R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
G. A RTICO A. L E D ONNE R. M ORESCO
Algebras of real-valued uniform maps
Rendiconti del Seminario Matematico della Università di Padova, tome 61 (1979), p. 405-418
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Algebras Maps.
G. ARTICO - A. LE DONNE - R. MOBESCO
(*)
Introduction.
The main
object
of this paper is aparticular
fullsubcategory
ofthe
category
of uniform spaces anduniformly
continuous functions(which
we shall sometimes callsimply
« maps)~).
Suchcategory,
which we denote
by 9ty
consists of those uniform spaces whose set of real-valued uniform maps turns out to be analgebra.
It iseasily
shown that the
category 9t
is closed underquotients,
y colimits andcoproducts;
on thecontrary subspaces
andproducts
ofobjects
in 9tgenerally
do notbelong
to U anylonger.
The
investigation
of certain classes ofalgebras
ofuniformly
con-tinuous functions has been tackled
by
J. R. Isbell in[1.1]
and A. W.Hager
in the moregeneral
context of vector lattices[H].
Howeverno condition has been
given
to characterize theobjects
of the ca-tegory
5l{. We can observe that there exist some classes of uniform spaces whichtrivially belong
to thecategory W
such as fine spaces andprecompact
spaces; moregenerally
we shall prove thatlocally
fine spaces
belong
to9t;
this fact is obtained as anapplication
of ourmain result
(Theorenl 1 .3)
w hichgives
a characterization of the spacesftX belonging
to U in terms of a certainuniformity e
of R.Such e
is the weakuniformity
of the continuouspolynomial
dominatedfunctions and it turns out that these functions are the
only uniformly
continuous functions from
~OR
to Requipped
with the usualuniformity:
so that
eR
is in 5l{. An accuratedescription of p
isgiven.
(*)
Indirizzodegli
AA.: Istituto di MatematicaApplicata
dell’Universit4 - ViaBelzoni,
7 - 35100 Padova,The second
paragraph
deals withconvexity
of thealgebras
of real-valued uniform maps in
C(X ) .
In
[H] Hager points
out that there exists a coreflection from thecategory
of uniform spaces onto thecategory % :
in the thirdparagraph
we
give
a direct construction of this coreflectionby
means of theuniformity
Q.The last section is devoted to the
study
of thealgebras
of real-valued uniform maps,
namely
of theirprime
ideals: wepoint
out someanalogies
between suchalgebras
and thealgebras C(X).
Thesimilarity
does not work on the order structure of these
quotients:
anexample
is
given
in which everyhyper-real quotient
field fails to be ~1.1. A characterization of the
objects
of W.In this paper we are concerned with uniformities
regarded
as filtersof
coverings
and all theproofs
are obtainedusing
the relative tech-niques ;
foraxioms, terminology
and notations we refer to[1.2].
If uis the usual
uniformity
on the realline,
we shallbriefly
write R in- stead ofuR ;
and we shall write instead ofR)
to denotethe set of all uniform maps from the uniform space
flX
to R.Let p
be auniformity
on R finer than u such thatU(,uR)
is analgebra:
since contains theidentity function i,
itnecessarily
contains the
polynomial
functions(in
onevariable);
moreover if acontinuous function
f
is dominatedby
apolynomial
p(i.e.
we have
belongs
toU(,uR)
becauseThe set of continuous
polinomial
dominated functions isplainly
an
algebra;
we denoteby p
the weakuniformity
inducedby
thisfamily
of functions.DEFINITION. A countable
covering open}
ofa
topological space X
is said to be a chain ifZJ~
f10
whenever|i-j|>1.
1.1 LEMMA. Let ce be the set of the chains of R which
satisfy
the condition:
I*)
there exist naturalnumbers n, m
such that for every real k > 0 it is: card[- k, k]
nUi-=F ~~ ~ m
+ 1~n(we
denoteby
card Athe power of the set
A).
a is a sub-basis of ~o.
PROOF. For real e >
0,
letUe
be the chain whose elements arethe balls
B(i8, E)
with radius 8 and centeri8,
i E Z and f: R - Rcontinuous and dominated
by
apolynomial
which can bethought
of the form m + xn without lack of
generality;
the inverseimage
is of course a chain and satisfies the condition * for:
then E a. Now choose 91 E a; every
Ui
E ~ is adisjoint
unionof open
intervals;
we aregoing
to shrink 91taking
inplace
ofUi
theset
Ui
made of the connectedcomponents
ofUi
which are not contained in a different thefamily
is still acovering:
infact’ if r
belongs
to asingle Ui ,
then x EI~2 ;
otherwise x E(a, b )
r1r1
(c, d)
where(ac, b)
is acomponent
ofUi , (c, d)
acomponent
ofa =
c E Uk
wouldimply Ui
nUk = 0 against
thedefinition;
soeither or
(c, d) U;. Trivially
91’ is a chain and a compo-nent
(a, b)
ofUi
borders on intervals of orIf
(a, b)
is acomponent
of we define on[a, b] : f (x)
= i if xbelongs just
toUi (such points
do exist since R isconnected); f (a) = j
if a
belongs
toU~
andsimilarly f (b) ;
elsewherelet
f
be linear.It is not hard to prove that the definition
of f is
agood
one;f
realizes TL sincef -1(n -1, n -~- 1 ) = Un,
for If m, n areconstants related to 91
by
theproperty
*,f
is dominatedby
thepoly-
nomial m + xn + |f(0)
|
-f- 1: infact,
since the indexes i for which[0, x] ( [x, 0]
if x0) meets U’
form an interval in Z(again
since[0 , x]
is connected and TL is a
chain)
and their number is less orequal
tom
+ xn,
and since xE Ui implies i-1 f (x)
i +1,
we have)f(r) - f(0 ) )
+ xn + 1. Thisimplies
that a is containedin e,
hencethe thesis follov-s. m
1.2 THEOREM. coincides with the
algebra
ofpolynomial
dominated continuous functions.
PROOF.
Trivially
thepolynomial
dominated continuous functionsbelong
to Then observe that a finite intersection of chains of a, .although
it is not achain,
verifies the condition ~x : in fact letqyi,
i =
1,
... , s, be chains of ot, mi and ni suitable constants as in *, and V -Clearly
for everypositive
real number 1~ we have :for suitable m, n. Let
f belong
tolT(eR)
and callflLi
thecovering
ofthe open balls with
integer
center and radius one: is coarserthan i0 =
.../B ’IDr
for somei0; e a.
It is not restrictive to sup- posef(0 )
==0, /(.r) ~0;
if k is thegreatest integer
which does not exceedf (x),
there existl~ -~- 1 points xo, ..., x~; E [o, x]
such thatf (xi)
=i;
since "U)
/-1(’lL1),
thepoints xi, i
=0, ... , k,
mustbelong
to distinctelements of
i0,
thenby
condition * k + + m, whichgives
+ m.
REMARK 1. A trivial consequence of the characterization of
U(eR)
is that ~O does not coincide with the fine
uniformity
on R: for instance exp(x) 0
1.3 THEOREM. For a uniform space
flX,
thefollowing
areequiv-
alent :
i)
is analgebra.
PROOF.
i)
=>ii):
Let be analgebra
andf E
To’see that
f
EU(,aX,
it isenough
to prove thatif g
E thenChoose a
polynomial
p > 0 such that: lim ==0;
x-+oo
and so
by hypothesis
we obtain thatp o f E
and also thatgo f
=ii)
+i) :
is closed under sums, and the square(any power)
of a map
f belonging
toeR)
is ineR). By hypothesis
= at last the thesis follows from the
equality
f . g = I ( ( f + g > 2 - f 2 - g2 ) ...
.1.4 COROLLARY. =
U(eR).
PROOF.
Apply
theorems 1.2 and 1.3.The
following
remarks show that theorem 1.3 cannot beimproved:
REMARK 2. There exist uniform spaces
pX
such that~O )
is not an
algebra:
let theprojections
xi, nbelong
to x while their
product
isuniformly
continuous for a uni-formity
such as aR X aR if andonly
if a is the discreteuniformity.
REMARK 3. Denote
by
the set of the bounded uniform maps frompX
to R. is analgebra
for every uniform spacepX.
REMARK 4. There exist uniform spaces
flX
such thateR)
is an
algebra
and is different from we R and prove thatU(R,
does not contain unbounded functions.Suppose
thatit contains such a function
f ; trivially
it is not restrictive to assumethat
f (R)
c[0,
+oo) ;
we choose a sequence xn E R such that = nand
f
is non-constant on everyneighbourhood
of x~ . Let 8n E(0, 2 )
such that Let
U == RBN, V==UB(n,8n);
neN
hence {U, TT~
is a chainbelonging
to ~O doesnot
belong
to the usualuniformity
since it has noLebesgue
number.Furthermore
U*(R)
is contained inU(R,
which is thereforean
algebra.
The same
argument
workschanging
R with a connected metric uniform space.We are
going
now toapply
theorem 1.3 tolocally
fine spaces(the
definition can be found in
[1.2]).
We indicate
by
the derivative of theuniformity u
andby ~.,u
the
locally
fine reflection of ,u(see [1.2] chapter VII).
1.5. LEMMA. Let
yX
be a uniform space and assume that there is a uniformcovering
IL whose elements arecompact.
Thenfl(l)
isthe fine
uniformity
and X isparacompact.
PROOF. Let flJ be an open
covering;
if U E’l1,
U n 4Y is uniform inU,
hence ‘l~ isuniformly locally uniform,
i.e. ‘l~ E,u~l~.
Now we haveand so
FTfl === #(1).
At last X isparacompact
since every open
covering
is normal( [E]
P8.8~.
1.6 THEOREM. If
flX
is alocally
fine uniform space, isan
algebra.
PROOF. Observe that
The first inclusion holds since ). is a
functor;
the second follows from thehypothesis
and lemma1.5;
the third is obvious. The result fol- lows now from theorem 1.3. r2.
Convexity
ofObserve that
owing
to theorem1.2, U(pR)
is an order-convex al-gebra
inC(R) ;
furthermore it is trivial thatU(pX) = C(X )
is a convexalgebra if It
is the fineuniformity
on X. However we have thefollowing:
2.1 PROPOSITION.
i)
Iff-lX
is aprecompact
space,U(pX)
is analgebra
andU(pX)
is order-convex if and
only
if it coincides withC*(X),
hence if andonly
if thecompletion
ofpX
is theStone-Cech compactification.
ii)
Iff-lX belong to %, U(pX)
is order-convex if andonly
if theSamuel
compactification
is theStone-Cech compactification.
PROOF.
i)
Trivialby
theequality:
#-ii)
First observe that is convex if andonly
ifis convex: indeed the
necessity
istrivial, conversely
forf
EC(X),
g E
U(,uX )
such that0 f g
we havef = //(1
-~-g) ~ (1 -[- g)
where thefirst factor is a bounded function. Furthermore if denotes the
precompact
reflection ofuX, U* (,uX ) = (see [1.2] II.30 ) ;
the conclusion follows from
i). ®
Recall that for a
topological space X
thefollowing
areequivalent:
i)
The fineuniformity
isprecompact.
ii) Every
admissibleuniformity
isprecompact.
iii)
X ispseudocompact.
Hence we conclude that if X is a
pseudocompact
space thenpX belongs
to 9t for every admissibleuniformity p
andU(pX)
is convexif and
only if p
is the fineuniformity.
Moreover for atopological space X
we can observe:
2.2 COROLLARY. Let
flX
be theStone-Cech compactification
ofthe
topological
space X . For every X such that card > 1 there is an admissibleuniformity p
for which is a non-convexalgebra.
PROOF. Trivial.
If in
proposition
2.1i)
we add acompleteness hypothesis, X
becomescompact,
henceflX
isfine;
however we cangive
anexample
of acomplete
space such that is a non-convexalgebra.
EXAMPLE. Take X = yi : card I >
~o}.
For every sub- set J of I such that card let:The
coverings flLj
form a basis for a’uniformity
p on the set X.Clearly flX
is acomplete
space. Takef
Eand,
for n EN,
letU~~
be acovering
of a such that the diameter off ( U)
is less than1/n
for every U E
%In’
~ then sayJ = yT n .
Weget
that%:1
refinesneN
for every n E
N,
hence = forevery k
EIBJ
since1 jJ1
for every it E N. Therefore consists of the functionsf
E RX such thatf (xi) - f (yi)
out of a suitable count-able
set,
hence it is analgebra; plainly
it is not convex becausethe characteristic function of the set
(s, : I e I)
is a bounded continu-ous function which is not a uniform map.
3. A coreflection on the
category W.
From the considerations at the
beginning
of section 1 weeasily get that
is the coarsestuniformity
finer than the usual one such that the set of the real-valued uniform maps is analgebra.
Theproblem
we are now
going
toinvestigate
is to see ifanalogously
for every uni- form spacepX
there exists a coarsestuniformity v
among the finerones
than p
for which the set of real-valued maps is analgebra.
Denote
by p*
theuniformity generated by
the sub-basis of the cover-ings f-1(91)
withU c- e.
Put for every ordinal number a take ,ua+1 = and for every limit ordinal numbera
put
¡..tOt =n lzfl; clearly
the set of the uniformities p "istotally
ordered.3.1 LEMMA. If a
p
and orXe %,
then a9*
and as a conse-quence for every a.
PROOF.
Indicate the set
3.2 THEOREM. Let
03BCX
be a uniform space. has a mini-(which necessarily
induces the sametopology
asIt).
PROOF. Defined ¡.tor. as
above,
there existssuch that
u~~+1 =
It- since the set of ,ua istotally
ordered and thereare less than exp
(exp (exp (card X ) ~~
uniformities. Putap
=we have c
U(,ua+1, eR)
=eR),
thereforeby
theorem 1.3. Furthermore f!:./-l is the smallest element
by
lemma 3.1.
Later on we shall need the
following interesting
lemma:3.3 LEMMA. Let A be a commutative
algebra
over a field ofcharacteristic
0, B
a vectorsubspace
of A . The vector space Cspanned by
the powers of the elements of B is analgebra.
PROOF. We prove that C contains the elements of the
type
for any x, y E
B, r, s E N.
For n fixed weconsider, for x, y
c- B andi =
0, 1,
... , n thefollowing
elements:ei e C and the matrix
(n
+1 )
x(n
+1)
which in theentry (i, k)
hasthe element ai,, = is invertible : ° in f act
where
a’,,,
= 2i’k and det(a:,k)
* 0 because it is the determinant of Vandermonde of the numbers1, 2, ... , 2n.
If we denoteby
then
’
inverse of
(ai,k),
we have henceBy
ani-O
inductive
argument
it can now beeasily
shown that if ... , x~ are distinct elements ofB,
thenxi 1 ... xn~ belongs
to C. ·3.4 COROLLARY. The vector space
spanned by U(,uX, eR)
inC(X)
is analgebra.
PROOF. In fact
U(pX, QR)
is closed under powers. -3.5 COROLLARY. The
algebra spanned
inC(X) by U(,uX )
is con-tained in then fl1 is the coarsest
uniformity
finerthan
for which this situation occurs.
PROOF. Trivial. m
3.6 PROPOSITION.
Using
the notations of theorem3.2,
PROOF. Take and call the
covering
of Rconsisting
of the open intervals with radius E N. There exist4Y,,
E which refines both and and there areordinal numbers such that Let a = sup an ; then and we have that and
by corollary
3.5f . g E
c- c .
REMARK 5. We are unable to say wether 3.6 may be
strengthened:
in all the
examples
we havetested,
we have found a = 1.The
uniformity
may be reachedby
an alternative construction ofalgebraic type:
for everyuniformity fllet p*
be the weakuniformity
of the
algebra generated by U(,uX )
inC(X ) :
then setfio
= fl,pa+1 ==
- for every ordinal
number,
and if a is a limit ordinalnumber, Corollary
3.5 shows thatpa == fla
for every ordinal num-03B203B1
ber a, hence the two constructions
proposed
arequite equivalent.
We think that
perhaps Hager
refers to this second construction in his paper[H].
In the same paper the author says that theassignation
a : is a coreflection onto the
category %:
a directproof
ofthis fact can be
easily given.
3.7 LEMMA. Let
f belong
toU(pX, vY);
thenf belongs
toU(fl* X,
v*Y),
hence toU(,ulX, V1Y)’
PROOF. Trivial.
3.8 PROPOSITION. a is a coreflection from the
category
of uniformspaces onto %.
PROOF.
By
transfinite induction it can beeasily
shown that if then for every ordinal number a,namely
for Furthermore iff E vY)
thenf E avY),
hence a is a coreflection. 8 ,
3.9 PROPOSITION. The functor a commutes with the
completion.
PROOF. First observe
that,
if we indicateby
thecompletion
of the uniform space is still an element of
~?,l,
hence theidentity
function of X is a map betweenapX
and~CX
which extends to a map from into On the other hand inducesover X a
uniformity
vbelonging
to%(pX)
therefore theidentity
func-tion
c : is a map which extends to thecompletions. 0
We make now a consideration about Rn
equipped
with the usualuniformity
u :employing techniques analogous
to the ones used inthe
proof
of 1.1 and1.2,
we can describe theuniformity
au = en which turns out to be the weakuniformity
of the functions dominatedby polynomials (with n variables):
in fact the fundamentaltopic
is toshow that a sub-basis for au is
composed
of the chains whichsatisfy
the
condition *,
where the interval[- k, k]
isreplaced by
the closedball with center in the
origin
and radius k.4. Prime and maximal ideals in
Owing
to the features of the uniformities studied in this paper, theproblem
ofexaminating
theproperties
of thealgebras
ofuniformly
continuous real-valued maps arises
quite naturally.
Suchalgebras being
bothq-algebras
and Riesz spaces, many results descenddirectly
from those theories.
DEFINITIONS. A
totally
ordered set X is said to be qi if for everypair
of subsetsA,
B such that A B and card(A
uB) NI
thereexists x E X such that A x
B ;
if for everypair
ofnon-empty
subsets
A,
Bsatisfying
theprevious
conditions there exists x E X such that the set X is said to be q .,q,,( =
In the
following proposition
we list a number of known facts(see [HIJ]
and[GJ]):
4.1 PROPOSITION.
Let 03BCX belong
to9ty
P aprime
ideal ofU(pX),
.~1 a maximal one; then:
i)
P isabsolutely
convex inii)
is atotally
ordereddomain;
iii) P( f ) ~ 0
if andonly
ifI (mod. P) ; iv)
is a map oflattices;
v) P
is contained in aunique
maximalideal;
vi) U(,uX)/M
is a real-closedfield;
vii) U(,uX )/M
is a field.With
regard
to thequotients
we may go on with thefollowing:
4.2 THEOREM. Let A be a lattice-ordered
sub-algebra
ofC(X ) with 1,
closed under boundedinversion,
a maximal ideal of A.Given s > 0
belonging
toA, put
and= (f e A :
= 0 for somenl.
ThenM(s)
isinfinitely large
if andonly
ifPROOF. If s is a bounded
function,
theproposition
followstrivially.
Assume now s unbounded so that
1,
is a proper ideal. IfM(s )
isinfinitely large, put g~ _ - ( (s - n) n 0 ~
and observethat gn
is abounded
function,
sothat 8 - n + gn
cannotbelong
to if. Since(s - n -~- gn) ’ g,~ = 0
it follows thatgn E M
for every n. Givenf E 18
there exists E N such that
f(Zn)
=0,
that isf
vanishes on the zero-set of g,;
by
asimple
calculation one sees that if thenBy
theequality f
weconclude
thatf belong
to M.Conversely
let gn be the functions defined above: the functions gnbelong
to7g
hence to.M,
and since gn + we haveM(s )
=-
M(s +~)>~.
o4.3 THEOREM. Let The
following
areequivalent:
i )
R for every maximal idealif;
ii)
iii)
cp isprecompact
is the weakuniformity induced by
allthe real-valued functions
uniformly
continuous onftX).
PROOF.
i)
=>ii):
ifU(pX)
contains an unbounded functionf , 1~
is a proper ideal andby
theorem 4.2 isinfinitely large
for every maximal idealI, .
ii)
=>i):
trivial.ii)
=>iii):
if cp is notprecompact,
there exists a uniformcovering
cu,of R and a map
f
EU(,uX )
such that cannot be refinedby
afinite uniform
covering
of cp. Thisnecessarily implies that f
isunbounded.
iii)
=>ii): by
definitions. 0When
U(,uX )/M
is not the realfield,
it is an ordered field which con-tains a copy of
R; naturally
we wonderif,
as ithappens
for the residuefields of
rings
of real-valued continuousfunctions,
turns outto be in the
general
case thisquestion
has anegative
answer: in factin view of 4.3 there are
hyper-real quotient
fields of and all of them havecofinality Ko : a
cofinal countable set can be obtainedby If(m
+x2n)
for a maximal ideal .lkl’ and natural numbers m, n.Incidentally
wepoint
out thefollowing
consequences of this ob- servation :,-,t) U(QR)
cannot beisomorphic
to anyC(X ) ;
however this factcan be
proved directly;
b)
all thequotient
fields of arecomplete
in theuniformity canoriically
inducedby
the order: in fact it can beeasily
shown(see [M] )
that if an ordered field is and not f}1 then it iscomplete;
hence in view of 4.1
vii) (see [HIJ])
if .1l1 is a maximal ideal of aw-algebra
A. andAIM
is not ?71 then it iscomplete (in
the order uni-formity).
Using
thetechniques
of[GJ]
13.7 we can prove thefollowing partial
result:4.4 PROPOSITION. If
ftX
is alocally
fine uniform space, ~il a maximal ideal ofU(,uX )
such thatU(,uX )/M
is notreal,
thenis ~1.
PROOF. We omit the
details;
observe that ifflLs
is a uniformcovering
of R of balls whose radiusis g 1/2,
with notations of[GJ] 13.7,
is
uniformly locally uniform,
hence hbelongs
to thenuse 4.2 to see that
We shall now make some considerations about the maximal spec- trum Max for
equipped
as usual with the hull-kerneltopology
whose closed sets arewhere I is an ideal of
U(,uX).
It is well known that Max( U(,uX )
a
compact
Hausdorff space; the natural function ~: X - Max( U(,uX))
defined
by
=If
EU(,uX) : f (x)
=01
isobviously
1-1 sinceU(pX) separates points;
is dense in Max( U(,uX ) ) .
Now recallthat a function between uniform spaces is said to be a
d-map
if thepreimages
of twouniformly separated
sets areuniformly separated
and a
d-isomorphism
if its inverse is ad-map
too. Recall also that in view of[1.2] II.3~,
a function betweenprecompact
spaces is a uniformisomorphism
if andonly
if it is ad-isomorphism.
Now we can statethe
following:
4.5. PROPOSITION. Let
pX belong
to(defined
asabove)
is a uniformisomorphism
onto itsimage;
henceis the Samuel
compactification
ofPROOF.
By
theprevious
remarks we shall prove that # is ad-isomorphism.
IfA, B
are(uniformly) separated
inthey
are contained indisjoint
closed setsV(I), V(J) respectively,
hence there exist i E E J such that i
+ j
-.--1;
then the functionsi, j
vanishrespectively
on and so that0-’(B)
areuniformly separated by
either function.Conversely
ifA,
B are subsets of X and there exists i Esuch that
i(A) = o, i(B) = 1,
then cY((2)),
cV( (1- i))
and
Y((i)) n Y((1- i))
= 0.As a consequence Max is the
completion
hencethe Samuel
compactification
ofREFERENCES
[E]
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GeneralTopology,
North HollandPublishing
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Methods inUniform Spaces,
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andits
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Fund. Math., 50 (1961), pp. 107-117.[1.1]
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ecorpi
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Manoscritto