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Vector and scalar potentials, Poincaré’s theorem and

Korn’s inequality

Chérif Amrouche, Philippe G. Ciarlet, Patrick Ciarlet

To cite this version:

Chérif Amrouche, Philippe G. Ciarlet, Patrick Ciarlet. Vector and scalar potentials, Poincaré’s

theo-rem and Korn’s inequality. 2008. �hal-00297289�

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———-Vector and scalar potentials, Poincar´e’s theorem and Korn’s

inequality

Ch´

erif Amrouche

a

, Philippe G. Ciarlet

b

, Patrick Ciarlet, Jr.

c

a

Laboratoire de Math´ematiques Appliqu´ees, CNRS UMR 5142, Universit´e de Pau et des Pays de l’Adour, IPRA, Avenue de l’Universit´e, 64000 Pau, France

b

Department of Mathematics, City University of Hong Kong, 83, Tat Chee Avenue, Kowloon, Hong Kong

c

Laboratoire POEMS, UMR 2706 CNRS/ENSTA/INRIA, ´Ecole Nationale Sup´erieure de Techniques Avanc´ees, 32, Boulevard Victor, 75739 Paris Cedex 15, France

Received *****; accepted after revision +++++ Presented by Philippe G. Ciarlet

Abstract

In this Note, we present several results concerning vector potentials and scalar potentials in a bounded, not nec-essarily simply-connected, three-dimensional domain. In particular, we consider singular potentials corresponding to data in negative order Sobolev spaces. We also give some applications to Poincar´e’s theorem and to Korn’s inequality.

R´esum´e

Dans cette note, nous pr´esentons plusieurs r´esultats concernant les potentiels vecteurs et les potentiels scalaires dans des domaines born´es tridimensionnels, ´eventuellement multiplement connexes. En particulier, on consid`ere des potentiels singuliers correspondant `a des donn´ees dans des espaces de Sobolev d’exposant n´egatif. On donne ´

egalement des applications au th´eor`eme de Poincar´e et `a l’in´egalit´e de Korn.

1. Weak versions of a classical theorem of Poincar´e

In this work, we assume that Ω is a bounded open connected ofR3with a Lipschitz-continuous boundary.

The notationX0 <, >X denotes a duality pairing between a topological space X and its dual X0. The letter C denotes a constant that is not necessarily the same at its various occurrences.

Email addresses: cherif.amrouche@univ-pau.fr (Ch´erif Amrouche), mapgc@cityu.edu.hk (Philippe G. Ciarlet), patrick.ciarlet@ensta.fr (Patrick Ciarlet, Jr.).

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Theorem 1 Let f ∈ H−m(Ω)3 for some integer m ≥ 0. Then, the following assertions are equivalent: (i)H−m(Ω)< f , ϕ >Hm 0 (Ω) = 0 for any ϕ ∈ Vm= {ϕ ∈ H m 0 (Ω)3; div ϕ = 0}, (ii)H−m(Ω)< f , ϕ >Hm 0(Ω) = 0 for any ϕ ∈ V = {ϕ ∈ D(Ω) 3; div ϕ = 0},

(iii) There exists a distribution χ ∈ H−m+1(Ω), unique up to an additive constant, such that f = grad χ

in Ω.

If Ω is in addition simply-connected, then the three previous statements are equivalent to: (iv) curl f = 0 in Ω.

Proof. For the equivalence between (i), (ii) and (iii), we refer to [4]. The implication (iii) =⇒ (iv) clearly holds. It thus remains to prove that (iv) =⇒ (iii). To begin with, let f ∈ H−m(Ω)3be such that curl f = 0

in Ω. We then use the same argument as in [6]. We know that there exist a unique u ∈ Hm

0 (Ω)3 and a

unique p ∈ H−m+1(Ω)/R (see [3]) such that

∆mu + grad p = f and div u = 0 in Ω. (1)

Hence ∆mcurl u = 0 in Ω, so that the hypoellipticity of the polyharmonic operator ∆m implies that

curl u ∈ C∞(Ω)3. Since div u = 0, we deduce that ∆u = curl curl u ∈ C(Ω)3. This also implies that

∆mu belongs to C(Ω)3and is an irrotational vector field. By the classical Poincar´e lemma, there exists

q ∈ C∞(Ω)3 such that ∆mu = grad q. Thus, we see that f = grad (p + q) and thanks to [4] Proposition

2.10, the function p + q belongs to the space H−m+1(Ω). 

We can give another proof of this implication (iv) =⇒ (iii) by using the following theorem: Theorem 2 Assume that the sets Ω and R3\ Ω are simply-connected. Let u ∈ Hm

0 (Ω)3, m ≥ 0, be a

function that satisfies div u = 0 in Ω. Then there exists a vector potential ψ in H0m+1(Ω)3 such that

u = curl ψ, div ∆m+1ψ= 0 in Ω, (2)

and the following estimate holds:

kψkHm+1(Ω)3≤ Cku kHm(Ω)3. (3)

Proof. Let u ∈ Hm

0 (Ω)3 be such that div u = 0 in Ω and let eu denote the extension of u by 0 in

R3\ Ω. Thus eu ∈ Hm

0 (R3)3, div eu = 0 inR3, and there exist an open ball B containing Ω and a vector

field w ∈ H0m+1(B)3 such that eu = curl w in B, and

kw kHm+1(B)3≤ Cku kHm(B)3. The open set Ω0

:= B \ Ω is bounded, has a Lipschitz-continuous boundary and is simply-connected. Furthermore, the vector field w0

:= w |Ω0 belongs to Hm+1(Ω0)3 and satisfies curl w0= 0 in Ω0. Hence there exists a function χ0

∈ H1(Ω0 ) such that w0 = grad χ0 in Ω0 . Hence in fact χ0 ∈ Hm+2(Ω0 ) and the estimate kχ0 kHm+2(Ω0)≤ Ckw0kHm+1(Ω0)3 holds. Since the function χ0∈ Hm+2(Ω0

) can be extended to a function eχ in Hm+2(R3), with

k eχkHm+2(R3)≤ Ckχ0kHm+2(Ω0)≤ Ckw0kHm+1(Ω0)3,

the vector field eϕ := w − grad eχ belongs to the space Hm+1(B)3 and satisfies eϕ|

Ω0 = 0. Then the restriction ϕ := eϕ|Ω is in the space H0m+1(Ω)3, satisfies the estimate (3), and curl eϕ= curl w = eu in

B. Thus u = curl ϕ in Ω, with ϕ ∈ H0m+1(Ω)3. Let now p ∈ H0m+2(Ω) denote the unique solution of

∆m+2p = div ∆m+1ϕ, so that the estimate

kpkHm+2(Ω)≤ CkϕkHm+1(Ω)3

holds. Then the function ψ = ϕ − grad p satisfies (2)-(3). 

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We can now give another proof of the above implication (iv) =⇒ (iii): Consider again the solution u ∈ Hm

0 (Ω)3 of (1) and let v ∈ H0m+1(Ω)3 denote the vector potential of u as given by Theorem 2. We

then have ∆mcurl u = 0. If m = 2k, with k ≥ 1, then H−m−1(Ω)3 < ∆mcurl u , v > H0m+1(Ω) 3= H−1(Ω)3 < ∆kcurl u , ∆kv >H1 0(Ω) 3 = Z Ω ∆ku · ∆kcurl v dx = k∆kuk2L2(Ω)3. This implies that ∆ku = 0 in Ω and thus u = 0 since u ∈ Hm

0 (Ω)3. The case m = 2k + 1 follows by a

similar argument. 

2. Scalar Potentials

Let Γi, 0 ≤ i ≤ I, denote the connected components of the boundary Γ of the domain Ω, Γ0being the

boundary of the only unbounded connected component ofR3\ Ω. We do not assume that Ω is

simply-connected, but we suppose that there exist J simply-connected, oriented and open surfaces Σj, 1 ≤ j ≤ J, called

“cuts”, contained in Ω, such that each surface Σj is an open subset of a smooth manifold, the boundary

of Σjis contained in Γ for 1 ≤ j ≤ J, the intersection Σi∩ Σj is empty for i 6= j, and finally the open set

Ω◦

= Ω \SJj=1Σj is simply-connected and pseudo-Lipschitz (see [1]). Finally, let [·]j denote the jump of

a function over Σj, for 1 ≤ j ≤ J.

We then define the spaces

H(curl, Ω) = {v ∈ L2(Ω)3; curl v ∈ L2(Ω)3}, H(div, Ω) = {v ∈ L2(Ω)3; div v ∈ L2(Ω)}, which are provided with the graph norm, and their subspaces

H0(curl, Ω) = {v ∈ H(curl, Ω); v × n = 0 on Γ}, H0(div, Ω) = {v ∈ H(div, Ω); v · n = 0 on Γ}.

For any function q in H1(Ω), grad q is the gradient of q in the sense of distributions in D0(Ω). It

belongs to L2(Ω)3and therefore can be extended to L2(Ω)3. In order to distinguish this extension from

the gradient of q in D0(Ω), we denote it by ^grad q. We finally observe that the space

KT(Ω) := {w ∈ H(curl, Ω) ∩ H0(div, Ω); curl w = 0 and div w = 0 in Ω}

is of dimension equal to J. As shown in [1] Prop. 3.14, it is spanned by the functions ^grad qT

j, 1 ≤ j ≤ J,

where each qT

j ∈ H1(Ω◦) is unique up to an additive constant and satisfies ∆qTj = 0 in Ω◦, ∂nqTj = 0 on

Γ, [qT

j]k = δjk, [∂nqjT]k = 0 andH−1/2k)< ∂nqjT, 1 >H1/2

k)= δjk for 1 ≤ k ≤ J. Theorem 3 For any function f ∈ L2(Ω)3 that satisfies

curl f = 0 in Ω and Z

f · v dx = 0 for all v ∈ KT(Ω), (4)

there exists a scalar potential χ in H1(Ω) such that f = grad χ and the following estimate holds:

kχkH1(Ω)≤ Ckf kL2(Ω)3. (5)

Proof. It suffices to show that, given any v ∈ H0(div, Ω) such that div v = 0 in Ω, there holds

(f , v )L2(Ω)3 = 0. For such v ∈ H0(div, Ω), let z = PJ

j=1 H−1/2(Σj) < v · n , 1 >H1/2(Σj) grad q^

T j

and w = v − z . According to [1], Theorem 3.17, there exists a vector potential ψ ∈ L2(Ω)3 satisfying

w = curl ψ, div ψ = 0 in Ω and ψ × n = 0 on Γ. Hence Z Ω f· v dx = Z Ω f · curl ψ dx = 0.

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The result is then a consequence of Theorem 1: there exists a function χ ∈ H1(Ω) satisfying f = grad χ

and the estimate (5) holds. 

Remark 4 Any function f ∈ L2(Ω)3 that satisfies curl f = 0 in Ω can be decomposed as:

f = grad χ + ^grad p, with χ ∈ H1(Ω) and grad p ∈ K^ T(Ω).

Such a result is alluded to in [7] (page 959) ; however it is not proven there.

The second condition in (4) is trivially satisfied when Ω is simply-connected since KT(Ω) = {0} in this

case.

Theorem 5 For any distribution f in the dual space of H0(div, Ω) that satisfies

curl f = 0 in Ω and H0(div,Ω)0 < f , v >H0(div,Ω)= 0 for all v ∈ KT(Ω), (6) there exists a scalar potential χ in L2(Ω) such that f = grad χ and the following estimate holds:

kχkL2(Ω)≤ Ckf kH

0(div,Ω)0. (7)

Proof. Let f be in the dual space of H0(div, Ω) with curl f = 0 in Ω. We know that there exists

ψ∈ L2(Ω)3 and χ

0∈ L2(Ω) such that f = ψ + grad χ0, with the estimate (see Proposition 1 of [5])

kψkL2(Ω)3+ kχ0kL2(Ω)≤ Ckf kH

0(div,Ω)0. Observe that, thanks to the density of D(Ω)3in H

0(div, Ω), we haveH0(div,Ω)0 < grad χ0, v >H0(div,Ω)= 0, for all v ∈ KT(Ω). Therefore, the function ψ ∈ L2(Ω)3 satisfies the conditions (4). By Theorem 3,

there exists a function p ∈ H1(Ω) such that ψ = grad p, with the estimate

kpkH1(Ω)≤ CkψkL2(Ω)3≤ Ckf kH

0(div,Ω)0.

Hence, the function χ = p + χ0 satisfies the announced properties. 

More generally, for any integer m ≥ 1, let us introduce the space

H0m(div, Ω) = {v ∈ H0(div, Ω); divv ∈ H0m(Ω)}.

We can prove that D(Ω)3 is dense in Hm

0 (div, Ω). Moreover, we can characterize its dual space, denoted

by H−m(div, Ω):

H−m(div, Ω) = {ψ + grad χ; ψ ∈ H0(div, Ω)0, χ ∈ H−m(Ω)}.

As a consequence of Theorem 5, it is easy to prove that, for any distribution f ∈ H−m(div, Ω) that

satisfies (6), there exists a scalar potential χ in H−m(Ω) such that f = grad χ. We thus obtain an

extension of part (iv) in Theorem 1 in the case where Ω is multiply-connected.

3. ”Weak” vector potentials

First, we note that the continuous embeddings H0(curl, Ω)0 ,→ H−1(Ω)3 and H0(div, Ω)0 ,→ H−1(Ω)3

hold. Besides, for any f ∈ H−1(Ω)3, we know that there exist a unique u ∈ H1

0(Ω)3 such that div u = 0

in Ω, and χ ∈ L2(Ω) such that f = ∆u + grad χ and the estimate

ku kH1(Ω)3+ kχkL2(Ω)/R≤ Ckf kH−1(Ω)3

holds. Letting ξ = curl u , we obtain f = curl ξ + grad χ. Since ξ ∈ L2(Ω)3 and χ ∈ L2(Ω), it follows

that curl ξ ∈ H0(curl, Ω)0 and grad χ ∈ H0(div, Ω)0. Therefore

H−1(Ω)3= H0(curl, Ω)0+ H0(div, Ω)0.

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Here, we consider the other kernel

KN(Ω) = {w ∈ H0(curl, Ω) ∩ H(div, Ω); curl w = 0 and div w = 0 in Ω}

which is of dimension equal to I. It is spanned (see Proposition 3.18 of [1] for a proof) by the functions grad qN

i , 1 ≤ i ≤ N , where each qiN ∈ H1(Ω) is the unique solution to the problem ∆qiN = 0 in Ω, qiN = 0

on Γ0,H−1/2(Γ0)< ∂nq N i , 1 >H1/2 0)= −1, and q N i = const on Γk,H−1/2(Γk)< ∂nq N i , 1 >H1/2 k)= δik, for 1 ≤ k ≤ I.

Theorem 6 For any distribution f in the dual space H0(curl, Ω)0 that satisfies

div f = 0 in Ω and H0(curl,Ω)0 < f , v >H0(curl,Ω)= 0 for all v ∈ KN(Ω), (8) there exists a vector potential ξ in L2(Ω)3 such that

f = curl ξ, with div ξ = 0 in Ω and ξ· n = 0 on Γ, (9)

and such that the following estimate holds:

kξkL2(Ω)3 ≤ Ckf kH

0(curl,Ω)0. (10)

Proof. Let f be in the dual space H0(curl, Ω)0. According to Corollary 5 of [5], there exist ψ ∈ L2(Ω)3

and ξ0∈ L2(Ω)3 with div ξ0= 0 in Ω and ξ0· n = 0 on Γ, such that f = ψ + curl ξ0and such that the

estimate

kψkL2(Ω)3+ kξ0kL2(Ω)3 ≤ Ckf kH

0(curl,Ω)0 holds. Thanks to the density of D(Ω)3 in H

0(curl, Ω), we deduce that for all v ∈ KN(Ω), we have H0(curl,Ω)0 < curl ξ0 , v >H0(curl,Ω)= 0. Since div f = 0, it follows that div ψ = 0. Then, thanks to the orthogonality condition,H0(curl,Ω)0 < f , grad q

N

i >H0(curl,Ω)= 0 for all i = 1, . . . , I, the condition

H−1/2i) < ψ · n , 1 >H1/2i)= 0 is satisfied for all i = 0, . . . , I. There thus exists a vector potential ϕ∈ L2(Ω)3 (see Theorem 3.12 of [1]) such that ψ = curl ϕ, with div ϕ = 0 in Ω and ϕ · n = 0 on Γ,

and such that the estimate

kϕkL2(Ω)3 ≤ CkψkL2(Ω)3.

holds. Hence, the vector function ξ = ξ0+ ϕ possesses the announced properties. 

Remark 7 Theorem 6 has been established in [5] when Γ is connected, in which case KN = {0}.

For any integer m ≥ 1, let us now introduce the space Hm

0 (curl, Ω) := {v ∈ H0(curl, Ω); curl v ∈ H0m(Ω)3}.

We can prove that D(Ω)3 is dense in Hm

0 (curl, Ω). Moreover, we can characterize its dual space as

H−m(curl, Ω) = {ψ + curl ξ; ψ ∈ H

0(curl, Ω)0, ξ ∈ H−m(Ω)3}.

Like in Section 3, given any distribution f ∈ H−m(curl, Ω), with m ≥ 1, that satisfies (8), there exists

a vector potential ξ ∈ H−m(Ω)3 such that f = curl ξ. Finally, using the decomposition (1) with m

replaced by m + 1, it is easy to prove, as in Section 3 , that

H−m−1(Ω)3= H−m(curl, Ω) + H−m(div, Ω), for m ≥ 1.

4. Generalized Korn’s Inequality Finally, we consider tensor fields.

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Theorem 8 Assume that Ω is simply-connected. Given any integer m ≥ 0, let e = (eij) ∈ H−m(Ω)3×3

be a symmetric matrix field that satisfies the following compatibility conditions for all i, j, k, l ∈ {1, 2, 3}: Rijkl:= ∂ 2e ik ∂xl∂xj + ∂ 2e jl ∂xk∂xi − ∂ 2e jk ∂xl∂xi − ∂ 2e il ∂xk∂xj = 0 in H−m−2(Ω). (11)

Then there exists a vector field v ∈ H−m+1(Ω)3such that e

ij = 12(∂x∂vij+∂v∂xji) and v is unique up to vector

fields in the space R(Ω) = {a + b ∧ idΩ; a , b ∈R3}.

Proof. Let e = (eij) ∈ Hs−m(Ω)3×3 (the subscript s denotes a symmetric matrix field), and let fijk := ∂eik

∂xj −

∂ejk

∂xi. Then fijk ∈ H

−m−1(Ω) and, thanks to the compatibility conditions (11), we have ∂ ∂xlfijk=

∂xkfijl. Hence the implication (iii) =⇒ (iv) in Theorem 1 shows that there exist distributions pij ∈ H−m(Ω), unique up to additive constants, such that

∂xkpij = fijk. Besides, since

∂xkpij = −

∂ ∂xkpji, we can choose the distributions pij in such a way that pij + pji = 0. Noting that the distributions

qij := eij+ pij belong to H−m(Ω) and satisfy ∂xkqij = ∂xjqik, we again resort to Theorem 1 to assert

the existence of distributions vi∈ H−m+1(Ω), unique up to additive constants, such that ∂x∂vij = qij. 

Define, for any integer m ≥ 0, the following spaces:

E(Ω) := {e ∈ Hs−m(Ω)3×3, Rijkl(e ) = 0} and H˙−m+1(Ω)3:= H−m+1(Ω)3/R(Ω)

By the previous theorem, for any e = (eij) ∈ E(Ω), there exists a unique ˙v = ( ˙vi) ∈ ˙H−m+1(Ω)3 such

that eij = 12(∂x∂ ˙vij +∂x∂ ˙vji). We may thus define a linear mapping F : E(Ω) → ˙H−m+1(Ω)3 by F (e ) = ˙v.

Using the same method as in [6], we can then prove the following result:

Theorem 9 The linear mapping F : E(Ω) → ˙H−m+1(Ω)3 is an isomorphism. Besides, there exists a

constant C ≥ 0 such that inf r∈R(Ω)kv + rkH−m+1(Ω) 3 ≤ C X i,j keij(v )kH−m(Ω) for all v ∈ H−m+1(Ω)3, and kv kH−m+1(Ω)3 ≤ C(kv kH−m(Ω)3+ X i,j keij(v )kH−m(Ω)) for all v ∈ H−m+1(Ω)3 where eij(v ) = 12(∂x∂vij +∂v∂xji). 5. Acknowledgement

This work was substantially supported by a grant from the Research Grants Council of the Hong Kong Special Administration Region [Project No. 9041076, City U 100105]

References

[1] C. Amrouche, C. Bernardi, M. Dauge, V. Girault, Vector potentials in three dimensional nonsmooth domains, Math. Methods Appl. Sci. 21 (1998), pp. 823–864.

[2] C. Amrouche, P.G. Ciarlet, L. Gratie, S. Kesavan, On the characterization of matrix fields as linearized strain tensor fields, J. Math. Pures Appl. 86, (2006), pp. 116-132.

[3] C. Amrouche, V. Girault, Probl`emes g´en´eralis´es de Stokes, Portug. Math. 49 (1992), pp. 464-503.

[4] C. Amrouche, V. Girault, Decomposition of vector spaces and application to the Stokes problem in arbitrary dimension, Czech. Math. Jour. 44, (1994), pp. 109–140.

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[5] C. Bernardi, V. Girault, Espaces duaux des domaines des op´erateurs divergence et rotationnel avec trace nulle, Publications du Laboratoire Jacques-Louis Lions R 03017 (2003).

[6] P.G. Ciarlet, P. Ciarlet Jr, Another approach to linearized elasticity and a new proof of Korn’s inequality, Math. Models Methods Appl. Sci. 15 (2005), pp. 259–271.

[7] P. Fernandes and G. Gilardi. Magnetostatic and electrostatic problems in inhomogeneous anisotropic media with irregular boundary and mixed boundary conditions, Math. Models Methods Appl. Sci. 7 (1997), pp. 957–991.

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