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effective real algebraic geometry
Mohab Safey El Din, Philippe Trebuchet
To cite this version:
Mohab Safey El Din, Philippe Trebuchet. Strong bi-homogeneous Bézout theorem and its use in
effective real algebraic geometry. [Research Report] RR-6001, INRIA. 2006, pp.46. �inria-00105204v4�
inria-00105204, version 4 - 23 Oct 2006
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Thème SYM
Strong bi-homogeneous Bézout theorem and its use
in effective real algebraic geometry
Mohab Safey El Din — Philippe Trébuchet
N° 6001
Mohab SafeyEl Din
∗
, PhilippeTrébu het
†
ThèmeSYMSystèmessymboliques ProjetsSALSA
Rapportdere her he n°6001O tobre200643pages
Abstra t: Let
(f
1
, . . . , f
s
)
be a polynomial family inQ[X
1
, . . . , X
n
]
(withs 6 n − 1
) of degree bounded byD
. Suppose thathf
1
, . . . , f
s
i
generates aradi al ideal, and denes a smoothalgebrai varietyV ⊂ C
n
. Consideraproje tion
π : C
n
→ C
. Weprovethat the degree of the riti al lo us of
π
restri tedtoV
is bounded byD
s
(D − 1)
n
−s
n
n
−s
. This resultisobtainedintwosteps. Firstthe riti alpointsof
π
restri tedtoV
are hara terized asproje tionsof thesolutionsof Lagrange'ssystemforwhi h abi-homogeneousstru ture isexhibited. Se ondlyweproveabi-homogeneousBézoutTheorem,whi hboundsthesum ofthedegreesoftheequidimensional omponentsof theradi alofanidealgenerated by a bi-homogeneous polynomial family. This result is improvedwhen(f
1
, . . . , f
s
)
is aregular sequen e. Moreover,weuse Lagrange'ssystemto designan algorithm omputing at least one point in ea h onne ted omponent of a smooth real algebrai set. This algorithm generalizes, to the non equidimensional ase, the one of Safey El Din and S host. The evaluation of the output size of this algorithm gives newupperbounds on the rst Betti numberofasmoothrealalgebrai set. Finally, weestimateits arithmeti omplexityand provethatintheworst asesitispolynomialinn
,s
,D
s
(D −1)
n−s
n
n
−s
andthe omplexity ofevaluation of
f
1
, . . . , f
s
.Key-words: omputeralgebra,polynomialsystemsolving,ee tivereal algebrai geom-etry
∗
Mohab.Safeylip6.fr
†
Résumé : Soit
(f
1
, . . . , f
s
)
une famille depolynmes dansQ[X
1
, . . . , X
n
]
(oùs 6 n − 1
) dedegrébornéparD
. Onsupposequehf
1
, . . . , f
s
i
engendreunidéalradi al,etdénitune variétéalgébrique lisseV ⊂ C
n
. Considérons une proje tion
π : C
n
→ C
. On prouveque ledegrédulieu ritiquede
π
restreinte àV
estborné parD
s
(D − 1)
n
−s
n
n
−s
. Cerésultat estobtenuendeux temps. Toutd'abord,on ara térise lespoints ritiquesde
π
restreinte àV
omme proje tions des solutions du système de Lagrange pour lequel on exhibe une stru turebi-homogène.Puis,onprouveunethéorèmedeBézoutbi-homogène,quibornela sommedesdegrésdes omposanteséqui-dimensionnellesduradi ald'unidéalengendrépar unefamilledepolynmesbi-homogènes. Cerésultatestaméliorédansle asoù(f
1
, . . . , f
s
)
est une suite régulière. De plus, on utilise la formulation Lagrangienne pour dé rire un algorithme al ulantau moins un point par omposante onnexe d'une variétéalgébrique réelle lisse. Cet algorithme généraliseau as non équi-dimensionnel eluide Safey El Din et S host. L'estimation de la taille de la sortie de notre algorithme donne de nouvelles (et meilleures)bornes sur lepremier nombrede Betti d'unevariété algébriqueréelle lisse. Finalement, onmontre qu'uneinstan eprobabilistede notrealgorithme est de omplexité polynomiale enn
,s
,D
s
(D − 1)
n
−s
n
n−s
et la omplexitéd'évaluation de
f
1
, . . . , f
s
. Mots- lés: al ulformel,résolutiondesystèmespolynomiaux,géométriealgébriqueréelle ee tive1 Introdu tion
Considerpolynomials
(f
1
, . . . , f
s
)
inQ[X
1
, . . . , X
n
]
(withs 6 n − 1
)ofdegreeboundedbyD
. Suppose that this polynomial family generates a radi al ideal and denes a smooth algebrai varietyV ⊂ C
n
. The oreofthispaperistogiveanoptimalboundonthedegree ofthe riti allo usofaproje tion
π : C
n
→ C
restri tedto
V
andtoprovideanalgorithm omputingatleastonepointin ea h onne ted omponentofthereal algebrai setV ∩ R
n
whoseworst ase omplexityispolynomialin thisbound.Motivation and des ription of the problem. Sin e omputing riti al pointssolves the problem of algebrai optimization, it hasmany appli ations in hemistry, ele troni s, nan ialmathemati s(see[15℄foranon-exhaustivelistofproblemsandappli ations). More traditionally, omputationsof riti alpointsareusedinee tiverealalgebrai geometryto omputeatleastonepointinea h onne ted omponentofarealalgebrai set. Indeed,every polynomialmappingrestri tedtoasmooth ompa trealalgebrai setrea hesitsextremaon ea h onne ted omponent. Thus, omputingthe riti allo usofsu hamappingprovides atleastonepointin ea h onne ted omponentof asmooth ompa trealalgebrai set.
In[22,25,26,9,10℄,theauthors onsiderthehypersurfa edenedby
f
2
1
+ · · · + f
s
2
= 0
tostudytherealalgebrai setV ∩ R
n
. Theproblemisredu ed,viaseveralinnitesimal de-formations,toasmoothand ompa tsituation.Su hte hniquesyieldalgorithmsreturning zero-dimensionalalgebrai setsen odedbyrationalparameterizationsofdegree
O(D)
n
(the best bound is obtained in [9, 10℄ and is(4D)
n
). Similarte hniques basedon theuse of a distan e fun tion to ageneri pointand a singleinnitesimal deformation(see [34℄) yield thebound
(2D)
n
ontheoutput.
Morere ently,otheralgorithms,avoidingthesumofsquares(andtheasso iatedgrowth ofdegree)havebeenproposed(see[2,35,7,4,5,38,37℄). The ompa tnessassumptionis droppedeitherby onsideringdistan efun tionsandtheir riti allo us(see[2,35,7,6℄)or byensuringpropernesspropertiesofsomeproje tionfun tions(see[37℄). Thesealgorithms omputethe riti allo iofpolynomialmappingsrestri tedtoequidimensionalandsmooth algebrai varietiesofdimension
d
, denedbypolynomialsystemsgeneratingradi alideals. Indeed,undertheseassumptions, riti alpoints anbealgebrai allydenedaspointswhere the ja obian matrix has rankn − d
, and thus by the vanishing of some minors of the onsideredja obianmatrix. Ontheonehand,someofthese algorithmsallowusto obtain e ientimplementations(see[36℄) whilethealgorithmsmentionedintheaboveparagraph donotpermittoobtainusableimplementations. Ontheotherhand,applyingthe lassi al Bézoutboundtothepolynomialsystemsdeningthe riti allo usofaproje tionprovides adegreebound on theoutputwhi h isequaltoD
n−d
((n − d)(D − 1))
d
(see[37, 7℄ where su haboundisexpli itlymentioned). Thisboundisworsethantheaforementionedbounds, butithasneverbeenrea hedin theexperimentsweperformedwithourimplementations.
Remark thatthesepolynomialsystemsdening riti alpointsarenotgeneri : theyare overdetermined,and the extra tedminors from theja obianmatrix depend on
f
1
, . . . , f
s
, sothat one anhopethat the lassi alBézoutboundis pessimisti .Ouraimistwofold:
providinganoptimalbound(inthesensethatit anberea hed)onthedegreeofthe riti allo usofapolynomialmappingrestri tedto analgebrai variety;
anddesigninganalgorithm omputingatleastonepointinea h onne ted omponent ofarealalgebrai setwhoseworst ase omplexityispolynomialin thisbound.
Main ontributions. Consideraproje tion
π
fromC
n
ontoalinewhosebase-lineve tor is
e
∈ C
n
, and the restri tion of
π
to the smooth algebrai varietyV ⊂ C
n
. Lagrange's hara terization of riti alpointsof
π
restri tedtoV
onsists in writingthat,ata riti al point, there exists alinear relation between the ve tors(grad(f
1
), . . . , grad(f
s
), e)
. The resultingpolynomialsystemis alledin thesequelLagrange's system. Additionalvariables areintrodu edand are lassi ally alled Lagrangemultipliers. Equipped withsu ha har-a terization, riti alpoints anbegeometri allyseenasproje tionsof the omplexsolution setof Lagrange's system. Weprovethat su ha hara terizationremainsvalid evenin non equidimensionalsituations, ontrarytothealgebrai hara terizationof riti alpointsused in [2, 35, 7,4, 5, 38, 37℄. Iff
1
, . . . , f
s
is a regular sequen e and if the riti al lo us ofπ
restri tedtoV
iszero-dimensional,thenLagrange'ssystemisazero-dimensionalideal,else itisapositivedimensionalideal.Sin e Lagrange multipliers appear with degree
1
in Lagrange's system, bounding the degree of the riti al lo us ofπ
restri ted toV
is equivalent to bounding the sum of the degrees of the isolated primary omponents of the ideal generated by Lagrange'ssystem. Lagrange'ssystem anbeeasilytransformedinto abi-homogeneouspolynomialsystemby abi-homogenizationpro esswhi hdistinguishthevariablesX
1
, . . . , X
n
fromtheLagrange multipliers. Thus,boundingthedegreeofa riti allo usisredu edtoprovingastrong bi-homogeneousBézoutTheorem,i.e. toprovingaboundonthesum ofthe degrees ofall the isolatedprimary omponentsdeninganon-emptybi-proje tivevarietyofanidealgenerated byabi-homogeneoussystem. Inthe sequel,thissumis alled thestrong bi-degreeofa bi-homogeneous ideal. Su h a result is obtained by using a onvenient notion of bi-degree, whi hisgivenoriginallyin[41℄. In[41℄,amulti-homogeneousBézouttheoremisprovedand providesaboundonthesumofthedegreesoftheisolatedprimary omponentsofmaximal dimension,whi hisnotsu ienttorea hourgoal.Wegeneralizethisresultbyprovingthatthesamequantityboundsthesumofthedegrees of allthe isolated primary omponentsdening abi-proje tivevariety of an ideal dened byabi-homogeneouspolynomialsystem(see Theorem1). Additionally, weprovethatthe strongbi-degree of anideal generated byabi-homogeneous polynomialsystemequalsthe strongdegreeofthisidealaugmentedwithtwogeneri homogeneousanelinearformslying respe tivelyin ea hblo kofvariables(seeTheorem2).
Thisallowsustoprovethatthe riti allo usofaproje tion
π : C
n
→ C
restri tedtoV
hasdegreeD
s
(D − 1)
n−s
n
n
−s
. Thisboundbe omes
D
s
(D − 1)
n−s n−1
n
−s
when
(f
1
, . . . , f
s
)
is a regular sequen e (see Theorem 3). Some omputer simulations show it is a sharp estimation,sin etheboundis rea hedonseveralexamples.Next,weusetheaforementionedpropertiesofLagrange'ssystemstogeneralize, tonon equidimensional situations,thealgorithm dueto Safey El Dinand S host(see [37℄)whi h omputesatleastonepointinea h onne ted omponentofasmoothandequidimensional realalgebrai set(seeTheorem5). Then,theestimationoftheoutputsizeofthisgeneralized algorithmprovidessomeimprovedupperboundsontherstBettinumberofasmoothreal algebrai set(seeTheorem6).
The omplexityofouralgorithmdependsonthe omplexityoftheroutineusedto per-form algebrai elimination. We onsider theelimination subroutine of [28℄ whi h inherits of[17, 18,19, 20℄. Thepro edureof [28℄ omnputesgeneri bersof ea h equidimensional omponentsofanalgebrai varietydened byapolynomialsystemprovidedasinput. Itis polynomialin theevaluation omplexityoftheinputsystem,andin anintrinsi geometri degree. This allows us to provethat the worst ase omplexity of ouralgorithm is poly-nomialin
n
,s
,theevaluation omplexityL
of(f
1
, . . . , f
s
)
andthebi-homogeneousBézout boundD
s
(D − 1)
n
−s
n
−s
n
(seeTheorem8).
Organizationofthepaper. Thepaperisorganizedasfollows. InSe tion2,weprovethe strongbi-homogeneousBézoutTheorem. Additionally,weprovethatthestrongbi-degreeof anidealequalsthestrongdegreeofthesameidealaugmentedwithtwogeneri anelinear formslyinginea hblo kofvariables. InSe tion3,wefo usonthepropertiesofLagrange's system and use our Bézout Theorem to prove somebounds on the degree of riti al lo i of proje tionson aline. In Se tion 4,wegeneralize the algorithm provided in [37℄ to the nonequidimensional ase. Moreover,usingtheresultsofthepre eding se tions,weprovide someimprovedupperboundsontherstBettinumberofasmoothrealalgebrai set. The lastse tionisdevotedtothe omplexityestimationofouralgorithm.
A knowledgments. WethankD.Lazard,J.Heintzandtheanonymousrefereesfortheir helpfulremarkswhi hhaveallowedustoimproveand orre tsomemistakesinthe prelim-inaryversionofthispaper.
2 Strong Bi-homogeneous Bézout theorem
This se tionis devoted to theproof of thestrong bi-homogeneousBézout Theorem. This onegeneralizesthestatementsof[40,41,31,32,24℄.
Intherstparagraph,weprovidesomeusefulpropertiesofbi-homogeneousidealswhi h allow to dene the notions of bi-degree and strong bi-degree of a bi-homogeneous ideal, thesenotionseemstogoba kto[40℄. Inthese ondparagraph,werelatethisbi-degreewith somepropertiesoftheHilbertbi-seriesofabi-homogeneousidealinthe asewhenitdenes azero-dimensional bi-proje tivevariety. Su h propertiesare already given in [40℄. Inthe thirdparagraph,weprovidea anoni alformofHilbertbi-series. Ourstatementsgeneralize slightlythoseof[31,32℄andallowustorelatetheHilbertbi-seriesofabi-homogeneousideal andtheHilbertseriesofthisideal,seenasahomogeneousone. Inthethirdparagraph,we investigatehowthebi-degreeofabi-homogeneousidealaugmentedwithabi-homogeneous
polynomial isrelated tothe bi-degreeof therst onsideredideal. Finally, weprovethat, undersomeassumptions,the lassi albi-homogeneousBézoutboundisgreaterthanorequal to thesumof thebi-degrees of theprime idealsasso iatedto thestudied bi-homogeneous ideal. Thisgeneralizestheresultsof[40,31,32,24℄. Additionally,weprovethatthisquantity is greaterthan or equalto thesum of thedegreesof the primary idealsasso iatedto the studiedbi-homogeneousidealaugmentedwithtwoanelinearformswhi h generalizesthe results of [41, 32℄. For ompleteness and readibility, we give full proofs of the required intermediateresults.
Wedenoteby
R
thepolynomialringQ[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
. 2.1 Preliminariesand main resultsInthisparagraph,weintrodu esomebasi sonbi-homogeneousideals. Weprovethatgivena bi-homogeneousideal
I ⊂ R
,thereexistsaminimalprimarybi-homogeneousde omposition ofI
,i.e. aprimary de ompositionsu hthat ea h primary omponentis abi-homogeneous ideal. Wedeneanotionofbi-degreeandstrongbi-degreeofbi-homogeneousideals. Finally, westatethemainresults(seeTheorems1
and2
below)ofthese tionwhi hboundthestrong bi-degreeofabi-homogeneousidealI
bythe lassi albi-homogeneousBézoutboundonthe onehand,and showthat thestrong bi-degree ofI
bounds thedegreeofI + hu − 1, v − 1i
(whereu
andv
are homogeneous linear forms respe tively hosen inQ[X
0
, . . . , X
n
]
andQ[ℓ
0
, . . . , ℓ
k
]
).Denition1 A linear formin
R
isa polynomialof degree1
whose support ontains only monomialsof degree atmost1
. A homogeneous linearformisalinear formwhose support ontainsonlymonomials ofdegree1
.A polynomial
f
inR
is said to be bi-homogeneous if and only if there exists a unique oupleof integers(α, β)
su hthatfor all(u, v) ∈ Q × Q
:f (uX
0
, . . . , uX
n
, vℓ
0
, . . . , vℓ
k
) = u
α
v
β
f (X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
n
).
The ouple(α, β)
is alled thebi-degree off
.Given a polynomial
f ∈ R
, the bi-homogeneous omponent of bi-degree(α, β)
off
, de-noted byf
α,β
, is the unique bi-homogeneous polynomial su h that the support off − f
α,β
does not ontainany monomialof bi-degree(α, β)
.An ideal
I ⊂ R
issaid tobeabi-homogeneousideal if andonlyiffor allf ∈ I
,andfor allbi-degree(α, β)
,f
α,β
∈ I
.Lemma1 Let
I ⊂ R
be a bi-homogeneous ideal. Then, there exists a nite polynomial familyf
1
, . . . , f
s
generatingI
su h thatea hf
i
(fori = 1, . . . , s
)isa bi-homogeneous poly-nomial.Proof. Consideranitesetofgenerators
F
ofI
(thereexistsonesin eR
isNoetherian). Sin eI
isabi-homogeneousideal,thenitesetF
e
ofthebi-homogeneous omponentsofall thepolynomialsinF
generatesanidealJ
whi his ontainedinI
.Considernow
f ∈ I
. Sin eI
isgeneratedbyF
andsin eea hpolynomialofF
isalinear ombinationofsomepolynomialsinF
e
,I
is ontainedinJ
.Lemma2 Let
Q
1
, . . . , Q
p
be afamily of bi-homogeneous ideals inR
. ThenQ
1
∩ · · · ∩ Q
p
isabi-homogeneousideal.Proof. Denote by
I
theidealQ
1
∩ · · · ∩ Q
p
and onsiderf ∈ I
. Foralli ∈ {1, . . . , p}
,f ∈ Q
i
andQ
i
is, by assumption, bi-homogeneous. Then, for alli ∈ {1, . . . , p}
, ea h bi-homogeneous omponent off
belongs toQ
i
, whi h implies that ea h bi-homogeneous omponentbelongstoI
.Givenabi-homogeneousideal
I ⊂ R
,wenowprovethat thereexists aprimary de om-positionofI
forwhi hea hprimary omponentisbi-homogeneous.Proposition 1 Let
I
be a bi-homogeneous ideal, andQ
1
∩ · · · ∩ Q
p
be aminimal primary de omposition ofI
. Then there exist primary bi-homogeneous idealsQ
′
1
, . . . , Q
′
p
su h thatI = Q
′
1
∩ · · · ∩ Q
′
p
.Proof. For
i = 1, . . . , p
, onsiderQ
i
, a primary ideal of the above minimal primary de omposition ofI
and letQ
′
i
be theideal generated by thebi-homogeneous polynomialsof
Q
i
. First, remarkthatQ
′
i
is non empty sin eit ontainsI
. WeprovenowthatQ
′
i
(fori = 1, . . . , p
)isaprimaryidealandthenthatI = Q
′
1
∩ · · · ∩ Q
′
p
. Letf
andg
betwopolynomialssu hthatf g ∈ Q
′
i
andg /
∈ Q
′
i
. Weshowbelowthatthisimpliesthereexistsaninteger
N
su hthatf
N
∈ Q
′
i
whi h, inturn,impliesQ
′
i
isaprimaryideal. Theproofisdonebyindu tiononthenumber
h
ofbi-homogeneous omponentsoff
. Ifh = 1
,f
is bi-homogeneous, and the result is obvious. Suppose now that for any polynomialf
e
havingh
bi-homogeneous omponents,f g ∈ Q
e
′
i
withg /
∈ Q
′
i
implies thereexistsaninteger
N
su hthatf
e
N
∈ Q
′
i
.Consider
f
havingh + 1
bi-homogeneous omponentsandsu hthat thereexistsg /
∈ Q
′
i
withf g ∈ Q
′
i
. Sin eQ
′
i
is bi-homogeneous,ea h bi-homogeneous omponentoff g
belongs toQ
′
i
. Remark that there exists one bi-homogeneous omponent of the produ tf g
of maximal degreewhi h anbewritten as aprodu tf
α,β
.g
α
′
,β
′
wheref
α,β
(resp.g
α
′
,β
′
) is abi-homogeneous omponentof bi-degree(α, β)
(resp.(α
′
, β
′
)
) of
f
(resp.g
). Moreover, withoutlossofgeneralityone ansupposeg
α
′
,β
′
∈ Q
/
i
: ifitisnotthe ase,itissu ientto substituteg
byg − g
α
′
,β
′
.Sin e
Q
i
is aprimaryideal, there existsM ∈ N
, su hthatf
M
α,β
∈ Q
i
. Moreover,sin ef
α,β
is bi-homogeneous,f
M
α,β
is bi-homogeneous. Thus, sin eQ
′
i
is generated by thebi-homogeneouspolynomialsof
Q
i
,thisimpliesf
M
α,β
∈ Q
′
i
. Sin ef g ∈ Q
′
i
,f
M
g ∈ Q
′
i
. Moreoverf
M
g = (f − f
α,β
)
M
g + f
α,β
M
g
whilef
M
α,β
∈ Q
′
i
. This implies(f − f
α,β
)
M
g ∈ Q
′
i
. Suppose now thatM
is the smallest integer su h that(f − f
α,β
)
M
g ∈ Q
′
i
and remark that this implies(f − f
α,β
)
M
−1
g /
∈ Q
′
i
. Thus, the abovef
ande
g = (f − f
α,β
)
M
−1
g /
∈ Q
′
i
insteadofg
. Fromtheindu tion hypothesis, thisimplies there exists an integerM
′
su h that
(f − f
α,β
)
M
′
∈ Q
′
i
, while theintegerM
is su h thatf
M
α,β
∈ Q
′
i
. Thus, onsideringthebinomialdevelopmentof(f −f
α,β
+ f
α,β
)
N
where
N > 2M
showsthatf
N
∈ Q
′
i
.It remainsto provethat
I = Q
′
1
∩ · · · ∩ Q
′
m
. Tothisend, remarkthat foralli
,I ⊂ Q
i
and asI
is bi-homogeneous,I ⊂ Q
′
i
whileQ
′
i
⊂ Q
i
. Thus one hasI ⊂ Q
′
1
∩ · · · ∩ Q
′
m
⊂
Q
1
∩ · · · ∩ Q
m
= I
whi h endstheproof.Fromnowon,givenabi-homogeneousideal
I
,weonly onsiderbi-homogeneousprimary de ompositionsofI
,i.e. de ompositionsofI
su hthatea hprimary omponentis bi-homo-geneous. Remarkthatfromsu habi-homogeneousprimaryde omposition,one anextra t aminimalprimaryde omposition. Fromtheuniquenessoftheisolatedprimary omponents ofaminimal primary de omposition (see[12℄), onededu esthe uniquenessof theisolated primary omponentsofabi-homogeneousminimalprimary de ompositionofI
. This leads tothefollowingresult.Corollary1 Let
I
be a bi-homogeneous ideal ofR
. There exists a minimal primary de- ompositionofI
su h that ea h primary omponent is a bi-homogeneous ideal. The set of isolatedbi-homogeneous omponents isunique.Note that primary ideals of
R
whi h ontain a power ofhX
0
, . . . , X
n
i
or a power ofhℓ
0
, . . . , ℓ
k
i
deneanemptybi-proje tivevarietyinP
n
(C) × P
k
(C)
.Denition2 A primary bi-homogeneous ideal is said to be admissible if and only if it ontainsneitherapowerof
hX
0
, . . . , X
n
i
nor apowerofhℓ
0
, . . . , ℓ
k
i
.A primary omponent of a bi-homogeneous ideal is said tobe admissible if itis an ad-missibleideal.
The setofadmissible isolatedbi-homogeneous omponentsofaminimal bi-homogeneous primaryde ompositionof anideal
I ⊂ R
is denotedbyAdm(I)
.Let
I ⊂ R
bea bi-homogeneousideal, and(d, e)
bea ouple inN
× N
. The ouple(d, e)
is an admissible bi-dimension ofI
if and only ifd 6 n
,e 6 k
andd + e + 2
equals the maximumof theKrulldimensions ofthe ideals inAdm(I)
.Remark1 Consider a bi-homogeneous ideal
I ⊂ R
and letJ = ∩
Q∈Adm(I)
Q
. From Lemma2,J
isabi-homogeneousideal.A bi-homogeneousideal
I
inR
denes anon-empty bi-proje tivevarietyV
inP
n
(C) ×
P
k
(C)
if and only ifAdm(I)
is not empty. Note also that the maximal dimension of the admissibleprimary omponentsofI
anbelessthantheKrulldimensionofI
.Inthehomogeneous ontext,thedegreeofanidealofKrulldimension
D
deninga non-emptyproje tivevarietyisobtainedasthe degreeofthis idealaugmentedwithD
generi linearforms (see[11℄). Below, weprovideasimilarpro essto dene anotionofbi-degree ofabi-homogeneousideal.In the sequel,a homogeneouslinear form
u =
P
n
i=0
u
i
X
i
∈ Q[X
0
, . . . , X
n
]
(resp.v =
P
k
j=0
v
j
ℓ
j
∈ Q[ℓ
0
, . . . , ℓ
k
]
)isidentiedtothepoint(u
0
, . . . , u
n
) ∈ Q
n+1
(resp.
(v
0
, . . . , v
k
) ∈
Q
k+1
).Proposition 2 Let
I ⊂ R
be an ideal of dimensionD > 2
and(d, e) ∈ N × N
su h thatd + e + 2 = D
. Either for any hoi e of homogeneous linear forms
(u
1
, . . . , u
d+1
)
inQ[X
0
,
. . . , X
n
]
and(v
1
, . . . , v
e+1
)
inQ[ℓ
0
, . . . , ℓ
k
]
the idealI + h(u
1
− 1), u
2
, . . . , u
d+1
, (v
1
− 1), v
2
, . . . , v
e+1
i
equalsQ[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
; or there exist an integer
D
∈ N
and a Zariski losed subsetH ( (C
n+1
)
d+1
×
(C
k+1
)
e+1
su hthatfor any hoi eofhomogeneouslinearforms
(u
1
, . . . , u
d+1
, v
1
, . . . ,
v
e+1
)
outsideH
(where fori ∈ {1, . . . , d + 1}
,u
i
∈ Q[X
0
, . . . , X
n
]
and forj ∈
{1, . . . , e + 1}
,v
j
∈ Q[ℓ
0
, . . . , ℓ
k
]
)the idealI + h(u
1
− 1), u
2
, . . . , u
d+1
, (v
1
− 1), v
2
, . . . , v
e+1
i
iszero-dimensionalanditsdegreeisD
.Proof. For
i ∈ {1, . . . , d + 1}
,p ∈ {0, . . . , n}
,j ∈ {1, . . . , e + 1}
, andq ∈ {0, . . . , k}
, letu
i,p
,andv
j,q
benew indeterminates. Denote byU
(resp.V
) theset of indeterminates{u
1,0
, . . . , u
d+1,n
}
(resp.{v
1,0
, . . . , v
e+1,k
}
).Let
K
betheeldofrationalfra tionsQ(U, V)
;fori ∈ {1, . . . , d + 1}
,letK
¯
i
betheeld ofrationalfra tionsQ
(U \ {u
i,0
, . . . , u
i,n
}, V)
andforj ∈ {1, . . . , e + 1}
,letK
j
betheeldofrationalfra tions
Q
(U, V \ {v
j,0
, . . . , v
j,k
})
.Considerfor
2 6 i 6 d + 1
(resp.2 6 j 6 e + 1
)thelinearformsu
i
=
P
n
p=0
u
i,p
X
p
(resp.v
j
=
P
k
q=0
v
j,q
ℓ
q
)andu
1
=
P
k
p=0
u
1,p
X
p
− 1
(resp.v
1
=
P
k
q=0
v
1,q
ℓ
q
− 1
).For
i ∈ {1, . . . , d + 1}
(resp.j ∈ {1, . . . , e + 1}
)andu = (u
0
, . . . , u
n
)
(resp.v =
(v
0
, . . . , v
k
)
) a point inQ
n+1
(resp.
Q
k+1
), denote by
ϕ
i,u
(resp.ψ
j,v
) the ring ho-momorphismϕ
i,u
: K[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
] → ¯
K
i
[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
(resp.ψ
j,v
:
K[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
] → K
j
[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
)su hthat: forall
p ∈ {0, . . . , n}
(resp.q ∈ {0, . . . , k}
),ϕ
i,u
(u
i,p
) = u
p
(resp.ψ
j,v
(v
j,q
) = v
q
), for allp ∈ {0, . . . , n}
(resp.q ∈ {0, . . . , k}
), andr ∈ {1, . . . , d + 1} \ {i}
(resp.s ∈ {1, . . . , e + 1} \ {j}
),ϕ
i,u
(u
r,p
) = u
r,p
(resp.ψ
j,v
(v
s,q
) = v
s,q
),
ϕ
i,u
(X
p
) = X
p
(resp.ψ
j,v
(X
p
) = X
p
)andϕ
i,u
(ℓ
q
) = ℓ
q
(resp.ψ
j,v
(ℓ
q
) = ℓ
q
).Finally, givena oupleof points
u = (u
1,0
, . . . , u
1,n
, . . . , u
d+1,0
, . . . , u
d+1,n
)
(resp.v =
(v
1,0
, . . . , v
1,k
, . . . , v
e+1,0
, . . . , v
e+1,k
)
)in(Q
n+1
)
d+1
(resp.
(Q
k+1
)
e+1
ringhomomorphism
ϑ
(u,v)
: K[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
] → Q[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
su h that forallp = 0, . . . , n
andq = 0, . . . , k
),ϑ
u,v
(u
i,p
) = u
i,p
,ϑ
u,v
(v
j,q
) = v
j,q
,ϑ
u,v
(X
p
) = X
p
andϑ
u,v
(ℓ
q
) = ℓ
q
.In the sequel,
J
0
= I
, fori ∈ {1, . . . , d + 1}
,J
i
is the idealI + hu
1
, . . . , u
i
i
, and fori ∈ {d + 2, . . . , D}
,J
i
istheidealI + hu
1
, . . . , u
d+1
, v
1
, . . . , v
i
−(d+1)
i
.We rst prove that the ideal
J
D
is either zero-dimensional inK[X
0
, . . . , X
n
,
ℓ
0
, . . . , ℓ
k
]
or equalsK[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
. The proof is done by proving that, fori = 1, . . . , D
,dim(J
i
) < dim(J
i
−1
)
.Consider the ase
i = 1
and suppose thatdim(J
1
) > dim(J
0
) > 0
. This implies that there exists an isolated primary omponentQ
0
ofJ
0
of dimensiondim(J
0
) > 0
and an integerN
su h thatu
N
1
∈ Q
0
.Sin e
J
0
isgeneratedbyapolynomialfamilywhi h doesnotinvolvetheindeterminatesu
1,0
, . . . , u
1,n
,foranyisolatedprimary omponentQ
ofJ
0
,Q
is generatedbyapolynomial familywhi h does not involve the indeterminatesu
1,0
, . . . , u
1,n
. Thus, foranyu ∈ Q
n+1
,ϕ
1,u
(Q
0
) = Q
0
∩ ¯
K
1
. Then,thereexistsaZariski- losedsubsetZ ⊂ C
n+1
su hthatforany point
u
inQ
n+1
\ Z
,
ϕ
1,u
(u
1
)
N
belongs to
Q
0
. Choose nown + 2
pointsu
1
, . . . , u
n+2
inQ
n+2
su hthathϕ
1,u
1
(u
N
1
), . . . , ϕ
1,u
n+2
(u
N
1
)i = h1i
. Sin ehϕ
1,u
1
(u
N
1
), . . . , ϕ
1,u
n+2
(u
N
1
)i ⊂ Q
0
,Q
0
= K[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
whi h ontra-di tsdim(Q
0
) = D > 0
. Thus,dim(J
1
) < dim(J
0
)
.Considernowthe asewhere
2 6 i 6 d + 1
and supposethatdim(J
i
) > dim(J
i−1
) > 0
. Thisimpliesthatthereexistsanisolatedprimary omponentQ
0
ofJ
i
−1
ofpositivedimension andanintegerN
su hthatu
N
i
∈ Q
0
.Sin e
J
i
−1
isgeneratedbyapolynomialfamilywhi hdoesnotinvolvetheindeterminatesu
i,0
, . . . , u
i,n
,Q
0
is generated bya polynomialfamily whi h does notinvolve the indeter-minatesu
i,0
, . . . , u
i,n
and thus for anyu ∈ Q
n+1
,
ϕ
i,u
(Q
0
) = Q
0
∩ ¯
K
i
. Then, for any pointu
inQ
n+1
,
ϕ
i,u
(u
i
)
N
belongs to
Q
0
. Choosingn + 2
pointsu
1
, . . . , u
n+2
inQ
n+2
su h thathϕ
i,u
1
(u
N
i
), . . . , ϕ
i,u
n+2
(u
N
i
)i = hX
0
N
, . . . , X
n
N
i ⊂ Q
. Sin eu
1
∈ J
i
−1
⊂ Q
0
andhu
1
i + hX
0
N
, . . . , X
n
N
i = h1i
this impliesthatQ
0
= K[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
whi h ontra-di tsthefa t thatQ
0
haspositivedimension. Thus,dim(J
i
) < dim(J
i
−1
)
.Provingthat
dim(J
d+2
) < dim(J
d+1
)
isdonebythesamewayasprovingthatdim(J
1
) <
dim(J
0
)
using the homomorphismψ
d+2,v
instead ofϕ
1,u
(foru ∈ Q
n+1
and
v ∈ Q
k+1
). Proving for
i > d + 2
thatdim(J
i
) < dim(J
i
−1
)
is done following the samearguments as thoseoftheaboveparagraph(usingthehomomorphismsψ
i,v
forv ∈ Q
k+1
).Thus,if
J
D
6= K[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
,onehasdim(J
D
) < dim(J
D−1
) < · · · < dim(J
i
) <
dim(J
i−1
) < · · · < dim(I)
whi himpliesJ
isbezero-dimensional. IfJ
D
= K[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
, for any(u, v) ∈ (Q
n+1
)
d+1
× (Q
k+1
)
e+1
,
ϑ
u,v
(J
D
)
equalsQ[X
0
, . . . , X
n
]
.Suppose now
J
D
to be zero-dimensional and onsider a Gröbner basisG
ofJ
D
. LetH ⊂ (C
n+1
)
d+1
× (C
k+1
)
e+1
betheZariki- losed setwhi h istheunionof zero-setsofthe ommondenominator of ea hpolynomialof
G
. Thus, for anypoint(u, v) ∈ (Q
n+1
)
d+1
×
(Q
k+1
)
e+1
\ H
zero-dimensionalanditsdegreeis theoneof
J
D
.Remark2 Fromthe proofof theabove Proposition, onededu esalso thefollowing:
Let
I ⊂ R
be a bi-homogeneous ideal whi h is an interse tion of admissible primary ideals. Then, there existsa Zariski- losed subsetH ( C
n+1
× C
k+1
su h that for all
(u
1
, v
1
) ∈ C
n+1
× C
k+1
\ H
,u
1
− 1
andv
1
− 1
do notdivide0
inR/I
andv
1
− 1
does not divide0
inR/I + hu
1
− 1i
.Moreoverif
I
isequidimensional,I + hu
1
− 1, v
1
− 1i
isequidimensional. Let
I ⊂ R
be an equidimensional bi-homogeneous ideal whi h is an interse tion of admissible primaryideals andJ = I + hu
1
− 1, v
1
− 1i
. IfJ 6= R
,thereexists(d, e) ∈
N
× N
su hthatd + e = dim(J)
andaZariski- losedsubsetH ( (C
n+1
)
d
× (C
k+1
)
e+1
su h that for any hoi e of homogeneous linear forms
(u
2
, . . . , u
d+1
, v
2
, . . . , v
e+1
) ∈
Q[X
0
, . . . , X
n
] × Q[ℓ
0
, . . . , ℓ
k
] \ H
,u
2
does not divide0
inR/J
,u
i
does not divide0
inR/J + hu
2
, . . . , u
i
−1
i
(fori = 3, . . . , d + 1
),v
2
does not divide zero inR/J +
hu
2
, . . . , u
d+1
i
andv
j
does not divide0
inR/J + hu
2
, . . . , u
d+1
, v
1
, . . . , v
j−1
i
(forj ∈
{3, . . . , e + 1}
).Inthesequel,weshallsaythataproperty
P
istrueforageneri hoi eoflinearforms, ifthereexistsaZariski- losedsubsetin thesetofthe onsideredlinearformssu hthatfor any hoi eofforms outsidethisZariski- losedsubset,thepropertyP
issatised.Proposition 2andtheuniqueness of
Adm(I)
allowsus todene thefollowingnotionof bi-degreeofabi-homogeneousidealI ⊂ R
.Denition3 Let
I ⊂ R
beabi-homogeneousidealofdimensionD
. For(d, e) ∈ N × N
su h thatd + e + 2 = D
, onsiderthelinearformsu
1
, . . . , u
d+1
(resp.v
1
, . . . , v
e+1
)whi hare ho-sen generi ally inQ[X
0
, . . . , X
n
]
(resp.Q[ℓ
0
,
. . . , ℓ
k
]
).C
d,e
(I)
denotes the degreeofI + hu
1
, . . . , u
d+1
− 1, v
1
, . . . , v
e+1
− 1i
. IfI
isprimary, the bi-degreeofI
isthesumP
d+e+2=D
C
d,e
(I)
.If
I
isnotprimary,the bi-degreeofI
isthesumofthebi-degreesofthe idealsofAdm(I)
havingmaximalKrulldimension.If
I
isnot primary,the strongbi-degreeofI
isthesum ofthe bi-degreesofthe ideals ofAdm(I)
(whi h areisolatedbydenition ofAdm(I)
. Remark3 LetI ⊂ R
beabi-homogeneousidealandJ = ∩
Q∈Adm(I)
Q
whi hisbi-homogeneous fromLemma2 . Notethat,bydenition,thebi-degree(resp. thestrongbi-degree)ofI
equals the bi-degree(resp. strongbi-degree) ofJ
.We are now ready to state the main results of this se tion. The rst onebounds the strongbi-degreeofabi-homogeneousideal
I ⊂ R
undersomeassumptions. Thisgeneralizes thestatementsof[40,39, 24℄ whi honly onsider withtheadmissible primary omponents ofAdm(I)
havingmaximaldimension.Theorem1 Let
s ∈ {1, . . . , n + k}
andf
1
, . . . , f
s
be bi-homogeneous polynomials inR
of respe tive bi-degree(α
i
, β
i
)
generating a bi-homogeneous idealI
. Suppose that there ex-ist at mostn f
i
su h thatβ
i
= 0
and at mostk f
i
su h thatα
i
= 0
, then the sum of the bi-degrees of the bi-homogeneous asso iated primes ofI
is bounded byB(f
1
, . . . , f
s
) =
X
I,J
(Π
i∈I
α
i
) . (Π
j∈J
β
j
)
whereI
andJ
aredisjointsubsetsforwhi htheunionis{1, . . . , s}
su hthatthe ardinality ofI
(resp.J
)isboundedbyn
(resp.k
).The following result generalizes the one of [41℄ and states that given an ideal
I ⊂
Q[X
1
, . . . , X
n
, ℓ
1
, . . . , ℓ
k
]
itsstrongdegree(inthemeaningof[23℄)isboundedbythestrong bi-degreeofabi-homogeneousideal onstru tedfrom abi-homogeneizationpro essapplied toea hpolynomialinI
.Theorem2 Consider themapping :
φ :
Q[X
1
, . . . , X
n
, ℓ
1
, . . . , ℓ
k
] → Q[X
0
, X
1
, . . . , X
n
, ℓ
0
, ℓ
1
, . . . , ℓ
k
]
f
7→ X
deg
X
(f )
0
ℓ
deg
ℓ
(f )
0
f (
X
X
1
0
, . . . ,
X
n
X
0
,
ℓ
1
ℓ
0
, . . . ,
ℓ
k
ℓ
0
)
wheredeg
X
(f )
(resp.deg
ℓ
(f )
)denotesthedegreeoff
seenasapolynomialinQ(ℓ
1
, . . . , ℓ
k
)[X
1
, . . . , X
n
]
(resp.Q(X
1
, . . . , X
n
)[ℓ
1
, . . . , ℓ
k
]
).Given an ideal
I ⊂ Q[X
1
, . . . , X
n
, ℓ
1
, . . . , ℓ
k
]
, denote byφ(I)
the ideal{φ(f) | f ∈ I} ⊂
Q[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
.Then,
φ(I)
isabi-homogeneousidealandthe sum ofthe degreesof theisolatedprimary omponentsofI
isboundedbythe strongbi-degreeofφ(I)
.TheproofoftheseresultsrelyonthestudyofHilbertbi-seriesofbi-homogeneousideals whi h areintrodu edin [40℄.
2.2 Hilbert bi-series: basi properties
We follow here [40℄ whi h introdu e Hilbert bi-series of bi-homogeneous ideals and study theirpropertieswhenthe onsideredbi-homogeneousidealhasbi-dimension
(0, 0)
.Notation. Given a ouple
(i, j) ∈ N × N
, we denote byR
i,j
theQ
-ve tor spa e of the bi-homogeneouspolynomialsinR
ofdegreei
inthesetofvariablesX
0
, . . . , X
n
andj
inthe setofvariablesℓ
0
, . . . , ℓ
k
.Givenabi-homogeneousideal
I ⊂ R
and a ouple(i, j) ∈ N × N
,wedenotebyI
i,j
the interse tionofI
withR
i,j
.Givena ouple
(i, j) ∈ N × N
, wedenote byR
6i,6j
theQ
-ve torspa eof polynomials inR
of degree less than or equal toi
(resp.j
) in the set of variablesX
0
, . . . , X
n
(resp.ℓ
0
, . . . , ℓ
k
).Givenanideal
I ⊂ R
anda ouple(i, j) ∈ N × N
,wedenote byI
6i,6j
theinterse tion ofI
withR
6i,6j
.Denition4 TheHilbertbi-seriesofabi-homogeneousideal
I ⊂ R
istheseriesP
i,j
dim (R
i,j
/I
i,j
) t
i
1
t
j
2
. The aneHilbertbi-series of anidealI ⊂ R
isP
i,j
dim (R
6i,6j
/I
6i,6j
) t
i
1
t
j
2
.Considerabi-homogeneousideal
I ⊂ R
ofKrulldimension2
. Thisse tionisdevotedto provethat,thereexists(i
0
, j
0
) ∈ N × N
su hthatforalli > i
0
andj > j
0
,dim(R
i,j
/I
i,j
) =
dim(R
i
0
,j
0
/I
i
0
,j
0
)
. Su haresultalreadyappearsin[40℄. Denote byR
′
the polynomial ring
Q[X
1
, . . . , X
n
, ℓ
1
, . . . , ℓ
k
]
. Consider the appli ationφ
i,j
: R
′
6i,6j
→ R
i,j
sendingapolynomialf ∈ R
′
6i,6j
ofdegreeα
(resp.β
)inthevariablesX
1
, . . . , X
n
(resp.ℓ
1
, . . . , ℓ
k
)to thepolynomialφ
i,j
(f ) = X
i
0
ℓ
j
0
f (
X
X
1
0
, . . . ,
X
n
X
0
,
ℓ
1
ℓ
0
, . . . ,
ℓ
k
ℓ
0
)
. GivenanidealI ⊂ R
′
and
(i, j) ∈ N × N
,φ
i,j
(I)
denotestheset{φ
i,j
(f ) | f ∈ I
6i,6j
}
. Additionally, onsider the mappingψ
i,j
: R
i,j
→ R
′
6i,6j
(whi h takes pla e of ade-homogenization pro ess in a homogeneous ontext) sending abi-homogeneous polynomial
f ∈ R
i,j
toψ
i,j
(f ) = f (1, X
1
, . . . , X
n
, 1, ℓ
1
, . . . , ℓ
k
) ∈ R
′
.
Givenabi-homogeneousideal
I ⊂ R
and(i, j) ∈ N × N
,ψ
i,j
(I)
denotestheset{ψ
i,j
(f ) |
f ∈ I
i,j
}
.Lemma3 Consider twointegers
i
andj
, an idealI
′
of
R
′
and
φ
i,j
the above appli ation fromR
′
6i,6j
toR
i,j
. Thendim(R
′
6i,6j
/I
6i,6j
′
) = dim(R
i,j
/φ
i,j
(I
6i,6j
′
)).
Proof. Remark thatR
i,j
,R
′
6i,6j
, andI
′
6i,6j
andφ
i,j
(I
′
6i,6j
)
are nite dimensionalQ
-ve torspa es.Moreover,for all
f ∈ R
′
6i,6j
and(i, j) ∈ N × N
,ψ
i,j
(φ
i,j
(f )) = f
. Then,ψ
i,j
(R
i,j
) =
R
′
6i,6j
andψ
i,j
(φ
i,j
(I
′
6i,6j
)) = I
6i,6j
′
. Hen e asψ
i,j
is an inje tive morphism,R
i,j
andR
′
6i,6j
ontheonehand,andI
′
6i,6j
andφ
i,j
(I
′
6i,6j
)
ontheotherhand,areisomorphi nite dimensionalQ
-ve torspa es.Sin eforve torspa es
E, F
withF ⊂ E
,dim(E) = dim(F ) + dim(E/F )
,wearedone.Thefollowinglemmaisusedfurther.
Lemma4 Let
I ⊂ R
beabi-homogeneousidealsu hthatX
0
(resp.ℓ
0
)isnotazerodivisor inR/I
. Denote byI
′
the idealI + hX
0
− 1, ℓ
0
− 1i ∩ R
′
. Thenφ
i,j
(I
′
6i,6j
) = I
i,j
. Proof. Considera bi-homogeneous polynomialp ∈ I
i,j
. Obviously,ψ
i,j
(p) ∈ I
′
6i,6j
.Sin e the bi-degree of
p
is, by denition, the ouple(i, j)
,φ
i,j
(ψ
i,j
(p)) = p
, this impliesp ∈ φ
i,j
(I
6i,6j
′
)
. Thus,I
i,j
⊂ φ
i,j
(I
′
6i,6j
)
;weprovenowthatφ
i,j
(I
′
6i,6j
) ⊂ I
i,j
.FromLemma1,sin e
I
isbi-homogeneous,thereexistsanitefamilyofbi-homogeneous polynomialsp
1
, . . . , p
m
generatingI
. Considerp
′
∈ I
′
6i,6j
. Then, there exist polynomialsq
r
(forr ∈ {1, . . . , m}
),P
andQ
inR
,su hthatp
′
=
P
m
r=1
q
r
.p
r
+ Q(X
0
− 1) + P (ℓ
0
− 1)
. Denotebyp
thepolynomialP
m
allthebi-homogeneous omponentsof
p
belongtoI
,andonejust hasto onsider the ase wherep
′
issu hthat
p
isbi-homogenous.Under this assumption, it is easy to see that
φ
i,j
(p
′
)
belongs to
R
i,j
and that there existsa ouple(α, β) ∈ Z × Z
su hthatφ
i,j
(p
′
) = X
α
0
.ℓ
β
0
.p
. If bothα, β
arepositive,thenφ
i,j
(p
′
) ∈ I
i,j
. Ifα < 0
andβ > 0
, thenX
−α
0
φ
i,j
(p
′
) = ℓ
β
0
p ∈ I
. Supposeφ
i,j
(p
′
) /
∈ I
. This would imply that
X
0
is a zero-divisorinR/I
, whi h is notpossible by assumption. Moreover,sin eφ
i,j
(p
′
)
hasbi-degree
(i, j)
,φ
i,j
(p
′
)
belongsto
I
i,j
. Similarargumentsallow usto on ludewhenα > 0
andβ < 0
andwhenbothα
andβ
arenegative.Givenapolynomial
f ∈ Q[X
0
, . . . , X
n
, ℓ
0
, . . . , ℓ
k
]
, andA
∈ GL
n+k+2
(Q)
, wedenotebyf
A
thepolynomialobtainedbyperformingthe hangeofvariablesindu edby
A
onf
. We denote byI
A
the ideal generated by
f
A
1
, . . . , f
s
A
. In the sequel, we onsider ex lusively matri esA
su h that the a tionofA
onR
is abi-gradedisomorphismof bi-degree(0, 0)
onR
withrespe ttothevariablesX
0
, . . . , X
n
andℓ
0
, . . . , ℓ
k
,i.e. forallhomogeneouslinear formsu ∈ Q[X
0
, . . . , X
n
]
(resp.v ∈ Q[ℓ
0
, . . . , ℓ
k
]
),u
A
(resp.v
A
) isa homogeneouslinear forminQ[X
0
, . . . , X
n
]
(resp.Q[ℓ
0
, . . . , ℓ
k
]
).Lemma5 Let
I ⊂ R
be a bi-homogeneous ideal, thenI
andI
A
have the same Hilbert bi-series.
Proof. Thea tion of
A
onR
is anisomorphismof bi-graded ringof bi-degree(0, 0)
, the inverse a tion ofA
is the a tion ofA
−1
. Thus,
R
i,j
equalsR
A
i,j
and, ifE ⊂ R
is aQ
-ve torspa e,dim(E) = dim(E
A
)
. Sin e forve torspa es
E, F
withF ⊂ E
,dim(E) =
dim(F ) + dim(E/F )
,wehavedim(R
i,j
/I
i,j
) = dim(R
A
i,j
/I
i,j
A
)
whi himpliestheequalityof theHilbertbi-seriesofI
andI
A
.Lemma6 Let
I ⊂ R
beabi-homogeneousidealwhi hisaninterse tionofadmissibleideals. Then,forageneri hoi eofhomogeneouslinearformu
1
(resp.v
1
)inQ[X
0
, . . . , X
n
]
(resp.Q[ℓ
0
, . . . , ℓ
k
]
) theaneHilbertbi-series ofI + hu
1
− 1, v
1
− 1i
equals theHilbertbi-series ofI
.Proof. FromRemark2,sin eis
u
1
andv
1
are hosengeneri allytheydonotdivide0
isR/I
. ChooseA
∈ GL
n+k+2
(Q)
su h thatthea tionofA
onR
isabi-gradedisomorphism ofbi-degree(0, 0)
andsu hthatu
A
1
= X
0
andv
A
1
= ℓ
0
. UsingLemma 5,theHilbert series ofI
equals the oneofI
A
. From Lemma 3 and Lemma 4, the ane Hilbert bi-series of
I
A
+ hX
0
− 1, ℓ
0
− 1i ∩ Q[X
1
, . . . , X
n
, ℓ
1
, . . . , ℓ
k
]
equalsthebi-seriesofI
A
whi hequalsthe oneof
I
.We prove now
ψ
′
i,j
: R
A
6i,6j
→ R
′A
6i,6j
sendingf ∈ R
A
6i,6j
tof (1, X
1
, . . . , X
n
,
1, ℓ
1
, . . . , ℓ
k
)
indu es an isomorphism betweenR
′A
6i,6j
/I
′A
6i,6j
andR
A
6i,6j
/(I
A
+ hX
0
− 1, ℓ
0
− 1i
6i,6j
)
whi hisimmediateusingtheisomorphismbetweenR
′A
6i,6j
/I
′A
6i,6j
andR
A
i,j
/I
i,j
A
.ThefollowingresultisusedintheproofofTheorem2.
Proposition 3 Let
I
be abi-homogeneous ideal ofR
. Then, the Hilbert seriesofI
equals the seriesobtainedbyputtingt
1
= t
2
inthe Hilbert bi-series ofI
.Proof. For all
d ∈ N
,denotebyR
d
theQ
-ve torspa eofthehomogeneouspolynomials ofR
of totaldegreed
. Forany ouple(i, j) ∈ N × N
, denote byR
i,j
theQ
-ve torspa e ofbi-homogeneouspolynomialsofbi-degree(i, j)
. Bydenition ofabi-homogeneousideal, iff
is a polynomial ofI
, then the bi-homogeneous omponents off
also belong toI
. Hen e themorphism fromI
d
toΠ
i+j=d
I
i,j
sending apolynomialonto itsbi-homogeneous omponentsis dened for anyf
ofI
and is invertible, i.e. is an isomorphismofQ
-ve tor spa es. Thisprovesthatdim(I
d
) =
P
i+j=d
dim(I
i,j
)
. With thesamearguments,weshow thatdim(R
d
) =
P
i+j=d
dim(R
i,j
)
. Consequentlydim(R
d
/I
d
) = dim(R
d
) − dim(I
d
) =
X
i+j=d
dim(R
i,j
) − dim(I
i,j
)
Ontheother hand,forall
(i, j) ∈ N × N
,dim(R
i,j
) − dim(I
i,j
) = dim(R
i,j
/I
i,j
)
.Proposition 4 Let
I ⊂ R
be a bi-homogeneous ideal and letJ = ∩
Q∈Adm(I)
Q
. Suppose thatJ
has Krull dimension2
. There exists(i
0
, j
0
) ∈ N × N
su h that for alli > i
0
andj > j
0
,dim(R
i,j
/J
i,j
) = dim(R
i
0
,j
0
/J
i
0
,j
0
)
whi h equalsthe bi-degree ofI
.Proof. FromRemark3,thebi-degreeof
I
isthebi-degreeoftheidealJ = ∩
Q∈Adm(I)
Q
. FromProposition2andDenition3,thebi-degreeofJ
isthedegreeoftheidealJ + hu −
1, v − 1i
whereu
(resp.v
) is a generi homogeneouslinear form inQ[X
0
, . . . , X
n
]
(resp.Q[ℓ
0
, . . . , ℓ
k
]
).Consider now
A
∈ GL
n+k+2
(Q)
su h thatu
A
= X
0
andv
A
= ℓ
0
, and su h that theanoni ala tionof
A
onR
isabi-gradedisomorphismonR
ofbi-degree(0, 0)
withrespe t to thevariablesX
0
, . . . , X
n
andℓ
0
, . . . , ℓ
k
. Notethat the bi-degree ofJ
equalstheoneofJ
A
whi h is thedegree of
J
A
+ hX
0
− 1, ℓ
0
− 1i
. Inthe sequel, denote byJ
′A
theidealJ
A
+ hX
0
− 1, ℓ
0
− 1i
∩ Q[X
1
, . . . , X
n
, ℓ
1
, . . . , ℓ
k
]
From Lemma 5,dim(R
i,j
/J
i,j
) = dim(R
A
i,j
/J
i,j
A
)
. Moreover, sin e by denition ofJ
A
,
X
0
(resp.ℓ
0
) is not a zero-divisor inR
A
/J
A
, from Lemma 4,
dim(R
A
i,j
/J
i,j
A
) =
dim(R
′A
i,j
/φ
i,j
(J
′A
6i,6j
))
. Finally,fromLemma3dim(R
′A
i,j
/φ
i,j
(J
′A
6i,6j
)) = dim(R
′A
6i,6j
/J
′A
6i,6j
)
. Thus, one hasdim(R
i,j
/J
i,j
) = dim(R
′A
6i,6j
/J
′A
6i,6j
)
. It is su ient to prove there ex-ists(i
0
, j
0
) ∈ N × N
su h that for all(i, j) ∈ N × N
satisfyingi > i
0
andj > j
0
,dim(R
′A
6i,6j
/J
′A
6i,6j
)
= dim(R
′A
6i
0
,6j
0
/J
′A
6i
0
,6j
0
)
and thatdim(R
′A
6i
0
,6j
0
/J
′A
6i
0
,6j
0
)
equals the degree ofJ
′A
.
Thesearea onsequen eof
dim(J
′A
) = 0
andfor
i
,j
andd
largeenoughdim(R
′A
6i,6j
/J
′A
6i,6j
) =
dim(R
′A
6d
/J
′A
6d
) = deg(J
′A
)
,whereR
′A
6d
(resp.J
′A
6d
)denotesthesetofpolynomialsinR
′A
(resp.
J
′A
)ofdegreelessthanorequalto
d
.2.3 Canoni al form of the Hilbert bi-series
Inthisparagraph,weprovidea anoni alformoftheHilbert bi-seriesofabi-homogeneous ideal
I ⊂ R
with respe t to the integersC
d,e
(I)
where(d, e)
lies in the set of admissible bi-dimensionsofI
.Lemma7 Let
I ⊂ R
beabi-homogeneousideal. Fori = 1, . . . , s
letf
i
beabi-homogeneous polynomialinR
of bi-degree(α
i
, β
i
)
. Fori = 1, . . . , s
,denotebyI
i
the idealI + hf
1
, . . . , f
i
i
andsupposethat for alli ∈ {1, . . . , s − 1}
,f
i+1
isnotadivisor of zeroinR/I
i
.Then the Hilbertbi-series of
I
s
equalsΠ
s
i=1
(1 − t
α
i
1
t
β
i
2
)
H(I)
.Proof. Wepro eedbyindu tionon
s
. Supposersts = 1
.Denoteby
ann
R/I
(f
1
)
theannihilatoroff
1
inR/I
. Thesequen ebelow0 → ann
R/I
(f
1
) −→ R/I
f
1
−→R/I −→ R/(I + hf
1
i) → 0
is exa t. Sin e
f
1
is nota zerodivisor inR/I
,ann
R/I
(f
1
)
is0
. Remark that, sin ef
1
is bi-homogeneous,andI
i,j
andR
i,j
ontainonlybi-homogeneouspolynomials,thefollowing one0 −→ R
i,j
/I
i,j
f
1
−→R
i+α
1
,j+β
1
/I
i+α
1
,j+β
1
−→ R
i,j
/(I + hf
1
i)
i,j
→ 0
is alsoexa t. Thus, lassi ally,the alternatesum ofthe dimensionof theve torspa esof thisexa tsequen eisnull. Addingthesesumsforall
(i, j) ∈ N × N
,oneobtains:(1 − t
α
1
1
t
β
1
2
)H(I) = H(I
1
)
where
(α
1
, β
1
)
isthe bi-degreeoff
1
. Supposenowtheresultto betruefors − 1
, i.e. the Hilbertbi-seriesofI
s
−1
,H(I
s
−1
)
,equalss
Y
−1
i=1
(1 − t
α
i
1
t
β
i
2
)
!
H(I)
. Sin e,byassumption,f
s
isnotadivisorof0
inR/I
s−1
,thefollowingsequen eis exa t:0 → ann
R/I
s−1
(f
s
) −→ R/I
s
−1
f
s
−→R/I
s
−1
−→ R/(I
s
−1
+ hf
s
i) → 0
whi h implies, as above, that
H(I
s
) = (1 − t
α
s
1
t
β
s
2
)H(I
s
−1
)
and then, using the indu tion hypothesis,H(I
s
) =
Π
s
i=1
(1 − t
α
i
1
t
β
i
2
)
H(I)
Lemma8 TheHilbertbi-series of