C OMPOSITIO M ATHEMATICA
E DMOND E. G RIFFIN
Families of quintic surfaces and curves
Compositio Mathematica, tome 55, n
o1 (1985), p. 33-62
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33
FAMILIES OF
QUINTIC
SURFACES AND CURVES *Edmond E. Griffin II
@ 1985 Martinus Nijhoff Publishers, Dordrecht. Printed in The Netherlands.
Introduction
Horikawa has
given
acomplete description
of thefamily
of all numericalquintics,
thatis,
the smooth surfaces ofgeneral type
withpg
=4, q
=0,
andci
= 5. Thisfamily
has two 40 dimensionalcomponents,
1 and II. 1 is thecomponent parametrizing quintic
surfaces inp3
with at worstrational double
point singularities.
The othercomponent, II,
parame- trizes numericalquintics, S,
on which the linearsystem |KS| 1
has onesimple
basepoint
P. Thesecomponents
meettransversely
in a 39dimensional sub-locus of II called
IIb.
Horikawashows, by analytic methods,
that if S GIIb
thenand that there is one obstruction to
deforming S
whoseleading
term is ofthe
form xy
= 0. Inparticular,
there are small deformations of any such S that are smoothquintic
surfacesin P3.
At the Montreal summer conference on
Algebraic Geometry
inAugust 1980,
Miles Reidposed
an openproblem [Reid].
Theproblem
is togive
an
explicit algebraic family, Y,
suchthat,
(1) St
is a smoothquintic
surfacein P3,
for t ~ 0 and(2) So
is a smooth member ofIIb.
Again,
Horikawa shows that the canonical map,is an
embedding
for t ~0,
whileis a 2 to 1 map onto a
quadric
cone. Thus the "canonical model" of thefamily, J, in p3
is afamily
of smoothquintics degenerating
to adoubled cone
pulse
aplane.
* This work forms a major part of the author’s doctoral thesis written at Harvard
University in 1982 under the advice of Phillip Griffiths. I wish to thank Phil again for all
his help and patience.
Note that
given
such anexplicit family,
thegeneric hyper-plane
section
of St
would be a smoothplane quintic
curve to t ~ 0. The surfacein II are characterized as ramified double covers of rational
surfaces,
ascan be seen from the fact that the
generic element, C, in 1 Kso 1
is asmooth
hyper-elliptic
curve.By
theadjunction formula,
or
Thus the
generic hyper-plane
section of J is afamily
of smoothplane quintics
for t ~0,
such thatCo
is a smoothhyper-elliptic
curve. Hencethe firest
step
in our program is tostudy hyper-elliptic
curves of genus 6equipped
with semi-canonical divisors. Once one sees how to deform such a curve to a smoothplane quintic
it will befairly straight-forward
todo the same for the surface case.
This observation
points
to thefollowing
verysuggestive
idea: It is clear thatknowledge
of families of surfacesyields knowledge
of families of curves. As will be seen, the methods used here work withequal
ease ineither
setting. Perhaps
there is somedeep
connection between thestudy
of
pairs,
L ~C,
of curves withspecial
line bundles(e.g. giving
anembedding
of Cin P2)
and thestudy
of surfaces ofgeneral type.
Ofcourse, this connection will not be made
explicit here,
but it seems thatthis
example
of thequintics
may, inpart, point
the way toexamining
it.The author wishes to
give special
thanks to Miles Reid whose sugges- tions and comments were veryhelpful. Especially
nice was the idea for apurely algebraic proof
of Theorem II.1. Preliminaries Denote
by R(X, D )
thering,
where X is an
algebraic variety,
D is a divisoron X,
and themultiplica-
tion is the usual
"cup" product.
In the cases at hand this will be agraded ring (generally
notgenerated
as analgebra by
itsdegree
onepart!)
whichis
finitely generated
overH0(X, O)
= C. Letbe the m-th
degree part
ofR( X, D).
In all thecomputations
to follow Dwill be a divisor such that for some m e
II, mD~|KX|,
the canonical linearsystem
on X.By P(en11, en22,..., e"k)
we will denote the"weighted projective space,"
[Mori].
where the
grading
isgiven by weight(xij)
= el.Let C be a smooth
algebraic
curve of genus g. C possesses ag’
if thereis a line
bundle,
L -C,
such that:(1) degc
L = d and(2)
dimH0(C, L) = L°(C, L) r +
1.Any r
+ 1 dimensional linearsub-system of 1 L will
be called ag"
on C.2. Curves
Consider a
family,
L ~ C - à such thatLt ~ Ct satisfies, (1) Ct
is asmooth,
genus 6 curve forall t,
(2) degc Lt
= 5 for all t,(3) h0(Ct, Lt) = 3 for t ~ 0, and (4) L,
is veryample
onCt
for t =1= 0.By
theUpper Semi-Continuity
Theorem[Hartshome],
and
by
Clifford’sTheorem, equality
must hold.So, Co
comesequipped
with a
where
Do
is some effective divisor ofdegree
5 onCo.
Now it issimple
tosee that
either 1 Do has
no basepoint,
in which case themorphism
is an
embedding, or |D0| 1
has one basepoint
P. In this caseDo -
P is ag24
onCo,
andhence, by
Clifford’sTheorem, Co
ishyper-elliptic and,
where
Q
is a Weierstrasspoint
onCo. Thus,
eitherCo
has a veryample
gs
orCo
ishyper-elliptic.
More can be said about
Do
=4Q
+ P in the latter case. Theadjun-
ction formula
yields,
So,
Now,
consider thefamily, KCt
0Lr 2 = (by def.) Mt ~ Ct.
For t ~ 0the above remark shows that
and for t =
0,
Since
hO(Ct, Mt ) =1,
one haswhich,
of course,implies
thatMo ~ OC0
or,Thus,
so that
This
implies
that P must be a Weierstrasspoint
on C ! Therefore.PROPOSITION 1:
If C
is asmooth,
genus6, hyperelliptic
curve, ina family of
smoothplane quintics
then itswhere the base
point
P is a Weierstrasspoint.
Up
until thispoint
no indication has beengiven
as to whether or notsuch a
pair, L0 ~ Co, actually
occurs as the "limit" of smoothplane quintics.
The main theorem of this section rectifies this situation.THEOREM 1: Given a smooth
hyper-elliptic
curve,C, of
genus6, together
with a Weierstrass
point
P EC,
setThen there exists
a flat family,
L~ l~0394,
such that(1) L0 ~ Co is isomorphic to
L - Cand
(2) Lt ~ Ct
is a smoothplane quintic
curvetogether
with the line bundle that embeds it inP2.
(See [Chang]
for arecently published, independent proof.)
REMARK: The theorem and
Proposition
1 combine to show that the closure of the locus ofplane quintics
in the moduli space of genus 6 curves, m6, consistsexactly
of thequintics
themselves and the locus ofhyper-elliptic
curves. Also note that the schemew25,6[ACGH] (which
parametrizes pairs
L ~ C withg(C)
=6, degc
L =5,
andhO(C, L) 3)
has two
components, W1
andW2,
each of dimension 12. Thefirst, W1, parametrizes
the smoothquintics
with theirunique gl.
Thesecond, W2, parametrizes
the smoothquintics
with theirunique g25.
Thesecond, W2, parametrizes
thepairs,
L ~C,
where C is ahyper-elliptic
curve and1 L = 2g12 + P,
P anarbitrary
basepoint
on C. The theorem says thatW1
meetsW2 precisely
in the co-dimension 1 sub-locus ofW2
parame-trizing pairs,
L ~C,
asabove,
with P a Weierstrasspoint.
For the
proof
of the theorem we will need two standard results.FACT 1: Let S be a
graded ring
over k and let T be anothergraded ring
such that
for
all n >
0 and some fixed d. Then[Hartshorne
Ex.II .5 .l 3 ]
FACT 2: Let C be a smooth curve of
genus >
2. ThenR(C, KC)
isfinitely generated (not necessarily
indegree one!)
andPROOF OF THEOREM I :
Begin by computing R
=R(C, P).
RecallIn
degree
The sections
u 2, v
ofOc (2P)
form a basis of theg2 = |2P| on C,
sinceP is a Weierstrass
point.
It is clear that there can be no
polynomial
relation of the formp ( u, v )
= 0 in R. On the other handthe number of monomials of
degree n
in u and vfor
0 n
12. The lastequality
is from the Riemann-Roch Theorem.Thus,
up todegree 12,
thering
isgenerated by
u and v.In
degree
13 we notethat 113P is
veryample
and thus there must be anew
generator!
There isexactly
one since #{uivj|i
+2 j
=13}
= 7 andIt is easy to see that w is "odd" with
respect
to the natural involution i : C ~ C. Thatis,
whileIn
R(C, P).
SetR+ = {x~R|i*x=x}
andR-= R - R+.
ThenR+
isspanned by
the monomials in u and vand R + by
monomials in which wappears to an odd power. Thus
W2 E R+
and must beequal
to ahomogeneous polynomial
ofdegree
26 in u and v. This can be seenby computing
dimensions as well. For alln, # {uivi|
i +2 j = n}
=[ n +
1and for n 11
h0(C, 0 (NP» = n -
5. So indegree
2
Thus we must have
where
g26(u, v )
is aweighted homogeneous polynomial
ofdegree
26.(By considering
the effect of i * one sees that the relation cannot have the form03BBw2 = wh12(u, v) + g’26(u, v )
withh12 ~
0 or À =0). Finally
checkthat
for n 11.
This means that
and that
(by
Facts 1 and2)
Also note that C is embedded in
P(l, 2, 13) by
the mapBefore
proceeding
one should note thatg26(0, v) ~
0. This is becauseC is assumed
non-singular.
To seethis,
consider the open setU(v) ~ Proj(R) given by
thedegree
0 elements in the localizationR(v) (i.e.
theopen set where v ~
0).
Thenwhere
g13(x)
=g13(x, 1)
is obtainedby replacing u2 by x
and vby y
ing26 ( u, v).
Ifg13(O)
= 0 then(0, 0, 0) 6
C. But then the Jacobi matrixhas rank 1 at
(0, 0, 0) ~
C and so C issingular.
Thereforeg13(0) ~
0 andso g26
(0, v )
=1= 0.The map
yields
the 2-to-1covering
mapBy
the Hurwitz genus formula there are 14 branchpoints
of this map onpl.
These break up into two sets. Thirteen of themgiven by
on
P1.
And the fourteenthgiven by
(This
is a fourteenthby
the fact thatg26(0, v )
=1=0.)
All of these rernarks
give
THEOREM I.A: Let C be a smooth
hyper-elliptic
curveof
genus 6. Thenwhere the
grading
isweight(u)
= 1weight( v )
= 2weight( w )
= 13and
g26(U, v)
is aweighted homogeneous polynomial
such that(1) g26(0, v)
=1= 0 and(2) g13(x, y)
has 13 distinct roots.REMARK: When
U2
= 0 we havew2
=ÀV13.
This seems toyield
twopoints
on C
namely
However,
under the C* action onP(1, 2, 13)
Thus these two
points
arereally
the same! This in turn means thatu 2 = 0
is indeed a branch
point.
As the next
step
in theproof
of Theorem 1 we write downgenerators
and relations for the
subring R ( C, 5P)~R(C, P).
Denote thissubring
by R(5).
ThenR(5)
is thegraded ring given by
for
each d >
0. It is easy to seeby counting
dimensions and the remarkson the
computation
of R thatwhere I =
(w2 - g26(u, v )) n R(5). Indeed,
these monomialsclearly
gener- ateR(5)
indegrees 1, 2,
and 3. Furthermore anymonomial,
m, ofdegree
5 d in R can be written as
uivj
wherei + 2j = 5d
or aswuivj
wherei + 2j = 5d - 13,
sincew2
=g26(u, v ).
Thus eitherFinally
it is easy to see that if51i
+2 j
thenuivj
is a monomial inU5, U3V, UV2,
andV5.
As to the
computation
of 1 let us setin
R(5).
First there are the "Koszul relations"
(Table 1).
These can be verynicely expressed
in thefollowing
determinantal form:The non-trivial relations in 1 come from the
equation W2 - g26(u, v )
as inTable 2. These last three
equations
define C as a Weil divisor on thedeterminantal variety
ofP(13, 2, 32) given by (*). They
are obtainedfrom each other
by
monomialreplacement.
TABLE 1
TABLE 2
For later reference the form of the
fj(xi, y )
will be examined moreclosely. By property 1)
in Theorem 2 the coefficient ofV15
inv2g26(u, v )
is non-zero. Since
V15 = y3
thisyields
with À =1= 0. Further
and since X3 =
uv2
thisgives
where
Q(xi, y )
is aweighted homogeneous polynomial
ofweight
five(namely Q(xi, y) = h25(u, v) = g26(u, v) - ÀV13/U). Similarly
it is easyto see that
Thus we have
where
TABLE 3
and each
f
isweighted homogeneous
ofweight
6.Next the lst
syzygies
arecomputed.
The first group of these canagain
be written in determinantal
form,
More
precisely
theeight
3 X 3 minors of these matrices should each have determinant zero.Expanding
across thetop
rowsyields,
The second group of
syzygies
involves the non-trivial relations r7, rg, and r9.They
areeasily
derived from the form of theequations
in table 3.Only
one of the four will becomputed
here.Consider
Thus
Continuing
in acompletely analogous
fashionyields
Collecting
all thesyzygies gives
Table 4.Note,
the curveCo
residesnaturally
in aweighted projective
space,and that the semi-canonical map
is
given by
therestriction,
toCo,
of theprojection
map inP(13, 2, 32 )
TABLE 4
from
the " weighted plane,"
to the standard
plane
The
single point
P ECo
which lies in Vis,
of course, the basepoint of |L0| 1
and
corresponds
to thespecial
branchpoint
definedby u2
= 0 in thediscussion above.
(Again
at firstglance
but these " two"
points
are identified under the C*action).
Finally,
on to the deformation of R to the semi-canonicalring
of aplane quintic.
The observation that the semi-canonical map is aprojec-
tion
to P2 suggests
that the deformation should somehow "eliminate"the
weighted
variables y, zl, and z2.(A
morespecific
motivation isgiven
in
[Griffin].)
To
implement
this ideaproceed
as follows:and
becomes
These new
equations, Rl, R2
andR3
are used to "eliminate" y, zl, and Z2 when t ~0,
and when t = 0R
i = ri.Specifically, they give
an embed-ding
for each non-zero t,
namely
where
and
Now consider the syzygy
Replacing rl by Ri gives
To
extend s1
to asyzygy S1 (which
must be done to insure thefamily
Cis
flat)
onesimple
alteration is necessary,Then
Note: It was in order to make this last
equation
work that we addedt203BBy
to rl above,
instead of thesimpler t03BBy. Thus S1
isClearly S1
~S1 as t ~ 0.Similarly
onehas,
with
Note that in the process of
extending s1
and s2, the alterations were"forced" on r4 and r5 .
Only
one more such calculation will be shown. Consider the syzygySubstituting RI, R2, R4
as aboveyields
so it r6 becomes
and r7
=R7,
r, =R g,
and r9 =R9
areunchanged
then sl, becomesREMARK: It as if
by magic
that the process ofextending
thesyzygies
has"forced" the
generic weight
fiveQ(xl, y)
down from thedegree
6relations r7, rg, r9 to the one
degree
5equation R6
when t ~ 0!Here, then,
is thefamily, W,
of smoothplane quintic
curves withCo =
C:where
TABLE 5
where
Q(xi, y )
is aweight
5homogeneous polynomial.
PROOF OF THEOREM I: Given a
smooth,
genus 6hyperelliptic
curve,C,
one can assume that one of the 14 branch
points on P1 ~ Proj(C[x, y])
of the 2-to-1 map
C
1is the
point (0, 1).
Letf(x, y )
be ahomogeneous polynomial
ofdegree
13 which vanishes at the other 13 branch
points.
Takein Theorem 2 and then set
Finally taking
in table 5
gives
the desiredfamily.
Q.E.D.
it is
interesting
to write down thesingle quintic equation (with parameter t )
thatgives
theplane
model of thefamily
W. This is doneby
’eliminating" y,
Zy and Z2 for t ~ 0 andusing R6.
The result is:where
First,
note that theplane
model ofCo
is a double conicplus
aTANGENT line. It is clear that for
Q(xl, y) sufficiently general (see
Theorem
2) C(xi)
isgeneral
and thus(*
**) represents
afamily of
smooth
plane quintics
for t ~ 0.Second,
in this case, it is easy toexplain why only
even powers of t appear in thefamily
above. This means that t - - tgives
an involutionon the whole
family.
To see that there must be such an involution and that it induces the naturalone, i,
onC,
consider the normalsheaf.
Themap
yields
on exact sequence,which defines the normal
sheaf, N.. By [SGAI]
the obstruction toextending
99 to any deformation ofCo
is an element ofHere J is an ideal in an Artin
ring Pli,
annihilatedby
mR. In this caseN,
is
supported
onpoints
andtherefore,
for all such J.
So,
the map 99 can be extended to thecomplete family
W.This in turn means that there must be an involution on W which induces
i on Co .
3. Surfaces
In order to
give
anexplicit algebraic description
of the deformation space of numericalquintic
surfaces webegin
with S e II.(i.e. Ks
has asimple
base
point [Horikawa]).
Thenjust
as in the curve case we can constructBy [Mumford]
and[Bombieri]
one has that R isfinitely generated
andthat in the case at hand
Then we
perturb
thedefining equations
in R to obtain the canonicalring
of a smoothquintic in p3 .
Thesecomputations
can be made in apurely cohomologica
fashion(see [Griffin])
once anexplicit
realization of S as a ramified double cover of aquadric
cone is seen.However,
there isa
purely algebraic
method that usesonly
the constructions in§2
and thefact that if
Co ~|Ks| and Co
is smooth thenCo
ishyper-elliptic,
of genus6,
andTo
begin
recall that theirregularity
Thus the exact sequence
where
Do E |1 2KC| I yields,
By
induction and SerreDuality, then,
for
all n
0. This means there is adegree preserving surjection
whose kernel is a
principal ideal, (xo),
withweight
xo = 1.The map above
simply
expresses the fact thatCo
is a canonical(i.e.
degree one) hyper-plane
section of S.So, by
suitable choice ofgenerators
we can write
That is,
We now
proceed
to find a nice form forÎ.
In order to see thepoint
ofthese
manipulations
the reader is advised toskip
forward to Theorem IIfor a clear statement of the result before
going through
the next fewpages.
Next,
for each relation in table 3 there must be a relation inR ( S, KS).
That
is,
I is obtained fromÎ by setting
xo = 0 so inRs,
we have Table6,
in which thea’s, b’s, c’s, d’s,
and e’s areweighted homogeneous polynomials
of theappropriate weight.
Consider
By
achange
ofcoordinates,
TABLE 6
ri becomes
where
So we may assume
that r1
has the formFurther, using
this relation we may assume that no monomial in any of theb’s, c’s, d’s,
or e’s is divisibleby x2.
Of course, all of thexi’s
inri - r9 must be
changed
butby altering
theb’s, c’s, d’s,
and e ’s the form of the relations isunchanged. Continuing
the samevein, replacing
y
by
where,
and xl
does not appear in any monomial inb12, yields
By
similarchanges,
and
we can arrange that neither xi nor x2 appears in any monon
Finally by using
r2, r3, r4,and rs
to reduce d we may assumeof x2y, X1Y, xlz2, X2Z2 appear in d.
Now the
syzygies
inRS
must also descend to those in R. Fo:s, becomes
which
implies,
or
Repeating
this process for the next elevensyzygies yields
TalLet
and remember that a = axo.
By
theprevious remarks,
for
some 03B2,
y E C.Reducing
s, mod xo thenyields
Thus
TABLE 7
(using r1
and r2 EI ).
And henceso
The
only generator
of I indegree
2 is rl soIf,
in theoriginal equations b2
isreplaced by b2 - 03BBr1,
which has noeffect
onÎ,
we then haveNext, CI
has the formReducing
S3 mod xoyields
The
only degree
four relation in Iinvolving
x2x3y is x2x3y -x43
whichhas no x, in it. Thus E = 0. Likewise for x2z2 the
only
relation is x2z2 - x3z1. So T = 0 as well. This leavesAgain
afteradjusting
c2by
an element of I we may conclude that c2 =SZ2-
Reducing
s5 mod xoyields
Since x2z2 - X3ZI involves no xl, we must have
03B2
= 8. Thisimplies
or
or
Once
again, adjusting
dby
an element ofÎ allows i
tobe,
It is easy to check that s2, s4, s6, S7, and S8
impose
no furtherconditions on
hi, ci,
ord.
So far wehave,
Setting
and
substituting
into s, in Table 7yields
or
Thus
Reducing
mod xogives
which
clearly implies p2
+ a = 0. Recall x, does not appear inb
1 so,and
Thus
and
The same process
applied
to S3gives
or
Hence
and
reducing
mod xogives
or
By
theprevious work,
neither xl nor x2 appear iné’
soBy
the relation * * one sees thatkl
= 0 and then thatRepeating
this somewhat tedious routinewith s5
in Table 7yields
or
Thus,
or mod xo,
Hence
and
Thus
Again
s,yields,
and thus
Substituting in s3 gives
and so
Now xl,
x2 ~
ciimplies
thatFrom
( *
** )
onehas,
Since Tl is the
only degree
z relation inÎ
this means,Finally,
s5gives.
or
So
by adjusting d
as before we may assume that d" = 0.This
completes
the determinationof a, bl, b2,
Cl, c2, and d. It also shows that Table 6 has the formTABLE 8
where the
el’s
areweight
fivehomogeneous polynomials
thatsatisfy
S9through
S12 in Table 7. It is very tedious to determine the actual form of theel’s
and so we leave this task to thepatient
reader.Hence,
THEOREM II: Let S be a numerical
quintic surface (Pg
=4, q
=0, ci
=5)
such
that |KS| has a
basepoint (i.e.
S EII).
Thenwhere
Î
isgenerated by
relationsand r7, r8, and r9 as in Table 8 above.
Note:
Conversely,
if theej’s
aresuitable,
i.e.they satisfy
thesyzygies
and Table 8 defines a smooth
surface,
then it ispossible
to check that this surface is indeed ofType
2. Onesimply
solves theequations
in terms ofxo, xl, x2, X3 over the open sets
x0 ~ 0, xi =1= 0,
etc. Thus if one has anexplicit description
of the suitableel’s (see
forexample
condition 2 inTheorem
I.a)
one wouldhave,
in some sense, a"parametrization"
of thedeformation space of the
type
II surfaces.It is clear that S E
IIb (i.e.
the canonicalimage
of Sin p 3
is asingular quadric)
if andonly
ifa
= 0. In order to show that any such an S EIIb
occurs as the limit of smooth
quintic
surfacesin P3
onesimply
followsthe curve case.
THEOREM III: Given S E
IIb
there exists afamily of surfaces, Y,
whosegeneric
member is a smoothquintic surface in p 3
and such thatSo
= S.PROOF: First write
S ~ Proj(R(S, KS)) ~ Proj(C[x0,
XI, x2, x3, y, zl,Z2
where
where
(x0,
x1, x2, x3, y, z1,z2)
is ofweight
five and where thei’s
are determined via the
syzygies
S9 - S12in,
Then set
where
R8 = r8 -qq = rg
As
before,
it is now easy to check that 5e is the desiredfamily.
Q.E.D.
REMARK: As in the curve case, one can eliminate the
weighted
variablesto obtain the canonical
image
of J inI? 3.
Theimage
ofSo
is aquadric
cone
plus
atangent plane.
Thecomputations
mimic the curve case andare left to the reader.
So we have
described, algebraically,
in thepreceeding
tables all of thedeformation space of the numerical
quintics. Component
1where 13
= 0and
component
II where t = 0 meet in the locusIIb when 13
= t = 0. Theonly piece
of information we have not recovered that Horikawa shows in[Horikawa]
is that thesecomponents
meettransversally.
Thisproject
ispostponed
to a later paper.References
[ACGH] ARBARELLO, E., M. CORNALBA, P.A. GRIFFITHS and J. HARRIS: Topics in the Theory of Algebraic Curves (to appear in Princeton University Press).
[Bombieri] BOMBIERI, E.: Canonical Models of Surfaces of General Type. Publ. Math.
IHES 42 (1973) 171-219.
[Chang] CHANG, H.: Deformation of quintic Plane Curves. Chinese Journal of Math. 9 (1981) 47-66.
[Hartshorne] HARTSHORNE, R.: Algebraic Geometry. Springer, New York, Heidelberg,
Berlin (1977).
[Horikawa] HORIKAWA, E.: On Deformations of Quintic Surfaces. Invent. Math. 31 (1975)
43-85.
[Mori] MORI, S.: On a Generalization of Complete Intersections. J. Math. Kyoto Univ. 15-3 (1975) 619-646.
[Mumford] MUMFORD, D.: The Canonical Ring of an Algebraic Surface. Annals of Math.
76 (1962) 612-615.
[Reid] REID, M.: Problem 12, Part 2. Problèmes Ouverts, Sem. Math. Super., Sem. Sci.
OTAN, p. 8 (1980).
[SGAI] GROTHENDIECK, E.: Seminaire de Geometries Algebrique, no. 1, Exposé III (1960)/1961).
(Oblatum 15-111-1983 & 29-IX-1983) Department of Mathematics
University of California, Los Angeles
Los Angeles, CA 90024
USA