fr/). We thank Bill Allombert for his insights and for providing us with the pari/gp code and the data needed for this project. We also thank Mounir Hayani for very inspiring remarks. The work of both authors was partly funded by the ANR through project FLAIR (ANR-17-CE40-0012).

2. Proof of Theorem 1.1

The proof of Theorem 1.1 borrows from our previous work [FJ], but we will try to be relatively self-contained. In particular we will work in the setting of [B], that is we will consider general class functions t : Gal(L/K) → C, and define2

ψ(x; L/K, t) := X p/OK N p≤x k≥1 t(Frobkp) log(N p); θ(x; L/K, t) := X p/OK N p≤x t(Frobp) log(N p);

2See for instance [FJ, Section 3.2] for a definition of Frob

p in the case where p is ramified.

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π(x; L/K, t) := X

p/OK

N p≤x p unram.

t(Frobp).

When L/Q is Galois, we will use the shorthands G := Gal(L/K), G+ := Gal(L/Q), as well as

t+= IndGG+t := X

aG∈G+/G:

aga−1∈G

t(aga−1).

Finally, we recall that the inner product of class functions t1, t2 : G → C is defined by

ht1, t2i := 1 |G| X g∈G t1(g)t2(g).

Lemma 2.1. Let L/K be an extension of number fields for which L/Q is Galois, and let t : Gal(L/K) → C be a class function. We have the estimate

π(x; L/K, t) = Z x 2− dψ(u; L/Q, t+) log u − ht, rGi x12 log x+ o  x 1 2 log x  .

Proof. Inclusion-exclusion implies that

θ(x; L/K, t) = ψ(x; L/K, t) +X `≥2 µ(`)ψ(x1`; L/K, t(·`)) = ψ(x; L/K, t) − ht, rGix 1 2(1 + o(1)) + O(x 1 3), by the Chebotarev density theorem and the identity |G|1 P

g∈Gt(g2) = ht, rGi. The claimed

estimate follows from a summation by parts and an application of the identity ψ(u; L/K, t) = ψ(u; L/Q, t+),

which is a consequence of Artin induction (see [FJ, Proposition 3.11]).  Proof of Theorem 1.1. Define tC1,C2 : Gal(L/K) → C by tC1,C2 =

|G| |C1|1C1−

|G|

|C2|1C2. It follows by Frobenius reciprocity (see [FJ, Section 3.2]) that t+C

1,C2 = |G+| |C+ 1| 1C+ 1 − |G+| |C+ 2| 1C+ 2 ≡ 0. Hence, Lemma 2.1 implies that

π(x; L/K, tC1,C2) = −htC1,C2, rGi x12 log x + o  x 1 2 log x  .

However, −htC1,C2, rGi = rG(gC2) − rG(gC1) > 0, and thus π(x; L/K, tC1,C2) > 0 for all large

enough values of x. 

3. Concluding remarks

We end this paper with two remarks. Firstly, we give a group theoretical criterion which implies the conditions of Theorem 1.1.

Lemma 3.1. Let G+ be a group and let H and K be subgroups having trivial intersection

and such that H centralizes K. Let h ∈ H be a non-square (in H), and let k ∈ K be a square (in K) which is a conjugate of h in G+. Then, the conjugacy classes C1 = Ch and C2 = Ck

in the group G = HK are such that rG(C2) > rG(C1); in other words, the conditions of

Theorem 1.1 hold.

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Proof. The fact that H centralizes K guarantees that G = HK = KH is a subgroup of G+. Moreover, any x ∈ G such that x2 = k can be written x = st with s ∈ H and t ∈ K (and in this decomposition there is a unique (s, t) corresponding to each x since H ∩ K = {1}). Thus k = s2t2, which implies that s2 ∈ H ∩ K. Therefore s2 = 1, and as a result

#{x ∈ G : x2 = k} = #{x ∈ K : x2 = k} · #{x ∈ H : x2 = 1} > 0 . By symmetry, we also have that

#{x ∈ G : x2 = h} = #{x ∈ H : x2 = h} · #{x ∈ K : x2 = 1} = 0 .

 Lemma 3.1 allows for a generalization of the example given in Section 1. For instance, take G+ = S

n, and let σ, τ ∈ Sn be permutations of order divisible by 4 which have the

same cycle type, but have disjoint supports. Consider the subgroups H = hσ2i and K = hτ i,

and the elements h = σ2 and k = τ2. We clearly have that r

K(k) ≥ 1 and rH(h) = 0, and

Lemma 3.1 applies.

Secondly, we discuss more precisely the rate of convergence in Figure 1. We recall that in this example G = h(12)(34), (5678)i and t = 1C1 − 1C2, where C1 = {(12)(34)} and C2 = {(57)(68)}. Since G is abelian of order 8, the class function rm(g) := #{h ∈ G : hm = g}

is identically equal to 1 for all odd m ≥ 1, and in particular, ht(·3), 1i = 0. The identity ψ(x; L/K, t) = ψ(x; L/Q, t+) ≡ 0 and the Chebotarev density theorem then imply that

θ(x; L/K, t) = ψ(x; L/K, t) − ψ(x12; L/K, t(·2)) − ψ(x 1 3; L/K, t(·3)) + O(x 1 5) = −ht, rGix 1 2 + X χ∈Irr(G) hχ, t(·2)iX ρχ xρχ2 ρχ + O(x15),

by the explicit formula (see for instance [N, Theorem 3.4.9]). Here, Irr(G) denotes the set of irreducible characters of G, and ρχ runs through the non-trivial zeros of the Artin

L-function L(s, L/K, χ). Now, in this particular example 8t(·2) = 1

{(5678)}+ 1{(5678)(12)(34)}+

1{(5876)}+ 1{(5876)(12)(34)}, and thus hχ, t(·2)i = χ((5678)) + χ((5678)(12)(34)) + χ((5876)) +

χ((5876)(12)(34)) (which is not identically zero). This explains why we expect the difference between the solid line and the data in Figure 1 to be roughly of order x−14. (More precisely, we expect order x−14 almost everywhere, and maximal order x−

1

4(log log log x)2.) References

[B] J. Bellaïche, Théorème de Chebotarev et complexité de Littlewood. Ann. Sci. Éc. Norm. Supér. (4) 49 (2016), no. 3, 579–632.

[FJ] F. Jouve and D. Fiorilli, Distribution of Frobenius elements in Galois extensions. arXiv:2001.05428 [N] N. Ng, Limiting distributions and zeros of Artin L-functions. Ph.D. thesis, University of British

Columbia, 2000.

[RS] M. Rubinstein and P. Sarnak, Chebyshev’s bias. Experiment. Math. 3 (1994), no. 3, 173–197.

Univ. Paris-Saclay, CNRS, Laboratoire de mathématiques d’Orsay, 91405, Orsay, France. Email address: [email protected]

Univ. Bordeaux, CNRS, Bordeaux INP, IMB, UMR 5251, F-33400, Talence, France. Email address: [email protected]

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