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SOME SUBCLASSES OF MULTIVALENT ANALYTIC FUNCTIONS INVOLVING

A GENERALIZED DIFFERENTIAL OPERATOR

C. SELVARAJ and K.A. SELVAKUMARAN

By using a generalized differential operator, defined by means of the Hadamard product, we introduce some new subclasses of multivalent analytic functions in the open unit disk and investigate their inclusion relationships. Some integral preserving properties of these subclasses are also discussed.

AMS 2010 Subject Classification: 30C45.

Key words: analytic functions, Hadamard product, subordination, close-to-convex with respect tok-symmetric points, quasi-convex with respect tok- symmetric points.

1. INTRODUCTION AND PRELIMINARIES LetAp denote the class of functionsf(z) of the form

(1) f(z) =zp+ n=1

anzp+n, p∈N={1,2,3, . . .},

which are analytic in the open unit disk U={z∈C:|z|<1}. For functions f given by (1) andg given by

g(z) =zp+ n=1

bnzp+n,

the Hadamard product (or convolution) of f and g is defined by (f ∗g)(z) =zp+

n=1

anbnzp+n.

Letf(z) andg(z) be analytic in U. Then we say that the functionf(z) is subordinate tog(z) inU, if there exists an analytic functionw(z) inUwith

w(0) = 0, |w(z)|<1, z∈U,

REV. ROUMAINE MATH. PURES APPL., 56(2011),1, 43–55

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such that

f(z) =g(w(z)), z∈U.

We denote this subordination byf(z)≺g(z).Furthermore, if the functiong(z) is univalent in U, thenf(z)≺g(z),z∈U⇔f(0) =g(0) andf(U)⊂g(U).

Let P denote the class of analytic functions h(z) with h(0) = 1, which are convex univalent in U and for whichR{h(z)}>0,z∈U.

Letα1, α2, . . . , αqandβ1, β2, . . . , βs(q, sN∪{0},q ≤s+1) be complex numbers such that βk = 0,1,2, . . . for k ∈ {1,2, . . . , s}. The generalized hypergeometric function qFs is given by

qFs1, α2, . . . , αq;β1, β2, . . . , βs;z) =

n=0

1)n2)n. . .q)n1)n2)n. . .s)n

zn

n!, z∈D, where (x)n denotes the Pochhammer symbol defined by

(x)n=x(x+ 1)(x+ 2)· · ·(x+n−1) forn∈Nand (x)0 = 1.

Corresponding to a functionGq,sp (α1;β1;z) defined by

(2) Gq,sp (α11;z) :=zpqFs1, α2, . . . , αq;β1, β2, . . . , βs;z),

where α1 = (α1, α2, . . . , αq) and β1 = (β1, β2, . . . , βs), C. Selvaraj and K.R.

Karthikeyan [11] recently defined the following generalized differential operator Dp,mλ1, β1)f :Ap→ Ap by

Dp,0λ1, β1)f(z) =f(z)∗ Gq,sp (α11;z), Dp,1λ1, β1)f(z) = (1−λ)(f(z)∗ Gq,sp (α11;z)) + λ

pz(f(z)∗ Gq,sp (α11;z)), Dp,mλ1, β1)f(z) =Dp,1λ (Dλp,m−11, β1)f(z)),

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where m∈N0 =N∪ {0} and λ≥0.

Iff(z)∈ Ap, then we have (4) Dλp,m1, β1)f(z) =zp+

n=1

p+λn p

m1)n2)n. . .q)n

1)n2)n. . .s)n ap+nzp+n n! . It can be seen that, by specializing the parameters the operator Dp,mλ1, β1) reduces to many known and new integral and differential operators. In par- ticular, when m= 0 and p= 1 the operator Dλp,m1, β1) reduces to the well known Dziok-Srivastava operator [3] and for p= 1,q = 2,s= 1, α1 =β1 and α2 = 1, it reduces to the operator introduced by F. Al-Oboudi [1]. Further we remark that, whenp= 1,q = 2,s= 1,α1 =β1,α2= 1 andλ= 1 the operator Dp,mλ1, β1) reduces to the operator introduced by G.S. S˘al˘agean [10].

It can be easily verified from (4) that

(5) λz(Dλp,m1, β1)f(z)) =pDp,m+1λ1, β1)f(z)−p(1−λ)Dp,mλ1, β1)f(z)

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and

(6) z(Dp,mλ1, β1)f(z)) =α1Dλp,m1+1, β1)f(z)1−p)Dp,mλ1, β1)f(z).

Throughout this paper, we assume that p, k∈N,εk= exp(2πik ) and (7) fλ,kp,m1, β1;z) = 1

k

k−1

j=0

ε−jpk (Dλp,m1, β1)f(εjkz)) =zp+· · · , f ∈ Ap. Clearly, for k= 1, we have

fλ,1p,m1, β1;z) =Dλp,m1, β1)f(z).

We now introduce the following subclasses of analytic functions.

Definition1.1. A functionf ∈ Apis said to be in the classSλ,kp,m1, β1;h), if it satisfies

(8) z(Dp,mλ1, β1)f(z))

pfλ,kp,m1, β1;z) ≺h(z), z∈U, where h∈ P and fλ,kp,m1, β1;z)= 0,z∈U.

Remark 1.1. If we letm= 0,thenSλ,kp,m1, β1;h) reduces to the function class Sp,kq,s1;h) introduced and investigated by Z.-G. Wang, Y.-P. Jiang and H.M. Srivastava [14].

Remark 1.2. If we let m = 0,q = 2, s= 1,α1 =a,α2 = 1 and β1 =c, then Sλ,kp,m1, β1;h) reduces to the function class Tp,k(a, c;h) introduced and investigated by N.-E. Xu and D.-G. Yang [15].

Remark 1.3. If we let m = 0,p = 1,q = 2, s= 1, α1 =β1 and α2 = 1, then Sλ,kp,m1, β1;h) reduces to the known subclass Ss(k)(φ) of close-to-convex functions with respect tok-symmetric points, introduced and studied recently by Z.-G. Wang, C.-Y. Gao and S.-M. Yuan [13].

Remark 1.4. Let h(z) = 1+z1−z and let q = 2, s= 1,α1 =β1 and α2 = 1.

Then Sλ,21,01, β1;h) =Ss. The classSs of functions starlike with respect to symmetric points has been studied by several authors (see [8], [9], [16]).

Definition1.2. A functionf ∈ Apis said to be in the classKp,mλ,k1, β1;h), if it satisfies

(9) z(Dp,mλ1, β1)f(z))

p gp,mλ,k1, β1;z) ≺h(z), z∈U,

for someg(z)∈ Sλ,kp,m1, β1;h), whereh∈ P andgp,mλ,k1, β1;z)= 0 is defined as in (7).

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Remark 1.5. If we let m = 0,p = 1,q = 2, s= 1, α1 =β1 and α2 = 1, then Kλ,kp,m1, β1;h) reduces to the known subclass Cs(k)(φ) of quasi-convex functions with respect tok-symmetric points, introduced and studied recently by Z.-G. Wang, C.-Y. Gao and S.-M. Yuan [13].

Definition 1.3. A function f ∈ Ap is said to be in the class QCp,mλ,k(δ;α1, β1;h), if it satisfies

(10) (1−δ)z(Dp,mλ1, β1)f(z))

p gp,mλ,k1, β1;z)z(Dλp,m1+1, β1)f(z))

p gλ,kp,m1+1, β1;z) ≺h(z), z∈U, for someδ,δ≥0 andg(z)∈Sλ,kp,m1, β1;h), whereh∈P andgλ,kp,m1, β1;z)= 0.

Remark 1.6. If we let m = 0,p = 1,q = 2, s= 1, α1 =β1 and α2 = 1, then QCp,mλ,k(δ;α1, β1;h) reduces to the known subclassQC(k)s (λ, φ) ofδ-quasi- convex functions with respect to k-symmetric points, introduced and studied recently by S.-M. Yuan and Z.-M. Liu [17]. Further if we set,

m= 0, p=k= 1, q= 2, s= 1, α1=β1, α2 = 1, δ= 1 and h(z) = 1 +z 1−z, thenQCp,mλ,k(δ;α1, β1;h) reduces to the familiar class of quasi-convex functions which was introduced and studied earlier by K.I. Noor [7].

We need the following lemmas to derive our results.

Lemma1.7 ([5]). Letβ andγ be complex numbers and leth(z)be analytic and convex univalent in U withR{βh(z) +γ}>0, z U. If q(z) is analytic in Uwith q(0) =h(0), then the subordination

q(z) + zq(z)

βq(z) +γ ≺h(z), z∈U implies that

q(z)≺h(z), z∈U.

Lemma1.8 ([6]). Let h(z) be analytic and convex univalent inU and let w(z) be analytic inU with R{w(z)} ≥0, z U. If q(z) is analytic in Uwith q(0) =h(0), then the subordination

q(z) +w(z)zq(z)≺h(z), z∈U implies that

q(z)≺h(z), z∈U. Lemma 1.9. Let f(z)∈ Sλ,kp,m1, β1;h). Then (11) z(fλ,kp,m1, β1;z))

pfλ,kp,m1, β1;z) ≺h(z), z∈U.

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Proof. Forf(z)∈ Ap, we have from (7) that fλ,kp,m1, β1;εjkz) = 1

k

k−1

n=0

ε−npk Dp,mλ1, β1)f(εn+jk z)

= εjpk k

k−1

n=0

ε−(n+j)pk Dp,mλ1, β1)f(εn+jk z)

=εjpk fλ,kp,m1, β1;z), j∈ {0,1, . . . , k1} and

(fλ,kp,m1, β1;z)) = 1 k

k−1

j=0

εj(1−p)k (Dλp,m1, β1)f(εjkz)). Hence

z(fλ,kp,m1, β1;z)) pfλ,kp,m1, β1;z) = 1

k

k−1

j=0

εj(1−p)k z(Dp,mλ1, β1)f(εjkz)) pfλ,kp,m1, β1;z) (12)

= 1 k

k−1

j=0

εjkz(Dλp,m1, β1)f(εjkz))

pfλ,kp,m1, β1;z) , z∈U. Since f(z)∈ Sλ,kp,m1, β1;h), we have

(13) εjkz(Dp,mλ1, β1)f(εjkz))

pfλ,kp,m1, β1;εjkz) ≺h(z), forj ∈ {0,1, . . . , k1}.

Noting that h(z) is convex univalent in U, from (12) and (13) we conclude that (11) holds true.

2. A SET OF INCLUSION RELATIONSHIPS Theorem 2.1. Let h(z)∈ P with

(14) R{h(z)}>max

1 1

λ,1−α1 p

, z∈U, λ >1.

Then

Sλ,kp,m+11+ 1, β1;h)⊂ Sλ,kp,m1+ 1, β1;h)⊂ Sλ,kp,m1, β1;h).

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Proof. From (5) and (7), we have (1−λ)fλ,kp,m1, β1;z) +λz

p (fλ,kp,m1, β1;z))= (15)

= 1 k

k−1 j=0

ε−jpk (Dλp,m+11, β1)f(εjkz)) =fλ,kp,m+11, β1;z).

Let f(z)∈ Sλ,kp,m+11+ 1, β1;h) and

(16) w(z) = z(fλ,kp,m1+ 1, β1;z)) pfλ,kp,m1+ 1, β1;z) .

Then w(z) is analytic inU, withw(0) = 1 and from (15) (withα1 replaced by α1+ 1) and (16) we have

(17) 1−λ+λw(z) = fλ,kp,m+11+ 1, β1;z) fλ,kp,m1+ 1, β1;z) . Differentiating (17) with respect to z and using (16), we get

(18) w(z) + zw(z)

λp(1−λ) +pw(z) = z(fλ,kp,m+11+ 1, β1;z)) p fλ,kp,m+11+ 1, β1;z) . From (18) and Lemma 1.9 (with α1 replaced by α1+ 1) we note that

(19) w(z) + zw(z)

λp(1−λ) +pw(z) ≺h(z), z∈U. In view of (14) and (19), we deduce from Lemma 1.7 that

(20) w(z)≺h(z), z∈U.

Suppose that

q(z) = z(Dλp,m1+ 1, β1)f(z)) pfλ,kp,m1+ 1, β1;z) .

Then q(z) is analytic in U, with q(0) = 1 and we obtain from (5) (with α1 replaced by α1+ 1) that

(21)

fλ,kp,m1+1, β1;z)q(z) = 1

λDλm+11+1, β1)f(z)+

11

λ

Dλp,m1+1, β1)f(z).

Differentiating both sides of (21) with respect to z, we get (22)

zq(z)+

p1

λ−1 +z(fλ,kp,m1+1, β1;z)) fλ,kp,m1+1, β1;z)

q(z) = z(Dλp,m+11+1, β1)f(z)) λfλ,kp,m1, β1;z) .

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Since f(z) ∈ Sλ,kp,m+11 + 1, β1;h), we find from (15) (with α1 replaced by α1+ 1), (16) and (22) that

(23) q(z) + zq(z)

pλ(1−λ) +pw(z) = z(Dλp,m+11+ 1, β1)f(z))

pfλ,kp,m+11+ 1, β1;z) ≺h(z), z∈U. From (14) and (20) we observe that

Rp

λ(1−λ) +pw(z)

>0.

Therefore, from (23) and Lemma 1.8 we conclude that q(z)≺h(z), z∈U which shows that f(z)∈ Sλ,kp,m1+ 1, β1;h).

To prove the second inclusion relationship, we now letf(z)∈ Sλ,kp,m1+ 1, β1;h) and set

s(z) = z(Dλp,m1, β1)f(z)) pfλ,kp,m1, β1;z) .

Then, by using a similar argument as detailed above, it follows from (6) and Lemma 1.8 that

s(z)≺h(z), z∈U. This implies that f(z)∈ Sλ,kp,m1, β1;h).

Theorem 2.2. Let h(z)∈ P with (24) R{h(z)}>max

11

λ,1−α1 p

, z∈U, λ >1.

Then

(25) Kp,m+1λ,k1+ 1, β1;h)⊂ Kp,mλ,k1+ 1, β1;h)⊂ Kp,mλ,k1, β1;h).

Proof. We only prove the first inclusion relationship in (25), since the other inclusion relationship can be justified using similar arguments.

Let f(z) ∈ Kp,m+1λ,k1 + 1, β1;h). Then there exists a function g(z) Sλ,kp,m+11+ 1, β1;h) such that

(26) z(Dp,m+1λ1+ 1, β1))

p gp,m+1λ,k1+ 1, β1;z) ≺h(z), z∈U.

An application of Theorem 2.1 yieldsg(z)∈ Sλ,kp,m1+1, β1;h) and Lemma 1.9 leads to

(27) ψ(z) = z(gλ,kp,m1+ 1, β1;z))

p gp,mλ,k1+ 1, β1;z) ≺h(z), z∈U.

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Let

φ(z) = z(Dp,mλ1+ 1, β1)f(z)) p gλ,kp,m1+ 1, β1;z) .

By using (5) (with α1 replaced byα1+ 1), q(z) can be written as follows gp,mλ,k1+ 1, β1;z)φ(z) = 1

λDλp,m+11+ 1, β1)f(z)+

(28)

+

11 λ

Dλp,m1+ 1, β1)f(z).

Differentiating both sides of (28) with respect to z and using (15) (with f replaced by g andα1 replaced by α1+ 1), we get

(29) φ(z) + (z)

λp(1−λ) +pψ(z) = z(Dp,m+1λ1+ 1, β1f(z)) p gp,m+1λ,k1+ 1, β1;z) . Now, from (26) and (29) we find that

(30) φ(z) + (z)

pλ(1−λ) +pψ(z) ≺h(z), z∈U. Combining (24), (27) and (30), we deduce from Lemma 1.8 that

φ(z)≺h(z), z∈U

which shows that f(z)∈ Kλ,kp,m1+ 1, β1;h) with respect to g(z)∈ Sλ,kp,m1+ 1, β1;h)).

Theorem 2.3. Let h(z)∈ P with R{h(z)}>{1αp1}, z∈U. Then QCp,mλ,k2;α1, β1;h)⊂ QCp,mλ,k1;α1, β1;h), 0≤δ1< δ2. Proof. From (6) and (7), we have

1−p)fλ,kp,m1, β1;z) +z(fλ,kp,m1, β1;z)) = (31)

=α1 1 k

k−1

j=0

ε−jpk (Dp,mλ1+ 1, β1)f(εjkz)) =α1fλ,kp,m1+ 1, β1;z).

Let f(z)∈ QCp,mλ,k2;α1, β1;h). Then there exists a functiong(z) in the class Sλ,kp,m1, β1;h) such that

(32) (1−δ2)z(Dλp,m1, β1)f(z))

p gλ,kp,m1, β1;z)2z(Dλp,m1+1, β1)f(z))

p gp,mλ,k1+1, β1;z) ≺h(z), z∈U. Furthermore, it follows from Lemma 1.9 that

(33) ν(z) = z(gλ,kp,m1, β1;z))

p gp,mλ,k1, β1;z) ≺h(z), z∈U.

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We now set

(34) ϕ(z) = z(Dp,mλ1, β1)f(z)) p gp,mλ,k1, β1;z) .

Thenϕ(z) is analytic inU, withϕ(0) = 1. By using (6),q(z) can be written as gp,mλ,k1, β1;z)ϕ(z) = α1

p Dp,mλ1+ 1, β1)f(z) (35)

1−α1 p

Dp,mλ1, β1)f(z).

Differentiating both sides of (35) with respect to z and using (31) (with f replaced by g), we find

(36) ϕ(z) + (z)

α1−p+pψ(z) = z(Dp,mλ1+ 1, β1f(z)) p gp,mλ,k1+ 1, β1;z) . Equivalently,

ϕ(z) + δ2(z)

α1−p+pψ(z) = (1−δ2)z(Dλp,m1, β1)f(z)) p gλ,kp,m1, β1;z) + (37)

+δ2z(Dp,mλ1, β1)f(z))

p gp,mλ,k1+ 1, β1;z) ≺h(z).

Since ν(z) ≺h(z) and δ1

2R{p h(z) +α1−p} >0, z∈ U, it follows from (37) and Lemma 1.8 thatϕ(z)≺h(z), z∈U.

Sinceh(z) is convex univalent inUand 0 δδ12 <1, we deduce from (32) and (34) that

(1−δ1)z(Dλp,m1, β1)f(z))

p gλ,kp,m1, β1;z) +δ1z(Dp,mλ1+ 1, β1)f(z)) p gλ,kp,m1+ 1, β1;z) =

= δ1 δ2

(1−δ2)z(Dp,mλ1, β1)f(z))

p gλ,kp,m1, β1;z) +δ2z(Dp,mλ1+ 1, β1)f(z)) p gp,mλ,k1+ 1, β1;z)

+ +

1−δ1

δ2

ϕ(z)≺h(z).

Thusf(z)∈QCp,mλ,k1;α1, β1;h) which completes the proof of Theorem 2.3.

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3. INTEGRAL OPERATOR

In this section, we consider the generalized Bernardi–Libera–Livingston integral operator F(z) defined by (cf. [2] and [4])

(38) F(z) = c+p

zc z

0 tc−1f(t)dt, f ∈ Ap, c >−p.

It is easy to verify that, F(z)∈ Ap,p-valent (cf. [12]) and F(z) =

zp+

n=1

c+p c+p+nzp+n

∗f(z) (39)

=

zp+ n=1

c+p

c+p+nanzp+n

, f ∈ Ap, c >−p.

We first prove

Theorem 3.1. Let h(z)∈ P and R{h(z)}>max

0,R(c) p

, z∈U,

where c is a complex number such that R(c) >−p. If f(z) ∈ Sλ,kp,m1, β1;h), then the function F(z) defined by (38) is also in the classSλ,kp,m1, β1;h).

Proof. Letf(z)∈ Sλ,kp,m1, β1;h).Then from (38), (39) and R(c)>−p, we note that F(z)∈ Ap,p-valent and

(40) (c+p)Dp,mλ1, β1)f(z) =cDλp,mF(z) +z(Dp,mλ1, β1)F(z)). Also, from the above, we have

(c+p)fλ,kp,m1, β1;z) = (41)

= 1 k

k−1

j=0

ε−jpk

cDp,mλ1, β1)F(εjkz) +εjkz(Dp,mλ1, β1)F(εjkz))

=

=cFλ,kp,m1, β1;z) +z

Fλ,kp,m1, β1;z) . Let

ϑ(z) = z(Fλ,kp,m1, β1;z)) p Fλ,kp,m1, β1;z) .

Then ϑ(z) is analytic inU, withϑ(0) = 1 and from (41) we observe that (42) p ϑ(z) +c= (c+p)fλ,kp,m1, β1;z)

Fλ,kp,m1, β1;z).

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Differentiating both sides of (42) with respect to z and using Lemma 1.9, we obtain

(43) ϑ(z) + z ϑ(z)

p ϑ(z) +c = z(fλ,kp,m1, β1;z))

p fλ,kp,m1, β1;z) ≺h(z).

In view of (43), Lemma 1.7 leads to ϑ(z)≺h(z).

If we let

Φ(z) = z(Dp,mλ1, β1)F(z)) p Fλ,kp,m1, β1;z)

then Φ(z) is analytic in U, with Φ(0) = 1 and it follows from (40) that (44) Fλ,kp,m1, β1;z)Φ(z) = c+p

p Dλp,m1, β1)f(z) c

pDp,mλ1, β1)F(z).

Differentiating both sides of (44), we get

(z) +z(Fλ,kp,m1, β1;z))

Fλ,kp,m1, β1;z) Φ(z) =

= (c+p)z(Dp,mλ1, β1)f(z))

p Fλ,kp,m1, β1;z) −cz(Dλp,m1, β1)F(z)) p Fλ,kp,m1, β1;z) . Equivalently,

(45) (z) +

pϑ(z) +c

Φ(z) = (c+p)z(Dp,mλ1, β1)f(z)) p Fλ,kp,m1, β1;z) . Now, from (42) and (45) we deduce that

Φ(z) + (z)

pϑ(z) +c = c+p pϑ(z) +c

z(Dp,mλ1, β1)f(z)) p Fλ,kp,m1, β1;z) (46)

= z(Dp,mλ1, β1)f(z))

p fλ,kp,m1, β1;z) ≺h(z).

Combining, R{h(z)}>max

0,R(c)p

and ϑ(z) ≺h(z) we have R{p ϑ(z) + c}>0,z∈U.Therefore, from (46) and Lemma 1.8 we find that Φ(z)≺h(z), which shows that F(z)∈ Sλ,kp,m1, β1;h).

By applying similar method as in Theorem 3.1, we have Theorem 3.2. Let h(z)∈ P and

R{h(z)}>max

0,R(c) p

, z∈U, R(c)>−p.

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If f(z)∈ Kλ,kp,m1, β1;h) with respect to g(z)∈ Sλ,kp,m1, β1;h), then the func- tion

F(z) = c+p zc

z

0 tc−1f(t)dt belongs to the class Kp,mλ,k1, β1;h) with respect to

G(z) = c+p zc

z

0 tc−1g(t)dt, provided that Gp,mλ,k1, β1;z)= 0, z∈U.

Acknowledgement. The authors thank the referees for their valuable comments and helpful suggestions.

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Received 12 February 2009 Department of Mathematics

Presidency College(Autonomous) Chennai-600 005, India

pamc9439@yahoo.co.in selvaa1826@gmail.com

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