Critical and ramification points of the modular
parametrization of
anelliptic
curvepar CHRISTOPHE DELAUNAY
RÉSUMÉ. Soit E une courbe
elliptique
définie sur Q de conduc-teur N et soit ~ son revêtement modulaire :
~ :
Xo (N)
~E (C) .
Dans cet article, nous nous intéressons aux points critiques et
aux points de ramification de ~. En
particulier,
nousexpliquons
comment donner une étude
plus
ou moinsexpérimentale
de ces points.ABSTRACT. Let E be an
elliptic
curve definedover Q
with con-ductor N and denote
by
~ the modular parametrization:~ :
Xo (N)
~E(C) .
In this paper, we are concerned with the critical and ramification
points of ~. In
particular,
weexplain
how we can obtain a moreor less
experimental study
of these points.1. Introduction and motivation
1.1. The modular
parametrization.
Let E be anelliptic
curve definedover Q
with conductor N. It is known from the work ofWiles, Taylor
andBreuil, Conrad, Diamond, Taylor ([16], [14], [3])
that E is modularand, hence,
that there exists a map cp, called the modularparametrization:
where
Xo(N)
is thequotient
of the extended upper halfplane
H = H Uby
the congruencessubgroup Fo (N) (which
we endow with its natural structure ofcompact
Riemannsurface).
Theanalytic
groupisomorphism
from
(C/A
toE((C)
isgiven by
theWeierstrass p
function and its derivativeand we will often
implicitly identify
these two spaces. We nowbriefly
describe the map cp.
The
pull-back by
cp of theholomorphic
differential dz isgiven by:
where
f (z)
is a(normalized)
newform ofweight
2 onro(N)
and c E Z isthe Manin’s constant. In this paper, we assume that we have c =
1;
infact all
examples
ofelliptic
curves we have studiedsatisfy
thisassumption (we
use the firstelliptic
curves from the verylarge
table constructedby
Cremona
[7]).
Since the differential2i-xf (z)dz
isholomorphic,
theintegral:
does not
depend
on thepath
and defines arnap §5 :
C.Furthermore, if l’ E ro(N),
we set:the map w does not
depend
on T and is called aperiod
off (see [6]
to
compute
itefficiently).
Theimage
of cv :C,
which is a grouphomomorphism,
is a lattice A c C andthen,
weget
a map:The curve E is in fact chosen
(en
evenconstructed)
such thatE(C)
and cp is the modular
parametrization.
Thisdescription
of the modularparametrization
is veryexplicit
and allows us to evaluate cp at apoint
T E
Xo(N),
indeed:o
First,
suppose that 7 is not a cusp, then we have :where the
(integers) a(n)
are the coefficients of the Fourierexpansion
off
at the cusp oo. Note thatthey
areeasily computable
sinceL( f, s) =
¿n a(n)n-S
=L(E, s)
is the L-function of E. The series(1.1)
is arapidly converging
series andgives
an efficient way to calculate cp.~
Suppose
now that 7represents
a cusp inXo(N). Then,
the series(1.1)
does not converge any more and we have to use a different method. Let be the "modular
symbol"
as described in[6] (it represents
apath linking
oo to T on which we will
integrate f ).
The Heckeoperator Tp,
where p is aprime number,
acts on modularsymbols
and we have:mod N then the cusps p7 and
(T + j ~ ~p (for j
=0, ... ,
p -1)
areequivalent
to T modTo(N),
so there existMo, Ml,
...,Mp
ETo(N)
suchthat:
Writing ~(T ~- j)/p} _ {(T + j)/p~ -
+{T~
andusing
the fact thatf
isa Hecke
eigenform
witheigenvalue a(p)
forTp,
we obtain:And we deduce from it the value of the map cp at the cusp T
(of
course, this is a torsionpoint
and with the methodabove,
we cancompute
itexactly
and not
only numerically).
1.2. Critical and ramification
points.
Thetopological degree of cp
canbe
efficiently computed by
several methods([6], [15], [17], [8]),
and wedenote
by
d =deg(cp)
thisinteger.
There arefinitely
manypoints z
EE(C)
for which~~cp-1(~z})~
d(we
will call z a ramificationpoint).
These
points
areimage
of criticalpoints (and
so criticalpoints
are finitein
number).
We are interested inlocalizing
andstudying
the ramification and the criticalpoints.
From the Hurwitz formula there areexactly 2g - 2
critical
points (counted
withmultiplicity) where g
is the genus ofXo(N)
and is
given by:
...In this
formula,
p =~SL2(7G) :
voo is the number of cusps and v2(resp. v3)
is the number ofelliptic points
of order 2(resp.
order3)
ofXo (N) .
Criticalpoints
are the zeros of the differentialdcp
=2i7rf (z)dz
andthen we are led to find all the zeros of
f . Nevertheless,
a zero off
may not be a criticalpoint
because dz hasonly
apolar part ([12]):
where Pj
are the cusps and ej(resp. e’)
theelliptic
elements of order 2(resp.
order3)
inXo(N). Thus,
c EXo(N)
is a criticalpoint
for cp if andonly
if c is a zero off
not due to apole
of dz. Forexample,
acusp P
is critical if andonly
if the order ofvanishing
off
at P is > 2.Note that the differential form
f (z)dz
isholomorphic
and so apole
of dz iscounterbalanced
by
a zero off . Thus,
the modular formf
vanishes at allelliptic
elements ofXo(N). Furthermore,
with the usual local coordinates forXo(N),
themultiplicity
of a zero off
at anelliptic
element of order 2(resp.
order3)
has to be counted up with theweight 1/2 (resp. 1/3).
So,
asimple (resp. double)
zero off ,
viewed as a functionf : C,
at an
elliptic
element of order 2(resp.
order3) compensates exactly
thecorresponding pole
of dz(viewed
inXo(N)).
Let c E
Xo(N)
be a criticalpoint
of the modularparametrization,
socp(c)
is a ramificationpoint
and is also analgebraic point
onE(Q)
definedover a certain number field K.
Then,
thepoint
is a rationalpoint
onE(~).
A naturalquestion
asked in[11]
is to determine the sub- groupgenerated by
all such rationalpoints. They
denoteby
thissubgroup.
A criticalpoint
c EXo(N)
is said to be a fundamental criticalpoint
if c EzR,
we denoteby
thesubgroup
ofE(Q) generated by
where c runs over all the fundamental critical
points.
In~11~,
the authors
proved
thefollowing:
Theorem 1.1
(Mazur-Swinerton-Dyer).
Theanalytic
rankof
E is lessthan or
equal
to the numbersof fundamental
criticalpoints of
oddorder,
and these nurrcbers have the same
parity.
In this paper, we are concerned with
studying
theseparticular points
of the modular
parametrization.
Moreprecisely,
for a fixedelliptic
curveE,
thequestions
and theproblems
we are interested in are to determine the criticalpoints,
to define a number field K in which live ramificationpoints,
to look at the behaviour of thesubgroups E(Q)"’
andE(Q)f°’"d,
etc..
Although
it is clear that thesequestions
can betheoretically
answeredwith a finite number of
algebraic (but certainly
unfeasible in thegeneral case) calculations,
thepart
3 and 4 of our work is more or lessexperimental
and some of the answers we
give
come from numericalcomputations
and arenot
proved
in arigorous
way.Nevertheless,
there are somestrong
evidenceto be
enough
self confident in theirvalidity.
2. Factorization
through
Atkin-Lehneroperators
In order to find
(numerically)
all the criticalpoints
of cp, we willexplain,
in the next
section,
how to solve theequation f (z)
=0, z
EXo(N).
Infact,
the results we have obtainedby
our methodsuggest
that the zeros off
are oftenquadratic points
inXo(N).
Let
WQ (with Q N and gcd(Q, N~Q)
=1)
be an Atkin-Lehneroperator.
Since
f
is aneigenform
forWQ,
we haveflwQ = + f,
we deduce that:Furthermore,
2P = 0 if thesign
is +1.Suppose that p
oWQ
= cp, then wecan factor the modular
parametrization through
the operatorW~ :
The map 7rQ is the canonical
surjection,
itsdegree
is 2 and we havedeg(cp)/2.
The fixedpoints
c ofWQ
inXo(N)
are criticalpoints
for 7rQ andthus are critical
points
for cp. The Hurwitz formulagives:
where 9Q is the genus of
Xo(N)/WQ.
We define a functionHn(A)
for n E Nand A 0.
If n =
1, Hl(0)
= is the Hurwitz class number of A(cf. [5]).
If n >
2,
we write =a2b
with bsquarefree,
and we let:For n E
N,
we denoteby Q(n)
thegreatest integer
such thatQ(n)2 ~ n, by Qo(n)
the number ofpositive
divisors of n andby p(n)
the Moebius function.Using
the results of[13],
we have:Proposition
2.1. Lettr(WQ, S2(N))
be the traceof
theoperator WQ
inthe space
S2(N) of
the cuspforms of weight
2 onro(N),
then:where:
The numbers gQ and
tr(WQ, S2(N))
are relatedby:
and so the number of fixed
points
ofWQ
inXo(N)
isgiven by
the formula:We are
looking
for all fixedpoints
ofWQ .
We let:and we search T E 1HI such that
WQT
= MT with M EChanging
the
coefficients
y, z et w ofWQ,
we can assume that M = I d and that= T.
Then,
the matrixW~
is"elliptic"
and:First,
suppose thatQ fl 2,
3 then z = -w and:Furthermore
Q
=det(WQ) = _Q2X2
+yNz
so we have(2Qx)2
=-4Q
+4Nyz
and thepoint:
is a fixed
point
ofWQ. Conversely,
we can check that every fixedpoint
hasthe form
(2.2).
In order to find all the fixedpoint:
. We search
/3 (mod 2N)
such that:~ For each divisor z of +
4Q)/4N,
weget
the fixedpoint:
For each new T, we check that it is not
equivalent
modro(N)
to apoint already
found. Wetry
a newdivisor z, eventually
wechange
the solutionf3
and we continue. Westop
when we have obtained all the fixedpoints (their
number is knownby
formula(2.1)).
The critical
point
T in formula(2.4)
hasprecisely
the form of anHeegner point
of discriminantC~’
for some spaceXo(N’)
withQ’
and N’ convenient(see ~4~, [9]
for more details aboutHeegner points).
Infact,
with the nota-tions above:
~ If 2 N and 2
y
and2 t z
then T is anHeegner point
of discriminant-Q
in the spaceXo(Q~.
~ If 2 N and 2
y
and 2f z
then T is anHeegner point
of discriminant-4Q
in the spaceXo(Q).
~ Otherwise T is an
Heegner point
of discriminant-4G~ (-Q
if 2y
and 2 in the space
Xo(N).
If T is a critical
point
for cp and anHeegner point
of discriminantA,
thenwrite A = where A’ is a fundamental discriminant and
f
is theconductor of the order 0 in the
quadratic
field K = In this case, the ramificationpoint cp(T)
is defined over the number field H =the
ring
class field of conductorf.
If
Q
= 2 or3,
wehave I x + w~ I
= 0or I x
+w[ I
= 1. The first case isdiscussed
above,
for thesecond,
we have toadapt
the method with w = 1 - ~; thischanges nearly nothing.
Theequation (2.3)
isreplaced by:
And the fixed
points
are:where A = -4
(resp.
A =-3)
wheneverQ
= 2(resp. Q
=3).
Sometimes,
the Atkin-Lehneroperators
does not suffice to factor cp andwe can also have to use other
operators;
thosecoming
from the normalizer inSL2(R) ([I]).
Inpractice,
thecomputations
areanalogous.
Example.
Let take E definedby:
Its conductor is N = 80 and the genus of
Xo (80) is g
=7,
furthermoredeg(p)
= 4 and we have to find 12 criticalpoints
for cp.First of factors
through
the Atkin-Lehneroperator W16
which has4 fixed
points
inXo(N).
The method above allows us to determine them:The operator:
belongs
to the normalizer ofTo (N)
and we have cp o W = cp. The operator W is an involution ofXo(N) (we
can notsimplify
it becauseW2
andS2
donot
commute).
There are 4 fixedpoints
of W which are:In
fact,
cp iscompletely
factorized:The critical
points
of 7r2 are ci, c2, c3 et C4- We have C5 =7r2(C5) _ 7r2(C7)
and C6 =
7r2(C6) == 7r2(CS),
so inXo(80)/W2:
Thus, 1r2(C5)
and7r2(c6)
are criticalpoints
for7r2.
Let denoteby Pl, P2, P3 and P4
thefollowing
different cusps ofXo(N):
- -- --
We have
7r2(Pl) == IP1, P2}
and7r2 (P3) = P3, P4 1.
Theoperator
W actson these cusps
by WPl
=P2
andWP,3
=P4.
We deduce that and7r2 (P3)
are criticalpoints
for W.Finally,
we have obtained the 12 criticalpoints
for cp and the ramificationpoints
are:Definition 1. An
elliptic
curve E isinvolutory if
there existsoperators Ul, U2, ..., Uk belonging
to the normalisatorof Fo(N)
inSL2(R) through
which cp can be
completely factorized :
and where
Xj
=Xj-l/Uj
andUj
is an involutionof Xj-l.
The curve of the
example
isinvolutory
and the critical and ramificationpoints
can becompletely
described. In the table(1),
wegive
a list off allinvolutory
curves E with conductor N 100 such that E is notisomorphic
to
Xo(N).
The column(Uj)j gives,
withorder,
involutions for acomplete
factorization of cp.
The factorizations
through operators (completely
orpartially) explain
most of the time
why
some criticalpoints
arequadratic.
Nevertheless thereare cases for which critical
points
arequadratic
whereas no factorizationseems to be
possible.
This is the case, forexample,
for the curve E definedby:
-
TABLE 1.
Involutory
curves with conductor N100,
andsuch that
deg( cp) =1=
1. The curves aregiven
in the formy2 +
alxy + a3y= ~3
-f-a2~2 -t~
+ as.with conductor N =
33,
the 4 criticalpoints
are thefollowing Heegner points:
We have
deg(p)
= 3 and it is hard toexplain
thisby
a naturaloperator.
If one wants to prove that a
quadratic point
is a zero off ,
one can use thefollowing
way.Let ~1,~2? ... , l’ J-L be a set of
representatives
for theright
cosetsof Fo (N)
in
SL2 (Z) ,
then classicalarguments
show that the coefficients of:belong
toZ[j] (at
least if N issquarefreee), where j
is the modular invariant and A the usual cusp form ofweight
12 on the full modular group. Thecomputation of P(X)
ispossible (but
delicate andlong
since the coefficientsexplode
withN).
Consider the constant term of thispolynomial P(0) _ G(j)
where G is apolynomial
withinteger
coefficients. We have:Let zo be a
quadratic point. Then, j(zo) belongs
to thering
ofintegers
of acertain number field and so
belongs
to some discretesubgroup
ofC,
henceit is easy to determine if
G(j(zo))
= 0.Furthermore,
the factorization ofG(x)
in irreducible elementsgives
the order ofvanishing at j(zo). Now, by
numerical
computations,
we can decidewhich qj
are such that0,
the
others qj
lead to zero off (A
does not vanish inH).
Coming
back to theexample
of theelliptic
curve E with conductor N = 33. We letf(T) = q + q2 - q3 _ q4 _ 2q5
+ ... be the newform ofweight
2on
ro(33)
associated to theelliptic
curve E.Then,
in this case, we have:And the
points j(ci), ’’’ ~(04),
where cl, - - - c4 are definedabove,
are thezeros of this
polynomial.
3. Localization of the zeros of
f
Whenever a zero of
f
is neither aquadratic point
onXo(N)
nor a cuspthen it is a transcendental number in H
(because j (z)
and z are bothalgebraic
if andonly
if z isquadratic).
In thissection,
we propose togive
amethod in order to calculate at least
numerically
the zeros off
and hencethe critical and ramification
points
of the modularparametrization.
Let:
Then,
wecomplete
the set{ao, ... , by
matrices aN+ 1, ... , a. in order to obtain a set ofrepresentatives
for theright
cosets ofTo(N)
inSL2(Z) .
i.e.:
If N is
prime,
we need notcomplete
the first setsince,
in this case, we have We let:be the classical fundamental domain for the full modular group
SL2(Z).
Then,
we define:where
WN
=0
is the Frickeinvolution,
is a fundamental domain forXo(N).
It may be not connected. We will search the zeros off
1T1
Proposition
3.l. There exists apositive
real number B =Bf
0.27 suchthat:
.1 . I I -
, 1 1
Proof.
Weapply
Rouch6’s theorem to the function q HEn
D.The
(very bad)
bound B 0.27 comes from 2n. DFor
applications
wecompute
a more accurate numerical value forB,
infact B seems to decrease as N grows. In
[11],
we say that a cuspa/b
isa
unitary
cusp ifgcd(b, N/b)
= 1(in
thisdefinition,
weimplicitly
suppose that therepresentative a/b
is such thatgcd(a, b)
= 1 andbiN).
Corollary
3.1. Leta/b
be anunitary
cusp, there exists aneighborhood
V C
Xo(N) of a/b
such that:Proof. If a/b
isunitary,
one can find an Atkin-Lehner operator W such thatWa/b =
oo, and we take V = >B}).
DThis also proves that an
unitary
cusp is never a criticalpoint
for cp; infact,
one can also prove thisby determining
the Fourierexpansion
off
atthe cusp
a/b.
Ifa/b
is notunitary,
thena/b
may be a criticalpoint (see
the
example above).
Atleast,
we remark that:Thus,
we canalways
choose z’ E such that and wecan
forget
the half-diskfz
EH , Izi
when we arelooking
forcritical
points.
All the considerations above allow us to restrict the domain of search for the zeros of
f (see figure 1).
FIGURE 1. Fundamental domain for
Xo(N) (and restrictions)
Then,
in the domainleft,
we localize the zeros off using Cauchy’s
inte-gral.
Moreprecisely,
wepartition
the domain in smallparts
R and for each R wecompute:
It is an
integer:
if it is zero then R does not contain any zero off ,
otherwiseR contains some zeros.
Then,
we divide R in smallparts
and continue.When the localization of a zero is
enough precise,
we use Newton method in order to obtain the desired accuracy.Once the zeros of
f obtained,
we check thatthey
areinequivalent (be-
cause the Newton ’s method may
jump
a zero out of the restricteddomain).
We eliminate those
coming
from theelliptic points.
There must have2g - 2
critical
points
left. The method above isquite
efficient inpractice,
evenin the case where zeros are
multiple.
Let denoteby
ci, c2, ... , C29_2 the criticalpoints
of p.Then,
we consider the ramificationpoints
associated:zj = =
(xj, yj).
From thealgebraic properties
of the zj thepolyno-
mials :
have rational coefficients. We can compute them
numerically
and weverify
that the results we obtain are closed to certain rational
polynomials;
thisprovides
a check ofcomputations. Indeed,
in each case we haveconsidered,
we
get
apolynomial
very close to a rationalpolynomial
and we can thenbe
enough
self confident in the results.Furthermore, P~
andPy
enable usto define a number field K where the
points zj
are defined.Example
Let consider theelliptic
curve of conductor N = 46 definedby
the
equation:
It is the first curve
(for
theconductor)
for which the criticalpoints
are notHeegner points.
The genus ofXo(46) is g
= 5 so there are 8 criticalpoints.
We determine them
by
the methodexplained
above:And
then,
we cancompute 7~.
andPy (numerically):
There are 93
isogeny
classes ofelliptic
curves with conductor N 100.Among them,
46 areinvolutory
and are listed in table(1) (more precisley
those which are not
isomorphic
toXo(N)).
There are 30 noninvolutory
curves for which all the critical
points
arequadratic (so
due to some fac-torization and "accidental" reason as for the case N =
33).
Some cuspsare critical
points
for 4 of the 93 curves,they
are allinvolutory (N
=48,
N = 64 and the 2 curves with N =
80).
The first case for which thegroup is not of finite index in
E(Q)
is obtainedby
the curvey2 ~- y
=~3 +~2 -
7~+ 5 with conductor N = 91. For this curveE( Q)crit
isof finite index. The
curve y2 = 3 -
x + 1 with conductor N = 92 is the firstexample
of curve with rank 1 for whichE(Q)crit
is a torsionsub-group.
4. A rank 2 curve
In this
section,
we comment some of the results we obtainedconcerning
the first
elliptic
curve of rank 2 overQ.
This is theelliptic
curve withconductor N = 389 defined
by:
The group
E(Q)
is torsion free of rank 2generated by G1
=(0, 0)
andG2
=(1, 0).
The genusof Xo(389) is g
=32,
there are 2 cusps(389
isprime)
and no
elliptic
element.Furthermore, deg(p)
= 40. Wecomputed
the 62critical
points
of cp. Aspredicted by
theorem1.1,
there are 2 fundamental criticalpoints:
More
astonishing,
2 criticalpoints
areHeegner points
of discriminants -19:Two critical
points belong
to the lineRe(s)
=1/2:
The last remark comes from a
generalization
of theorem 1.1:Theorem 4.1. Let r be the
analytic
rankof E
and m be the numberof
critical
points of
odd orderlying
on the line1/2
+~
If
2t
N or 4 ~N,
then r m and these numbers have the sameparity. If a(2)
= 2 we have thestronger inequality
r + 2 m.~ then r m and these numbers have the same
parity if
andonly if a(2) =
-1.Proof. First,
the endpoints
of the line I =1/2
+ zR are not criticalpoint
since
f
hasonly
asingle
zero at the cusp1/2 (indeed,
if 41
N thenf(T
+1/2) _ - f (T),
if21 IN
then1/2
is aunitary
cusp and so asingle
zero of
f
and if 2~’
N the cusp1/2
and oo areequivalent).
A direct calcula- tion also shows that there are not anyelliptic point
on I(because
N >11),
thus all zeros of
f
on I n IHI are criticalpoints
for cp.If 4
1
N thenf (T
+~) _ - f (T)
and theproposition
comes from theo-rem 1.1.
Otherwise,
let we have:where
L(E, s)
is the L-function of E(or f )
andL2(E, X)
is its Euler factor at p = 2. One can see that the order ofvanishing v
of2L2(E, 2-s) -
1 ats =0 is:
~ v = 2 if
a(2)
= 2(in
this case, we have 2{ N).
. v = 0 otherwise.
Then the order of
vanishing
of(the analytic
continuationof ) L*(E, s)
ats = 1 is r’ = r + v.
Furthermore,
and we can follow the
proof
of Mazur andSwinnerton-Dyer.
Since the order ofvanishing
ofL* (E, s)
at s = 1 is r’ then:Let
1 /2 ~- itl,
... , the zeros off
of odd orderlying
on 7DBLThen,
is of constant
sign,
and theintegral:
J ‘
is not zero.
But,
thisintegral
is a linear combination ofJo,
... ,Jr,.t
and so r’. This proves theinequalities
of the theorem.If N is odd then the Fricke involution:
/ - , - -,. ,
maps the line
Re(s)
=1/2
to itself. Sincef(z)
= 0 Of(WNz)
= 0 withthe same order of
vanishing,
theparity
of the number of zero of odd order off lying
on I n H isgiven by
theparity
of the order ofvanishing
off
atthe fixed
point
ofWN (i.e.
at T =1/2~). But, flwN
=-Ef,
where E isthe
sign
of the functionalequation
ofL(E, s),
so we see that this order has the sameparity
than theanalytic
rank of E.If
211N
then the Atkin-Lehner involution:I --,- - I - I- 1
maps the line I to itself. The same
argument
as before allows us to con-clude except that in this case we have
flwN/2 == a(2)e f
whichexplains
theeventual difference between the
parities.
DFor our curve E with conductor N =
389,
we havecp(c3)
=cp(c4)
= 0 sowe have determined the
polynomial ~*(X -~(cp(c)))
where theproduct
runsthrough
the criticalpoints except
c3 and c4 and wheredenotes the x-coordinate of P. The numerical
computations
of leadto a
polynomial
which is closed to a rationalpolynomial, giving
a check ofcomputations.
Thispolynomial
is the square of an irreduciblepolynomial over Q
ofdegree
30 with denominator:It also appears that the
sub-group
is a torsion group.Acknowledgement.
Parts of this work has been writtenduring
a Post-doctoral
position
at theEcole Polytechnique
F6d6rale de Lausanne. The author is verypleased
to thank theprof.
EvaBayer
and the members ofthe "Chaire des structures
alg6briques
etg6om6triques"
for theirsupport
and their kindness.References
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Christophe DELAUNAY Institut Camille Jordan Bâtiment Braconnier
Universite Claude Bernard Lyon 1 43, avenue du 11 novembre 1918 69622 Villeurbanne cedex, France
E-mail : delaunay@igd.univ-lyon1.fr