C OMPOSITIO M ATHEMATICA
S IDDHARTHA S AHI
On Kirillov’s conjecture for archimedean fields
Compositio Mathematica, tome 72, n
o1 (1989), p. 67-86
<http://www.numdam.org/item?id=CM_1989__72_1_67_0>
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
On Kirillov’s conjecture for Archimedean fields
SIDDHARTHA SAHI*
Department of Mathematics, Princeton University, Princeton, NJ 08544, U.S.A.
Received 23 March 1988.
Abstract. Let Gn = GL(n, F) where F is either R or C and let P. be the subgroup consisting of those
matrices whose last row is (0, 0, ... , 0, 1). A long standing conjecture of A.A. Kirillov asserts that any irreducible unitary representation of Gn remains irreducible upon restriction to Pn. In this paper this conjecture is completely proved for F = C and partial results are obtained for F = R.
Introduction
The
general
linear groups form a natural class of reductive groups whoserepresentation theory
is nowfairly
well understood[B, T, V].
The foundation of the non-archimedeantheory
is the work of Bernstein andZelevinsky [BZ],
andcentral to their
approach
is the notion of the derivatives of an admissiblerepresentation
ofGL(n, F),
where F is non-archimean. This notion in- volves restriction of thegiven
admissiblerepresentation
to asubgroup Pn(F) ~ GL(n - 1, F)
IFn-1consisting
of matrices with last row(0,...,0, 1).
This paper was motivated
by
three considerations.First,
since the groupPn(F)
is not
reductive,
it isproblematic
to define the derivatives in the case when F isarchimedean;
but it seemed that onemight
still be able to make sense of thehighest
derivative for irreducibleunitary representations.
Of course, this wasintimately
involved with Kirillov’sConjecture [K]
which statesCONJECTURE 1.1. If F is a local field and 03C0 is an irreducible
unitary representation
ofGL(n, F) then ni Pn(F)
is irreducible.So the second motivation was to
study
thisconjecture.
This turned out to beinextricably
intertwined with thefollowing conjecture
which was the thirdmotivation.
CONJECTURE 1.2. If F is a local field
and n, and 03C02 are
irreducibleunitary representations
ofGL(n1, F)
areGL(n2, F). Then ni
x 03C02 is an irreduciblerepresentation
ofGL(nl
+ n2’F). (By
ni x 03C02 we mean therepresentation
obtained
by unitary parabolic
induction from therepresentation 03C01 ~
03C02 of the Levisubgroup GL(n1, F)
xGL(n2, F)).
* Research partially supported by NSF Grants No. MCS-8108 814 (A04) and 215-6109.
Compositio
© 1989 Kluwer Academic Publishers. Printed in the Netherlands.
For non-archimedean fields these
conjectures
are all theorems due to Bernstein. ForR,
and C.Conjecture
1.2 isimplicit
in[V].
A word now about our methods and results. From now on F is either R or
C;
and for z E
F,
we will write Re z for its real part(so
Re z = z if F =R).
The first
ingredient
is the classicalMackey theory of unitary representations
ofsemi-direct
products.
In thisconnection,
we note thefollowing
facts about the groupsPn(F).
(i)
The groupPn(F)
is a semi-directproduct GL(n - 1, F) Fn-1
with thesecond factor normal and abelian.
(ii)
For z EF,
we will denoteby e
theunitary
charactere(z)
=exp(i Rez),
anduse it to
identify
thealgebraic
andunitary
duals ofFn, writing (Fn)*
for both.(iii)
On(Fn-1)*,
the groupGL(n - 1, F)
hasexactly
two orbitsviz.,
0 and(Fn-1)*B0. Furthermore,
if~~(Fn-1)*B0
isgiven by ~(t(x1,...,xn-1)) =
xn-1, then
StabGL(n-1,F)(~) ~ Pn-1(F),
imbedded in the top left corner ofGL(n, F).
Thisimplies
thefollowing
result(see [M]).
FACT 1.1.
Every
irreducibleunitary representation
ofPn(F)
is obtained in oneof two ways
either
(a) by trivially extending
an irreducibleunitary representation
ofGL(n - 1, F)
or
(b) by extending
an irreducibleunitary representation
ofPn-1(F)
toPn-1(F)
Fn-1by
the character X andunitarily inducing
toPn(F).
NOTATION. We shall write
G
for the set of irreducibleunitary representations
of G. Also we shall use E and I for the two constructions
(really functors) given
in parts(a)
and(b)
of the above fact.Then the above
fact,
and a bit more, is summarizedby
theequality
Ên(F)
=E(GL(n - 1, F)) I(n-1(F)). (*)
We shall use the convention that
Pi (F)
=G0(F)
= trivial group(consisting
ofthe
identity
elementalone).
With this in mind anditerating (*)
we observe:FACT 1.2.
Every
irreducibleunitary representation i
ofPn(F)
is of the form 03C4 = Ik-1E03C3 for some k1,
where k and
03C3 ~ GL(n - k, F)
areuniquely
determinedby
i .DEFINITION 1.1.
(i)
If T is aunitary representation
ofPn(F) (not necessarily
irreducible)
we shall say that i ishomogeneous of depth
k iffor some
unitary representation
6 ofGL(n - k, F).
(ii)
If p is aunitary representation
ofGL(n, F)
we shall say that p is adducible ofdepth k
if03C1|pn(F)
ishomogeneous
ofdepth k ;
and ifwe shall write a =
Ap
and term it the adducedrepresentation
of p.Note that if p is
adducible,
the03C1| Pn(F)
is irreducible if andonly
ifAp
isirreducible.
We are now in a
positon
to state thekey
result aboutadducibility.
THEOREM 2.1.
If
p and u are adduciblerepresentations of GL(r, F)
andGL(s, F) of depths
k andt,
then p x 6 is adducibleof depth
k + e andUsing
Theorem 2.1 and a semi-classical fact about the discrete series ofGL(2, R)
we can deduceConjectures
1.1 and 1.2 fortempered representations
ofGL(n, R)
andGL(n, C).
This is the content of Theorem 3.1.Then, using
an extension of some arguments in Stein[St]
and results ofVogan
on the
unitary
dual ofGL(n, C),
we establish bothConjectures
1.1 and 1.2 forF = C. This is Theorem 3.2.
In some remarks at the end of Section 3 we indicate the additional effort necessary to prove Kirillov’s
Conjecture
for F = Il and also suggest some connections with thetheory
of rank ofrepresentations
asdeveloped by
Howeand Scaramuzzi.
Section 2. The considerations in this section are motivated
by
Bernstein andZelevinsky [BZ].
We will be concerned with three instances of the
following
situation:A is a group and B and C are
"disjoint" commuting subgroups
ofA,
so thatB x C is imbedded in A. D is an extension of B x C
by
anormal,
abelian factor N such thatA/D is
compact.For a group
G,
letRep
G be the category ofunitary representations
ofG,
andthen we define a bifunctor " x " from
Rep
B xRep
C toRep
A as follows.For ni E
Rep
B and n2 ERep C,
we shall denoteby
ni x n2 therepresentation
of A obtained
by extending
03C01 Q9 n2 from B x C to D(trivially
onN)
and thenunitarily inducing
from D to A.The three cases are
Here
by Gn, Pn
andMm n
we mean the groupsGL(n, F), Pn(F)
andMmxn(lF) -
theadditive group of m x n matrixes with entries in
F,
where F is some fixed local field.We will also consider the
following
functors:(a)
E:Rep Gn _
1 ~Rep Pn
is the trivial extension functor.(b)
I :Rep Pn-1
~Rep Pn
is the"Mackey
induction" functor.(c)
R :Rep Gn ~ Rep Pn
is the restriction functor.The above functors enter into the definition of "adduction" . The
following
lemma shows how
they
"distribute" over the " x -functors".LEMMA 2.1.
If 03C1 ~ Rep Gr, 03C3 ~ Rep Gs, 03C4 ~ Rep Pt, ’
thenThe rest of the section is devoted to the
proof
of this Lemma. The ideas areclosely
related to[BZ]
anddepend
on classical results ofMackey.
Proof.
Now on G =
Gr+s,
there are twoQ,
P double cosets viz. 1 =Q.l.P
and w =QwP
where w is the matrix of the
cyclic permutation (r,
r + s, r + s -1,...,
r -1).
Since 1 has
strictly
smaller dimension thanG,
w is theonly
double coset withnonzero Haar measure.
So
by Mackey’s subgroup
Theorem([Wr; 5.3.4.1])
Parts
(ii), (iii), (iv)
areapplications
ofunitary
inductionby
stages. We shall beconsidering
varioussubgroups
ofGn
andPn
and theirrepresentations.
It isconvenient to
adopt
thefollowing
convention:A
diagram
such asmeans a
representation
of thesubgroup
of Pr+t+1 which
is p on1 on
etc.
(ii)
Consider thefollowing diagram
ofsubgroups
ofPr+t+1
and their represen- tations.Starting
from the indicatedrepresentation at the bottom,
the induced represen- tation at the top(- - -)
may becomputed
via the left andright paths (shown
by ~).
The two methodsyield I( p
xr)
and p x Irrespectively.
(iii)
Consider thefollowing diagram of subgroups of Pr + and
their represen- tationsThe arrows marked "E"
correspond
to the functor of trivial extension to the last column. The other two arrowscorrespond
tounitary
induction and from the definition of induction thediagram obviously
commutes. The left andright paths yield E( p
xi)
and p x ETrespectively.
(iv)
Theproof
of thisidentity
is a littlelong
butquite straightforward.
(a)
Therepresentation
Ir x Q is obtainedby
induction in thefollowing diagram
Let us write S for the group on the left
and y
for the indicatedrepresentation.
Consider also the group R
and let 03B4 =
IndRS(03BC).
Then, appealing
to inductionby
stages, we have(b)
On the otherhand,
therepresentation I(03C4
x03C3)
is obtainedby
induction inthe
diagram
shown below.Where x
is the character of the normalsubgroup
N ~ IFt+scorresponding
to thelast column
given by ~(t(x1,..., Xt+s))
=e(Xt+s).
Let us write
So
for the group on the left and po for the indicated representa-tion,
thenNow,
the groupSo
is not asubgroup
of R.However,
let w be the matrix of thecyclic permutation (t, t
+1,..., t
+s) ;
and writeS 1
=w·S0
and ,u 1 = w·03BC0 for theconjugates
ofSo
and poby
w. ThenS1 is
asubgroup
ofR and, clearly,
This
identity corresponds
to induction in thefollowing diagram
Where x 1 = w·~0 so that
~1(t(x1,...,xs+t))
=e(xt).
Let us
write 03B41
=IndRS1(03BC1).
Then it suffices to prove that 03B4and 03B4
1 areequivalent representations
of R.(c)
LetYf(f
and03C4
be therepresentation
spaces of J and T and write Jf for the Hilbert space tensorproduct
ofYf(f
andA,.
Our method ofproof
is togive explicit
realizations of 03B4 and03B41
on the spaceL2(Ft+s; )
and show that thedesired
equivalence
isimplemented by
apartial
Fourier transform.(d)
Note first that thegroup R
is a semidirectproduct Q t>
N where N = Fs+tand
Q
is a maximalparabolic subgroup
ofGt+s.
R acts on N
by conjugation
and so also on itsunitary
dual V. V isagain isomorphic
to Ft+s and under the actionof R,
there is aunique
orbit (D which is open, dense and of fullLebesgue
measure. Furthermore x 1belongs
to (9 andStabR(~1)
=Sl’
so 03B41
may be realizedexplicitly
onL2(O; ) ~ L2(V; ).
Carrying
out the necessarycomputations,
one obtains thefollowing
ex-pressions.
Suppose
rand
write
Let p
EPt
beuniquely
determinedby solving
Finally, let q = |det ql
if F = Rand q = I det ql2
if F = C. Then(e)
LetNp Ns
be thesubgroups
of Ncorresponding
to the top t and lowers entries in the last column.
Write V, and V
for theunitary
dualsof Nt
andNs.
Then therepresentation
17:is realized on the space
L2(Vt; 03C4).
Let T be the
following subgroup
of R:Then the natural
projection
from R to T is ahomomorphism.
.
Now T acts
transitively
onNs by left multiplication
and we may lift this action to R. Let 0 denote theidentity
element ofN,,
then it iseasily
checked thatso b may be realized on the space:
Again,
after somecomputation,
one obtains thefollowing explicit description.
Let r, q, n, p be as
before,
and letWrite
Then,
for~ ~ L2(Vt
CNs; ).
(f)
Nowcorresponding
to thedecomposition
N =N,
~N,,
we have the dualdecomposition V = V,
~Vs.
Define
by
We shall now show that F
intertwines 03B4 and 03B41.
Now
using
the formula for03B41(r)
from(d)
andwriting
v =(03BC, 03B6), n
=[m],
theintegrand
above becomesso
with
Substituting 03B6’
= pw +Ch,
this becomesSubstituting
in(t),
andnoting that |det q| = 1 det g 11 det h we
have(v)
Consider thefollowing diagram
The
representation
obtainedby
inductionalong
the extreme left arrow isI(03C1
xRa)
andinvoking
inductionby
stages we see thatSimilarly Ep
x J is obtained via the extremeright
arrow and we see thatSo to
complete
theproof,
it suffices to prove thefollowing
claim:CLAIM. If 03C3 is a
unitary representation
ofGs,
thenProof.
WritePs+1
=Gs Ns
withNs ~ Fs.
ThenIndPs+1Gs(03C3)
can be realizedon
L’(N,; Jeu)
with the action:On the other
hand,
let V be the dual group ofN,,,
thenI(R03C3)
is realizable onL2(V; 03C3)
with thefollowing
action:For 03BE = (03BE1,..., çs) in V,
let v =v(03BE)
denote the s x s matrixFor
g ~ Gs
let03BE’ = 03BEg
and v’ =v(03BE’).
Then v’ is invertible if03BE’s ~
0(i.e.
foralmost all
ç),
and ifthen p
is an element ofP,.
With the above notation yi =
I(R6)
isgiven by:
Let F :
L2(Ns; 03C3) ~ L2(V; 03C3)
be the(inverse)
Fourier transformgiven by
Then
After the substitution z
= g-1(y - x),
this becomesNow let T :
L2(V; 03C3) ~ L2(V; 03C3)
be the(unitary) "multiplication"
operatorwhere v =
v(03BE)
as in(2).
ThenThis shows that ToF is a
(unitary) intertwining
operator for y and y,.Q.E.D.
Here is the crucial
THEOREM 2.1.
If p
and Q are adduciblerepresentations of GL(r, F)
andGL(s, F)
of depths
k andt,
then p x u is adducibleof depth
k +t,
andProof By assumption, R03C1 ~ Ik-1E(A03C1)
and R03C3 ~I~-1(A03C3).
Nowby
Lemma 2.1(i)
Section 3.
In this section we examine some consequences of Theorem 2.1. As a first step, we need to prove
adducibility
for somerepresentations
which serve asbuilding
blocks.
LEMMA 3.1.
(i) If x
is aunitary
characterof GL(n, F),
then n is adducibleof depth
1 andA03C0 =
03C0|GL(n - 1, F)
whereGL(n - 1, F)
is imbedded in the topleft
cornerof GL(n, F).
(ii) If
n is a discrete seriesrepresentation of GL(2, R),
then n is adducibleof depth
2 and An is the trivialrepresentation of
the trivial group.Proof. (i)
This is trivial.(ii)
This result iswell-known,
but for the sake ofcompleteness
we include thefollowing
sketch which uses some pretty ideas from classicalcomplex analysis.
Recall
[L]
that the discrete series{03B4m}
ofGL(2, R)
isparametrized (up
to theaction of the
center) by
thepositive integers m 2,
and therepresentation ô.
may beexplicitly
realized as follows.Let X =
CBR
be thecomplex plane
minus the real axis. LetThen the
Dm(X)
are therepresentation
spaces for the discrete series representa- tionô.
andH2(X)
is the usualHardy
space(on
which the limit of discrete series may berealized).
Now it is a consequence of the
Payley-Wiener
theorem that1 dt is an
isometry
up to a constant; and it is an easy matterto show that
is also an
isometry
up to a constant.Finally,
let F be the Fourier transform fromL2(R) ~ L2(R),
and letT.
be the operatorSmoF-1 : L2(R) ~ Dm(X).
ThenT.
is anisometry
up to a constant and it iscompletely straightforward
to check thatThese formulas show that
(T-1mo03B4mo Tm) ~ IE(10)
where10
is the trivial repre-sentation of the trivial group
Go. Q.E.D.
Before
continuing,
let us note thefollowing
immediatecorollary,
part of which is well known and may beproved by
other methods.(See [W],
for(i)
and(ii)
forGL(n, C)
and[KS]
forGL(n, R)).
THEOREM 3.1.
(i) Every
irreducibletempered representation of GL(n, C)
orGL(n, R)
isfully induced from a
relative discrete seriesrepresentation of
some Levisubgroup.
(ii) If 03C31,...,03C3k
are irreducible andtempered so is
03C31 ··· x 6k.(iii) Every tempered representation of GL(n, C)
andGL(n, R)
is adducibleof (maximal) depth
n, so that the adducedrepresentation
is the trivialrepresentation of
the trivial group.Proof.
Let a be atempered representation
.ofGL(n, C)
orGL(n, R). Then, by
a well known result of
Harish-Chandra,
there is acuspidal parabolic subgroup
M N and a relative discrete series
representation ô
of M such that 6 is a sub-representation
ofIndGMN(03B4
01).
In the case of
GL(n, C),
M isnecessarily
of the formGL(1, C)
x ... xGL(1, C)
and ô = x
~ ···
Q9 nn where 03C0i areunitary
characters. ForGL(n, R),
M has to beof the form
where the
ni’s
areunitary
characters for theGL(1, Rl’s
and discrete seriesrepresentations
for theGL(2, Rl’s.
So
IndGM·N(03B4) =
ni x ... x n, where each ni is either a character ofG,
ora discrete series
representation. Now, by
Lemma 3.2 all theni’s
are adducible andAn
is the trivialrepresentation
of the trivial group in each case.So, by
Theorem2.1, n,
1 ··· x nk is adducible andtrivial
representation
of the trivial group.This shows first of all that 03C01 x ... x
03C0k)|Pn
= In1 E 1 and
is thereforeirreducible;
secondsince, by assumption 03C3
is containedin ni
1 x ... x 03C0k, o- mustactually
beequal
to 03C01 x ... x 03C0k. This proves(i)
and(iii).
To prove(ii)
we notethat we can first write
each 03C3i
as ni, x ... x 03C0in where 03C0ij is either aunitary
character of
G,
or a discrete seriesrepresentation.
So ul ··· x Uk = 03C011 x 03C012 x ... x 03C0kn which is irreducibleby
the argument as before.Q.E.D.
We now continue with the main argument.
LEMMA 3.2. For s E
(0, 2),
leta 2m(j, s)
the Steincomplementary
series representa- tion with parameter s.(See [V], [Ge], [St]) of GL(2m, F)
with F = R or C. Then03C32m(j, s)|p is
irreducible.Proof.
As remarked in[V],
it suffices to treat the case ofQ2m(s) = a 2m(1, s).
LetQ
be theparabolic subgroup
ofGL2m.
It followsby [St]
that03C32j(S)|Q
are allequivalent,
irreducible andisomorphic
to theunitarily
induceddegenerate principal
seriesrepresentation ( 1 m
x1m)|Q
where1 m
is the trivialrepresentation of GLm.
Let S ~ P ~
Q
be the"strip"
groupThen,
it isclearly enough
to show that( 1 m
x1m)|S is
irreducible. This isimplicit
in
[St,
p.479]
and we sketch the necessary extension of his argument.First of
all,
therepresentation ( 1 m
x1n)|S
may beexplicitly
realized onL2(Mm; C)
with the actionwhere
g-1 = (ô b1) ~
S.Let T be an
intertwining
operator for( 1 m
x1m)|S.
Since T commutes withtranslations,
its Fourier transform is the operator ofmultiplication by
a boundedmeasurable function
03BC(x). Further,
since T commutes with the action of[],
itfollows
that 03BC(a·x) = 03BC(x)
almosteverywhere.
But under the actionof GLm
thereis an orbit of full measure in
Mm. So J.1
must be constant on thisorbit,
henceT must be a scalar. This proves the
irreducibility
of1.
x1m|S
and thelemma.
Q.E.D.
We are now
ready
to prove Kirillov’sconjecture
for C. For this we shall use thefollowing
result ofVogan.
FACT 3.1
[V]. Every
irreducibleunitary representation
ofGLn(C)
is thex
-product
ofunitary
characters and Steinrepresentations.
THEOREM 3.2.
(i) If
n is an irreducibleunitary representation ofGL(n, C)
thenni P is
irreducible.(ii) If
03C0i are irreducibleunitary representations of GL(ni, C)
and n =Eni
thenXi03C0i
is an irreducible
unitary representation of GL(n, C).
Proof.
We shall prove(i)
and(ii) simultaneously by
induction on n.For n = 0 or 1 the results are
trivially
true. Let us assume it for n m and let03C0 be an irreducible
unitary representation of GL(n
+1, C). Then,
if n is aunitary
character or Stein
complementary
seriesrepresentation, (i)
isimplied by
Lemmas3.1 and 3.2. If not then
by
Fact3.1,
we can write n = 03C01 x n2 with ni irreducibleunitary representations of GL(n; C)
andeach ni
m.By
the inductivehypothesis,
each
03C0i|P
is irreducible. Soby
Theorem 2.1nlP
ishomogeneous
andwhere
An,
are irreduciblerepresentations
ofGL(mi, C) with mi
= ni -depth(ni)
ni. Thus m, + m2 ni + n2 = m + 1.Again, by
the inductivehypothesis,
An =A03C01
xArc2
is irreducible. Thisimplies
thatn 1 P
isirreducible, establishing (i)
for n = m + 1. Infact,
the argumentjust given
also proves(ii). Q.E.D.
In
conclusion,
some remarks are in order.First, Vogan [V]
has shown that every irreducibleunitary representation
ofGL(n, R)
is a x-product
of thefollowing:
(i) Unitary
characters(ii)
Steinrepresentation (iii) Speh representations
(iv) Speh complementary
seriesrepresentations.
Our
approach
shows that in order to proveConjectures
1.1 and 1.2 for Il itsuffices to establish Kirillov’s
conjecture
forrepresentations
of types(iii)
and(iv).
Secondly,
the notion of N-rank of aunitary representation of GL(n, F)
has beenconsidered in
[H]
and[Sc],
and its connection with rates ofdecay
of matrixcoefficients has been established in
[Sc].
In theexisting definition,
the rank ofa
representation
is at most[n/2].
This isunsatisfactory
since adisproportionately large
number ofrepresentations
ofGL(n, F)
turn out to have rank[n/2].
In thisconnection it seems that the
following
alternative definition has some merit:DEFINITION 3.1. A
representation 03C0 ~ GL(n, C)
has rank n - k if k is the smallest value of the index i such atAi03C0
is the trivialrepresentation
of the trivial group.Using
results from[Sc]
it is not too hard to show that this definition agrees with the earlier definition for rank[n/2]
and further differentiates amongrepresentations
ofrank[n/2]. Also,
Theorem 3.1implies
thattempered representations
have rank n - 1.Once Kirillov’s
conjecture
isproved
forR,
one can use the same definition forGL(n, R).
Finally,
M. Tadic[Tl]
has shown that the fullunitary
dual ofGL(n, R)
andGL(n, C)
may be deduced from an apriori knowledge
of Kirillov’sconjecture (more specifically
fromConjecture 1.2).
It seemspossible
that onemight
be ableto
give
an inductive argument thatsimultaneously
establishes both Kirillov’sconjecture
and the classification.Added in
proof:
It is shown in[S]
thatAu 2m(j, s)
= 62m -2 (j, s)
for all m 1.Taken
together
with Theorem 2.1 and Fact3.1,
this enables one toexplicitly
compute An for all irreducible
unitary representations
ofGL(n, C).
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